Phil Lucht Math & Physics Archive
Home / Math and Physics Files / Math / Wedge World / tensor wedge doc / Resolved Issues and Support

Where next with Wedge

DOCX · 47.8 KB
Open DOCX file

A short working note by Phil dated 9.14.15, written after eight sections on the wedge product in the main and dual spaces. It works out wedge products such as 2-blade with vector and 2-blade with 2-blade using antisymmetrized sums over permutations. It then writes general multivectors for n = 3 and as sums over multi-indices, asking how eI^eJ behaves and how this relates to Spivak's and Sjamaar's notation.

AI-written summary; may contain errors.

Extracted text (machine-read; may contain errors)
Where next with Wedge? PhL 9.14.15 I have now written a total of 8 sections on the wedge product in both the main and dual spaces. The next step is to define a wedge product for higher order objects in Λ. I could start with w ≡ v1 ^ v2 and call it a bivector and ask about its properties. I might want to know about h = w ^ v for example. Well. w lies in the space L2 whose general elements are given by T = Σij Fij ei ^ ej = Σi<j Tij ei ^ ej Then I guess one could say T ^ v = (Σij Fij ei ^ ej) ^ (Σk vk ek) L2 ^ L1 = Σijk Fijvk (ei ^ ej ^ ek) = element of L3. = Σi<j<k [ΣP (-1)P FP(i)P(j)vP(k)] (ei ^ ej ^ ek) = Σi<j<k Tijk (ei ^ ej ^ ek) Tijk = ΣP (-1)P FP(i)P(j)vP(k OK, now try a fancier example: T ^ H = (Σij Fij ei ^ ej)^(Σab Gab ea ^ eb) L2 ^ L2 = Σijab FijGab ( ei ^ ej ^ ea ^ eb ) = Σi<j<a<b [ΣP (-1)P FP(i)P(j)GP(a)P(b)] ( ei ^ ej ^ ea ^ eb ) = Σi<j<a<b Tijab ( ei ^ ej ^ ea ^ eb ) Tijab = ΣP (-1)P FP(i)P(j)GP(a)P(b) So I think doing the wedge products of pure "blades" is straightforward in this manner. Question: for a pair of 2-blads as shown above, how do I relate that to Spivak's notation Where is it that we get a multibladed answer? Maybe that was the Clifford Geometric product. No, it is the product of multivectors. So how do I write a general multivector let's say for n = 3 F = f + Σi Fi ei + Σij Fij ei ^ ej + Σijk Fijk ei ^ ej^ ek G = g + Σi Gi ei + Σij Gij ei ^ ej + Σijk Gijk ei ^ ej^ ek The result seems straightforward. F^G = ( f + Σi Fi ei + Σij Fij ei ^ ej + Σijk Fijk ei ^ ej^ ek ) ^ ( g + Σi Gi ei + Σij Gij ei ^ ej + Σijk Gijk ei ^ ej^ ek) = [ ( f + Σi Fi ei + Σij Fij ei ^ ej + Σijk Fijk ei ^ ej^ ek ) ^ g + ( f + Σi Fi ei + Σij Fij ei ^ ej + Σijk Fijk ei ^ ej^ ek) ^ (Σi Gi ei) + etc There will be terms which are elements of all four blade spaces. Is there some compact way to do all this? F = ΣIFIeI I = all possible ordinary multiindices having 0,1,2 or up to n pieces G = ΣJGJeJ I = all possible ordinary multiindices F^G = ΣIJ FIGJ (eI^eJ) What do I know about (eI^eJ)? In the following, a and b are generally different integers. eI^eJ = ( ei ^ ei ^ .... ^ ei) ^ ( ej ^ ej ^ .... ^ ej) Sjamaar does not use I and J in the above "super general" sense, he might have I for a k-form and J for n l-form.