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One-semester course notes on solid mechanics by Krzysztof Wilmanski of the University of Zielona Gora, Poland, for the ROSE School in Pavia. They cover vectors and tensors, kinematics, balance of mass and momentum, thermodynamics, linear elasticity (Green functions, waves, plane strain), thermo- and poroelasticity, viscoelasticity, plasticity and dislocations. It is a downloaded book by another author, not Phil's own work.
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Fundamentals of Solid Mechanics
Course at the European School for Advanced Studies in Earthq uake Risk Reduction
(ROSE School), Pavia, Italy
Krzysztof Wilmanski
University of Zielona Gora, Poland
http://www.mech-wilmanski.de
Contents
Introduction, historical sketch 5
1 Modicum of vectors and tensors 9
1.1 Algebra . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 9
1.2 Analysis . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17
2 Geometry and kinematics of continua 21
2.1 Preliminaries . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 1
2.2 Reference configuration and Lagrangian description . . . . . . . . . . . . . 22
2.3 Displacement, velocity, Eulerian description . . . . . . . . . . . . . . . . . 30
2.4 Infinitesimal strains . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 36
2.5 Compatibility conditions . . . . . . . . . . . . . . . . . . . . . . . . . . . . 40
3 Balance of mass and momentum 43
3.1 Conservation of mass . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 43
3.2 Conservation of momentum . . . . . . . . . . . . . . . . . . . . . . . . . . 48
3.2.1 Lagrangian description . . . . . . . . . . . . . . . . . . . . . . . . . 48
3.2.2 Eulerian description . . . . . . . . . . . . . . . . . . . . . . . . . . 4 9
3.2.3 Moment of momentum . . . . . . . . . . . . . . . . . . . . . . . . . 51
3.2.4 Stress analysis . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 52
4 Thermodynamics of solids 61
4.1 Energy conservation law . . . . . . . . . . . . . . . . . . . . . . . . . . . . 61
4.2 Second law of thermodynamics . . . . . . . . . . . . . . . . . . . . . . . . 64
5 Elastic materials 69
5.1 Non-linear elasticity . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 69
5.2 Linear elasticity, isotropic and anisotropic material s . . . . . . . . . . . . 71
5.2.1 Governing equations . . . . . . . . . . . . . . . . . . . . . . . . . . 71
5.2.2 Navier-Cauchy equations, Green functions, displace ment potentials 77
5.2.3 Beltrami-Michell equations . . . . . . . . . . . . . . . . . . . . . . 89
5.2.4 Plane strain and plane stress . . . . . . . . . . . . . . . . . . . . . 90
5.2.5 Waves in linear elastic materials . . . . . . . . . . . . . . . . . . . 95
5.2.6 Principle of virtual work . . . . . . . . . . . . . . . . . . . . . . . . 104
3
4 CONTENTS
5.3 Thermoelasticity . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 107
5.4 Poroelasticity . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 111
6 Viscoelastic materials 115
6.1 Viscoelastic fluids and solids . . . . . . . . . . . . . . . . . . . . . . . . . . 115
6.2 Rheological models . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 118
6.3 Three-dimensional viscoelastic model . . . . . . . . . . . . . . . . . . . . . 123
6.4 Differential constitutive relations . . . . . . . . . . . . . . . . . . . . . . . 128
6.5 Steady state processes and elastic-viscoelastic corre spondence principle . . 129
7 Plasticity 135
7.1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 35
7.2 Plasticity of ductile materials . . . . . . . . . . . . . . . . . . . . . . . . . 138
7.3 Plasticity of soils . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 149
7.4 Viscoplasticity . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 154
8 Dislocations 157
8.1 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 57
8.2 Continuum with dislocations . . . . . . . . . . . . . . . . . . . . . . . . . 159
8.3 On plasticity of metals . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 164
8.4 Dislocations in geophysics . . . . . . . . . . . . . . . . . . . . . . . . . . . 165
9 Appendix: Green functions for isotropic elastic material s 169
9.1 Purpose . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 169
9.2 Statics of isotropic elastic materials . . . . . . . . . . . . . . . . . . . . . . 170
9.3 Dynamic Green function for isotropic elastic materials . . . . . . . . . . . 173
Introduction, historical sketch
Remnants of old civil engineering constructions prove that already in ancient times
the human being was able to build very complex structures. Th e old masters had both
experience and intuition with which they were able to create the most daring structures.
However, they did not use in their work any theoretical model s as we understand them
today. Most likely, it was first in XVI century that notions ne cessary for such a modeling
were invented.
Leonardo da Vinci (1452-1519) sketched in his notebooks a po ssible test of the tensile
strength of a wire.
Arc of Ctesiphon (the winter palace of Sassanids, Iraq) cons tructed in 129
B.C. (left panel) and the dome of the Florence cathedral desi gned and built
by Filippo Brunelleschi in 1425 (right panel) — two examples of the early
ingenious constructions.
’In his book on mechanics1Galileo (Galileo Galilei, 1564-1642) also dealt with the
strength of materials, founding that branch of science as we ll. He was the first to show
1Dialogo di Galileo Galilei Linceo Matematico Sopraordinar io dello Studio di Pisa,
in Florenza, Per Gio: Batista Landini MDCXXXII
5
6 Introduction
that if a structure increased in all dimensions equally it wo uld grow weaker — at least he
was the first to explain the theoretical basis for this. This i s what is known as the square-
cube law. The volume increases as the cube of linear dimensio ns but the strength only
as the square. For that reason larger animals require propor tionally sturdier supports
than small ones. A deer expanded to the size of an elephant and kept in exact proportion
would collapse, its legs would have to be thickened out of pro portion for proper support’2.
Below we mention only a few scientists whose contributions a re particularly important
for the development of continuum mechanics at its early stag e. Many further details can
be found in the article of J. R. Rice3.
Robert Hooke is considered to be the founder of linear elasti city. He discovered in
1660 (published in 1678), the observation that the displace ment under a load was for
many materials proportional to force. However, he was not aw are yet of the necessity of
terms of stress and strain. A similar discovery was made by E. Mariotte (France, 1680).
He described as well the explanation for the resistance of be ams to transverse loadings.
He considered the existence of bending moments caused by tra nsverse loadings and devel-
oping extensional and compressional deformations, respec tively, in material fibers along
upper and lower portions of beams. The first to introduce the r elation between stresses
and strains was the Swiss mathematician and mechanician Jac ob Bernoulli (1654-1705).
In his last paper of 1705 he indicated that the proper way of de scribing deformation was
to give force per unit area, i.e. stress, as a function of the e longation per unit length,
i.e. strain, of a material fiber under tension. Numerous most important contributions
were made by the Swiss mathematician and mechanician Leonha rd Euler (1707-1783),
who was taught mathematics by Jacob’ brother Johann Bernoul li (1667-1748). Among
many other ideas he proposed a linear relation between stres sσand strainεin the form
σ=Eε(1727). The coefficient Eis now usually called Young’s modulus after English
naturalist Thomas Young who developed a similar idea in 1807 .
Since the proposition of Jacob Bernoulli the notion that the re is an internal tension
acting across surfaces in a deformed solid has been commonly accepted. It was used, for
example, by German mathematician and physicist Gottfried W ilhelm Leibniz in 1684.
Euler introduced the idea that at a given section along the le ngth of a beam there were
internal tensions amounting to a net force and a net bending m oment. Euler introduced
the idea of compressive normal stress as the pressure in a flui d in 1752.
The French engineer and physicist Charles-Augustin Coulom b (1736-1806) was ap-
parently the first to relate the theory of a beam as a bent elast ic line to stress and strain
in an actual beam. He discovered the famous expression σ=My/I for the stress due to
the pure bending of a homogeneous linear elastic beam; here Mis the bending moment,
yis the distance of a point from an axis that passes through the section centroid, parallel
to the axis of bending, and Iis the integral of y2over the section area. The notion of
shear stress was introduced by French mathematician Parent in 1713. It was the work
of Coulomb in 1773 to develop extensively this idea in connec tion with beams and with
the stressing and failure of soil. He also studied frictiona l slip in 1779.
The most important and extensive contributions to the devel opment of continuum
2quotation from I. Asimov’s Biographical Encyclopedia of Sc ience and Technology, Doubleday, 1964.
3J. R. RIiscIcscIesc; Mechanics of Solids , published as a section of the article on Mechanics in the 199 3
printing of the 15th edition of Encyclopaedia Britannica (v olume 23, pages 734 - 747 and 773), 1993.
Introduction 7
mechanics stem from the great French mathematician Augusti n Louis Cauchy (1789-
1857), originally educated as an engineer. ’In 1822 he forma lized the stress concept in
the context of a general three-dimensional theory, showed i ts properties as consisting of
a 3 by 3 symmetric array of numbers that transform as a tensor, derived the equations
of motion for a continuum in terms of the components of stress , and gave the specific
development of the theory of linear elastic response for iso tropic solids. As part of this
work, Cauchy also introduced the equations which express th e six components of strain,
three extensional and three shear, in terms of derivatives o f displacements for the case
when all those derivatives are much smaller than unity; simi lar expressions had been
given earlier by Euler in expressing rates of straining in te rms of the derivatives of the
velocity field in a fluid’4.
In this book we present a modern version of those models in whi ch not only linear
elastic but also viscoelastic and plastic materials are inc luded. The full nonlinear theory
is not included but some of its basic notions such as Lagrangi an and Eulerian descriptions
are indicated.
In the presentation we avoid many mathematical details in or der to be understandable
for less mathematically skillful engineers and natural sci entists. Those who would like
to clean up some mathematical points we refer to the work of M. Gurtin [4]. Nonlinear
problems are presented in many modern monographs. We quote h ere only four examples
[2], [11], [21], [22].
Linear models of elasticity, viscoelasticity, plasticity , viscoplasticity and dislocations
are presented. To keep the volume of the notes related to the e xtent of the one-semester
course we have not included such important subjects as coupl ing to thermal effects,
a theory of brittle materials (damage), some topics, such as critical states of soils or
earthquake mechanics, are only indicated. The book almost d oes not contain exercises
which we offer to students separately.
Some examples, auxiliary remarks and reminders which are no t necessary for the
systematic presentation of the material are confined by the s igns⋆...♣. References are
made in two ways. I have selected a number of books and monogra phs — 24 to be exact
— which were used extensively in preparing these notes and wh ich may serve as a help
in homework of students. Many references to particular issu es and, especially, historical
notes, are made in the form of footnotes. I would like to apolo gy to these readers who
do not speak Polish for some references in this language. I di d it only occasionally when
the English version is not available and when I wanted to pay a tribute to my collegues
and masters for teaching me many years ago the subject of cont inuum mechanics.
4J. R. RIiscIcscIesc; Mechanics of Solids , published as a section of the article on Mechanics in the 199 3
printing of the 15th edition of Encyclopaedia Britannica (v olume 23, pages 734 - 747 and 773), 1993.
8 Introduction
Chapter 1
Modicum of vectors and
tensors
1.1 Algebra
The most important notions of mechanics such as positions of points, velocities, ac-
celerations, forces are vectors and many other important ob jects such as deformations,
stresses, elasticity parameters form tensors. Therefore w e begin our presentation with
a brief overview of a vector calculus in Euclidean spaces. We limit the presentation
to three-dimensional spaces as continuum mechanics does no t require any more general
approach.
Vectors are objects characterized by the length and the dire ction. A vector space V
is defined by a set of axioms describing three basic operation s on vectors belonging to
this space: a multiplication by a real number, an addition, a nd a scalar product. The
first operation
∀a∈V∀α∈ℜb=αa∈V (1.1)
defines, for any vector a, a new vector b=αawhose direction is the same (it has the
opposite orientation for α <0) as this of the vector aand the length is αtimes larger
(or smaller for|α|<1) than this ofa. The second operation
∀a,b∈Va+b=c∈V (1.2)
defines for two vectors a,ba new vectorcwhich is constructed according to the rule of
9
10 Modicum of vectors and tensors
triangle shown in Fig.1.1.
Fig. 1.1: Addition of vectors
The third operation
∀a,bα=a·b, α∈ℜ, (1.3)
is a scalar product which for any two vectors a,bdefines a real number. For any vector
a
a·a=|a|2, (1.4)
it defines its length |a|, while for two vectors a,bit specifies the angle ϕ=(a,b)between
them
a·b=|a||b|cosϕ. (1.5)
These three operations satisfy a set of axioms, such as assoc iativity, commutativity, etc.
which we do not specify here as in the analytical description these are replaced by similar
axioms for operations on real numbers.
One should also mention that, by means of the above operation s one can introduce
the vector0whose length is 0and direction is arbitrary as well as a number of linearly
independent vectors which defines the dimension of the vecto r spaceV. We say that
the spaceVis three-dimensional if for any three different non-zero vec torsa1,a2,a3of
different direction the relation
α1a1+α2a2+α3a3=0, (1.6)
is satisfied only if the numbers α1,α2,α3are all equal to zero. This property allows to
replace the above presented geometrical approach to vector calculus by an analytical ap-
proach. This was an ingenious idea of René Descartes (1596-1 650). For Euclidean spaces
which we use in these notes we select in the vector space Vthree linearly independent
vectorsei,i=1,2,3,which satisfy the following condition
ei·ej=δij, i,j=1,2,3, (1.7)
whereδijis the so-called Kronecker delta. It is equal to one for i=jand zero otherwise.
Fori=jwe have
ei·ei=1, (1.8)
which means that each vector eihas the unit length. Simultaneously, for i/negationslash=j,
ei·ej=0⇒ϕ=π
2, (1.9)
1.1 Algebra 11
whereϕis the angle between eiandej. It means that these vectors are perpendicular.
We call such a set of three vectors {e1,e2,e3}the base (or basis) vectors of the space
V. Obviously, any linear combination
a=a1e1+a2e2+a3e3∈V, (1.10)
is a non-zero vector for ainot simultaneously equal to zero. It is easy to see that any
vector from the space Vcan be written in this form. If we choose such a vector athen
a·ei=3summationdisplay
j=1(ajej)·ei=3summationdisplay
j=1ajδij=ai. (1.11)
The numbers aiare called coordinates of the vector a. Clearly, they may be written in
the form
ai=|a||ei|cos((a,ei))=|a|cos((a,ei)), (1.12)
i.e. geometrically it is the length (with an appropriate sig n depending on the choice of
ei!) of projection of the vector aon the direction of the unit vector ei.Certainly,(a,ei)
denotes the angle between the vectors aandei.
The above rule of representation of an arbitrary vector allo ws to write the operations
in the vector space in the following manner
b=αa=(αai)ei,b=biei, bi=αai,
c=a+b=(ai+bi)ei,c=ciei, ci=ai+bi, (1.13)
α=a·b=aibi, α=aibi,
where we have introduced the so-called Einstein convention that a repetition of an index
in the product means the summation over all values of this ind ex. For instance,
aibi≡3summationdisplay
i=1aibi. (1.14)
Relations (1.13) allow for the replacement of geometrical r ules of vector calculus by
analytical rules for numbers denoting coordinates of the ve ctor. A vector ain the three-
dimensional space is in this sense equivalent to the matrix (a1,a2,a3)Tprovided we
choose a specific set of base vectors {e1,e2,e3}. However, in contrast to matrices which
are collections of numbers, vectors satisfy certain rules o f transformation between ma-
trices specified by the rotations of base vectors. It means th at two different matrices
(a1,a2,a3)Tand(a1′,a2′,a3′)Tmay define the same vector if the coordinates aiand
ai′are connected by a certain rule of transformation. We can spe cify this rule immedi-
ately if we consider a rotation of the base vectors {e1,e2,e3}to the new base vectors
{e1′,e2′,e3′}. We have
ei′=Ai′iei, Ai′i=ei′·ei=cos((ei′,ei)),
ei=Aii′ei′, Aii′=ei·ei′=cos((ei,ei′)), (1.15)
ei′=Ai′iAij′ej′⇒Ai′iAij′=δi′j′.
12 Modicum of vectors and tensors
Hence the matrix (Aii′)is inverse to the matrix (Ai′i)Obviously, these matrices of
transformation Ai′iandAii′are square and formed of sine and cosine functions of angles
between base vectors {e1,e2,e3}and{e1′,e2′,e3′}.
⋆Example: Further we refer frequently to the rotation in the case of a tw o-dimensional
space. In a three-dimensional space a rotation is defined by t hree angles (e.g. Euler an-
gles of crystallography). In the two-dimensional case we ne ed one angle, say φ, which we
assume to be positive in the anticlockwise direction (see: F ig. 1.2).
Fig. 1.2: Rotation of the basis on the plane perpendicular to e3
Then we have
A11′=e1·e1′=cosφ, A12′=e1·e2′=cosparenleftBigπ
2+φparenrightBig
=−sinφ,
A21′=e2·e1′=cosparenleftBigπ
2−φparenrightBig
=sinφ, A22′=e2·e2′=cosφ, (1.16)
A33′=e3e3′=1,
and the remaining components are zero. Similarly, we can find the components of the
matrixAi′i. Then we have
(Aii′)=
cosφ−sinφ0
sinφcosφ0
0 0 1,(A
i′i)=cosφsinφ0
−sinφcosφ0
0 0 1,(A
ii′)T=(Ai′i).
(1.17)
The last property, which holds also in a three-dimensional c ase, together with (1.15)
means that the matrix (Ai′i)is orthogonal. This is the general property of all matrices
of rotation. We shall return to this property in the discussi on of the deformation of
continua.
As an example let us consider the two-dimensional transform ation of the vector
a=aiei,(ai)=(1,2,3), (1.18)
1.1 Algebra 13
withφ=π/6. We have
a=ai′ei′, ai′=Aii′ai⇒ (1.19)
⇒(ai′)=(cosφ+2sinφ,−sinφ+2cosφ,3)=
=parenleftBig
1+√
3/2,√
3−1/2,3parenrightBig
.
♣
Bearing the above considerations in mind we can write for an a rbitrary vector a
a=aiei=ai′ei′⇒ai′=(aiei)·ei′=Aii′ai, (1.20)
In mathematics the rule of transformation (1.20) is conside red to be the formal defi-
nition of the vector.
We return now to objects defined in a general case on three-dim ensional vector spaces.
One of the most important objects defined on these spaces is a t ensor of the second rank
which transforms an arbitrary vector into another vector. I n addition this transformation
should be linear and homogeneous. Formally, we can write
b=t(a)=Ta, (1.21)
whereTis independent of a. The first part of this relation means that the vector bis
the value of the function tcalculated for a chosen vector a. The second part means that
the functiontis linear. It should be invertible, i.e. the tensor T−1should exist and be
unique
a=T−1b,TT−1=1, (1.22)
where1is the unit tensor. These properties indicate that a represe ntation of the tensor
Tin any set of base vectors is a square matrix.
For a chosen set of base vectors {e1,e2,e3}we can introduce the operation of the
tensor product⊗which defines the unit tensor 1as the matrix (δij)and we write
1=δijei⊗ej. (1.23)
Clearly, in order to be a unit tensor it must possess the follo wing property
a=1a⇒aiei=(δijei⊗ej)(akek), (1.24)
which means that the tensor product operates in this way that we take the scalar product
of the second unit vector in 1(i.e.ejin our case) with the vector aappearing after the
unit tensor. Then (1.24) becomes
aiei=δijeiakδjk, (1.25)
which is, of course, an identity.
Making use of the tensor product we can write the following re presentation for an
arbitrary tensor of the second rank
T=Tijei⊗ej. (1.26)
14 Modicum of vectors and tensors
Matrix(Tij)is the representation of the tensor Tin the basis{e1,e2,e3}. The numbers
Tijare called components of the tensor T. Now the relation (1.21) can be written in the
form
biei=(Tijei⊗ej)(akek)=Tijakeiej·ek=Tijajei⇒bi=Tijaj. (1.27)
The tensorTchanges both the direction and the length of the vector a. For the
length we have the relation
|b|2=b·b=(Ta)·(Ta)= (1.28)
=TijajTilal=ajTijTilal=a·TTTa.
Usually|b|/negationslash=|a|. However, if the tensor Tpossesses the property TTT=1the length of
the vectorbremains the same as this of the vector a. Such tensors are called orthogonal
and we denote them usually by O. Obviously, they have the property
OT=O−1, (1.29)
which may also be used as the definition of orthogonality of th e tensor. Orthogonal
tensors yield only rotations of vectors.
Once we have the length of the vector bwe can easily find the angle of rotation caused
by the tensorT. We have for the angle ϕ=(a,b)
a·b=|a||b|cosϕ⇒cosϕ=Tijaiaj√aiairadicalbig
(TijajTikak). (1.30)
The representation (1.26) allows to specify rules of transf ormation of components of
an arbitrary tensor of the second rank T. Performing the transformation of base vectors
{e1,e2,e3}→{e1′,e2′,e3′}we obtain
T=Tijei⊗ej=Tij(Aii′ei′)⊗(Ajj′ej′)=
=Aii′Ajj′Tijei′⊗ej′=Ti′j′ei′⊗ej′.
Hence
Ti′j′=Aii′Ajj′Tij. (1.31)
Similarly to vectors, this relation is used in tensor calcul us as a definition of the tensor
of the second rank.
Majority of second rank tensors in mechanics are symmetric. They possess six in-
dependent components instead of nine components of a genera l case. However, some
particular problems, such as Cosserat media and couple stre sses, interactions with elec-
tromagnetic fields require full nonsymmetric tensors. An ar bitrary tensor can be always
split into a symmetric and antisymmetric parts
T=Ta+Ts,Ta=1
2parenleftBig
T−TTparenrightBig
,Ts=1
2parenleftBig
T+TTparenrightBig
, (1.32)
1.1 Algebra 15
and, obviously, Tapossesses only three off-diagonal non-zero components whil eTspos-
sesses six components. It is often convenient to replace the antisymmetric part by a
vector. Usually, one uses the following definition
V=Vkek, Vk=−1
2ǫijkTa
ij⇒Ta
ij=−ǫijkVk. (1.33)
whereVis called the axial vector and ǫijkis the permutation symbol (Levi-Civita sym-
bol). It is equal to one for the even permutation of indices {1,2,3},{2,3,1},{3,1,2},
minus one for the odd permutation of indices {2,1,3},{1,3,2},{3,2,1}and zero oth-
erwise, i.e.
ǫijk=1
2(j−i)(k−i)(k−j). (1.34)
This symbol appears in the definition of the so-called exteri or or vector product of
two vectors. The definition of this operation
b=a1×a2, (1.35)
is such that the vector bis perpendicular to both a1anda2,its length is given by the
relation
|b|=|a1||a2|sin((a1,a2)), (1.36)
and the direction is determined by the anticlockwise screw r ule. For instance
e3=e1×e2, (1.37)
for the base vectors used in this work. In general, we have for these vectors
ei×ej=ǫijkek. (1.38)
Consequently, for the vector product of two arbitrary vecto rsa1=a1
iei,a2=a2iei,we
obtain
b=bkek=a1×a2=parenleftbiga1
ieiparenrightbig×parenleftbiga2
jejparenrightbig=a1ia2jǫijkek⇒bk=ǫijka1ia2j.(1.39)
The vector product is well defined within a theory of 3-dimens ional vector spaces. How-
ever, for example for two-dimensional spaces of vectors tan gent to a surface at a given
point, the result of this operation is a vector which does not belong any more to the
vector space. It is rather a vector locally perpendicular to the surface.
The permutation symbol can be also used in the evaluation of d eterminants. For a
tensorT=Tijei⊗ej, we can easily prove the relation
detT=ǫijkT1iT2jT3k. (1.40)
In mechanics of isotropic materials we use also the followin g identity ("contracted
epsilon identity")
ǫijkǫimn=δjmδkn−δjnδkm. (1.41)
16 Modicum of vectors and tensors
A certain choice of base vectors plays a very important role i n the description of
properties of tensors of the second rank. This is the content s of the so-called eigenvalue
problem. We proceed to present its details.
First we shall find a direction ndefined by unit vector, |n|=1, whose transformation
by the tensorTinto the vector Tnis extremal in the sense that the length of its projection
onngiven byn·Tnis largest or smallest with respect to all changes of n. This is the
variational problem
δ(n·Tn−λ(n·n−1))=0, (1.42)
for an arbitrary small change of the direction, δn. Hereλis the Lagrange multiplier
which eliminates the constraint on the length of the vector n:n·n=1. Obviously, the
problem can be written in the form
δn·[(Ts−λ1)n]=0, (1.43)
for arbitrary variations δn.
Let us notice that
n·Tn=n·(Ta+Ts)n=n·Tsn. (1.44)
Consequently, the antisymmetric part Tahas no influence on the solution of the problem.
Bearing the above remark in mind, we obtain from (1.43)
(Ts−λ1)n=0, (1.45)
or, in components,parenleftbigTs
ij−λδijparenrightbignj=0. (1.46)
It means that λare the eigenvalues of the symmetric tensor Tsandnare the corre-
sponding eigenvectors.
The existence of nontrivial solutions of the set of three equ ations (1.46) requires that
its determinant is zero
det(Ts−λ1)=0, (1.47)
i.e. vextendsinglevextendsinglevextendsinglevextendsinglevextendsinglevextendsingleTs
11−λ Ts
12Ts
13
Ts
12Ts
22−λ Ts
23
Ts
13Ts
23Ts
33−λvextendsinglevextendsinglevextendsinglevextendsinglevextendsinglevextendsingle=0. (1.48)
This can be written in the explicit form
λ
3−Iλ2+IIλ−III=0, (1.49)
where
I=trTs=Ts
ii, II=1
2parenleftbigI2−trTs2parenrightbig=1
2parenleftBig
(Ts
ii)2−Ts
ijTs
ijparenrightBig
, III=detTs,(1.50)
are the so-called principal invariants of the tensor Ts. Obviously, the cubic equation
(1.49) possesses three roots. For symmetric real matrices t hey are all real. It is customary
in mechanics to order them in the following manner
λ(1)≥λ(2)≥λ(3). (1.51)
1.2 Analysis 17
However, in more general mathematical problems, in particu lar when the spectrum of
eigenvalues is infinite, the smallest eigenvalue is chosen a s the first and then the eigenvalue
sequence is growing.
Clearly
I=λ(1)+λ(2)+λ(3),
II=λ(1)λ(2)+λ(1)λ(3)+λ(2)λ(3), (1.52)
III=λ(1)λ(2)λ(3).
Once we have these values we can find the corresponding eigenv ectorsn(1),n(2),n(3)from
the set of equations (1.45). Only two of these equations are i ndependent which means
that we can normalize the eigenvectors by requiringvextendsinglevextendsinglen(α)vextendsinglevextendsingle=1, α=1,2,3.It is easy to
show that these vectors are perpendicular to each other. Nam ely we have for α,β=1,2,3
n(β)·bracketleftBigparenleftBig
Ts−λ(α)1parenrightBig
n(α)bracketrightBig
=0⇒parenleftBig
λ(α)−λ(β)parenrightBig
n(α)·n(β)=0. (1.53)
If the eigenvalues are distinct, i.e. λ(α)/negationslash=λ(β)forα/negationslash=βwe obtain
n(α)·n(β)=0, (1.54)
and, consequently, the vectors n(α),n(β)are perpendicular (orthogonal). The proof can
be easily extended on the case of twofold and threefold eigen values.
The above property of eigenvectors allows to use them as a spe cial set of base vectorsbraceleftbig
n(1),n(2),n(3)bracerightbig
. Then the tensor Tscan be written in the form
Ts=3summationdisplay
α=1λ(α)n(α)⊗n(α). (1.55)
We call this form the spectral representation of the tensor Ts. Obviously, the tensor in
this representation has the form of diagonal matrix
parenleftbigTs
αβparenrightbig=
λ(1)0 0
0λ(2)0
0 0λ(3)
. (1.56)
1.2 Analysis
Apart from algebraic properties of vectors and tensors whic h we presented above, prob-
lems of continuum mechanics require differentiation of thes e objects with respect to
spatial variables and with respect to time. Obviously, such problems appear when vec-
tors and tensors are functions of coordinates in space and ti me. Then we speak about
vector or tensor fields.
One of the most important properties of the vector fields defin ed on three-dimensional
domains is the Helmholtz (1821-1894) decomposition1. For every square-integrable vector
1C. AImscIrscIoscIuscIcscIhscIesc, C. BIescIrscInscIascIrscIdscIisc, M. DIascIuscIgscIesc, V. GIiscIrscIascIuscIlscItsc ;. Vector potentials in three dimensional
non-smooth domains, Mathematical Methods in the Applied Sciences, 21, 823—864, 1998.
18 Modicum of vectors and tensors
fieldvthe following orthogonal decomposition holds
v(x)≡v(x1,x2,x3)=gradϕ+rotψ,x=xiei, (1.57)
wherexiare Cartesian coordinates of the point xof the three-dimensional Euclidean
spaceE3,
gradϕ=∂ϕ
∂xiei,rotψ=ǫijk∂ψk
∂xjei, (1.58)
andϕ,ψare called scalar and vector potential, respectively.
The operator rot(it is identical with curlwhich is used in some texts to denote the
same operation) can be easily related to the integration alo ng a closed curve. Namely G.
Stokes (1819-1903) proved the Theorem that for all fields vdifferentiable on an oriented
surfaceSwith the normal vector nthe following relation holds
integraldisplay
S(rotv)·ndS=contintegraldisplay
∂Sv·dx, (1.59)
i.e.integraldisplay
Sǫijk∂vk
∂xjnidS=contintegraldisplay
∂Svidxi,
where∂Sis the boundary curve of the surface S.
On the other hand, integration over a closed surface is relat ed to the volume integra-
tion. This is the subject of the Gauss (1777-1855) Theorem di scovered by J. L. Lagrange
in 1762.
For a compact domain V⊂E3with a piecewise smooth boundary ∂Vthe following
relation for a continuously differentiable vector field vholds
integraldisplay
VdivvdV=contintegraldisplay
∂Vv·ndS, (1.60)
where∂Vdenotes the boundary of the domain of volume integration Vandnis a unit
vector orthogonal to the boundary and oriented outwards.
G. Leibniz (1646-1716) Theorem for volume integrals which w e use in analysis of bal-
ance equations of mechanics describes the time differentiat ion of integrals whose domain
is time-dependent. It has the following form
d
dtintegraldisplay
V(t)f(t,x)dV=integraldisplay
V∂f
∂t(t,x)dV+contintegraldisplay
∂Vf(t,x)v·ndS, (1.61)
wheretdenotes time,xis the point within V,vis the velocity of boundary points of the
domainV. Instead of a rigorous proof it is useful to observe the way in which the above
structure of the time derivative arises. The right-hand sid e consists of two contributions:
the first one arises in the case of time independent domain of i ntegration, V, and due to
time differentiation there is only a contribution of the inte grandfwhile the second one
arises when the function fis time independent (i.e. time tis kept constant in f) and the
1.2 Analysis 19
volumeVchanges. They add due to the linearity of the operator of diffe rentiation as in
the case of differentiation of the product d(fg)/dt=gdf/dt+fdg/dt . The structure of
the second contribution is explained in Fig.1.3.
Fig. 1.3: Interpretation of Leibniz Theorem
Locally the change of the volume can be written in the form dV=dSn·vdt, where
vis the velocity of the point of the boundary. Consequently, t he change of the domain
of integration for the increment of time dthas the form
integraldisplay
V(t+dt)f(t)dV−integraldisplay
V(t)f(t)dV=
contintegraldisplay
∂V(t)f(t)v·ndS
dt. (1.62)
Now the second contribution of (1.61) easily follows.
As a particular case of the last Theorem we have for f=1
d
dtintegraldisplay
VdV=contintegraldisplay
∂Vv·ndS=integraldisplay
VdivvdV⇒dV
dt=integraldisplay
VdivvdV. (1.63)
This relation indicates that divvdescribes the local time changes of the volume. This
interpretation is useful in the analysis of the mass balance equation of continuum me-
chanics.
More details of the vector calculus and its applications in m echanics can be found
in numerous books on continuum mechanics and thermodynamic s (e.g. [22]). In some
exercises and examples we use curvilinear coordinates rath er than Cartesian coordinates
applied in the above presentation. We demonstrate their pro perties and appropriate rules
of transformations in these examples.
20 Modicum of vectors and tensors
Chapter 2
Geometry and kinematics of
continua
2.1 Preliminaries
As mentioned in Chapter 1 a theoretical description of mecha nical behaviour of structures
requires continuous models. It means that a collection of po ints of structures form a three-
dimensional continuum of a certain mathematical construct (the so-called differentiable
manifold). The points Xof the setB0of such a continuum move in a three-dimensional
space of motionE3. The main purpose of continuum mechanics is to determine thi s
motion for any given set of external agents (forces, or given displacements of boundaries
of structure, or a mixture of both). It means that one has to so lve the set of governing
equations in order to find a current position of an arbitrary p ointX∈B0of the material
bodyB0. A collectionBtof positions of all points from the material body B0at a
given instant of time tis called the current configuration of the body. Once a partic ular
model is selected (elasticity, viscoelasticity, plastici ty, viscoplasticity, etc.) the knowledge
of these current configurations allows to calculate deforma tions, stresses, dissipation of
energy, work done on the system or any other quantity which ma y be of practical interest.
In some cases one is interested only, for instance, in the dis tribution of stresses in the
system. As we know from the classical linear elasticity such problems may be solved by a
transformation of the governing set of equations of motion i nto equations for stresses. In
the linear elasticity we call them Beltrami-Michell equati ons. However, in general such a
transformation is difficult if possible at all and, therefore we limit our attention in these
notes to the formulation of governing equations of motion on ly marginally referring to
other approaches.
Engineering problems arise usually in connection with a par ticular geometry of struc-
tures which may lead to considerable simplifications of mech anical models. This is related
to the fact that one or two spacial dimensions of a structure a re much smaller than the
remaining dimension. This yields models of shells, plates, rods, bars and their combi-
nations such as fibrous media, nets and so on. We refer to model s of such structures
21
22 Geometry and kinematics of continua
in some examples but, due to a limited volume of these notes we shall not go into any
details of their modeling.
A configurationBtas a collection of points in E3occupied by points X∈B0of the
material body is in some cases of practical interest not suffic ient to describe a geometry
of the system. For instance, in the description of suspensio ns or liquid crystals one may
need additional local degrees of freedom related to rotatio ns of microparticles. In some
other cases one may even need additional tensors as a natural space in which the motion
appears is not Euclidean. This appears in the description of a continuous distribution of
dislocations important in the theory of plasticity. Someti mes an appropriate extension of
the classical continuum necessary to describe such systems can be done by the so-called
microstructural variables. We mention some of them further in this book. However, it
is not always the case (e.g. a nonlinear theory of dislocatio ns, or diffusion processes of
mixtures). Such problems shall not be considered in these no tes.
2.2 Reference configuration and Lagrangian descrip-
tion
The choice of the reference configuration B0with respect to which the motion of the
body is measured is arbitrary. If possible we choose a natura l stress-free configuration.
This is not always convenient for solids (e.g. for prestress ed structures) and it is never
possible for fluids. These cases will be discussed separatel y but, in principle, the analysis
presented below can be taken over also for such cases. In thos e many systems in which we
can choose a natural configuration we assume its deformation to be zero. The motion of
the body, i.e. the function which describes the geometry of a ll subsequent configurations
is described by the function of two variables: time, t, and the point, X, of the reference
configurationB0. The latter specifies the particle which is described. In cho sen Cartesian
coordinate systems we have
x=f(X,t),i.e.xk=fk(X1,X2,X3,t),X∈B0, k=1,2,3,(2.1)
where
x=xkek,X=XKeK, (2.2)
are position vectors in the current configuration and refere nce configuration, respectively.
As the reference configuration is one of the configurations ap pearing in the real motion
of the body, for instance, the one for t=0, we can, certainly, choose the same coordinate
system for all configurations, i.e.
xk=δkKXK,ek=δkKeK. (2.3)
However, in the analysis of certain invariance properties ( e.g. isotropy of the material,
material objectivity, etc.), it is convenient to distingui sh between these two systems as
we did in the relation (2.1). The coordinate system with the b ase vectorseKis called
2.2 Reference configuration and Lagrangian description 23
Lagrangian and the coordinate system with the base vectors ekis called Eulerian.
Fig. 2.1: Transformation from the reference configuration B0to the current
configurationBt.The function of motion fdescribes time changes of position
ofmaterialpoints X∈B0intox∈Btwhilethedeformationgradient Fdescribes
the transformation of material vectors (e.g. a tangent vect ordXof the curve
C0into a tangent vector dxof the curveCt)
The vector function f(X,t), the function of motion, is assumed to be twice continu-
ously differentiable with respect to all variables. Consequ ently, it must be also continuous.
This property of the theories of continuum eliminates many i mportant processes from
continuous models. Some examples are shown in Fig. 2.2. In pr actical applications, we
overcome this difficulty by some additional sophisticated co nstructions (e.g. for cracks in
solids or vorticities in fluids). We shall point out some of th em further in these notes.
Fig. 2.2: Some motions (nontopological) which cannot be des cribed by con-
tinuous functions of motion.
24 Geometry and kinematics of continua
The function of motion f(X,t)specifies the local rule of transformation of the so-
called material vectors. If we select a smooth curve C0in the reference configuration B0,
given by a parametric equation X=X(S), whereSis the parameter along this curve
then in each point of this curve the tangent vector is given by the derivative dX/dS.A
corresponding infinitesimal vector dX=(dX/dS)dSchanges during the motion in the
following way
dx=(Gradf)dX≡(Gradf)dX
dSdS=dx
dSdS, (2.4)
or, in coordinates,
dxk=∂fk
∂XKdXK=∂fk
∂XKdXK
dSdS=dxk
dSdS. (2.5)
Hence, in the current configuration, the tangent vector dX/dSof the curveC0changes
into the tangent vector dx/dSof the curveCtgiven by the relation x=f(X(S),t)in the
configurationBtwhich is the image of the curve C0of the initial configuration B0. This
new vector has, in general, a different length and a different d irection than the vector
dX/dS. All such vectors, V, which fulfil the above indicated rule of transformation whe n
changing the configuration B0intoBt
v=FV,F=Gradf, (2.6)
i.e.vk=FkKVK, FkK=∂fk
∂XK,
are called material vectors. This transformation by means o f the objectFwhich is called
the deformation gradient is the most important notion descr ibing geometrical changes of a
continuum during the deformation. Before we present the ful l analysis of the deformation
gradientFlet us consider two simple examples.
⋆We begin with the simplest case of a uniform extension of a cub e in three perpen-
dicular directions (see: Fig. 2.3.)
Fig. 2.3: Reference configuration of a cube with the vector Vof the
examples
2.2 Reference configuration and Lagrangian description 25
described by the following function of motion in Cartesian c oordinates
x1=X1(1+ε1), x2=X2(1+ε2), x3=X3(1+ε3), (2.7)
whereε1,ε2,ε3are three constants. Then the deformation gradient is given by the
relation
F=FkKek⊗eK,(FkK)=
1+ε10 0
0 1+ε20
0 0 1+ ε3. (2.8)
Obviously, it is independent of coordinates, i.e. the defor mation is homogeneous. We
check the action of the deformation gradient on a chosen vect orV. An example of this
vector is shown in Fig. 2.3. In coordinates indicated in this Figure the vector Vhas the
following components
V=−e
1+e2+e3.
Its image after the deformation is as follows
v=FV= (2.9)
=((1+ε1)e1⊗e1+(1+ε2)e2⊗e2+(1+ε3)e3⊗e3)(−e1+e2+e3)=
=−(1+ε1)e1+(1+ε2)e2+(1+ε3)e3.
Hence the current image vof the vectorVhas a different length and a different direction
|v|2=v·v=3summationdisplay
i=1(1+εi)2,|V|2=V·V=3, (2.10)
cos((v,V))=summationtext3
i=1(1+εi)
√
3radicalBigsummationtext3
i=1(1+εi)2.
Obviously, for ε1=ε2=ε3the angle between vandVis equal to zero.♣
⋆The second example describes the so-called simple shearing in the plane perpendic-
ular toe1. Then
x1=X1, x2=X2+X3tanϕ, x3=X3, (2.11)
and the corresponding deformation gradient is as follows (L agrangian and Eulerian base
vectors are identical ek=δkKeK)
F=FkKek⊗eK,(FkK)=
1 0 0
0 1 tanϕ
0 0 1
. (2.12)
The current image of the vector Vis now given by the relation
v=FV= (2.13)
=(e1⊗e1+e2⊗e2+e3⊗e3+tanϕe2⊗e3)(−e1+e2+e3)=
=−e1+(1+tanϕ)e2+e3.
26 Geometry and kinematics of continua
Also in this case the vector vhas the different length and direction from the vector V
|v|2=v·v=2+(1+tan ϕ)2,|V|2=V·V=3, (2.14)
cos((v,V))=3+tanϕ
√
3radicalBig
2+(1+tan ϕ)2.
♣
The deformation gradient Fis, obviously, represented by a square matrix. However, it
is not a tensor of the second rank. Clearly, if we change the La grangian basis eK→eK′=
AK′KeK(compare (1.15)) but keep unchanged the Eulerian basis ekthe deformation
gradient transforms as follows
FkK′=AKK′FkK, (2.15)
i.e. it transforms as three vectors for k=1,2,3rather than a tensor. The same property
possesses the first index under the transformation ek→ek′=Ak′kek,andeKis kept
unchanged
Fk′K=Akk′FkK. (2.16)
This is one of the reasons why the notation for Lagrangian and Eulerian coordinates is
different.
The deformation gradient can be written in a different form in which these trans-
formation rules possess an obvious interpretation. This is the subject of the so-called
polar decomposition Theorem. For a nonsingular deformatio n gradientF,detF>0(we
return to the justification of this property in the Chapter on the conservation of mass)
there exist an orthogonal matrix Rand a symmetric tensor Usuch that
F=RU,RT=R−1,UT=U, (2.17)
FkK=RkLUKL,(RkL)T=(RkL)−1, UKL=ULK,
and this decomposition is unique. Rdescribes the local rotation and the right stretch
tensorUthe local deformation. We show the construction of these obj ects. Let us note
that in the following product
C=FTF=UTRTRU=U2, (2.18)
CKL=FkKFkL=UKMUML,
the orthogonal part Rdoes not appear. Hence, in order to find Uwe have to take
"the square root" of C. Obviously, it is not the same operation which we perform wit h
numbers. We define it through the eigenvalues. Namely, we cal culate first the eigenvalues
and eigenvectors of the tensor C
(C−λC1)KC=0. (2.19)
Obviously
det(CKL−λCδKL)=0, (2.20)
2.2 Reference configuration and Lagrangian description 27
and the solution of this cubic equation gives three eigenval uesλ(1)
C,λ(2)
C,λ(3)
Cof the tensor
C. They are all real and positive ( detC=(detF)2>0!). From (2.19) one can find then
unit eigenvectors K(1)
C,K(2)C,K(3)C. They are orthogonal (compare (1.54)). Hence, we can
write the tensor Cin the spectral representation
C=3summationdisplay
α=1λ(α)
CK(α)
C⊗K(α)
C. (2.21)
Simultaneously, the eigenvalue problem for Uhas the following form
(U−λU1)KU=0. (2.22)
If we multiply this equation by Ufrom the left we have
(UU−λUU)KU=parenleftbig
C−λ2
U1parenrightbig
KU=0. (2.23)
Consequently
λU=radicalbig
λC,KU=KC. (2.24)
Hence, we obtain the following spectral representation for the right stretch U
U=3summationdisplay
α=1radicalBig
λ(α)
CK(α)
C⊗K(α)
C. (2.25)
This is what was meant by taking a square root of C. OnceUis given we can calculate
Rfrom (2.17)
R=FU−1. (2.26)
The above presented procedure is simultaneously the proof o f the polar decomposition
Theorem.
⋆Before we proceed let us consider a simple example for the app lication of the above
procedure. We find the polar decomposition of the deformatio n gradient in the simple
shearing given by the relation (2.12). The Lagrangian and Eu lerian base vectors are
assumed to be identical ek=δkKeK. We have
C=CKLeK⊗eL,(CKL)=
1 0 0
0 1 tan ϕ
0 tanϕ1+tan2ϕ
. (2.27)
The eigenvalue problem yields the following equation for ei genvaluesλC
(1−λC)bracketleftbig(1−λC)parenleftbig(1−λC)+tan2ϕparenrightbig−tan2ϕbracketrightbig=0. (2.28)
The solution has the form
λ(1)
C=1, λ(2)C=parenleftbigg1−sinα
cosαparenrightbigg2
, λ(3)
C=parenleftbigg1+sinα
cosαparenrightbigg2
, (2.29)
28 Geometry and kinematics of continua
where
tanα=1
2tanϕ. (2.30)
The corresponding eigenvectors follow from (2.19). We obta in
K(1)
C=e1,
K(2)
C=−parenleftbigg1√
2cosα√1−sinαparenrightbigg
e2+parenleftbigg1√
2√
1−sinαparenrightbigg
e3, (2.31)
K(3)
C=parenleftbigg1√
2cosα√1+sinαparenrightbigg
e2+parenleftbigg1√
2√
1+sinαparenrightbigg
e3.
According to the relation (2.25) we obtain for the tensor U
U=e1⊗e1+cosαe2⊗e2+sinα(e2⊗e3+e3⊗e2)+parenleftbigg2
cosα−cosαparenrightbigg
e3⊗e3.(2.32)
Its inverse has the form
U−1=e1⊗e1+parenleftbigg2
cosα−cosαparenrightbigg
e2⊗e2−sinα(e2⊗e3+e3⊗e2)+cosαe3⊗e3.(2.33)
Consequently, according to the relation (2.26), we have for the orthogonal part
R=FU−1=e1⊗e1+cosαe2⊗e2+sinα(e2⊗e3−e3⊗e2)+cosαe3⊗e3.(2.34)
For the linear theory which we consider further in this book i t is useful to collect the
above results in the case of the small angle ϕ. Thenα≈ϕ/2and we obtain
U=e1⊗e1+e2⊗e2+ϕ
2(e2⊗e3+e3⊗e2)+e3⊗e3,
U−1=e1⊗e1+e2⊗e2−ϕ
2(e2⊗e3+e3⊗e2)+e3⊗e3, (2.35)
R=e1⊗e1+e2⊗e2+ϕ
2(e2⊗e3−e3⊗e2)+e3⊗e3.
On the plane perpendicular to e1these objects yield the following transformations of the
edges of unit length of the rectangular prism
Ue2=e2+ϕ
2e3,Fe2=RUe2=e2, (2.36)
Ue3=ϕ
2e2+e3,Fe3=RUe3=ϕe2+e3.
Obviously, the vectors e2ande3along the edges are material.
2.2 Reference configuration and Lagrangian description 29
We demonstrate these transformations in Fig. 2.4.
Fig. 2.4: Geometry of the linear simple shearing on the plane perpendicular
toe1.
Obviously, the symmetric stretch tensor Uyields the change of shape from the rectan-
gle to the parallelogram with the symmetry axis of the declin ationπ/4. The orthogonal
tensorRrotates back the deformed parallelogram in such a way that th e horizontal edge
before the deformation becomes horizontal after the deform ation as well.♣
The above presented example indicates that U=UKLeK⊗eLdescribes the true local
deformation. This is the reason for calling it the right stre tch tensor while its square
C=U2=CKLeK⊗eLis called the right Cauchy-Green deformation tensor.
AsR=RkKek⊗eKdescribes local rotations — due to orthogonality — it does no t change
the length of material vectors.
The polar decomposition Theorem can be also written in the du al form
F=VR,V=Vklek⊗el=VT,R=RkKek⊗eK,RT=R−1, (2.37)
B=FFT=V2=BT.
ThenVis called the left stretch tensor and Bthe left Cauchy-Green deformation tensor.
For the latter we can easily prove
λB=λC,kB=FKC
|FKC|,B=1
|FKC|23summationdisplay
α=1λ(α)
CparenleftBig
FK(α)
CparenrightBig
⊗parenleftBig
FK(α)
CparenrightBig
,(2.38)
i.e. Cauchy-Green tensors CandBhave the same eigenvalues.
In Fig. 2.5 [5] we demonstrate schematically the interpreta tion of the polar decom-
30 Geometry and kinematics of continua
position.
Fig. 2.5: Polar decomposition of the deformation gradient Fas the
composition of stretch Vfollowed by rotation R(i.e.VR) or vice versa ( RU)
2.3 Displacement, velocity, Eulerian description
The motion of the body can be described not only by the functio n of motionfbut,
as customary in the linear elasticity, by the displacement v ectoru.Similarly tof, it is
defined with respect to a chosen reference configuration, say B0,
x=f(X,t)=X+u(X,t). (2.39)
Then the gradient of deformation has the form
F=1+Gradu. (2.40)
Provided we identify the Lagrangian and Eulerian coordinat e systems the Cauchy-Green
deformation tensors have then the following form
C=FTF=1+Gradu+(Gradu)T+(Gradu)TGradu,(2.41)
i.e.CKL=δKL+δKk∂uk
∂XL+δLk∂uk
∂XK+∂uk
∂XK∂uk
∂XL,
B=FFT=1+Gradu+(Gradu)T+Gradu(Gradu)T,(2.42)
i.e.Bkl=δkl+δkK∂ul
∂XK+δlK∂uk
∂XK+∂uk
∂XK∂ul
∂XK.
2.3 Displacement, velocity, Eulerian description 31
These relations show that the displacement vector is not ver y convenient in nonlinear
models. There are also other reasons for not using it in such t heories (see: [22]). However,
it is a very useful notion in linear models and it shall be exte nsively used in this book.
For our further considerations in these notes it is importan t to specify the above
geometrical description under the assumption of small defo rmations. We proceed to do
so.
We base our considerations on the analysis of the right Cauch y-Green deformation
tensorC. It is clear that rotations cannot be assumed to be small as ev en in the case of
lack of deformation the system may rotate as a rigid body and t his rotation, of course,
cannot be small. For this reason, we cannot constrain the def ormation gradient Fand
rather measures of deformations are appropriate tools. The undeformed configuration
is characterized by the deformation gradient F=1. Consequently, this configuration
is described by the deformation tensors C=1andB=1. The spectral representation
of the tensorC(2.21) indicates that this tensor differs a little from the un it tensor if
its eigenvalues λ(α)
Cdeviate a little from unity. These eigenvalues are called pr incipal
stretches. It is convenient to introduce a norm for the tenso rC−1rather than for C.
It is done by the following relation
/bardblC−1/bardbl= max
α=1,2,3vextendsinglevextendsinglevextendsingleλ(α)
C−1vextendsinglevextendsinglevextendsingle. (2.43)
Then, we say that the body undergoes small deformations if th e norm ofCsatisfies
the condition
/bardblC−1/bardbl≪1. (2.44)
Under this condition one does not have to distinguish betwee n Lagrangian and Eulerian
coordinates. For an arbitrary function h(x,t)we have
∂h
∂XKeK=FkK∂h
∂xkeK≈∂h
∂xkek. (2.45)
It means that Eulerian coordinates can be treated for small d eformations as Lagrangian
coordinates.
For small deformations, it is convenient to introduced diffe rent measures of deforma-
tion. One defines for arbitrary deformations the following m easures
— Green-St. Venant measure
E=1
2(C−1), λE=λC−1
2, (2.46)
— Almansi-Hamel measure
e=1
2parenleftbig1−B−1parenrightbig, λe=1−1/λC
2. (2.47)
For small deformations
λe=λC−1
2λC≈λC−1
2=λE. (2.48)
Hence, both these measures, Eande, are not distinguishable.
32 Geometry and kinematics of continua
In terms of the displacement vector the Almansi-Hamel measu re of small deformations
can be written in the following form
e≈1
2parenleftBig
gradu+(gradu)TparenrightBig
+Oparenleftbigε2parenrightbig,i.e.ekl≈1
2parenleftbigg∂uk
∂xl+∂ul
∂xkparenrightbigg
+Oparenleftbigε2parenrightbig,(2.49)
where
ε≡/bardblgradu/bardbl≪1,/bardblgradu/bardbl=radicalbig
(gradu)·(gradu)=radicalbigg
∂uk
∂xl∂uk
∂xl. (2.50)
andOparenleftbigε2parenrightbigare contributions of the order ε2=(gradu)·(gradu)and higher.
This measure will be used in linear models discussed further .
In the description of fluids it is convenient to change the ref erence configuration.
Obviously, in contrast to solids one cannot expect an existe nce of configurations which are
stress-free. Consequently, any choice of the reference con figuration will be not natural for
fluids. The most suitable seems to be the current configuratio n and, indeed, it is chosen
as the reference configuration in most works on fluid mechanic s. Such a description does
not identify particles. In any point xof the space of motion, occupied by the material
one can specify the velocity v(x,t)as a function of time. By means of this field one can
find trajectories of particles and, consequently, identify them. In a particular case of the
reference configuration B0these trajectories are labeled by points X∈B0. We proceed
to describe the details of such a description.
The velocity of particles is defined in the Lagrangian descri ption by the time derivative
of the function of motion
˙ x≡v=∂f
∂t(X,t),i.e.vk=∂fk
∂t(X1,X2,X3,t). (2.51)
Consequently, if we define the trajectory of motion of the par ticleXas the curvef(X,t)
parametrized by the time t, the velocity is the vector tangent to the trajectory. In
the Eulerian description we change the variables X→xby the function X=f−1(x,t)
inverse tofwith respect to X. Such a function exists because we assume the determinant
detF/negationslash=0. Then the velocity in the Eulerian description is the follow ing vector function
v=v(x,t),x∈Bt, (2.52)
and it points in the direction tangent to the trajectory of th e particleXwhich is instan-
taneously located in the point xof the configuration space. Consequently, the equation
of this trajectory is given by the set of three ordinary differ ential equations
dx
dt=v(x,t),x(t=0)=X. (2.53)
For a given velocity field this is a highly nonlinear set which can be only seldom solved
analytically.
In order to appreciate the details of the Eulerian descripti on, we consider three con-
figurations:B0which has been discussed before and two current configuratio nsBt,Bτ
2.3 Displacement, velocity, Eulerian description 33
for instances of time tandτ, respectively. Then the function of motion mapping these
configurations on each other forms the diagram shown in Fig. 2 .6.
In these mappings we have
x=f(X,t),ξ=f(X,τ)⇒ξ=ft(x,τ)=fparenleftbigf−1(x,t),τparenrightbig. (2.54)
Hence, the function of the relative motion ft(.,τ)describes positions of points xof the
configuration in the instant of time tat the new instant of time τ. Obviously, these
functions specify the corresponding gradients of deformat ion
dx=F(X,t)dX, dξ=F(X,τ)dX,⇒ (2.55)
⇒dξ=Ft(x,τ)dx,Ft(x,τ)=F(X,τ)F−1(X,t)vextendsinglevextendsingle
X=f−1(x,t).
Fig. 2.6: Three configurations yielding Eulerian descripti on
Consequently,
Ft(x,τ=t)=1, (2.56)
and, for this reason we say that Ft(.,τ)is the relative deformation gradient with respect
to the configuration at the instant of time t.
The above notion allows to introduce time derivatives of arb itrary quantities in the
Eulerian description. As an example let us consider a materi al vector function Q(X,t).
Its current image is as follows
q(X,t)=F(X,t)Q(X,t). (2.57)
Hence
∂q
∂t(X,t) =F(X,t)∂Q
∂t(X,t)+(Gradv)Q(X,t),Gradv≡∂F
∂t(X,t),(2.58)
i.e.∂qk
∂t=FkK∂QK
∂t+∂vk
∂XKQK,∂vk
∂XK=∂FkK
∂t≡∂2fk
∂t∂XK.
34 Geometry and kinematics of continua
These rules of differentiation are straightforward. It is no t so in the Eulerian description.
We have rather
q(x,t) =Fparenleftbigf−1(x,t),tparenrightbigQparenleftbigf−1(x,t),tparenrightbig,
q(ξ,τ) =Fparenleftbigf−1(ξ,τ),τparenrightbigQparenleftbigf−1(ξ,τ),τparenrightbig⇒ (2.59)
⇒q(x,t)=F−1
t(ξ,τ)q(ξ,τ)vextendsinglevextendsingle
ξ=f−1
t(x,τ).
The time derivative of q(x,t)is now defined in the same way as in the Lagrangian
description in the limit τ→t. We obtain
Lvq(x,t) =dbracketleftbigF−1
t(ξ,τ)q(ξ,τ)bracketrightbig
dτvextendsinglevextendsinglevextendsinglevextendsinglevextendsingle
τ=t=
=∂q
∂t(x,t)+(v·grad)q(x,t)+dbracketleftbigF−1
t(ξ,τ)bracketrightbig
dτvextendsinglevextendsinglevextendsinglevextendsinglevextendsingle
τ=tq(x,t).(2.60)
The last contribution can be transformed in the following wa y
dbracketleftbigF−1
tFtbracketrightbig
dτ=0=dF−1
t
dτFt+F−1
tdFt
dτ⇒dF−1
t
dτ=−F−1
tdFt
dτF−1
t. (2.61)
Hence
dbracketleftbigF−1
t(ξ,τ)bracketrightbig
dτvextendsinglevextendsinglevextendsinglevextendsinglevextendsingle
τ=t=−dFparenleftbigf−1(x,t),tparenrightbig
dtF−1parenleftbigf−1(x,t),tparenrightbig=
=−gradv(x,t), (2.62)
i.e.
dF−1
tkl
dτvextendsinglevextendsinglevextendsinglevextendsingle
τ=t=−dFkK
dtF−1
Kl=∂vk
∂XK∂XK
∂xl=∂vk
∂xl. (2.63)
The quantity
L=gradv, (2.64)
is called the velocity gradient and it plays an important rol e in nonlinear fluid mechanics.
Obviously it can be split into symmetric and antisymmetric p arts
L=D+W,D=1
2parenleftBig
L+LTparenrightBig
,W=1
2parenleftBig
L−LTparenrightBig
, (2.65)
i.e.∂vk
∂xl=Dkl+Wkl, Dkl=1
2parenleftbigg∂vk
∂xl+∂vl
∂xkparenrightbigg
, Wkl=1
2parenleftbigg∂vk
∂xl−∂vl
∂xkparenrightbigg
.
The tensorDis called the stretching and the tensor Wis called the spin.
Substitution of (2.64) in (2.60) yields
Lvq(x,t) =∂q
∂t(x,t)+(v·grad)q(x,t)−Lq(x,t), (2.66)
i.e.Lvqk=∂qk
∂t+vl∂qk
∂xl−∂vk
∂xlql.
2.3 Displacement, velocity, Eulerian description 35
This is the so-called Lie derivative of qrelated to the velocity field v. Obviously,
additional contributions to the standard partial time deri vative are nonlinear and they
play an important role in nonlinear theories. This derivati ve of a vector field in Eulerian
description as well as analogous derivatives of tensor field s have an important property
that they are objective, i.e. invariant with respect to a cha nge of observer. We shall not
discuss this subject in these notes.
Let us complete this juxtaposition of Lagrangian and Euleri an description of geometry
with the proof of the Euler-Piola-Jacobi identities which a re frequently used by the
transformation of balance equations. Namely
DivparenleftbigJF−Tparenrightbig(X,t)=0,divparenleftbigJ−1FTparenrightbig(x,t)=0. (2.67)
We prove the first one. The dual identity follows in the simila r manner. We write it
in Cartesian coordinates
∂parenleftbigJF−1
Kkparenrightbig
∂XK=∂J
∂XKF−1
Kk+J∂F−1
Kk
∂XK
=JF−1
Ll∂FlL
∂XKF−1
Kk−JF−1
KlF−1
Lk∂FlL
∂XK,
and (2.67) follows when we use the symmetry ∂FlL/∂XK=∂FlK/∂XL. In the derivation
we have used the identity
∂parenleftbig
F−1
KkFkLparenrightbig
∂XK=0=∂F−1
Kk
∂XKFkL+F−1
Kk∂FkL
∂XK(2.68)
=⇒∂F−1
Kk
∂XK=−F−1
KlF−1
Lk∂FlL
∂XK.
The Lagrangian description yields as well an identity which is very useful in wave
analysis. Usually, it is proved as a part of the so-called Had amard Theorem. We show
this identity in the different way. For a given set of two fields : deformation gradient
F(X,t)and the velocity field v=(X,t)one has to require the so-called integrability
conditions∂FkK
∂t=∂vk
∂XK,∂FkK
∂XL=∂FkL
∂XK, (2.69)
for the function of motion f(X,t)to exist. IfFandvare not given apriori but derived
fromfthen the integrability conditions (2.69) are identically f ulfilled. On the other hand,
ifFandvare not sufficiently smooth, for example they possess a singul arity on a moving
surfaceSthen we can require the integrability conditions to be fulfil led only in a weaker
form. We investigate the first one and write it as
d
dtintegraldisplay
PFkKdV−contintegraldisplay
∂PvkNKdS=0, (2.70)
for all subbodies P. Obviously, if there are no singularities this condition is equivalent
to (2.69). We present the local form of this relation in Chapt er 4 on balance equations.
36 Geometry and kinematics of continua
2.4 Infinitesimal strains
Now we return to the analysis of the deformation under the ass umption (2.44), i.e. to
the case of small deformations which is of the main concern in these notes.
The most important property of small deformation is the iden tity of the Lagrangian
and Eulerian description, i.e. we can identify the systems o f coordinates xk=δkKXK,
ek=δkKeKand the dependence on xkandXKis the same. As a consequence, we can
write the right Cauchy-Green deformation tensor in the form
F=1+gradu⇒C=FTF≈gradu+(gradu)T+1≈FFT=B,(2.71)
i.e.Ckl=∂uk
∂xl+∂ul
∂xk+δkl,
asε=/bardblgradu/bardbl≪1.
Simultaneously, the Almansi-Hamel deformation tensor (2. 48) has the following form
e=1
2parenleftbig1−B−1parenrightbig=1
2parenleftBigg
1−3summationdisplay
α=11
λ(α)
Bk(α)
B⊗k(α)
BparenrightBigg
=
=1
23summationdisplay
α=1parenleftBigg
1−1
λ(α)
BparenrightBigg
k(α)
B⊗k(α)
B=1
23summationdisplay
α=1parenleftBigg
1−1
λ(α)
CparenrightBigg
k(α)
B⊗k(α)
B≈(2.72)
≈3summationdisplay
α=1λ(α)
C−1
2K(α)
C⊗K(α)
C=3summationdisplay
α=1λ(α)
eK(α)
C⊗K(α)
C,vextendsinglevextendsinglevextendsingleFK(α)
Cvextendsinglevextendsinglevextendsingle≈1.
Hence, for small deformations, as already indicated (compa re (2.49)),
e≈1
2parenleftBig
gradu+(gradu)TparenrightBig
, (2.73)
i.e.ekl≈∂uk
∂xl+∂ul
∂xk.
This is the most commonly used measure of deformation in line ar theories. If relation
(2.73) is used as the definition of the deformation measure eand not as an approximation
of Almansi-Hamel tensor, eis called the strain field. We proceed to investigate some of
its properties.
We begin with a certain invariance problem which plays an imp ortant role in all
branches of continuum mechanics. One should expect that the description of deforma-
tion should not change if we rotate very slowly the body as a wh ole. This rigid body
rotation should be slow in this sense that we should not evoke inertial body forces such
as centrifugal forces. These would, certainly, produce def ormations. Therefore we inves-
tigate only a static problem. The rigid body rotation is then defined by the following
relation in the Lagrangian description
x=OX,OT=O−1,F|rigid=1+Gradu|rigid=O, (2.74)
2.4 Infinitesimal strains 37
whereOis the constant orthogonal matrix. Hence, in the case of the A lmansi-Hamel
deformation tensor defined by (2.73)
C|rigid=FTF=OTO=1,e|rigid=1
2parenleftBig
O+OTparenrightBig
−1, (2.75)
which means that the rigid rotation yields undeformed body w hose measure of defor-
mation is the Cauchy-Green tensor Cbut it yields a deformation if it is defined by the
strain fielde, i.e. by the simplified Almansi-Hamel tensor (2.73). Hence, it is not a proper
measure for large deformations. The original definition (3. 46) yields, of course, for the
rigid rotation the vanishing deformation e=1
2parenleftbig1−B−1parenrightbig=1
2parenleftBig
1−OOTparenrightBig
=0.
Displacements in the linear theory for the rigid rotation (r igid displacement) are given
by the relation
w(x)=u0+(O0−1)(x−x0), (2.76)
whereu0is an arbitrary vector, x0is the reference point and xis the position of the
point of the body. O0denotes a constant orthogonal matrix and, therefore, it des cribes
an arbitrary time-independent rotation. As already mentio ned, we do not introduce the
time dependence in order to eliminate inertial effects. In th e above relation, the difference
O0(x−x0)−(x−x0)is the displacement of point xdue to the rotation around the point
x0. On this displacement we superpose the displacement u0=u(x0)of the pointx0.
Consequently
gradw=O0−1. (2.77)
In order to see the consequences of this relation in the case o f the linear model, we
consider the spectral representation of the matrix of rotat ionO0.We have
(O0−λo1)ko=0⇒det(O0−λo1)=0, (2.78)
from which it follows
parenleftbig
1−λoOT
0parenrightbig
ko=0⇒detparenleftbigg
O0−1
λo1parenrightbigg
=0, (2.79)
Hence
λ2
o=1⇒λo=±1. (2.80)
It means that the matrix O0possesses two real eigenvalues. We skip the negative value
which describes the mirror picture. Let us choose the refere nce system in such a way
that one of the axes coincide with the eigenvector correspon ding toλo= 1. Then the
matrixO0has the form (compare (1.17))
parenleftbigO0
klparenrightbig=
1 0 0
0 cosϕsinϕ
0−sinϕcosϕ
. (2.81)
38 Geometry and kinematics of continua
Clearly, this matrix possesses, in addition to real eigenva lues, the complex eigenvalues as
well
(1−λo)bracketleftBig
(cosϕ−λo)2+(sinϕ)2bracketrightBig
=0⇒ (2.82)
⇒λ(1)
o=1orλ2o−2cosϕλo+1=0,
i.e.λ(2,3)
o=cosϕ±isinϕ=e±iϕ.
These eigenvalues determine the angle of rotation ϕaround the single real eigenvector
corresponding to λ0=1.
For small angles of rotation, the orthogonal matrix contain s the nontrivial antisym-
metric part
O0=1+Ω0,parenleftbig
Ω0
klparenrightbig
=
0 0 0
0 0ϕ
0−ϕ0
,ΩT
0=−Ω0. (2.83)
The rigid displacement is characterized by the following Gu rtin Theorem:
The following three statements are equivalent:
1.wis a rigid displacement field, i.e.
w=u0+Ω0(x−x0),ΩT0=−Ω0. (2.84)
2. The strain field eis vanishing on the domain Bt.
3.whas the projection property on Bt, i.e. for any pair of points x,y∈Bt
(w(x)−w(y))·(x−y)=0. (2.85)
Namely, we have
[u0+Ω0(x−x0)−u0−Ω0(y−x0)]·(x−y)=0,
due to the antisymmetry of Ω0. Hence 1.⇒3. Now we take the derivative of (2.85) with
respect toxand then with respect to y. Evaluating it at x=ywe obtain
[(grad)xw(x)]T·(x−y)−(w(x)−w(y))=0
⇒[gradw(x)]T+gradw(x)=2e(x)=0,
i.e. 3.⇒2. Finally, for e=0we havegrad(gradw)=0. Hencewis a linear function of
x:w=u0+A(x−x0)and, ase=0⇒A+AT=0, it must have the form of the rigid
displacement which means 2. ⇒1. This completes the proof.
The above Theorem implies immediately the Kirchhoff Theorem : if two displacement
fieldsuandu′produce the same strain field ethen
u=u′+w, (2.86)
wherewis a rigid displacement. We have, obviously, grad(u−u′)+[grad(u−u′)]T=0
which yields, according to Gurtin’s Theorem, that wis the rigid displacement.
2.4 Infinitesimal strains 39
An arbitrary displacement u(x)can be split into the displacement caused by the
deformation and this caused by the rigid rotation. Then for s mall deformations
gradu=e+Ω, (2.87)
where
Ω=1
2parenleftBig
gradu−(gradu)TparenrightBig
, (2.88)
and the vector
ω=1
2rotu, ωk=−1
2εkijΩij, (2.89)
is the rotation vector.
Bearing for subbodies Pof small volumes Vthe relation (1.63) in mind as well as
the relation (2.51) for the velocity under small deformatio ns (i.e. identical Lagrange and
Euler reference systems)
v(x,t)=∂u
∂t(x,t) (2.90)
we have
δV
δt=integraldisplay
Pdiv∂u
∂tdV=d
dtintegraldisplay
PdivudV≈Vtre
δt⇒δV
V=tre, (2.91)
i.e.tredescribes the dilatation.
A special important class of deformations is defined by the ho mogeneous displacement
field
u(x)=u0+A(x−x0), (2.92)
where the point x0, the vectoru0and the tensor Aare independent of x. Ifu0=0and
Ais symmetric then uis called a pure strain from x0.
⋆The following deformations for homogeneous displacement fi elds should be men-
tioned:
1) simple extension of amount e in the direction n,|n|=1,
u=e((x−x0)·n)n,gradu=en⊗n, (2.93)
e=en⊗ni.e.(eij)=
e0 0
0 0 0
0 0 0
,
Ω=0,
for the base vectors {e1=n,e2,e3};
2) uniform dilatation of amount e
u=e(x−x0),gradu=e1, (2.94)
e=e1i.e.(eij)=
e0 0
0e0
0 0e,
Ω=0;
40 Geometry and kinematics of continua
3) simple shear of amount κwith respect to the directions {m,n},m·n=0(compare
(2.35)) and both these vectors are unit
u=κm·(x−x0)n,gradu=κm⊗n (2.95)
e=1
2κ(m⊗n+n⊗m)i.e.(eij)=
0κ/2 0
κ/2 0 0
0 0 0,
Ω=1
2κ(m⊗n−n⊗m),
for the base vectors {e1=m,e2=n,e3}.♣
2.5 Compatibility conditions
Providedeis given, the relation for the strain field
e=1
2parenleftBig
gradu+(gradu)TparenrightBig
, (2.96)
can be considered to constitute the set of the first order part ial differential equations
for the displacement field u. The uniqueness of solution is answered by the Kirchhoff
Theorem — two solutions differ at most by a rigid displacement fieldw. We answer now
the question of existence of such solutions.
Let us define the rotoperator for the tensor ein the following way
∀a=const[rote]a=rotbracketleftbigeTabracketrightbigi.e.rote=ǫijk∂emk
∂xjei⊗em. (2.97)
Then, for the strain tensor
rote=gradω, (2.98)
where the rotation vector ωis defined by the relation (2.89). It follows from the simple
calculation
rote=1
2rotparenleftBig
gradu+(gradu)TparenrightBig
=1
2gradrotu=gradω, (2.99)
or, in coordinates
ǫijk∂emk
∂xj=1
2ǫijk∂
∂xjparenleftbigg∂um
∂xk+∂uk
∂xmparenrightbigg
=1
2ǫijk∂2uk
∂xj∂xm=∂ωi
∂xm. (2.100)
Hence
rotrote=0, (2.101)
where we have used the relation (2.99)
rotrote=ǫpnm∂2ωi
∂xm∂xnep⊗ei≡0.
2.5 Compatibility conditions 41
The relation (2.101) is the equation of compatibility.
It can be proved that the equation of compatibility is sufficie nt for the existence of
solutions of the equation (2.96) provided the domain Btis simply connected. We leave
out a rather simple proof (e.g. [4]).
A similar but much more complicated relation can be shown for the nonlinear theory
(see: Sect. 2.5 of [22]). It follows from the assumption that the space of motion is
Euclidean which means that its tensor of curvature is zero. W e shall not present this
problem in these notes. However, we discuss further the case of the body with continuous
distribution of dislocations for which this condition is vi olated.
The compatibility condition in the explicit form is as follo ws
ǫijkǫlmn∂2ejm
∂xk∂xn=0. (2.102)
It can be easily shown that for a particular case of plane disp lacements in which
u=u1e1+u2e2the set of six independent equations (2.102) reduces to the s ingle
relation
2∂2e12
∂x1∂x2=∂2e11
∂x2∂x2+∂2e22
∂x1∂x1. (2.103)
This equation is used in the construction of the so-called Be ltrami-Michell equations of
linear elasticity which we have already mentioned at the beg inning of this Chapter and
which we present in Chapter 5.
42 Geometry and kinematics of continua
Chapter 3
Balance of mass and
momentum
Classical continuum mechanics is primarily concerned with the search for solutions for
the function of motion. In the Lagrangian description curre nt values of mass density
are then given by a simple kinematical relation. Field equat ions for these fields follow
from two fundamental equations of physics — conservation of mass and momentum. Some
additional fields such as density of dislocations or plastic deformations require additional
evolution equations which we discuss further in these notes . In this Chapter we present
these two conservation laws of mechanics in both Lagrangian and Eulerian description.
We mention as well the consequences of the third mechanical c onservation law — moment
of momentum conservation. It is a basis for the field equation s in models of systems in
which an additional local degree of freedom, the rotation (s pin), plays a rule. This is,
for instance, the case for liquid crystals. For classical co ntinua considered in these notes
it restricts the form of the stress tensor, an object appeari ng in the conservation law for
momentum.
3.1 Conservation of mass
As in the mechanics of points the mass in continuum mechanics is a measure of inertia
of subbodies of the body B0. SubbodiesP⊂B0are subsets of a certain mathematical
structure which we do not need to present in details. Each sub body has a prescribed
massM(P)>0and we make the assumption (continuity) that this quantity c an be
described by the density ρ0
M(P)=integraldisplay
Pρ0(X)dV. (3.1)
In contrast to material points of classical mechanics of poi nts and rigid bodies the ma-
terial pointX∈B0possesses no mass, the mass density ρ0serves only the purpose of
determining the mass of finite subbodies through the relatio n (3.1). In this sense, the
43
44 Balance of mass and momentum
mass density is not measurable. We measure in laboratories t he mass of bodies and
assuming the homogeneity we define the mass density as the fra ction
ρ0≈M(P)
V(P). (3.2)
According to the law of mass conservation the mass M(P)does not change in any
process
dM(P)
dt=0. (3.3)
We may have mass supplies from other components due to chemic al reactions or phase
changes but this requires the construction of continuum mec hanics of mixtures of many
components which we shall not present in these notes. This as sumption on conservation
does not mean that mass density remains constant in processe s. Its changes are connected
with changes of the volume occupied by the subbody Pat any instant of time. On
the other hand this volume is given by the function of motion. Namely, in a current
configuration the points X∈Poccupy the following domain in the space of motion E3
Pt={x|x=f(X,t),X∈P}. (3.4)
Such domains we call material. Hence the mass of Pcan be written in the form
M(P)=integraldisplay
PtρdVt, (3.5)
whereρis the current mass density and dVtis the volume element in the current config-
uration. The element dVtis the transformation of the element dV=dX1dX2dX3to the
current configuration. In Cartesian coordinates we can writ e it in the following way
dVt= [(Fe1dX1)×(Fe2dX2)]·(Fe3dX3)=
= [(Fk1ek)×(Fl2el)]·(Fm3em)dV= (3.6)
=εklmFk1Fl2Fm3dV=JdV, J=detF,
where the relation (1.40) has been used and we have used the sa me base vectors in
Lagrangian and Eulerian coordinates ek=δkKeK.Consequently
ρ=ρ0J−1. (3.7)
Hence for a given deformation gradient Fchanges of the mass density are determined.
For this reason, the field of mass density does not appear amon g unknown fields in the
Lagrangian description. Obviously, in the reference config urationJ=1. Both the initial
mass density ρ0and the current mass density must be positive. Consequently , we have
the condition
J >0. (3.8)
This condition yields the local invertibility of the functi on of motion x=f(X,t):
X=f−1(x,t).
3.1 Conservation of mass 45
The relation (3.5) can be also written in the local form in tim e
d
dtintegraldisplay
PtρdVt=0, (3.9)
for all material domains Pt. Making use of the Leibniz Theorem (1.56) we can write it
in the following form integraldisplay
Pt∂ρ
∂tdVt+contintegraldisplay
∂Ptρv·ndSt=0. (3.10)
Bearing the Gauss Theorem (1.60) in mind, we obtain
integraldisplay
Ptparenleftbigg∂ρ
∂t+div(ρv)parenrightbigg
dVt=0. (3.11)
Hence, for almost all points of the body (except of points whe reρis discontinuous) the
following local form of the mass conservation in Eulerian de scription follows
∂ρ
∂t+div(ρv)=0, (3.12)
i.e.∂ρ
∂t+∂
∂xk(ρvk)=0.
Obviously, (3.7) fulfills this equation identically. In ord er to see it, we rewrite the
above equation in the form
parenleftbigg∂ρ
∂t+∂ρ
∂xkvkparenrightbigg
+ρ∂vk
∂xk=0. (3.13)
The expression in the parenthesis is called the material tim e derivative. It is identical
with the partial time derivative in the Lagrangian descript ion. Namely we have
∂ρ(fk(X,t),t)
∂t=∂ρ
∂t+∂ρ
∂xk∂fk
∂t=∂ρ
∂t+∂ρ
∂xkvk. (3.14)
Hence, in Lagrangian coordinates, (3.13) yields
∂J−1
∂t+J−1F−T·∂F
∂t=0,F−T·∂F
∂t=∂FkK
∂tF−1
Kk. (3.15)
On the other hand, the rule of differentiation of determinant s yields
∂J−1
∂t=−1
J2∂J
∂F·∂F
∂t=−1
J2JF−T·∂F
∂t, (3.16)
and (3.15) becomes the identity.
Apart from the continuity relation (3.12) the relation (3.1 0) yields also a very useful
relation on moving surfaces on which the mass density posses ses a finite discontinuity.
46 Balance of mass and momentum
In order to find this relation, we consider first a descending f amily of subbodies {Pi}
intersecting the surface Sin the reference configuration. We assume that this surface
moves in the direction of its unit normal Nwith the speed U, i.e. the velocity of points
of the singular surface is UN. The family of subbodies is descending in this sense that
at each instant of time they have the same common part with the singular surface and
their volume is diminishing to zero with the growing index i
∀i/negationslash=jPi∩S=Pj∩S,lim
i→∞(volPi)=0,volPi=integraldisplay
PidV. (3.17)
This construction with an appropriate orientation of norma l vectors is shown in Fig. 3.1.
Fig. 3.1: A singular surface Sintersecting the family of subbodies {Pi}
Now the relation (3.3) can be written in the form
d
dtintegraldisplay
Piρ0dV=d
dtintegraldisplay
P+
iρ0dV+d
dtintegraldisplay
P−
iρ0dV,P+
i∪P−
i=Pi, (3.18)
whereP+
i,P−
iare the parts ofPicreated by the intersection with S. Obviously, ρ0is
constant within each of these two subbodies but it does not ha ve to possess the same
value if the surface Sis the surface of discontinuity for the mass density. Simult aneously,
due to the motion of Sthe subbodiesP+
i,P−
ichange in time. Hence, according to the
Leibniz Theorem, we obtain
d
dtintegraldisplay
Piρ0dV=−integraldisplay
∂P+
i∩Sρ+
0UdS+integraldisplay
∂P−
i∩Sρ−0UdS=0, (3.19)
where the opposite sign in the integrals follows from the opp osite orientation of the
outward oriented normal vector of P+
iand the normal vector of the surface S. The
3.1 Conservation of mass 47
quantitiesρ+
0andρ−0are, of course, the values of the mass density on two sides of t he
surfaceS. Hence, this surface is carrying the discontinuity of the ma ss density
[[ρ0]]=ρ+
0−ρ−0. (3.20)
Taking the limit i→∞in (3.19) we obtain the following local form of this relation
U[[ρ0]]=0. (3.21)
In a particular case of the surface Swhich is not moving — we say then that the surface
is material — we have U=0and the jump of mass density [[ρ0]]may be arbitrary. If it
is different from zero the surface Sis the surface of contact of two different materials.
Otherwise the initial mass density ρ0must be continuous [[ρ0]]=0.
The same considerations can be repeated for the current confi guration. Instead of
the surfaceSwe have to consider its current image Stmoving with the speed c, i.e. its
velocity iscn. The subbodies in the reference configuration have to be tran sformed to
the current configuration Pi(t)={x|x=f(X,t),X∈Pi}.Then (3.9) yields
integraldisplay
Pi(t)∂ρ
∂tdV+contintegraldisplay
∂P+
i(t)ρw·ndSt+contintegraldisplay
∂P−
i(t)ρw·ndSt=0, (3.22)
wherew=vfor points of the surfaces beyond Sandw=cnfor points onS. Again
taking the limit, we obtain
[[ρ(v·n−c)]]≡ρ+parenleftbig
v+·n−cparenrightbig
−ρ−parenleftbig
v−·n−cparenrightbig
=0 (3.23)
where, obviously, v±are the limits of the particle velocity on the surface St. The relation
(3.23) is Eulerian counterpart of Lagrangian relation (3.2 1). It is clear that for the
material surfaceStwe havev·n=cand the particle velocity is continuous.
The above presented analysis can be repeated for the equatio n (2.70) which has the
formal structure of balance equation. We have
d
dtintegraldisplay
PiFkKdV=d
dtintegraldisplay
P+
iFkKdV+d
dtintegraldisplay
P−
iFkKdV=
=integraldisplay
Pi∂FkK
∂tdV−integraldisplay
∂P+
i∩SF+
kKUdS+integraldisplay
∂P−
i∩SF−
kKUdS= (3.24)
=contintegraldisplay
∂PivkNKdS,
whereF±
kKare the limits of the deformation gradient on both sides of th e surfaceS.
Taking the limit described above we obtain
[[FkK]]U+[[vk]]NK=0,[[FkK]]=F+
kk−F−
kK,[[vk]]=v+
k−v−
k. (3.25)
This is the kinematical compatibility condition which is th e part of the Hadamard The-
orem and which we have mentioned in Section 2.3. It says that t he discontinuity of
velocity on a singular surface — it may be, for instance, the f ront of the so-called shock
wave — yields necessarily the discontinuity of deformation andviceversa .
48 Balance of mass and momentum
3.2 Conservation of momentum
3.2.1 Lagrangian description
The momentum for continuum is again defined for subbodies rat her than points as we
know it from the classical mechanics of mass points. Namely, it refers to the motion of
the center of gravity of small material portions and then for an arbitrary subbody Pit
has the form
M(P)=integraldisplay
Pρ0vdV. (3.26)
Its time changes depend on interactions with the external wo rld of the subbody. If these
interactions are zero the momentum is conserved
dM
dt=0. (3.27)
However, if we cut Pfrom the bodyB0which itself interacts with the external world
it cannot be expected that the interactions of subbody vanis h. They are transmitted
through the surface ∂Pas well as directly into the interior of P. The latter may be,
for instance, gravitational or they may be created by the rot ational motion of the body
in the form of centrifugal or Coriolis forces. Consequently , instead of (3.27) we have to
writedM
dt=contintegraldisplay
∂PtNdS+integraldisplay
Pρ0bdV, (3.28)
wheretNare the so-called tractions, i.e. forces acting on a unit sur face of∂Pin the
reference configuration, and bare called body forces. They may result from the action
of the gravity but they may be as well a consequence of the moti on of the body as a
whole which results, for instance, in centrifugal forces. A . L. Cauchy (1789-1857) has
shown that the tractions are linear functions of the unit nor mal vectorNof the surface
∂P, i.e. [22]
tN=PN,i.e.t(N)
k=PkKNK,tN=t(N)
kek,P=PkKek⊗eK, (3.29)
wherePis independent of N. This object is called Piola-Kirchhof stress tensor even
though it is not a tensor. t(N)
kare components of the stress vector for a particular choice
of the subbodyP, i.e. for a particular choice of the surface ∂P.
Making use of the Gauss Theorem we can write (3.28) in the form
integraldisplay
Pparenleftbigg
ρ0∂v
∂t−DivP−ρ0bparenrightbigg
dV=0, (3.30)
which must hold for all subbodies of B0. Consequently, for almost all points of the body
B0
ρ0∂v
∂t=DivP+ρ0b, (3.31)
i.e.ρ0∂vk
∂t=∂PkK
∂XK+ρ0bk.
3.2 Conservation of momentum 49
This is the local form of the momentum conservation law in Lag rangian description.
Obviously∂vk/∂t≡∂2fk/∂t2is the acceleration in this description.
The most important consequence of the above analysis is the e xistence of the stress
tensorP. However, the Lagrangian description has the disadvantage of referring to a
nonphysical reference surface. Practical applications ar e mostly based on the Eulerian
description. We return later to the comparison of both appro aches.
3.2.2 Eulerian description
Let us make the transformation from the Lagrangian to Euleri an description in the
momentum balance (3.30). We have
integraldisplay
Ptparenleftbigg
ρ0∂v
∂t−DivP−ρ0bparenrightbigg
J−1dVt=0, (3.32)
where (3.6) has been used and the function in parenthesis sti ll depends onxthrough the
function of motion f−1(x,t). However
DivP=∂PkK
∂XKek=∂PkK
∂xl∂xl
∂XKek=F·(gradP), (3.33)
Using the identity (2.67) 2, the relation (3.7) and making the transformation of variab les
X→xwe have
integraldisplay
Ptparenleftbigg
ρparenleftbigg∂v
∂t+(v·gradv)parenrightbigg
−divT−ρbparenrightbigg
dVt=0,T=J−1PFT, (3.34)
i.e.σkl=J−1PkKFlK,T=σklek⊗el.
The new stress tensor Tis called the Cauchy stress tensor. Components of the Cauchy
stress tensor are often defined in Cartesian coordinates x1=x, x2=y, x3=zand base
vectors{ex,ey,ez}. Then the components are denoted in the following way
(σkl)=
σxτxyτxz
τxyσyτyz
τxzτyzσz. (3.35)
The components σ
x,σy,σzare called normal stresses and the components τxy,τxz,τyz
are called shear stresses. Normal components are also descr ibed by a double index
σx=σxx,σy=σyy,σz=σzz.
Now transforming the stress contribution from the volume to surface integral we
obtain integraldisplay
Ptρparenleftbigg∂v
∂t+(v·gradv)parenrightbigg
dVt−contintegraldisplay
∂PtTndSt=integraldisplay
PtρbdVt. (3.36)
Consequently, the stress vector (traction) in the current c onfiguration is given by the
relation
tn=Tni.e.t(n)
k=σklnl. (3.37)
50 Balance of mass and momentum
In contrast to the stress vector (traction) tNappearing in the relation (3.28) the above
stress vector describes the force of surface interaction pe r unit area of the current surface
∂Pt.
The relation (3.37) is called the Cauchy relation. The local form of the momentum
balance (3.34)
ρparenleftbigg∂v
∂t+(v·gradv)parenrightbigg
=divT+ρb, (3.38)
i.e.ρparenleftbigg∂vk
∂t+vl∂vk
∂xlparenrightbigg
=∂σkl
∂xl+ρbk.
is called the Cauchy equation.
In fluid mechanics the local momentum equation is also used in a different form
ρparenleftbigg∂vk
∂t+2vlWklparenrightbigg
=parenleftbigg∂σkl
∂xl−1
2ρ∂v2
∂xkparenrightbigg
+ρbk, v2=v·v, (3.39)
whereWklis the spin (compare (2.65)) and which follows from the ident ity
vl∂vk
∂xl=2vlWkl+1
2∂v2
∂xk. (3.40)
Then for potential (irrotational) flows
v=gradϕ,i.e.vk=∂ϕ
∂xk⇒W=0, (3.41)
and the momentum balance becomes
∂vk
∂t=1
ρ∂σkl
∂xl−∂
∂xkparenleftbigg1
2v2+Φparenrightbigg
,b=−gradΦ, (3.42)
which immediately yields the Bernoulli Theorems for ideal fl uids (e.g. [21]). Namely,
for ideal fluids which do not carry the shear stresses the stre ss tensor is reduced to the
diagonal form
T=−p1i.e.σkl=−pδkl, (3.43)
wherep=−1
3σkkis the pressure. Then an arbitrary direction is principal fo r this stress
tensor. Equation (3.42) has now the following form (it is ass umed thatρ=ρ(p)!)
∂vk
∂t=−∂
∂xkparenleftbigg
P+1
2v2+Φparenrightbigg
, P=integraldisplaydp
ρ+const., (3.44)
wherePis the so-called pressure function. Obviously, for slow mot ions in which one can
neglect the acceleration this relation indicates that P+1
2v2+Φis only a function of
time, and this, in turn, yields the Bernoulli Theorem. This f orm of momentum balance
yields the theory of water waves.
As in the case of mass balance equation, the conservation of m omentum yields condi-
tions on a singular surface which may carry the discontinuit ies of mass and momentum.
3.2 Conservation of momentum 51
In the Lagrangian description, we have to introduce again a d escending family of sub-
bodies{Pi}defined by (3.18) and then (3.28) can be written in the form
integraldisplay
Piρ0∂v
∂tdV−integraldisplay
∂P+
i∩Sρ+
0v+UdS+integraldisplay
∂P−
i∩Sρ−0v−UdS=contintegraldisplay
∂PiPNdS+integraldisplay
Piρ0bdV,(3.45)
for each member Piof this family. Again the minus sign follows from the opposit e
orientation of normal vectors. In the limit i→∞we obtain
ρ0U[[v]]+[[PN]]=0, (3.46)
whereNis the unit normal of the surface S. Consequently, a discontinuity of the stress
vector (traction) on a singular surface yields the disconti nuity of the velocity and this,
in turn, according to Hadamard Theorem (compare (3.25)), yi elds a discontinuity of the
deformation.
For the Eulerian description we obtain the following dual re lation
integraldisplay
Pi(t)ρ∂v
∂tdV+integraldisplay
∂P+
i(t)ρvw·ndS+integraldisplay
∂P−
i(t)ρvw·ndS=contintegraldisplay
∂Pi(t)TndSt+integraldisplay
Pi(t)ρbdV,(3.47)
Again, in the limit we obtain (compare (3.22), (3.23))
[[ρ(v·n−c)v]]−[[Tn]]=0. (3.48)
Obviously, the expression (v·n−c)describes the motion of the particles with respect
to the moving singular surface in the direction normal to thi s surface. If we account for
the mass conservation (3.23) then
ρ(v·n−c)[[v]]−[[Tn]]=0. (3.49)
where the value ρ(v·n−c)is taken on any side of the surface as they are equal. For
material surfaces we obtain, of course,
[[Tn]]=0, (3.50)
i.e. the continuity of tractions. This relation is fundamen tal for the formulation of bound-
ary conditions in terms of stresses. Otherwise, if the tract ion is discontinuous on the
nonmaterial surface it yields necessarily the discontinui ty of velocity.
The relations for mass and momentum conservations on singul ar surfaces (3.23), (3.49)
are called the dynamic compatibility conditions.
3.2.3 Moment of momentum
It can be easily shown that the moment of momentum conservati on yields the symmetry
of the Cauchy stress tensor. The classical definition of the m oment of momentum for the
subbodyP⊂B0has the form
K(t)=integraldisplay
Pρ0x×vdV, (3.51)
52 Balance of mass and momentum
wherex=f(X,t)is the position of the point X∈Pat the instant of time t. Its time
changes are described by the relation
d
dtintegraldisplay
Pρ0x×vdV=contintegraldisplay
∂Px×(PN)dS+integraldisplay
Pρ0x×bdV. (3.52)
In Cartesian coordinates this relation can be written in the form
integraldisplay
Pρ0εijkxj∂vk
∂tdV=contintegraldisplay
∂PεijkxjPkKNKdS+integraldisplay
Pρ0εijkxjbkdV. (3.53)
In the first integral, the observation that the contribution with the derivative ∂xj/∂t=vj
is identically zero has been used. The surface integral can b e transformed in the following
waycontintegraldisplay
∂PεijkxjPkKNKdS=integraldisplay
Pεijkparenleftbigg
FjKPkK+xj∂PkK
∂XKparenrightbigg
dS. (3.54)
Bearing (3.31) in mind, we obtain
εijkFjKPkK=0, (3.55)
in almost all points of B0. Consequently, the definition of the Cauchy stress tensor (3 .34)
yields
εijkσjk=0,i.e.T=TT. (3.56)
Hence, the conservation of moment of momentum yields the sym metry of the Cauchy
stress tensor.
3.2.4 Stress analysis
Due to the symmetry of the Cauchy stress tensor we can easily s olve the problem of
the biggest and smallest local stresses. We begin this analy sis with the maximum and
minimum of normal stresses, i.e. these stress components wh ich are perpendicular to the
surface of the cross-section of the system. If ndenotes the unit vector perpendicular to
the surface at the point xin the current configuration then we have to find this vector
for which the stress vector projected on n, i.e.n·tn=n·(Tn)is maximum or minimum.
We have solved this problem already for tensors of deformati on (compare (2.19)). The
directionnis given by the solution of the eigenvalue problem
(T−σ1)n=0, (3.57)
whereσare eigenvalues of T. These are given by the equation
det(T−σ1)=0. (3.58)
In the explicit form it reads
σ3−Iσσ2+IIσσ−IIIσ=0, (3.59)
3.2 Conservation of momentum 53
where
Iσ= trT=σ11+σ22+σ33=σ(1)+σ(2)+σ(3),
IIσ=1
2parenleftbigI2
σ−trT2parenrightbig=vextendsinglevextendsinglevextendsinglevextendsingleσ11σ12
σ12σ22vextendsinglevextendsinglevextendsinglevextendsingle+vextendsinglevextendsinglevextendsinglevextendsingleσ
11σ13
σ13σ33vextendsinglevextendsinglevextendsinglevextendsingle+vextendsinglevextendsinglevextendsinglevextendsingleσ
22σ23
σ23σ22vextendsinglevextendsinglevextendsinglevextendsingle=
=σ
(1)σ(2)+σ(1)σ(3)+σ(2)σ(3), (3.60)
IIIσ= detT=vextendsinglevextendsinglevextendsinglevextendsinglevextendsinglevextendsingleσ
11σ12σ13
σ12σ22σ23
σ13σ23σ33vextendsinglevextendsinglevextendsinglevextendsinglevextendsinglevextendsingle=σ
(1)σ(2)σ(3),
are the principal invariants of the stress tensor T. The name ’invariant’ refers to the fact
that these quantities remain the same in all frames of refere nce, i.e. they are independent
of the choice of the base vectors. Once we have the three solut ionsσ(1),σ(2),σ(3)of the
equation (3.59), which are called principal values of the st ress tensorT, we can find
from the set (3.57) three corresponding normalized eigenve ctorsn(1),n(2),n(3). They
are called principal directions of the stress tensor T. Obviously, they are orthogonal,
i.e.n(α)·n(β)=δαβ. According to the relation (3.57) we have
n(α)·Tn(β)=0forα/negationslash=β. (3.61)
Hence, if we choosebraceleftbig
n(1),n(2),n(3)bracerightbig
as the basis vectors we obtain the following spectral
representation of stress tensor
T=3summationdisplay
α=1σ(α)n(α)⊗n(α). (3.62)
The graphical representations of the stress tensor Tin an arbitrary Cartesian basis
{ex,ey,ez}and in the principal directionsbraceleftbign(1),n(2),n(3)bracerightbigare shown in Fig. 3.2.
Fig. 3.2: Stress components in Cartesian coordinates — an ar bitrary
coordinate system (left panel) and the system of principal d irections (right
panel)
54 Balance of mass and momentum
In order to appreciate the notions of stress tensors we prese nt a few simple examples.
⋆Let us begin with an example of the Cauchy stress tensor for wh ich we want to find
principal stresses and the principal directions. In a chose n frame of Cartesian coordinates
it has the form of the following matrix
(σij)=
5 2−3
2 4 1
−3 1−3,T=σ
ijei⊗ej, (3.63)
where the inputs are in MPa. The corresponding eigenvalue pr oblem has the form
5−σ2−3
2 4−σ1
−3 1−3−σn
1
n2
n3=0
0
0
, (3.64)
and the eigenvector nshould be of the unit length
n=n
iei,n·n=(n1)2+(n2)2+(n3)2=1. (3.65)
Obviously, the determinant of the set of equations (3.64) mu st be zero. Hence
−det(T−σ1)=σ3−Iσσ2+IIσσ−IIIσ=0. (3.66)
Coefficients of this equation, the principal invariants of th e stress tensor T, are given by
the relations
Iσ= trT=6MPa, IIσ=1
2parenleftbigIσ−trT2parenrightbig=−21(MPa)2, (3.67)
IIIσ= detT=−101(MPa)3.
The solution of (3.66) (it has ben obtained by Maple7 )has the form
σ(3)=−4.3099MPa, σ(2)=3.3832MPa, σ(1)=6.9267MPa. (3.68)
It is easy to check that the following identities are satisfie d
Iσ=σ(1)+σ(2)+σ(3), IIσ=σ(1)σ(2)+σ(1)σ(3)+σ(2)σ(3),(3.69)
IIIσ=σ(1)σ(2)σ(3).
Now, by means of the equations (3.64) and the normalization c ondition (3.65) we find
the corresponding eigenvectors. They are as follows
n(1)= 0.8394e1+0.5043e2−0.2029e3,
n(2)= 0.4256e1−0.8419e2−0.3319e3, (3.70)
n(3)= 0.3382e1−0.1922e2+0.9212e3.
3.2 Conservation of momentum 55
Obviously, due to the relation n(α)·ei=cosparenleftbigparenleftbign(α),eiparenrightbigparenrightbig, the components of eigenvectors
are cosines of the angles between eigenvectors and correspo nding base vectors. We have
parenleftBig
n(1),e1parenrightBig
= 70.230,parenleftBig
n(1),e2parenrightBig
=101.080,parenleftBig
n(1),e3parenrightBig
=22.900,
parenleftBig
n(2),e1parenrightBig
= 64.810,parenleftBig
n(2),e2parenrightBig
=147.340,parenleftBig
n(2),e3parenrightBig
=109.380,(3.71)
parenleftBig
n(3),e1parenrightBig
= 32.920,parenleftBig
n(3),e2parenrightBig
=59.720,parenleftBig
n(3),e3parenrightBig
=101.710.
The spectral representation of the stress tensor has the for m
T=6.9267n(1)⊗n(1)+3.3832n(2)⊗n(2)−4.3099n(3)⊗n(3). (3.72)
Hence, the biggest value of the stress is n(1)·Tn(1)= 6.9267MPa, it is tension
(positive value!) in the direction n(1). The smallest value is n(3)·Tn(3)=−4.3099MPa,
it is compression (negative value!). On surfaces perpendic ular to the principal directions
n(1),n(2),n(3)shear stresses are equal to zero: n(α)·Tn(β)=0forα/negationslash=β.♣
⋆In the second example we calculate the stress vector tnon the plane intersecting
the cube which is loaded on the faces by the stress Tgiven by the formula (3.63). The
plane crosses the points (1,0,0.5),(0,1,1),(1,1,0)as shown in Fig. 3.3.
Fig. 3.3: Intersection of the cube discussed in the example
On the same Figure we indicate the components of stresses act ing on the back faces
of the cube. The plane intersecting the cube is, obviously, g iven by the equation
p(x1,x2,x3)=x1+0.5x2+x3−1.5=0. (3.73)
56 Balance of mass and momentum
The vector perpendicular to this plane is parallel to gradp=e1+0.5e2+e3and, after
the normalization, it yields the following normal vector n
n=2
3e1+1
3e2+2
3e3. (3.74)
Now the stress vector on the plane is specified by the relation
tn=Tn=σijnjei=2e1+10
3e2−3e3. (3.75)
The normal component of the stress acting in the intersectio n by the plane follows as
σn=n·tn=4
9=0.4444MPa. (3.76)
Consequently, the shear stress on this plane is given by the v ector
τn=tn−σnn=1
27(46e1+86e2−89e3),|τn|=4.8902MPa. (3.77)
♣
⋆In this example we show the difference between the stress tens ors of Piola-Kirchhoff
and Cauchy. Let us consider again the deformation of the pris m described in the example
(2.7). We make the simplifying assumption that the material is incompressible, i.e. its
volume remains constant during the deformation. This is pra ctically fulfilled for many
materials, e.g. for rubber-like materials. Then
J=1⇒(1+ε1)(1+ε2)(1+ε3)=1. (3.78)
Assuming that the prism is loaded by the force Pin the direction e3we conclude from
symmetryε1=ε2. Hence
1+ε1=1+ε2=1√1+ε3. (3.79)
The reference area on which the external force Pis distributed, say A0=(ae1)·(ae2)=
a2, changes due to the deformation to A=(aFe1)·(aFe2)=a2(1+ε1)2=a2/(1+ε3).
Consequently, the normal components of the Piola-Kirchhoff and Cauchy stress in the
e3-direction, respectively, are as follows
P33=P
a2, σ33=P
a2(1+ε3). (3.80)
Hence, even a moderate elongation of, say, ε3= 0.1yields the 10% difference in these
components. The component σ33which is indeed measured in laboratory is bigger than
the component of the Piola-Kirchhoff stress. This difference may even yield a change in
the behaviour of stresses in function of deformation. There are cases where the growing
Cauchy stress corresponds to a decaying Piola-Kirchhoff str ess andviceversa . This may
lead to erroneous conclusions concerning the so-called mat erial stability.♣
3.2 Conservation of momentum 57
There are two two-dimensional cases in which the above stres s analysis possesses a
simple geometrical interpretation. The first case — plane st resses — appears when the
stress tensor consists of four non-zero components
(σij)=
σxτxy0
τxyσy0
0 0 0, (3.81)
whereσ
x≡σxx,σy=σyy.
The second case — plane strains — appears when the stress tens or consists of five
non-zero components
(σij)=
σxτxy0
τxyσy0
0 0σz, (3.82)
withσ
x≡σxx,σy=σyy,σz≡σzz.
Then the eigenvalue problem
(T−σ1)n=0, (3.83)
Fig. 3.4: Transformation of the stress tensor for 2D-case
yieldsσ(3)=0andn(3)=ezin the first case and σ(3)=σzandn(3)=ezin the second
case. For this reason it is sufficient to consider the problem o n the plane perpendicular
toez. We consider the components of the stress on the plane perpen dicular to the unit
vectorn= cosϕex+sinϕey(see Fig. 3.4.). It is convenient to introduce the vector
perpendicular to n:n+=−sinϕex+cosϕey.
The stress vector tnis obviously given by the relation
tn=Tn=(σxcosϕ+τxysinϕ)ex+(τxycosϕ+σysinϕ)ey. (3.84)
58 Balance of mass and momentum
Then the normal component σnand the tangential component τnare as follows
σn=tn·n=σx+σy
2+σx−σy
2cos2ϕ+τxysin2ϕ, (3.85)
τn=tn·n+=−σx−σy
2sin2ϕ+τxycos2ϕ.
If we eliminate the angle ϕfrom these relations we obtain the relation which should
hold for an arbitrary intersection of the square on the plane perpendicular to ez. This
equation has the form
τ2
n+parenleftbigg
σn−σx+σy
2parenrightbigg2
=parenleftbiggσx−σy
2parenrightbigg2
+τ2
xy. (3.86)
This is the equation of the circle on the plane of (σn,τn)-variables whose center lies on
the axisτn=0at the point1
2(σx+σy). It is called Mohr’s circle. The radius of this
circle is equal toradicalBig
1
4(σx−σy)2+τ2xy. For a given tensor (3.81) or (3.82) the angle ϕ
yields the values of the components of the stress vector on th e plane of intersection as
indicated in Fig. 3.5.
As a particular case of relations (3.85) we can locate the pos ition of the principal
direction and the principal values of stresses for this two- dimensional case. We use the
property of the principal direction that the shear stress on the plane perpendicular to
this direction is vanishing. Then (3.85) 2yields
Fig. 3.5: Mohr’s circle
tan2ϕ0=2τxy
σx−σy. (3.87)
3.2 Conservation of momentum 59
Certainly, this corresponds to the point of intersection of the circle with the line τn=0.
The values of normal stresses for this angle are
σ(1),(2)=σx+σy
2±radicalBiggparenleftbiggσx−σy
2parenrightbigg2
+τ2xy, (3.88)
σ(1)= maxσn, σ(2)=minσn,
It follows as well from the Mohr circle that the maximum shear stresses are equal to
the radius of the circle
maxτn=radicalBiggparenleftbiggσx−σy
2parenrightbigg2
+τ2xy≡σ(1)−σ(2)
2, (3.89)
and they appear on the plane which forms angles π/4and3π/4with principal directions.
Let us mention that a similar construction can be also made fo r the general three-
dimensional case. Below we present an example of such a const ruction. It is performed
for three principal directions separately. Then for each di rection one can perform a
two-dimensional construction described above. This follo ws from the fact that in the
principal direction shear stress is equal to zero which mean s that the stress distribution
in the remaining directions is two-dimensional. This const ruction is useful, for instance,
in motivation of various yield criteria. Applications in ro ck mechanics are discussed by
Jaeger, Cook and Zimerman [6].
⋆We construct Mohr’s circles for the stress tensor
(σij)=
1−9 2
−9 1 2
2 2 16. (3.90)
Principal stresses and corresponding principal direction s are as follows
σ
(1)= 16.3288,n(1)=−0.7024e1−0.7024e2+0.1155e3.
σ(2)= 10.00n(2)=0.7071e1−0.7071e2, (3.91)
σ(3)=−8.3288,n(3)=0.08166e1+0.08166e2+0.9933e3,
The construction of Mohr’s circles is shown in Fig. 3.6. Each circle is constructed
for two-dimensional coordinates on planes perpendicular t o the corresponding principal
direction. For instance, the left circle corresponds to str ess distribution on the plane
perpendicular to n(3). Any state of stresses in an arbitrary cross-section is a poi nt of the
60 Balance of mass and momentum
dashed area.
Fig. 3.6: An example of Mohr’s circles for three-dimensiona l stress
distribution.♣
However, in contrast to the two-dimensional case presented above, this three-dimen-
sional construction does not seem to have any practical bear ing. It shows only that the
most important principal stresses σ(1),σ(2),σ(3)determine the maximum shear stresses asparenleftbigσ(1)−σ(3)parenrightbig/2,parenleftbigσ(2)−σ(3)parenrightbig/2,parenleftbigσ(1)−σ(2)parenrightbig/2and the orientations of planes on which
they act are determined by the angle π/4between the normals to those planes and the
corresponding principal directions.
Chapter 4
Thermodynamics of solids
Continuum mechanics describes not only processes of deform ations caused by the me-
chanical forces but it must account for various nonmechanic al effects which are necessarily
coupled to mechanical processes. For instance, any process in which a dissipation of en-
ergy appears, and such are processes in viscoelastic or plas tic materials, must account
for the nonmechanical transport of energy, for example by co nduction. It is also natural
to include stresses which appear due to changes of temperatu re (the so-called thermal
stresses) or stresses caused by chemical reactions in struc tural elements. These phe-
nomena require some thermodynamical considerations. For t his reason, we present in
this Chapter fundamental elements of continuum thermodyna mics, in particular the first
law, called the principle of conservation of energy and the s econd law, called the entropy
inequality.
Even in the case of purely mechanical processes in which the d issipation does not
appear the energy conservation law may be quite useful as an e xample of some variational
principles of classical elasticity clearly shows. We retur n to these problems later.
4.1 Energy conservation law
We begin from the formulation of the law of the energy conserv ation in the Lagrangian
description. Even though the origin of the subject goes back to the works of Fourier at
the beginning of XIX century the formulation of this law can b e found first in the work
of J. R. Mayer in 1842. However the real modern development in this field began at the
end of XIX century with works of Maxwell, Boltzmann and many o thers.
The classical systems without the so-called internal degre es of freedom are charac-
terized by the total energy consisting of two contributions : the internal energy and the
kinetic energy. The first one describes the accumulation of e nergy in the system due to
interactions of particles which change their microstates a s a consequence of deformation
and temperature. If a subsystem is completely isolated from the external world its total
energy remains constant. This is, of course, not the case if f orces acting on the sys-
tem perform working or the contact with other subbodies yiel ds the exchange of energy
61
62 Thermodynamics of solids
caused by the difference of temperature. Bearing all these ag ents in mind, we can write
the energy conservation law for any subbody P⊂B0in the form
d
dtintegraldisplay
Pρ0parenleftbigg
ε+1
2v2parenrightbigg
dV=contintegraldisplay
∂P(−Q·N+tN·v)dS+integraldisplay
Pρ0(b·v+r)dV, (4.1)
whereεdenotes the internal energy density per unit mass of the refe rence configuration
and1
2ρ0v2≡1
2ρ0v·vis the density of the kinetic energy per unit volume of the ini tial
configuration. The surface terms consist of the working of st ressestN·vand of the
nonmechanical transfer of energy per unit reference surfac e and unit time, Q·N, in which
Qis called the heat flux vector. The vectorial form of the heat fl ux (i.e. the linearity with
respect to the normal vector N) is the consequence of the Cauchy Theorem analogous to
this which we have used in the construction of the stress tens ors. The volume integral on
the right-hand side describes the supply of energy by the wor king of body forces b·vand
the radiation r. The last contribution plays no role for solids as the supply of energy in
the form of radiation is essential only on boundaries of soli ds. Therefore we shall neglect
it in further considerations.
The transformation to the local form requires the same steps as in the case of mo-
mentum conservation law. Bering the relation (3.29) in mind , we obtain for almost all
points of the body B0
ρ0∂
∂tparenleftbigg
ε+1
2v2parenrightbigg
+DivparenleftBig
Q−PTvparenrightBig
=ρ0b·v. (4.2)
Differentiation of the kinetic energy and power of stresses y ields
ρ0∂ε
∂t+DivQ+v·parenleftbigg
ρ0∂v
∂t−DivPparenrightbigg
−P·Gradv=v·(ρ0b).
Bearing the momentum conservation (3.31) in mind we obtain
ρ0∂ε
∂t+DivQ=P·Gradv, (4.3)
i.e.ρ0∂ε
∂t+∂QK
∂XK=PkK∂vk
∂XK≡PkK∂FkK
∂t.
This is the so-called equation of balance of internal energy . Due to the working of stresses
on the right-hand side it is not a conservation law.
On a singular surface the conservation of energy yields a con dition important for
contact problems — boundary conditions, phase transformat ions, etc. The same procedure
which we have used for the conservation of mass and momentum l eads to the following
local relation
ρ0Ubracketleftbiggbracketleftbigg
ε+1
2v2bracketrightbiggbracketrightbigg
−bracketleftBigbracketleftBig
Q−PTvbracketrightBigbracketrightBig
·N=0, (4.4)
at each point of the singular surface. In a particular case of the continuous velocity, the
relation (3.46) yields immediately
ρ0U[[ε]]−[[Q]]·N=0, (4.5)
4.1 Energy conservation law 63
i.e. on material surfaces on which U=0the heat fluxQ·Nis continuous and this yields
an important boundary condition commonly used, for instanc e, in physics of structures.
Otherwise the relation (4.5) plays an important role in the t heory of phase transforma-
tions.
Performing straightforward transformation we can write th e above equations in the
Eulerian form. The equation (4.1) becomes
d
dtintegraldisplay
Ptρparenleftbigg
ε+1
2v2parenrightbigg
dVt=integraldisplay
PtdivparenleftBig
−J−1FQ+parenleftBig
J−1FPTparenrightBig
vparenrightBig
dVt+integraldisplay
Ptρ(b·v+r)dVt,
(4.6)
where we have used the Gauss Theorem and the Euler-Piola-Jac obi identities (2.67).
Obviously
q=J−1FQ, (4.7)
i.e.qk=J−1FkKQK,
is the current value of the heat flux vector which describes th e nonmechanical transfer
of energy per unit current surface and unit time.
Bearing the relation (3.34) for Cauchy stresses in mind, we o btain
d
dtintegraldisplay
Ptρparenleftbigg
ε+1
2v2parenrightbigg
dVt=integraldisplay
Ptdiv(−q+T·v)dVt+integraldisplay
Ptρ(b·v+r)dVt. (4.8)
Now, as in the previous cases we perform the differentiation w ith respect to time
d
dtintegraldisplay
Ptρparenleftbigg
ε+1
2v2parenrightbigg
dVt=integraldisplay
Pt∂
∂tbracketleftbigg
ρparenleftbigg
ε+1
2v2parenrightbiggbracketrightbigg
dVt+contintegraldisplay
∂Ptρparenleftbigg
ε+1
2v2parenrightbigg
v·ndSt.(4.9)
Accounting for the conservation of mass (3.12) we can transf orm this relation to the
following local form
ρ∂
∂tparenleftbigg
ε+1
2v2parenrightbigg
+ρ(v·grad)parenleftbigg
ε+1
2v2parenrightbigg
=
=div(−q+T·v)+ρ(b·v+r),
i.e.ρ∂
∂tparenleftbigg
ε+1
2v2parenrightbigg
+ρvk∂
∂xkparenleftbigg
ε+1
2v2parenrightbigg
= (4.10)
=∂
∂xk(−qk+σklvl)+ρ(bkvk+r).
This is the local form of the first law of thermodynamics, i.e. the law of conservation of
energy.
As in the case of the Lagrangian description we can apply the l aw of conservation of
64 Thermodynamics of solids
momentum (3.38). Then it follows
ρparenleftbigg∂ε
∂t+v·gradεparenrightbigg
+divq=T·(gradv)+ρr, (4.11)
i.e.ρparenleftbigg∂ε
∂t+vk∂ε
∂xkparenrightbigg
+∂qk
∂xk=σkl∂vk
∂xl+ρr.
This is the Eulerian form of the balance equation of internal energyε. As before, it is
not the conservation law due to the presence of the stress pow er∂σkl(∂vk/∂xl)which,
as it is said in physics, does not have a divergence form.
Similarly to the previous considerations we can construct t he energy conservation law
on singular surfaces in the Eulerian description. We obtain the following counterpart of
the Lagrangian relation (4.4)
ρ(v·n−c)bracketleftbiggbracketleftbigg
ε−1
2v2bracketrightbiggbracketrightbigg
+[[q−Tv]]·n=0, (4.12)
where the mass balance (3.23) has been used. In a particular c ase of ideal fluids one can
transform the last contribution in the following way
[[Tv]]·n=−[[pv·n]]=ρ(v·n−c)bracketleftbiggbracketleftbiggp
ρbracketrightbiggbracketrightbigg
,
where we have assumed [[v]]=0i.e.[[p]]=0. Consequently
r=[[h]]=−[[q]]·n
ρ(v·n−c), h=ε+p
ρ, (4.13)
wherehis called the specific enthalpy and rdenotes the so-called latent heat. This
notion plays an important role in the theory of phase transfo rmations (e.g. evaporation,
condensation, melting, etc.) and chemical reactions (e.g. combustion).
4.2 Second law of thermodynamics
The first traces of the second law of thermodynamics can be fou nd even in the works
of Fourier whose relation for the heat flux was constructed at the end of XVIII century
(published in 1808 and republished in part in his book: Théorieanalytiquedelachaleur
in 1822) in such a way that the heat transfer was possible only from hotter to colder
areas of the body otherwise not loaded. S. Carnot in 1824 cons tructed a procedure for
the determination of the efficiency of heat engines which was d irectly related to the second
law of thermodynamics. The most essential step was done by L. Boltzmann whose works
in years 1868-1872 yielded the famous H-Theorem. This theor em which corresponds to
the modern entropy inequality shows that the macroscopic ir reversibility can be reflected
by a single scalar function. The proof of Boltzmann was done f or ideal gases and it
was based on the hypothesis that macroscopic modelling alwa ys enhances an element of
4.2 Second law of thermodynamics 65
probability. For the details of the motivation of the modern form of the second law of
thermodynamics we refer to the book of K. Wilmanski [22].
In these notes we do not need to go into any details of thermody namics. The reference
to the second law will be made occasionally but we shall not pr esent any details of the
strategy of constructing thermodynamic models. In this Cha pter we demonstrate this
strategy on the example of an ideal fluid in order to explain so me basic notions.
The construction of nonequilibrium thermodynamics is base d on the assumption of the
existence of an entropy function which is a constitutive sca lar satisfying in the Lagrangian
description the balance law of the following form
d
dtintegraldisplay
Pρ0ηdV+contintegraldisplay
∂PH·NdS=integraldisplay
PˆηdV, (4.14)
for any subbodyP⊂B0whereηis the specific entropy, His the entropy flux and ˆηis
the entropy production density. It is assumed that for every process in the system the
entropy production is nonnegative for any subbody P⊂B0
integraldisplay
PˆηdV≥0. (4.15)
This formulation of the second law of thermodynamics has two features. First of all
the effect of radiation is neglected. We have already mention ed that the energy radiation
has no practical bearing and the same assumption is made for t he entropy. Secondly, the
structure of balance law (4.14) is such that surfaces have no contributions to the entropy
production. This may not be the case and it is assumed here onl y for simplicity.
For many models of classical continuum thermodynamics one c an prove that the
entropy fluxHand the heat flux Qare proportional
H=Q
T, (4.16)
whereTis the absolute temperature. In many systems of practical im portance, such as
mixtures, this relation does not hold (e.g. [22]). However, it is sufficient for our purposes.
Then the second law can be written in the form
d
dtintegraldisplay
Pρ0ηdV+contintegraldisplay
∂PQ·N
TdS≥0, (4.17)
which is called Clausius-Duhem inequality.
We can easily construct its local counterparts
ρ0∂η
∂t+DivparenleftbiggQ
Tparenrightbigg
≥0in regular points of B0, (4.18)
and this is called the entropy inequality as well as
ρ0U[[η]]−bracketleftbiggbracketleftbiggQ·N
Tbracketrightbiggbracketrightbigg
=0 in points of singular surfaces. (4.19)
66 Thermodynamics of solids
As before, we can transform these laws to the Eulerian descri ption. Then they have
the form
ρparenleftbigg∂η
∂t+(v·grad)ηparenrightbigg
+divparenleftBigq
TparenrightBig
≥0in regular points of Bt, (4.20)
and
ρ(v·n−c)[[η]]+bracketleftBigbracketleftBigq·n
TbracketrightBigbracketrightBig
=0 in points of singular surfaces. (4.21)
The last relation shows that indeed singular surfaces descr ibed by the second law
following from the balance law (4.14) do not produce entropy . An extension of thermo-
dynamics on processes in which it is not the case is complicat ed and not much has been
done in this direction. However, a particular case of (4.21) plays an important role in
the theory of phase transformations in spite of their irreve rsibility. If we assume that the
velocity is continuous [[v]]=0, and, additionally, that the temperature does not suffer a
jump either, [[T]]=0, then we have
ρ(v·n−c)bracketleftbiggbracketleftbigg
ψ+p
ρbracketrightbiggbracketrightbigg
=0, ψ=ε−Tη, (4.22)
whereψis the so-called Helmholtz free energy function. This relat ion for surfaces sepa-
rating two phases yields the equation for phase equilibrium line. In a particular case of
evaporation and condensation it leads to the so-called Maxw ell construction.
As we indicated above the entropy inequality must hold only f or real processes in
systems. We explain this limitation on a simple example of an ideal fluid.
⋆In order to see the consequences of the second law of thermody namics, we have
to construct field equations for a chosen set of fields. In the c ase of ideal fluids these
fields are the mass density ρ(x,t),velocityv(x,t)and temperature T(x,t). They are
described by the mass, momentum and energy conservation equ ations
∂ρ
∂t+div(ρv)=0,
ρparenleftbigg∂v
∂t+(v·grad)vparenrightbigg
=−gradp, (4.23)
ρparenleftbigg∂ε
∂t+(v·grad)εparenrightbigg
+divq=−pdivv,
where the Cauchy stress tensor is reduced to the pressure p=−1
3trTasT=−p1. The
above set becomes the set of field equations if we define additi onallyp,ε,qin terms of
ρ,v,Tand their derivatives. For ideal fluids these constitutive r elations have the form
p=p(ρ,T), ε=ε(ρ,T),q=−KTgradT, (4.24)
whereKTis the so-called heat conductivity. The relation for the hea t flux is called the
Fourier relation of heat conduction.
The entropy inequality (4.20), i.e.
ρparenleftbigg∂η
∂t+(v·grad)ηparenrightbigg
+divparenleftBigq
TparenrightBig
≥0, η=η(ρ,T), (4.25)
4.2 Second law of thermodynamics 67
must hold for all solutions of the set (4.23) with constituti ve relations (4.24). It means
that on the class of solutions of the entropy inequality we im pose constraints in the
form of field equations. Such constraints can be eliminated i n the same way as we do
for problems of mechanics with constraints, i.e. by means of Lagrange multipliers. This
technique is now commonly used in continuum thermodynamics (e.g. [11], [21], [22]).
In our simple example we can eliminate constraints directly . As the derivatives of the
velocity∂v/∂tandgradvdo not enter the entropy inequality, the laws of mass and
momentum conservation do not restrict the class of solution of this inequality. Hence,
we have to account only for the energy conservation. We do so b y eliminating the heat
flux. It follows
ρparenleftbigg∂ψ
∂t+(v·grad)ψparenrightbigg
+ηparenleftbigg∂T
∂t+(v·grad)Tparenrightbigg
− (4.26)
−p
ρparenleftbigg∂ρ
∂t+(v·grad)ρparenrightbigg
+1
Tq·gradT≤0,
where, as already indicated in (4.22),
ψ=ε−Tη=ψ(ρ,T), (4.27)
denotes the Helmholtz free energy function and we have used t he mass balance equation
to eliminate divv=(∂ρ/∂t+v·gradρ)/ρ. The chain rule of differentiation yields
∂ψ
∂t=∂ψ
∂ρ∂ρ
∂t+∂ψ
∂T∂T
∂t, (4.28)
and similarly for gradψ. The contributions containing the derivatives ∂ρ/∂t,∂T/∂t
are linear with respect to these derivatives. As they are not constraint anymore and,
consequently, can be chosen arbitrarily, their coefficients must be zero in order to fulfil
the inequality. This yields the following results
p=ρ2∂ψ
∂ρ, η=−∂ψ
∂T⇒ε=ψ−T∂ψ
∂T, (4.29)
D=−q·gradT≥0⇒KT≥0.
The identities for p,η,εshow that we need only a constitutive relation for the Helmho ltz
free energy ψin order to reproduce the remaining relations. For this reas on, such func-
tions are called thermodynamical potentials. Simultaneou sly, the entropy inequality is
reduced to the so-called residual inequality which restric ts the functionDcalled the dis-
sipation function. In our simple case it yields the conditio n for the heat conduction which
is equivalent to Fourier’s assumption on the flow of energy in the heat conductor from
hotter to colder regions. In irreversible mechanical proce sses the dissipation is related to
the viscosity (viscoelastic materials) and to the plastic w orking (viscoplastic materials).
Let us complete this example with a relation which follows fr om the thermodynamic
identities. We have
dψ=dε−ηdT−Tdη=∂ψ
∂TdT+∂ψ
∂ρdρ=−ηdT+p
ρ2dρ⇒
⇒dη=1
Tparenleftbigg
dε−p
ρ2dρparenrightbigg
. (4.30)
68 Thermodynamics of solids
This is the so-called Gibbs equation for ideal fluids. ♣
Chapter 5
Elastic materials
Relations which we presented in previous Chapters describe properties of any continuous
system. In this sense they are universal. However, in order t o find the behaviour of
a particular material system they are not sufficient. We have t o perform the so-called
closure which means that we have to add certain relations whi ch yield field equations for
a chosen set of fields. Together with initial and boundary con ditions these field equations
form a mathematical problem of partial differential equatio ns. Solutions of the latter may
be analytical and we show some of them in these notes or they ma y be approximations
following, for example, from numerical procedures. This pr oblem shall not be considered
in this booklet.
We begin the demonstration of the closure procedure with a cl ass of materials called
elastic. In the next Subsection we present briefly equations of nonlinear elasticity and
then we discuss extensively linear problems for isotropic m aterials.
5.1 Non-linear elasticity
The fundamental field which we want to find in continuum mechan ics is the function
of motionf. For the so-called elastic materials it is the only unknown fi eld as thermal
problems are ignored. This means that the temperature is ass umed to be constant,
processes are isothermal.
The governing equation for the function of motion follows fr om the momentum con-
servation (3.31), i.e.
ρ0∂v
∂t=DivP+ρ0b,v=∂f
∂t,x=f(X,t),P=P(X,t),X∈B0,(5.1)
where the body force b(X,t)is assumed to be given.
In order to transform (5.1) into the field equation for fwe have to specify the Piola-
Kirchhoff stress tensor P. We do so with the help of the second law of thermodynamics.
Elimination of the heat flux contribution DivQby means of the energy balance (4.3) and
the assumption of the constant temperature yields the condi tion that for all isothermal
69
70 Elastic materials
processes the following inequality must be satisfied
ρ0∂ψ
∂t≤P·Gradv, ψ=ε−Tη. (5.2)
We now make the basic constitutive assumption which defines t he class of nonlinear
elastic materials. Namely, we assume that the Helmholtz fre e energy function ψdepends
on the motion of continuum solely through the deformation gr adient
ψ=ψ(F). (5.3)
It means that, for instance, rates of deformation do not have any influence on the free
energy. Substitution of this assumption in the inequality ( 5.2) yields
parenleftbigg
ρ0∂ψ
∂F−Pparenrightbigg
·∂F
∂t≤0, (5.4)
and this condition should hold for all derivatives ∂F/∂t. Consequently, we have to require
P=ρ0∂ψ
∂F, (5.5)
and the inequality (5.4) is identically satisfied as equalit y. This means that the dissipation
in such processes is zero, i.e. all processes in elastic mate rials are reversible.
Many applications of such a model are based on the isotropy as sumption. It means
that reactions of the material on a given external loading ar e independent of the ori-
entation of a sample. Simultaneously, we require that local rotations do not influence
the reaction of the material. It means that the Helmholtz fre e energy depends on the
deformation gradient F=RUin such a way that Rdoes not appear in the constitu-
tive relation. Hence, we can replace the dependence on Fby the dependence on the
right Cauchy-Green tensor C=FTF=U2. Simultaneously, the isotropy of the material
means that the constitutive relation should not change by an arbitrary change of the
reference coordinates. This is possible if the constitutiv e dependence of a scalar function
onCis reduced to the dependence on the invariants of C. Finally, we have
ψ=ψ(I,II,III), I=trC, II=1
2parenleftbigI2−trC2parenrightbig, III=detC.(5.6)
Substitution in (5.5) and the chain rule of differentiation y ield
P= 2ρ0Fparenleftbigg∂ψ
∂I∂I
∂C+∂ψ
∂II∂II
∂C+∂ψ
∂III∂III
∂Cparenrightbigg
=
= 2ρ0Fparenleftbigg∂ψ
∂I1+∂ψ
∂II(I1−C)+∂ψ
∂IIIIIIC−1parenrightbigg
=
= 2ρ0parenleftbigg∂ψ
∂IB+∂ψ
∂IIparenleftbigIB−B2parenrightbig+∂ψ
∂IIIIII1parenrightbigg
F−T, (5.7)
where, for convenience, we have used the left Cauchy-Green t ensor, defined by the relation
(2.37):B=FFT.This is equivalent to Cbecause both deformation measures CandB
5.2 Linear elasticity, isotropic and anisotropic material s 71
have the same invariants (compare (2.38)). Now, using the de finition (3.34) of the Cauchy
stressT=J−1PFTwe obtain
T=/beth01+/beth1B+/beth−1B−1, (5.8)
where
/beth0= 2ρparenleftbigg
II∂ψ
∂II+III∂ψ
∂IIIparenrightbigg
, (5.9)
/beth1= 2ρ∂ψ
∂I,/beth−1=−2ρIII∂ψ
∂II, ρ=ρ0J−1≡ρ0√
III,
(compare (3.7)). The coefficients /beth0,/beth1,/beth−1are called elasticities or response coefficients
and they are functions of invariants I,II,III . The relation (5.8) defines the so-called
compressible Mooney-Rivlin material. Many other constitu tive relations for non-linear
elastic materials are presented, for instance, in [2], [14] or [22]. Their main applications
serve the purpose of description of such materials as rubber , many polymeric materials,
biological tissues, etc. We shall not discuss them any furth er in these notes.
5.2 Linear elasticity, isotropic and anisotropic mate-
rials
5.2.1 Governing equations
Let us summarize geometrical and dynamic relations for a lin ear model which we have
presented in Chapters 2 and 3.
As indicated the convenient way to describe the motion of the linear material is
through the displacement field uwhich is the function of Lagrangian coordinates and
time. This is the so-called displacement approach. As in a li near model we do not dis-
tinguish between Lagrangian and Eulerian reference system s, the displacement function
which is the main field of the linear elasticity is the followi ng sufficiently smooth function
u=u(x,t)i.e.uk=uk(x1,x2,x3,t),u=ukek,x=xkek. (5.10)
This function defines the velocity vand the strain field eof the linear model
v=∂u
∂t,e=1
2parenleftBig
gradu+(gradu)TparenrightBig
, (5.11)
i.e.vk=∂uk
∂t, ekl=1
2parenleftbigg∂uk
∂xl+∂ul
∂xkparenrightbigg
.
In some applications (e.g. theory of acoustic waves) it is co nvenient to introduce the
velocityvand the strain field eas unknown fields instead of the displacement u. Then
these fields must satisfy the following integrability condi tion
∂e
∂t=1
2parenleftBig
gradv+(gradv)TparenrightBig
i.e.∂ekl
∂t=1
2parenleftbigg∂vk
∂xl+∂vl
∂xkparenrightbigg
, (5.12)
72 Elastic materials
which is, obviously, satisfied if the displacement field uis given.
Additionally, the strain field must fulfil the compatibility condition (2.102) which
follows from the Euclidean character of the space of motion, i.e.
ǫijkǫlmn∂2ejm
∂xk∂xn=0. (5.13)
As already indicated there are six independent relations wh ich follow from (5.13). Namely
2∂2e12
∂x1∂x2=∂2e11
∂x2
2+∂2e22
∂x2
1,
2∂2e23
∂x2∂x3=∂2e22
∂x2
3+∂2e33
∂x2
2,
2∂2e13
∂x1∂x3=∂2e11
∂x2
3+∂2e33
∂x2
1,
∂2e11
∂x2∂x3=∂2e12
∂x3∂x1−∂2e23
∂x2
1+∂2e13
∂x1∂x2, (5.14)
∂2e22
∂x1∂x3=∂2e23
∂x1∂x2−∂2e13
∂x2
2+∂2e12
∂x2∂x3,
∂2e33
∂x1∂x2=∂2e13
∂x2∂x3−∂2e12
∂x2
3+∂2e23
∂x1∂x3.
If we substitute the strain-stress relations in these compa tibility conditions we obtain
equations for stresses. If the boundary value problem is als o formulated in stresses then
this set can be solved. This approach is called the stress app roach. We show further
some examples of such a formulation.
In the displacement approach, purely mechanical problems ( isothermal processes)
require the field equation for the displacement u. This follows from the linear form of
the momentum conservation
ρ∂2u
∂t2=divT+ρb, (5.15)
whereρ≈const, provided we specify the Cauchy stress tensor Tin terms of the dis-
placement and its derivatives. As in the nonlinear case, the constitutive dependence of T
is given by a function of the strain field e. Assuming that initial stresses (i.e. stresses in
the configuration in which e=0) are zero the most general linear form of such a relation
is as follows
σkl=cklijeij,T=σijei⊗ej,e=eijei⊗ej, (5.16)
wherecijklare 81 constants ( = 34). However, the symmetry of the Cauchy stresses
σij=σjiand of the strain field eij=ejireduces the number of independent constants
to 21. This can be easily seen in a Voigt notation which is comm only used in the
crystallography. It replaces the components of the second r ank tensors by six-dimensional
vectors
(e11,e22,e33,e23,e13,e12) = (e1,e2,e3,e4,e5,e6), (5.17)
(σ11,σ22,σ33,σ23,σ13,σ12) = (σ1,σ2,σ3,σ4,σ5,σ6).
5.2 Linear elasticity, isotropic and anisotropic material s 73
Then the relation (5.16) can be replaced by the following mat rix relation
σα=Cαβeβ, α,β=1,...,6. (5.18)
One can easily find the correspondence between cijklandCαβwhich we do not quote
here. Obviously, the 6×6matrix(Cαβ)is symmetric which means that it possesses
6+30/2=21 independent components. This is the maximum number of indep endent
material parameters which may appear in the relation (5.16) . Materials which require
this number of constants are called anisotropic. They do not possess any particular
symmetry properties which means that samples cut from such a material in different
directions yield different response to the same external loa ding.
Some particular cases of material symmetry are of practical importance. We call the
material orthotropic if it possesses three orthogonal plan es of symmetry defined by the
base vectors{e1,e2,e3}. Then in this reference system the stress-strain relation r educes
to the following relation in Voigt’s notation
σ1
σ2
σ3
σ4
σ5
σ6
=
C11C12C130 0 0
C12C22C230 0 0
C13C23C330 0 0
0 0 0 C440 0
0 0 0 0 C550
0 0 0 0 0 C66
e1
e2
e3
e4
e5
e6
, (5.19)
i.e. it is described by 9material parameters. The material is transversely isotrop ic if it
is symmetric with respect to a rotation about an axis of symme try. Ife3is such an axis
then in Vogt’s notation the stress-strain relation is as fol lows
σ1
σ2
σ3
σ4
σ5
σ6
=
C11C12C130 0 0
C12C11C130 0 0
C13C13C330 0 0
0 0 0 C440 0
0 0 0 0 C440
0 0 0 0 01
2(C11−C12)
e1
e2
e3
e4
e5
e6
, (5.20)
i.e. it is described by 5material parameters.
In spite of many anisotropic materials appearing in practic al applications (e.g. wood,
composites, many rock structures) in these notes we concent rate on isotropic materials
which were already investigated in the nonlinear case. This limitation is connected with
technical difficulties.
Linear isotropic elastic material is characterized by two m aterial parameters. For
instance, for such materials, we can write the relation (5.1 6) in the form
T=λ(tre)1+2µei.e.σij=λekkδij+2µeij, (5.21)
i.e.cijkl=λδijδkl+µ(δikδjl+δilδjk),
whereλ,µare the so-called Lamé constants and the relation (5.21) is c alled Hooke’s law.
74 Elastic materials
This law corresponds to the constitutive relation for the He lmholtz free energy
ρψ=1
2T·e=1
2σijeij=1
2parenleftBig
λ(tre)2+2µe·eparenrightBig
=1
2(λ(ekk)(ell)+2µeklekl),(5.22)
Namely, the nonlinear relation (5.5) can be easily transfor med to the thermodynamic
relation of the linear model
T=ρ∂ψ
∂e. (5.23)
⋆We have
T=J−1PFT=J−1ρ0∂ψ
∂FFT=
=ρparenleftbigg∂ψ
∂CKL∂CKL
∂FmMparenrightbigg
FlMem⊗el=
= 2ρ∂ψ
∂CKLFkKδmkδLMFlMem⊗el=
= 2ρFkK∂ψ
∂CKLFlLem⊗el= (5.24)
= 2ρFkK∂ψ
∂EMN∂EMN
∂CKLFlLem⊗el=
=ρFkK∂ψ
∂EMNδMKδNLFlLem⊗el≈ρ∂ψ
∂eklek⊗el.
♣
The Hooke law yields in particular the following relation fo r the volume changes given
in the linear theory by the trace of the strain field, tre,
p=−1
3trT=−Ktre, K=λ+2
3µ, (5.25)
whereKis the so-called compressibility (or bulk) modulus. It is of ten used in soil
mechanics together with G=µand the latter is called the shear (Kirchhoff) modulus.
Substitution of (5.25) in (5.21) yields immediately the fol lowing inverse relations
e=1
2µparenleftbigg
T−λ
3λ+2µ(trT)1parenrightbigg
, (5.26)
i.e.eij=1
2µparenleftbigg
σij−λ
3λ+2µσkkδijparenrightbigg
.
Coefficients1/2µandλ/[2µ(3λ+2µ)]are called compliances. They form the following
isotropic compliance matrix
c′
ijkl=1
2µδikδjl−λ
2µ(3λ+2µ)δijδkl⇒eij=c′
ijklσkl, (5.27)
which is the inverse to the isotropic elasticity matrix cijkl.
5.2 Linear elasticity, isotropic and anisotropic material s 75
The relation (5.26) is usually written in the following expl icit form
e11=1
E(σ11−ν(σ22+σ33)),
e22=1
E(σ22−ν(σ11+σ33)),
e33=1
E(σ33−ν(σ11+σ22)), (5.28)
e12=1
2µσ12, e13=1
2µσ13, e23=1
2µσ23,
and the comparison with (5.26) yields
E=µ(3λ+2µ)
λ+µλ=Eν
(1+ν)(1−2ν)
⇒
ν=λ
2(λ+µ)µ=E
2(1+ν), (5.29)
whereEis called Young (elasticity) modulus and νis the Poisson number. Then it
follows for the compressibility modulus
K=E
3(1−2ν). (5.30)
Values of material parameters are not quite arbitrary and we shall demonstrate various
limits which they have to fulfil as we proceed with the present ation of particular problems.
We shall see, for example that the compressibility modulus Kand the shear modulus
µare nonnegative. It means that, due to (5.29) 4, Poisson’s number is: ν >−1and,
according to (5.29) 3,ν≤0.5. As Poisson’s number ν, by means of (5.28), assigns
the expansion of the material under the loading in the perpen dicular (lateral) direction
(e.g.σ22=σ33=0,σ11<0⇒e22=e33=−νσ11/E;e22,e33would be expected to
be positive for positive E) it is often speculated that ν >0. It has been shown that it
must not be the case1.
1e.g.R.LIascIkscIescIssc; Foam structures with a negative Poisson’s ratio, Science 235:1038—1040, 1987,
G.W.MIiscIlscItscIoscInsc; Composite materials with Poisson’s ratios close to -1. Journal of the Mechanics and
Physics of Solids, 40(5):1105—1137, 1992.
76 Elastic materials
In Fig. 5.1. we show a two-dimensional structure2which possesses the property ν <0.
Table:Elasticconstantsforchosenmaterialsattemperature 200C.
λbracketleftbig
1010Pabracketrightbig
µbracketleftbig
1010Pabracketrightbig
Ebracketleftbig
1010Pabracketrightbig
νKbracketleftbig
1010Pabracketrightbig
aluminium 5.63 2.60 6.98 0.34 7.36
brass 8.90 3.60 9.76 0.36 11.30
copper 10.63 4.55 12.29 0.35 13.66
duralumin 5.78 2.70 7.24 0.34 7.58
ice (−40C)0.70 0.36 0.96 0.33 0.94
iron 10.49 8.20 21.00 0.28 15.96
lead 4.07 0.57 1.64 0.44 4.45
marble 4.15 2.70 7.04 0.30 5.95
plexiglass 0.28 0.12 0.32 0.35 0.36
polystyrene 0.28 0.12 0.32 0.35 0.36
steel 11.78 8.0 20.76 0.30 17.11
Fig. 5.1: A structure modelled by a linear elastic continuum with the
negative Poisson number ν
In the other limit ν=0.5there are no volume changes
tre=1−2ν
EtrT⇒ν=0.5tre=0andK=∞, (5.31)
i.e.J=1andρ=ρ0. Such materials are called incompressible.
2U.D.LIascIrscIsscIescInsc,O.SIiscIgscImscIuscInscIdsc,S.BIoscIuscIwscIsscItscIrscIasc; Design and fabrication of compliant micro-mechanisms
and structures with negative Poisson’s ratio, JournalofMicroelectromechanicalSystems, 6:99—106, 1997.
5.2 Linear elasticity, isotropic and anisotropic material s 77
5.2.2 Navier-Cauchy equations, Green functions, displace ment
potentials
Substitution of the Hooke law (5.21) in the momentum balance (5.15) yields immediately
the governing equations for the displacement u
ρ∂2u
∂t2= (λ+µ)graddivu+µdivgradu+ρb≡ (5.32)
≡(λ+µ)gradtre+µ∇2u+ρb,
or in Cartesian coordinates
ρ∂2uk
∂t2=(λ+µ)∂2ul
∂xk∂xl+µ∂2uk
∂xl∂xl+ρbk. (5.33)
These are Navier-Cauchy equations. They are also called Lam é equations.
⋆In many practical problems it is convenient to use curviline ar coordinates. For the
purpose of these notes we need only cylindrical and spherica l coordinates. We shall not
go into any details and present below the basic relations for these two systems and for
the so-called physical components of the quantities. Let us only briefly explain the latter
notion.
We assume that curvilinear coordinates are introduced in th e three-dimensional Euclid-
ean space, i.e.
yα=yα(x1,x2,x3), α=1,2,3,⇒xk=xkparenleftbigy1,y2,y3parenrightbig, k=1,2,3,(5.34)
are equations of parametric lines. Then the covariant and co ntravariant base vectors are
given by the following relations
gα=∂r
∂yα,r=xkek,gα·gβ=δα
β, (5.35a)
i.e.gαis tangent to the yα-parametric line, and gαis perpendicular to the parametric
surfaceyα=const.
Both cylindrical and spherical coordinates are orthogonal , i.e. the metric tensor
gαβ=gα·gβ, (5.36)
is diagonal. One can introduce unit base vectors
e(α)=gα1√gαα(do not add!) ,e(α)·e(β)=δαβ. (5.37)
Then the displacement vector uand the deformation tensor ehave the following compo-
nents
u=u(α)e(α), uα=u·gα, u(α)=uα√gαα(do not add!) , (5.38)
e=e(α)(β)e(α)⊗e(β), eαβ=gα·egβ, e(α)(β)=eαβ√gαα√gββ(do not add!) ,
78 Elastic materials
which are called physical components.
Differentiation of an arbitrary vector, say — the displaceme nt vectoru, yields
∂u
∂yα=∂
∂yα(uµgµ)=∂uµ
∂yαgµ+uµ∂gµ
∂yα=parenleftbigg∂uµ
∂yα+Γµ
αβuβparenrightbigg
gµ, (5.39)
whereΓµ
αβ=gµ·∂gβ
∂yα≡gµ·∂2r
∂yα∂yβ,∂uµ
∂yα+Γµ
αβuβ=∇αuµ,
whereΓµ
αβare called Christoffel symbols and ∇αis the covariant derivative of the vector.
Similar relations follow for tensors of the second order.
In the relations quoted below for cylindrical and spherical coordinates we have re-
placed partial derivatives of the Cartesian coordinates by covariant derivatives of the
corresponding curvilinear coordinates and components of t he vectors and tensors are
physical components in the corresponding coordinate syste ms.♣
⋆1) Cylindrical coordinates .
These coordinates are defined by the following transformati on of Cartesian coordinates
x1=rcosθ, x2=rsinθ,
x3=z,r=eixi,
r=y1=radicalBig
(x1)2+(x2)2, θ=y2=arctanparenleftbiggx2
x1parenrightbigg
,
z=y3=x3.
(5.40)
The corresponding unit base vectors are
er=cosθe1+sinθe2,eθ=−sinθe1+cosθe2,ez=e3. (5.41)
Then the strain function eis as follows
err=∂ur
∂r, eθθ=ur
r+1
r∂uθ
∂θ, ezz=∂uz
∂z,
erθ=1
2parenleftbigg∂uθ
∂r−uθ
r+1
r∂ur
∂θparenrightbigg
, eθz=1
2parenleftbigg1
r∂uz
∂θ+∂uθ
∂zparenrightbigg
, (5.42)
ezr=1
2parenleftbigg∂ur
∂z+∂uz
∂rparenrightbigg
.
The momentum balance equations become
ρ∂2ur
∂t2=∂σrr
∂r+1
r∂σrθ
∂θ+∂σrz
∂z+σrr−σθθ
r+ρbr,
ρ∂2uθ
∂t2=∂σrθ
∂r+1
r∂σθθ
∂θ+∂σθz
∂z+ρbθ, (5.43)
ρ∂2uz
∂t2=∂σrz
∂r+1
r∂σθz
∂θ+∂σzz
∂z+ρbz.
5.2 Linear elasticity, isotropic and anisotropic material s 79
The displacement equations are in this case
ρ∂2ur
∂t2=µparenleftbigg
∇2ur−ur
r2−2
r2∂uθ
∂θparenrightbigg
+
+(λ+µ)∂
∂rbracketleftbigg1
r∂
∂r(rur)+1
r∂uθ
∂θ+∂uz
∂zbracketrightbigg
+ρbr,
ρ∂2uθ
∂t2=µparenleftbigg
∇2uθ−uθ
r2+2
r2∂ur
∂θparenrightbigg
+ (5.44)
+(λ+µ)1
r∂
∂θbracketleftbigg1
r∂
∂r(rur)+1
r∂uθ
∂θ+∂uz
∂zbracketrightbigg
+ρbθ,
ρ∂2uz
∂t2= (λ+µ)∂
∂zbracketleftbigg1
r∂
∂r(rur)+1
r∂uθ
∂θ+∂uz
∂zbracketrightbigg
+ρbz.
In addition, the Laplace operator in cylindrical coordinat es has the following form
∇2=∂2
∂r2+1
r∂
∂r+1
r2∂2
∂θ2+∂2
∂z2, (5.45)
while the volume changes are
tre=1
r∂
∂r(rur)+1
r∂uϕ
∂ϕ+∂uz
∂z. (5.46)
♣
⋆2) Spherical coordinates.
We have here
x1=rsinθcosϕ, x2=rsinθsinϕ,
x3=rcosθ,r=xiei,
r=y1=√xkxk, ϕ=y2=arctanparenleftbiggx2
x1parenrightbigg
,
θ=y3=arccosx3√xkxk,(5.47)
and the corresponding base vectors
er= sinθcosϕe1+sinθsinϕe2+cosθe3,
eϕ=−sinϕe1+cosϕe2, (5.48)
eθ= cosθcosϕe1+cosθsinϕe2−sinθe3.
80 Elastic materials
The strain function ehas the form
err=∂ur
∂r, eϕϕ=1
rsinθ∂uϕ
∂ϕ+ur
r+uθ
rcotθ,
eθθ=1
r∂uθ
∂θ+ur
r, erϕ=1
2parenleftbigg1
rsinθ∂ur
∂ϕ−uϕ
r+∂uθ
∂rparenrightbigg
, (5.49)
erθ=1
2parenleftbigg1
r∂ur
∂θ−uθ
r+∂uθ
∂rparenrightbigg
, eϕθ=1
2parenleftbigg1
r∂uϕ
∂θ−uϕ
rcotθ+1
rsinθ∂uθ
∂ϕparenrightbigg
.
The momentum balance equations are as follows
ρ∂2ur
∂t2=∂σrr
∂r+1
rsinθ∂σrϕ
∂ϕ+1
r∂σrθ
∂θ+2σrr−σϕϕ+σrθcotθ
r+ρbr,
ρ∂2uϕ
∂t2=∂σrϕ
∂r+1
rsinθ∂σϕϕ
∂ϕ+1
r∂σϕθ
∂θ+3σrϕ+2σϕθcotθ
r+ρbϕ,(5.50)
ρ∂2uθ
∂t2=∂σrθ
∂r+1
rsinθ∂σϕθ
∂ϕ+1
r∂σθθ
∂θ+3σrθ+(σθθ−σϕϕ)
r+ρbz.
The displacement equations are in this case
ρ∂2ur
∂t2=µbraceleftbigg
∇2ur−2
r2bracketleftbigg
ur+1
sinθ∂
∂θ(uθsinθ)+1
sinθ∂uϕ
∂ϕbracketrightbiggbracerightbigg
+
+(λ+µ)∂tre
∂r+ρbr,
ρ∂2uϕ
∂t2=µbraceleftbigg
∇2uϕ+2
r2sinθbracketleftbigg∂ur
∂ϕ+∂uθ
∂θcotθ−uϕ
2sinθbracketrightbiggbracerightbigg
+ (5.51)
+(λ+µ)1
rsinθ∂tre
∂ϕ+ρbϕ,
ρ∂2uθ
∂t2=µbraceleftbigg
∇2uθ−2
r2bracketleftbigg∂uθ
∂θ−uθ
2sin2θ−∂uϕ
∂ϕcosθ
sin2θbracketrightbiggbracerightbigg
+
+(λ+µ)1
r∂tre
∂ϕ+ρbθ,
where the Laplace operator has the form
∇2=1
r2∂
∂rparenleftbigg
r2∂
∂rparenrightbigg
+1
r2sinθ∂
∂θparenleftbigg
sinθ∂
∂θparenrightbigg
+1
r2sinθ∂2
∂ϕ2, (5.52)
and the volume changes are
tre=1
r2sinθbracketleftbigg∂
∂rparenleftbigurr2sinθparenrightbig+∂
∂θ(uθrsinθ)+∂
∂ϕ(uϕr)bracketrightbigg
. (5.53)
♣
The set of displacement equations can be solved provided we s pecify initial and bound-
ary conditions. The latter may be given in terms of displacem ents or their derivatives.
5.2 Linear elasticity, isotropic and anisotropic material s 81
In Fig. 5.2. we show a domain Bton which the equation (5.33) is defined and whose
part of the boundary ∂Bσ
tis loaded by a given traction tnand on the remaining part of
the boundary ∂Bu
t, ∂Bσ
t∪∂Bu
t=∂Bt, the displacement ubis given.
Hence
u(x,t)=ub(x,t)forx∈∂Bu
t, (5.54)
λ(divu)n+µparenleftBig
gradu+(gradu)TparenrightBig
n(x,t)=tn(x,t)forx∈∂Bσ
t,
i.e.
uk(x,t)=ub
k(x,t)forx∈∂Bu
t, (5.55)
λ∂ul
∂xlnk+µparenleftbigg∂uk
∂xl+∂ul
∂xkparenrightbigg
nl(x,t)=tn
k(x,t)forx∈∂Bσ
t.
In the sequel we show a few typical examples of this boundary v alue problem.
Fig. 5.2: Boundary conditions of linear elasticity
One of the important general features of the set (5.32) is its hyperbolicity. We shall
not go into a detailed mathematical definition of this notion . We rather use its physical
interpretation that hyperbolic systems describe the propa gation of waves of weak discon-
tinuity (acoustic waves). We shall show this property farth er in a few different ways but
it can also be immediately seen when we use Helmholtz decompo sition (1.57)
u=gradϕ+rotψ, (5.56)
i.e.uk=∂ϕ
∂xk+ǫklm∂ψm
∂xl,
82 Elastic materials
whereϕ,ψare scalar and vector displacement potentials. Substituti on in (5.33) yields
∂
∂xkbracketleftbigg
ρ∂2ϕ
∂t2−(λ+2µ)∇2ϕbracketrightbigg
+ǫkpq∂
∂xpbracketleftBigg
ρ∂2ψq
∂t2−µ∇2ψqbracketrightBigg
=0, (5.57)
∇2=∂2
∂xm∂xm,
if we neglect for simplicity the body forces. The contributi ons in square brackets should
be zero independently as a differentiation of (5.57) shows. C onsequently
∂2ϕ
∂t2=c2
L∇2ϕ, c2
L=λ+2µ
ρ=K+4
3µ
ρ, (5.58)
∂2ψ
∂t2=c2
T∇2ψ, c2T=µ
ρ<c2
L.
The inequality follows for K >0,µ >0which we justify further. These are two linear
wave equations of the second order. In the one-dimensional s pecial case they have the
following form
parenleftbigg∂
∂t−cL∂
∂x1parenrightbiggparenleftbigg∂ϕ
∂t+cL∂ϕ
∂x1parenrightbigg
= 0, (5.59)
parenleftbigg∂
∂t−cT∂
∂x1parenrightbiggparenleftbigg∂ψ
∂t+cT∂ψ
∂x1parenrightbigg
= 0,
with the following d’Alambert solutions (e.g. [21])
ϕ=ϕ−(x1+cLt)+ϕ+(x1−cLt), (5.60)
ψ=ψ−(x1+cTt)+ψ+(x1−cTt),
whereϕ−,ϕ+,ψ−,ψ+are arbitrary twice differentiable functions, i.e. they ind eed de-
scribe waves with speeds of propagation cLandcT. As we show further the scalar
potentialϕdescribes the so-called longitudinal wave, i.e. a wave in wh ich the motion of
particles is in the same direction as the propagation of the w ave. Its speed of propagation
iscL=radicalbig
(λ+2µ)/ρ.The vector potential ψdescribes the so-called transversal wave
with the motion of particles perpendicular to the direction of propagation and its speed
of propagation is cT=radicalbig
µ/ρ.We present properties of these dynamic solutions later in
many details.
Some solutions of the set of displacement equations for the i nfinite medium can be
constructed by means of Green functions. These are function s specifying the displacement
in an arbitrary point in the case of a single force f=fkekacting at the point x=0. This is
the method well-known in many branches of physics as well as s tructural mechanics where
it is called the influence function method [12]. In the static case (i.e. for the acceleration
∂2u/∂t2identically zero) the displacement u(x)can be written in the following form
ui=Gikfk, (5.61)
5.2 Linear elasticity, isotropic and anisotropic material s 83
where
Gik(x)=λ+3µ
8πµ(λ+2µ)parenleftbiggδik
r+λ+µ
λ+3µxixk
r3parenrightbigg
, r=√xpxp. (5.62)
This solution has been found by W. Thomson (lord Kelvin) in 18 48. Once we have
this solution we can find the displacement in an infinite mediu m for an arbitrary set of
loading forces using the superposition. For instance, for t he forcePδ(r)δ(z)acting in
the direction of the z-axis this function yields the following form of the displac ement in
cylindrical coordinates {r,θ,z}
u=P
4πµ√
r2+z2bracketleftbigg1
4(1−ν)rz
(r2+z2)er+parenleftbigg
1−1
4(1−ν)r2
r2+z2parenrightbigg
ezbracketrightbigg
.(5.63)
Hence, the component of the displacement uzin the direction of the force diminishes as√
r2+z2. There is also an additional component urin the radial direction er. Obviously,
the solution is singular in the point r=0,z=0, i.e. in the point of action of the force.
The similar procedure can be applied in the full dynamic case . We obtain
Gij(x,t)=1
4πρbraceleftbigg
δparenleftbigg
t−r
cTparenrightbiggparenleftbiggδij
c2
Tr−xixj
c2
Tr3parenrightbigg
+
+δparenleftbigg
t−r
cLparenrightbiggxixj
c2
Lr3+ (5.64)
+bracketleftbigg
Hparenleftbigg
t−r
cLparenrightbigg
−Hparenleftbigg
t−r
cTparenrightbiggbracketrightbiggt
r3parenleftBig
3xixj
r2−δijparenrightBigbracerightbigg
,
where the Dirac- δof the argument t−r/cTactivates the first contribution when the shear
wave of the speed cTarrives to a chosen point, the Dirac- δof the argument t−r/cLac-
tivates the second contribution, when the longitudinal wav e of the speed cLarrives to a
chosen point, and the Heaviside function contributions HparenleftBig
t−r
cLparenrightBig
=braceleftbigg1fort>r
cL
0fort<r
cL
andHparenleftBig
t−r
cTparenrightBig
=braceleftbigg1fort>r
cT
0fort<r
cTof the third contribution activate this term be-
tween both waves.
Derivation of the above static Green function as well as the d ynamic Green function
can be found in the Appendix. In their derivation we use integ ral Fourier transform
method.
Inspection of the relation (5.64) shows that it consists of c ontributions which possess
different properties when r→0and whenr→∞. In the first case we can neglect the
first two contributions because they are proportional to 1/rin contrast to the last term
which is proportional to 1/r3. Consequently, this term dominates for small r. We call
it the near field approximation. On the other hand, these are t he first two terms which
dominate for large rand we can neglect the last contribution. We call this case th e
far field approximation. We shall use these approximations i n estimates of the action of
dislocations in the last Chapter of this book.
84 Elastic materials
The method of Green function can be also extended on finite dom ains and this method
is also indicated in the Appendix. However, construction of solutions of boundary value
problems for finite domains by means of Green functions requi res a rather involved in-
tegrations. These can be performed numerically but analyti cal solutions can be found
easier using other methods.
An extensive class of methods has been proposed for static pr oblems (compare the
presentation of many examples in the classical books of Timo shenko and Goodier [18] and
Landau and Lifshitz [8]). They lead to solutions of simpler L aplace or Poisson equations
for functions called potentials. We present some of them.
Some elements of the solution by means of one scalar and one ve ctor function can be
found already in the early paper of J. Boussinesq (1878)3,4. It has been fully developed
by P. F. Papkowich (1932) and H. Neuber (1934). Namely, they h ave shown that the
following relation
u=Φ−1
4(1−ν)grad[Φ0+x·Φ], (5.65)
satisfies identically the displacement equations provided the scalar and vector Papkovich-
Neuber potentials, Φ0,Φfulfil Poisson’s equations
∇2Φ0−ρx·b
µ=0,∇2Φ+ρb
µ=0, (5.66)
i.e. forb=0they are harmonic functions. The proof is by substitution.
The procedure of solution is as follows. We solve the equatio ns (5.66) with boundary
conditions formulated in terms of functions Φ0,Φ. These follow either from relations
(5.65) if they are given for displacements on the boundary or from the relations for the
stress vector on the boundary. Then we have to use the followi ng relation for stresses
σij=2µbracketleftbigg∂2Ψ
∂xi∂xj−2(1−ν)parenleftbigg∂Φi
∂xj+∂Φj
∂xiparenrightbigg
−δijν∇2Ψbracketrightbigg
, (5.67)
where
Ψ=Φ0+xkΦk,∇2Ψ=2∂Φk
∂xk, (5.68)
which is the consequence of the Hooke law (5.21).
In many problems it is sufficient to introduce three functions . For instance, for the
half-space we choose Φ0andΦ=(Φ1,Φ2,0). Displacements in the space caused by the
body forces are determined by means of Φ0=0,Φ=(Φ1,Φ2,Φ3).
For axial symmetric cases one applies Boussinesq represent ation. Forb=0, we have
in cylindrical coordinates
ur=∂Ψ
∂r, uz=∂Ψ
∂z−4(1−ν)Φr,Ψ=Φ0+zΦz. (5.69)
3Valentin Joseph Boussinesq, 1842-1929.
4J.BIoscIuscIsscIsscIiscInscIescIsscIqsc; Équilibre d’élasticité d’un solide isotrope sans pesanteu r, supportant différents poids,
C. R. Acad. Sci., Paris, 86, 1260-1263, 1878.
P.F.PIascIpscIkscIoscIvscIiscIcscIhsc; Solution Générale des équations differentielles fondament ales d’élasticité exprimée
par trois fonctions harmoniques, Compt. Rend. Acad. Sci. Paris 195: 513—515 , 1932.
H. NIescIuscIbscIescIrsc; Ein neuer Ansatz zur Lösung räumlicher Probleme der Elastiz itätstheorie, Z. Angew.
Math. Mech. 14: 203—212, 1934.
5.2 Linear elasticity, isotropic and anisotropic material s 85
Another class of potentials was introduced also by J. Boussi nesq and later rediscov-
ered by Somigliana and Galerkin5. This Boussinesq-Somigliana-Galerkin solution has
the form
u=∇2g−1
2(1−ν)graddivg, (5.70)
where
∇2∇2g=−1
µρb, (5.71)
i.e. the vector potential gis biharmonic for b=0.
All these classes give rise to complete solutions of the disp lacement equations.
A different harmonic potential, particularly useful for hal f-space problems, was intro-
duced by E. Trefftz6. Namely
u1=∂Φ
∂x1+λ+µ
µx3∂2Φ
∂x1∂x3,
u2=∂Φ
∂x2+λ+µ
µx3∂2Φ
∂x2∂x3,∇2Φ=0. (5.72)
u3=−λ+2µ
µ∂Φ
∂x3+λ+µ
µx3∂2Φ
∂x2
3.
Fig. 5.3: Boussinesq problem
5J. BIoscIuscIsscIsscIiscInscIescIsscIqsc; Application des potentiels à l’étude de l’équilibre et des m ouvements des solides
élasiques, Paris: Gauthier-Villars, 1885.
C.SIoscImscIiscIgscIlscIiscIascInscIasc; Sulle equazioni della elasticità, Ann. Math. , (2)17, 37.64, 1889.
B.GIascIlscIescIrscIkscIiscInsc; On an investigation of stresses and deformations in elastic isotropic solids (in Russian),
Dokl. Akad. Nauk SSSR , 353-358, 1930.
6E.TIrscIescIfscIfscItscIzsc; Mathematische Elastizitätstheorie , in:Handbuch der Physik, Bd. VI, Berlin, Springer,
1928.
86 Elastic materials
Substitution of these relations in (5.32) for the static cas e and without body forces
yields the identity. By means of this potential we can constr uct the solution of the
Boussinesq problem shown in Fig. 5.3.
The stress tensor in terms of potential Φis given in the form
σ11
2µ=∂2Φ
∂x2
1+λ+µ
µx3∂3Φ
∂x2
1∂x3−λ
µ∂2Φ
∂x2
3,
σ22
2µ=∂2Φ
∂x2
2+λ+µ
µx3∂3Φ
∂x2
2∂x3−λ
µ∂2Φ
∂x2
3,
σ33
2µ=−λ+µ
µ∂2Φ
∂x2
3+λ+µ
µx3∂3Φ
∂x3
3, (5.73)
σ12
2µ=∂2Φ
∂x1∂x2+λ+µ
µx3∂3Φ
∂x1∂x2∂x3,
σ23
2µ=λ+µ
µx3∂3Φ
∂x2∂x2
3,
σ13
2µ=λ+µ
µx3∂3Φ
∂x1∂x2
3.
Consequently, the shear stresses σ23andσ13are zero on the plane x3= 0.Hence,
the potential defined by relations (5.72) can be used only for half-spaces loaded in the
direction perpendicular to this surface.
⋆Now we specify the potential Φdescribing the load in the form of the force Pe3as
indicated in Fig. 5.3. This solution is known as the Boussine sq problem. It is easy to
check that the following form of the potential
Φ=−P
4π(λ+µ)ln(x3+r), r=√xkxk, (5.74)
is a harmonic function, i.e. it satisfies the Laplace equatio n (5.72). Differentiation with
respect tox3yields
∂Φ
∂x3=−P
4π(λ+µ)1
r,∂2Φ
∂x2
3=P
4π(λ+µ)x3
r3, (5.75)
∂3Φ
∂x3
3=P
4π(λ+µ)parenleftbigg1
r3−3x2
3
r5parenrightbigg
.
Substitution in (5.73) 3yields the following relation for the normal stress in x3-direction
σ33=−3P
2πx3
3
r5, r=√xkxk. (5.76)
This component of stresses is zero on the plane x3=0except of the point r=0where it
is singular. However, if we transform stresses to spherical coordinates and integrate over
an arbitrary half-sphere of the radius rit becomes equal to P. In this sense, we satisfy
the boundary conditions.
5.2 Linear elasticity, isotropic and anisotropic material s 87
It is a straightforward calculation to find the displacement . For the vertical component
u3we obtain
u3=−P
4π(λ+µ)1
rparenleftbigg
1−λ+µ
µparenleftbigg
1+x2
3
r2parenrightbiggparenrightbigg
. (5.77)
This function of x3andR=radicalbig
x2
1+x22(i.e.r2=R2+x23) is shown in Fig. 5.4. Units
are arbitrary and we have chosen λ=4.15×1010Pa andµ=2.7×1010Pa. Obviously,
there is a singularity at the point of action of the force r=radicalbig
R2+x2
3=0.
Fig. 5.4: Vertical displacement in the Boussinesq problem a s a function of
vertical distance z=x3from the surface and horizontal distance Rfrom the
axisx3♣
The Boussinesq problem can be also solved by means of another Trefftz potentials
which are defined in the following way
ui=ϕi+x3χi. (5.78)
It is a convenient method for problems of the half-space beca use the function ϕisatisfies
forx3=0the same boundary condition as the displacement ui. Both functions, ϕiand
χi, are harmonic
∇2ϕi=0,∇2χi=0. (5.79)
The function χiis connected to ϕithrough the compatibility condition with the static
displacement equations. Substitution in (5.33) with ∂2ui/∂t2=0,bi=0yields
2∂χ3
∂xi+λ+µ
µ∂
∂xiparenleftbigg
χ3+∂ϕk
∂xk+x3∂χk
∂xkparenrightbigg
=0. (5.80)
In many cases it is sufficient to assume that χipossesses a potential
χi=∂ψ
∂xi,∇2ψ=0. (5.81)
88 Elastic materials
Then (5.80) becomes
2∂2ψ
∂xi∂x3+λ+µ
µ∂
∂xiparenleftbigg∂ψ
∂x3+∂ϕk
∂xkparenrightbigg
=0. (5.82)
We can integrate once this equation with respect to xi. Assuming the constant to be
zero we obtain∂ψ
∂x3=−1
3−4ν∂ϕk
∂xk,1
3−4ν≡λ+µ
λ+3µ. (5.83)
Now, solving the boundary value problem for ϕiwe can find from the above relation the
functionψand then the displacement from the definition of the Trefftz po tential which
has now the form
ui=ϕi+x3∂ψ
∂xi. (5.84)
This representation yields not only the solution of the Bous sinesq problem but also
the solution of the so-called Cerrutti problem7in which the boundary x3is loaded by the
tangential force Pin thex1-direction. We present the displacement for both problems
in juxtaposition in the Table below. Both solutions were com bined by R. D. Mindlin8.
Numerous solutions of similar problems can be found in the bo ok of K. L. Johnson9.
Table:SolutionsofBoussinesqandCerruttiproblemsforhalf-spa ce
J. Boussinesq V. Cerrutti
u1=Px1
4πµparenleftBig
x3
r3−1−2ν
r(r+x3)parenrightBig
Px1
4πµparenleftBig
1
r+x2
1
r3+(1−2ν)parenleftBig
1
r+x3−x2
1
r(r+x3)2parenrightBigparenrightBig
u2=Px2
4πµparenleftBig
x3
r3−1−2ν
r(r+x3)parenrightBig
Px1x2
4πµparenleftBig
1
r3−(1−2ν)1
r(r+x3)2parenrightBig
u3=P
4πµparenleftBig
x2
3
r3+1−2ν
rparenrightBig
P
4πµparenleftBig
x1x3
r3+(1−2ν)x1
r(r+x3)parenrightBig
The above presented displacement formulation shall be also used further in the wave
analysis.
7Valentino Cerrutti, 1850-1909
8R. D. MIiscInscIdscIlscIiscInsc; Force at a point in the interior of a semi-infinite solid, Office of Naval Research
Project NR-064-388 Contract Nonr-266(09), Technical Repo rt No. HCU-9-s:K, >NR-266(09)-CE, May
1953.
see also:I.A.OIkscIuscImscIuscIrscIasc; On the generalization of Cerrutti’s problem in an elastic ha lf-space,Struc-
tural Engn./Earthquake Eng., 12, 2, 17-26, 1995,
D.A.PIoscIzscIhscIascIrscIsscIkscIiscIisc; Generalization of the Cerruti Problem, Doklady Physics ,53, No. 5, pp. 283—286,
Pleiades Publishing, Ltd, 2008.
9K.L.JIoscIhscInscIsscIoscInsc; Contact Mechanics, (ninth printing) Cambridge University Press , 2003.
5.2 Linear elasticity, isotropic and anisotropic material s 89
5.2.3 Beltrami-Michell equations
Static problems of linear elasticity can be also solved in a d ifferent way. Namely, if the
boundary conditions prescribe tractions then we can direct ly find distributions of stresses.
This can be done by use of the compatibility conditions (5.13 ) or rather (5.14) as there
are only six independent compatibility conditions. These i ndependent conditions may be
also obtained by the contraction in (5.13) and then written i n the form
∂2eij
∂xk∂xk+∂2ekk
∂xi∂xj−∂2eik
∂xj∂xk−∂2ejk
∂xj∂xk=0. (5.85)
Substitution of the inverted Hooke law (5.26) yields
∇2σij+2(λ+µ)
3λ+2µ∂2σkk
∂xi∂xj−λ
3λ+2µδij∇2σkk− (5.86)
−parenleftbigg∂2σkj
∂xi∂xk+∂2σki
∂xj∂xkparenrightbigg
=0.
Bearing the momentum balance equation (i.e. the equilibriu m condition in the static
case!) in mind
∂σij
∂xj+ρbi=0, (5.87)
we reduce the system of equations (5.86) to the following for m
∇2σij+2(λ+µ)
3λ+2µ∂2σkk
∂xi∂xj−λ
3λ+2µδij∇2σkk+ (5.88)
+ρ∂bi
∂xj+ρ∂bj
∂xi=0.
The trace of this relation yields
∇2σkk=−3λ+2µ
λ+2µρ∂bk
∂xk. (5.89)
Hence, we can eliminate this Laplace operator contribution in (5.88). We obtain
∇2σij+1
1+ν∂2σkk
∂xi∂xj=−ρparenleftbigg∂bi
∂xj+∂bj
∂xiparenrightbigg
−ν
1−νδijρ∂bk
∂xk. (5.90)
These are Beltrami-Michell stress equations. Together wit h boundary conditions for
tractions they form the well-posed problem for the determin ation of stresses. Many
examples of applications of these equations extended by the contribution of pore pressure
can be found in geomechanics (e.g. [20]).
In a particular case of potential body forces
ρbi=−∂Γ
∂xi,∇2Γ=0, (5.91)
90 Elastic materials
the set of equations (5.90) has the form
∇2σij+1
1+ν∂2σkk
∂xi∂xj=−2∂2Γ
∂xi∂xj. (5.92)
Therefore for such external forces the pressure is a harmoni c function
∇2p=0, p=−1
3σkk. (5.93)
Simultaneously, the application of Laplace operator to (5. 92) yields
∇2∇2σij=0, (5.94)
i.e. all components of stresses are biharmonic functions.
5.2.4 Plane strain and plane stress
We complete these considerations with a brief presentation of two special cases of statics:
plane strain and plane stress systems (compare (3.81), (3.8 2). Then all functions depend
only on two variables, say, xα,α=1,2.
For a system extended to infinity in the x3-direction we have the plane strains —
u3-component of displacement is identically zero and, conseq uently
e3k=0. (5.95)
Constitutive relations reduce to the form
σαβ=λ∂uγ
∂xγδαβ+µparenleftbigg∂uα
∂xβ+∂uβ
∂xαparenrightbigg
,
σ33=λ∂uγ
∂xγα,β,γ=1,2. (5.96)
The displacement equations have then the following form
(λ+µ)∂2uβ
∂xα∂xβ+µ∂2uα
∂xβ∂xβ+ρbα=0. (5.97)
They can be solved, as in a general case, by means of various po tentials which satisfy
either Laplace or Poisson equation. The most important of th em are:
1) Galerkin function F=(F1,F2,0)
uα=λ+2µ
µ∂2Fα
∂xβ∂xβ−λ+µ
µ∂2Fβ
∂xα∂xβ⇒ (5.98)
⇒(λ+2µ)∂4Fα
∂xβ∂xβ∂xγ∂xγ+ρbα=0i.e.∇2∇2Fα+ρbα
λ+2µ=0.
In many cases it is sufficient to introduce only one component o f this function.
5.2 Linear elasticity, isotropic and anisotropic material s 91
The stress in the direction of x3-axis is as follows
σ33=2µν
1−2ν∂2
∂xα∂xα∂Fβ
∂xβ=2µν
1−2ν∂
∂xβ∇2Fβ. (5.99)
2) Papkovich-Neuber potentials
uα=∂(Φ0+xβΦβ)
∂xα−4(1−ν)Φα, (5.100)
with the following equations for potentials
4µ(1−ν)∂2Φ0
∂xβ∂xβ+ρxβbβ=0,
4µ(1−ν)∂2Φα
∂xβ∂xβ−ρbα=0, α=1,2. (5.101)
3) Airy function. Compatibility conditions (5.85) reduce i n the plane case to the
single equation
∂2e11
∂x2∂x2+∂2e22
∂x1∂x1=2∂2e12
∂x1∂x2. (5.102)
In terms of stresses this condition and the equilibrium cond itions without body forces
have the form
∂2σ11
∂x2∂x2+∂2σ22
∂x1∂x1−λ
2(λ+µ)∂2
∂xβ∂xβ(σ11+σ22)=2∂2σ12
∂x1∂x2,
∂σ11
∂x1+∂σ12
∂x2=0,∂σ12
∂x1+∂σ22
∂x2=0. (5.103)
The following Airy function F
σαβ=−∂2F
∂xα∂xβ+δαβ∂2F
∂xγ∂xγ, (5.104)
satisfies identically the equilibrium conditions and yield s the following form of the com-
patibility condition
∇2∇2F=∂4F
∂xα∂xα∂xβ∂xβ≡∂4F
∂x4
1+2∂4F
∂x2
1∂x2
2+∂4F
∂x4
2=0, (5.105)
i.e. it is a biharmonic function.
Now we consider the case of plane stresses. It appears in membranes, i.e. systems
whose one dimension, say in the x3-direction, is much smaller than in the remaining two
directions. Then we can use an approximation
σ3k≈0. (5.106)
92 Elastic materials
Simultaneously
σαβ=2µeαβ+2µλ
λ+2µδαβeγγ, α,β,γ=1,2, (5.107)
which implies the following set of displacement equations
µparenleftbigg∂2uα
∂xβ∂xβ+3λ+2µ
λ+2µ∂2uβ
∂xα∂xβparenrightbigg
+ρbα=0. (5.108)
If we invert the constitutive relations (5.107)
eαβ=1
2µparenleftbigg
σαβ−λ
3λ+2µδαβσγγparenrightbigg
, (5.109)
then the compatibility relation (5.102) yields the followi ng equation
∂2σ11
∂x2∂x2+∂2σ22
∂x1∂x1−λ
3λ+2µ∂2
∂xβ∂xβ(σ11+σ22)=2∂2σ12
∂x1∂x2. (5.110)
Hence, we can again introduce the Airy function Fby the relation (5.104) which satisfies
identically equilibrium conditions and it is again a biharm onic function satisfying the
equation (5.105).
By means of this Airy function one solves in the linear elasti city the Flamant (1892)
problem (stresses and displacements in a linear elastic wed ge loaded by point forces at
its sharp end; in particular the solution for the half-plane ), punch problems and many
others. We present here a simple example of a solution for a me mbrane with a hole. This
solution indicates an important property of mechanical sys tems with imperfections that
they yield stress concentration.
⋆In order to appreciate an influence of structure discontinui ties on the distribution
of stresses we consider a simple example of an infinite membra ne with hole (cavity) of
radiusa(see: Fig. 5.5.)10.
Fig. 5.5: Extension of a membrane with the circular cavity
10CIhscIisc-TIescIhscWIascInscIgsc ;Applied Elasticity , McGraw-Hill, N. Y., 1953
5.2 Linear elasticity, isotropic and anisotropic material s 93
The membrane is loaded uniformly in the x-direction by the lo ad of intensity S.
Clearly, if the hole is not there the stress in the membrane ha s the following components
σx=S, σy=τxy=0. (5.111)
This solution corresponds to the Airy function
F0=1
2Sy2=1
4Sr2(1−cos2θ). (5.112)
This relation implies the following components of stresses in the polar coordinates
σ0
rr=1
r∂F0
∂r+1
r2∂2F0
∂θ2=1
2S(1+cos2θ),
σ0
θθ=∂2F0
∂r2=1
2S(1−cos2θ), (5.113)
τ0
rθ=−∂
∂rparenleftbigg1
r∂F0
∂θparenrightbigg
=−1
2Ssin2θ.
We have made this transformation of coordinates as the probl em with the cavity is easier
in polar coordinates. For the problem with the cavity the fol lowing boundary conditions
must be fulfilled
σrr=τrθ=0forr=a, (5.114)
σrr=σ0
rr, τrθ=τ0
rθ, σθθ=σ0
θθforr→∞.
The structure of the function F0suggests that we can try to find the Airy function for
the more general case in the following form
F=f1(r)+f2(r)cos2θ. (5.115)
This function must be biharmonic. Substitution of (5.115) i n the equation for Airy
function in polar coordinates (compare (5.45))
parenleftbigg∂2
∂r2+1
r∂
∂r+1
r2∂2
∂θ2parenrightbiggparenleftbigg∂2F
∂r2+1
r∂F
∂r+1
r2∂2F
∂θ2parenrightbigg
=0, (5.116)
yields two equations as the general equation should hold for arbitrary angles θ. They
have the following form
parenleftbiggd2
dr2+1
rd
drparenrightbiggparenleftbiggd2f1
dr2+1
rdf1
drparenrightbigg
=0, (5.117)
parenleftbiggd2
dr2+1
rd
dr−4
r2parenrightbiggparenleftbiggd2f2
dr2+1
rdf2
dr−4f2
r2parenrightbigg
=0.
The solutions of these simple ordinary differential equatio ns have the form
f1(r) =c1r2lnr+c2r2+c3lnr+c4, (5.118)
f2(r) =c5r2+c6r4+c7
r2+c8.
94 Elastic materials
This yields the Airy function in the form
F=parenleftbigc1r2lnr+c2r2+c3lnr+c4parenrightbig+parenleftBig
c5r2+c6r4+c7
r2+c8parenrightBig
cos2θ. (5.119)
Hence relations for stress components are as follows
σrr=1
r∂F
∂r+1
r2∂2F
∂θ2=c1(1+2lnr)+2c2+c3
r2−parenleftbigg
2c5+6c7
r4+4c8
r2parenrightbigg
cos2θ,
σθθ=∂2F
∂r2=c1(3+2lnr)+2c2−c3
r2+parenleftbigg
2c5+12c6r2+6c7
r4parenrightbigg
cos2θ,(5.120)
τrθ=−∂
∂rparenleftbigg1
r∂F
∂θparenrightbigg
=parenleftbigg
2c5+6c6r2−5c7
r4−2c8
r2parenrightbigg
sin2θ.
Stresses should be finite in infinity which means that constan tsc1andc6must be
identically zero. The remaining boundary conditions lead t o the following solution
σr=S
2parenleftbigg
1−a2
r2parenrightbigg
+S
2parenleftbigg
1+3a4
r4−4a2
r2parenrightbigg
cos2θ,
σθ=S
2parenleftbigg
1+a2
r2parenrightbigg
−S
2parenleftbigg
1+3a4
r4parenrightbigg
cos2θ, (5.121)
τrθ=−S
2parenleftbigg
1−3a4
r4+2a2
r2parenrightbigg
sin2θ.
It is seen that for r=aandθ=π/2andθ=3π/2the circumferential stress σθθhas
the maximum value equal to 3S. This is three times more than in the case without the
hole. In Fig. 5.6. we show the behaviour of σθθfor these two values of the angle.
Fig. 5.6: Circumferential stresses σθθ/Sin function of the distance from the
holer/a.♣
The problem of the concentration of stresses in the vicinity of various holes has a very
extensive literature due to its practical bearing.
5.2 Linear elasticity, isotropic and anisotropic material s 95
5.2.5 Waves in linear elastic materials
We return to the analysis of the displacement equations (5.3 2). We begin with a proof
of existence of two waves described by these equations. This is based on Hadamard
Theorem which we sketch for the purpose of the linear theory. We consider a point xA
on a singular surface on which both the strain eand the velocity vare continuous but
their higher derivatives such as the acceleration ∂v/∂tor the gradient of strain grademay
suffer a finite discontinuity. The point xAchanges its position with the moving singular
surface and, say, after a small time increment δtis located in a point xB=xA+δx. We
assume that this change happens in the direction nperpendicular to the surface and with
the speedc, i.e.δx=cnδt.Then the change of the value of the gradient of displacement
between these two points can be calculated on the path ahead o f the singular surface
and behind this surface and, consequently, along the paths o n which the gradient of
displacement possesses continuous derivatives. We have
∂ui
∂xjvextendsinglevextendsinglevextendsinglevextendsingle
B=∂ui
∂xjvextendsinglevextendsinglevextendsinglevextendsingle
A+∂2ui
∂xj∂xkvextendsinglevextendsinglevextendsinglevextendsingle+
Aδxk+∂2ui
∂xj∂tvextendsinglevextendsinglevextendsinglevextendsingle+
Aδt= (5.122)
=∂ui
∂xjvextendsinglevextendsinglevextendsinglevextendsingle
A+∂2ui
∂xj∂xkvextendsinglevextendsinglevextendsinglevextendsingle−
Aδxk+∂2ui
∂xj∂tvextendsinglevextendsinglevextendsinglevextendsingle−
Aδt,
where the signature " +" and "−" indicates the limits on both sides of the surface.
Subtracting these relations, we easily arrive at the follow ing compatibility condition
bracketleftbiggbracketleftbigg∂2ui
∂xj∂xkbracketrightbiggbracketrightbigg
=−1
cbracketleftbiggbracketleftbigg∂2ui
∂xj∂tbracketrightbiggbracketrightbigg
nk, (5.123)
where[[...]]=(...)+−(...)−is the difference of limits on both sides of the surface. In the
same way we prove the identity for the acceleration
bracketleftbiggbracketleftbigg∂2ui
∂xj∂tbracketrightbiggbracketrightbigg
=−1
cbracketleftbiggbracketleftbigg∂2ui
∂t2bracketrightbiggbracketrightbigg
nj. (5.124)
These identities form the contents of Hadamard Theorem. The y can be combined to give
the following relationbracketleftbiggbracketleftbigg∂2ui
∂xj∂xkbracketrightbiggbracketrightbigg
=1
c2bracketleftbiggbracketleftbigg∂2ui
∂t2bracketrightbiggbracketrightbigg
njnk. (5.125)
Now we form the jump of the displacement equations on the sing ular surface described
above. We obtain
ρbracketleftbiggbracketleftbigg∂2ui
∂t2bracketrightbiggbracketrightbigg
=(λ+µ)bracketleftbiggbracketleftbigg∂2uk
∂xi∂xkbracketrightbiggbracketrightbigg
+µbracketleftbiggbracketleftbigg∂2ui
∂xk∂xkbracketrightbiggbracketrightbigg
. (5.126)
Substitution of (5.125) yields
parenleftbigg
c2δik−λ+µ
ρnink−µ
ρδikparenrightbiggbracketleftbiggbracketleftbigg∂2uk
∂t2bracketrightbiggbracketrightbigg
=0. (5.127)
96 Elastic materials
Consequently, we obtain the eigenvalue problem in which the discontinuity of accelera-
tion is the eigenvector. The eigenvalues can be found by the s eparation of longitudinal
and transversal contributions. If we multiply the relation (5.127) by a unit vector t
perpendicular to n(i.e.tini=0) then we obtain
parenleftbigg
c2−µ
ρparenrightbiggparenleftbiggbracketleftbiggbracketleftbigg∂2uk
∂t2bracketrightbiggbracketrightbigg
tkparenrightbigg
=0. (5.128)
Hence, either the projection of discontinuity on the direct ion perpendicular to nis zero
and then we obtain the identity, or it is different from zero an d then
c2=c2
T=µ
ρ. (5.129)
This is the square of the speed of propagation of the front of t he wave on which the
acceleration suffers the transversal discontinuity. We cal l such waves transversal (shear
waves). Obviously, in order to be real the speed of propagati on yields the condition
µ>0, (5.130)
which is one of the limitations of material parameters menti oned at the beginning of this
Chapter.
Now we multiply the equation (5.127) by the vector n. It follows
parenleftbigg
c2δik−λ+2µ
ρparenrightbiggparenleftbiggbracketleftbiggbracketleftbigg∂2uk
∂t2bracketrightbiggbracketrightbigg
nkparenrightbigg
=0. (5.131)
Hence, either the projection of discontinuity on the direct ionnis zero and then we obtain
the identity, or it is different from zero and then
c2=c2
L=λ+2µ
ρ. (5.132)
This is the square of the speed of propagation of the front of t he wave on which the
acceleration suffers the longitudinal discontinuity. We ca ll such waves longitudinal. As
before, for existence of these waves we have to require
λ+2µ>0, (5.133)
which is the second limitation of material parameters. When both conditions (5.130) and
5.2 Linear elasticity, isotropic and anisotropic material s 97
(5.133) are satisfied we say that the set of displacement equa tions (5.32) is hyperbolic.
Fig. 5.7: Schematic picture of longitudinal and transversa l waves
In Fig. 5.7. we demonstrate schematically the motion of part icles by the transition
of longitudinal and transversal waves.
Any dynamic solution of the displacement equations (5.32) d escribes the propagation
of the wave front which divides the domain Btat the instant of time tinto a part
which is not yet disturbed by the loading and the part behind t he front where the
dynamic displacement evolves. Exact solutions of this art c an be constructed by the
use of dynamic Green function for finite domains. However, te chnical difficulties in
construction of such solutions are so extensive that it pays off to consider a local structure
of dynamic disturbances. This is usually done by means of the Fourier analysis of plane
waves. The latter assumption means that we replace the three -dimensional propagation
by a one-dimensional local approximation. The solution is a ssumed to have the form
u=RebraceleftBig
Aei(k·x−ωt)bracerightBig
, (5.134)
whereAis a complex constant amplitude, ωis the so-called frequency of the wave. We
assume that it is given. Such waves are called monochromatic . The vectorkhas the
structurek=kn,n·n=1and the unit vector nis the direction of propagation of the
wave. It is assumed to be constant which means that the wave is plane.kis the so-called
wave number and it may be complex. Consequently the function (5.134) can be written
in the form
u=e−Imk(n·x)ReparenleftBig
AeiRek(n·x−cpht)parenrightBig
, cph=ω
Rek, (5.135)
andcphis called the phase speed. Imkdescribes the damping of the wave. The above
relation can be also written in the form of a real function
u=e−Imk(n·x)A0cos(Rek(n·x−cpht)+φ),A=A0eiφ, (5.136)
andA0is the real amplitude. [Rek(n·x−cpht)+φ]is called the phase and φis called
the phase shift.
98 Elastic materials
It is convenient to change phase in the following manner
Rek(n·x−cpht)+φ=2πparenleftbiggRek
2πn·x−ω
2πtparenrightbigg
+φ=
=2πparenleftBign·x
l−ftparenrightBig
+φ, l=2π
Rek, f=ω
2π. (5.137)
The quantity fis called the technical frequency and lis the wave length of the mono-
chromatic wave of frequency ω.
The full solution of the displacement equations (5.32) can b e constructed by means
of the combination of monochromatic waves which form then co ntributions to a Fourier
series. This representation of waves is called spectral.
We do not need to go into all details of the spectral analysis a nd present only solutions
of the form (5.134). Substitution of this relation in the dis placement equations yields
ρ(−iω)2Ai=(λ+µ)Ak(ikk)(iki)+µAi(ikk)(ikk),
i.e.bracketleftbigρω2δik−(λ+µ)kikk−µk2δikbracketrightbigAk=0, k=radicalbig
kkkk. (5.138)
This is again the eigenvalue problem. As in the case of the wav e front which we have
discussed above we separate the tangential and longitudina l components. Scalar multi-
plication by the unit vector tperpendicular to kyields
bracketleftbigρω2−µk2bracketrightbigAktk=0. (5.139)
Hence, the projection of the amplitude on the direction perp endicular to the direction of
propagationn=k/kdifferent from zero yields
k2=ω2
c2
T. (5.140)
This is the so-called dispersion relation for transversal m onochromatic waves. It shows
that the wave number is real in this case and that the phase spe ed is equal to the speed
of propagation of transversal waves
cph=cT, (5.141)
i.e. the phase speeds are independent of the frequency of the monochromatic wave. Such
waves are called non-dispersive. As Imk=0they are not attenuated (damping is zero).
Now scalar multiplication of the equation (5.138) by kyields
bracketleftbigρω2−(λ+2µ)k2bracketrightbigAknk=0. (5.142)
Again for the projection of the amplitude on the direction of propagation different from
zero we obtain
k2=ω2
c2
L. (5.143)
5.2 Linear elasticity, isotropic and anisotropic material s 99
This dispersion relation for longitudinal monochromatic w aves yields the phase speed
equal to the speed cL
cph=cL, (5.144)
and this is again independent of the frequency. As transvers al waves, also longitudinal
monochromatic waves are non-dispersive and not attenuated .
The two sorts of waves which we presented above are called bul k waves because they
propagate inside of the body. In the case of a boundary the sit uation changes. We
consider here a simple case of a half-space with the plane bou ndary which yields the
so-called surface waves. In the case under consideration th ey were discovered by J.
W. Rayleigh (1887)11. On the boundary perpendicular to the x3-axis we assume the
boundary conditions
Tn|x3=0i.e.σk3|x3=0=0,n=−e3, (5.145)
i.e. the boundary is stress-free. It means that the wave has b een created far away from
the origin of coordinates and its source will be ignored in th e analysis. Simultaneously,
we have the following Sommerfeld condition
u|x3→∞=0. (5.146)
It is easier to seek the solution of the problem when we make th e following decompo-
sition of the displacement vector
u=uL+uT,rotuL=0,divuT=0, (5.147)
whereuLis called the potential part and uTis the solenoidal part. Obviously, it is directly
connected with the Helmholtz decomposition (1.57): uL= gradϕ,anduT= rotψ.
These two parts must satisfy equations
∂2uL
∂t2=c2
L∇2uL,∂2uT
∂t2=c2
T∇2uT, (5.148)
following directly from the displacement equations (5.32) (compare (5.58)).
We seek the solution in the form of the following ansatz
uL=ALe−γx3ei(kx1−ωt)e1+BLe−γx3ei(kx1−ωt)e3, (5.149)
uT=ATe−βx3ei(kx1−ωt)e1+BTe−βx3ei(kx1−ωt)e3.
Hence, we consider the plane problem. We anticipate a progre ssive wave solution in the
x1-direction and the decay of the solution in the x3-direction provided the coefficients
γ,βare positive. If such a solution does not exist it means that t he surface wave does
not appear.
Substitution of the ansatz (5.149) in wave equations (5.148 ) leads to the compatibility
conditions
γ2
k2=1−c2
R
c2
L,β2
k2=1−c2
R
c2
T, cR=ω
k, (5.150)
11J.W.(SItscIrscIuscItscItsc)RIascIyscIlscIescIiscIgscIhsc; On waves propagated along the plane surface of an elastic sol id,Proc.
London Math. Soc., 17:4-11, 1887.
100 Elastic materials
wherecRis the phase speed of the wave. Now we use the properties of the potential and
solenoidal parts. We have
ǫ231∂uL
1
∂x3+ǫ213∂uL
3
∂x1= 0⇒BL=iγ
kAL, (5.151)
∂uT
1
∂x1+∂uT
3
∂x3= 0⇒BT=ik
βAT.
Consequently
uL=parenleftBig
e1+iγ
ke3parenrightBig
ALe−γx3ei(kx1−ωt), (5.152)
uT=parenleftbigg
e1+ik
βe3parenrightbigg
ATe−βx3ei(kx1−ωt).
Obviously, the Sommerfeld condition is satisfied by these fu nctions ifγ,β >0. The
stress components which we need in boundary conditions (5.1 45) can be written in the
form
1
ρσ33=parenleftbigc2
L−2c2Tparenrightbig∂u1
∂x1+c2
L∂u3
∂x3, (5.153)
1
ρσ13=c2
Tparenleftbigg∂u1
∂x3+∂u3
∂x1parenrightbigg
.
Hence, forx3=0the substitution of (5.152) leads to the set of two equations
parenleftbigg
2−c2
R
c2
Tparenrightbigg
AL+2AT= 0, (5.154)
2γβ
k2AL+parenleftbigg
2−c2
R
c2
Tparenrightbigg
AT= 0.
This is the homogeneous set of equations for amplitudes AL,AT. It possesses nontrivial
solutions if the determinant is equal to zero
parenleftbigg
2−c2R
c2
Tparenrightbigg2
−4radicalBigg
1−c2
R
c2
TradicalBigg
1−c2
R
c2
L=0, (5.155)
where relations (5.150) have been used. This equation for cRis called Rayleigh dispersion
relation. It is clear that the speed of Rayleigh waves cRis independent of the frequency
ω. Consequently, Rayleigh waves are non-dispersive.
The solution of the equation (5.155) is shown in Fig. 5.8. As
cT
cL=radicalbiggµ
λ+2µ=radicalbigg
1
21−2ν
1−ν<1, (5.156)
the speed of Rayleigh waves is smaller than the speed of trans versal waves. It has a
physical interpretation in terms of the so-called construc tive interference of longitudinal
5.2 Linear elasticity, isotropic and anisotropic material s 101
and transversal waves which happens after these waves are re flected from the boundary
and so create the surface wave.
Fig. 5.8: Dimensionless speed of Rayleigh waves cR/cTas a function of the
fraction of transversal and longitudinal speeds cT/cL.
Let us inspect the relations for components of displacement s. According to (5.147)
they have the form
u1=parenleftbigALe−γx3+ATe−βx3parenrightbigei(kx1−ωt), (5.157)
u3=iparenleftbiggγ
kALe−γx3+k
βATe−βx3parenrightbigg
ei(kx1−ωt).
We choose the real part of these relations with cos(kx1−ωt). Then by eliminating the
time from these relations, we obtain
(Reu1)2
α2
1+(Reu3)2
α2
3=1, (5.158)
where
α1=ALe−γx3+ATe−βx3, (5.159)
α3=γ
kALe−γx3+k
βATe−βx3.
Hence the orbits of particles are ellipses with semiaxes |α1|,|α3|. One can easily show
that the motion is anticlockwise. This is opposite to the dir ection of motion of water
particles in shallow water waves. The size of these ellipses diminishes exponentially with
the depthx3. This is the reason for calling such a wave the surface wave. I t can be shown
that the elliptic motion of particles in planes x2=constis the only motion possible for
Rayleigh waves. Transversal Rayleigh waves do not exist.
The lack of dispersion in the plane case presented above expl ains the disastrous action
of surface waves in earthquakes. In contrast to bulk waves wh ich move from the point
102 Elastic materials
source (hypocenter) in approximately spherical form and ar e the first two arrivals, the
surface wave moves from epicenter in approximately cylindr ical form and arrives as the
last one (cR< cT< cL). Hence the energy which carries the wave is distributed on a
much larger surfaces for bulk waves than for surface waves.
Fig. 5.9: An application of surface waves: testing of rails
The nondispersive character of three waves which we have con sidered above is rather
exceptional. Whenever the problem comprises a characteris tic length waves become
dispersive. This is the case for surface waves in boreholes, tunnels, layers, or media with
microstructure such as porous materials (characteristic l ength — dimensions of channels).
We consider here the simplest example of Love waves12.
A. E. H. Love (1911) has solved the problem of propagation of w aves in a layer of
thicknessHon an elastic half-space. The plane of contact of these two me dia (interface)
is perpendicular to the upward oriented x3-axis and the origin of the coordinates lies
on this plane. We distinguish the material properties by a ’p rime’, i.e.ρ′,c′
Tare the
mass density and the speed of transversal waves in the layer w hileρ,cTare the mass
density and the speed of transversal waves in the half-space . We assume that the motion
of particles is perpendicular to the (x1,x3)-plane of propagation of waves. Then the
problem is described by two wave equations
∂2u′
2
∂t2=c′2
T∇2u′
2for0<x3<H, (5.160)
∂2u2
∂t2=c2
T∇2u2forx3<0.
One can show that longitudinal surface waves (i.e. waves wit h a displacement (u′
1,0,u′3)
in the plane x2=const) for this configuration do not exist.
12C.G.LIascIisc, K.WIiscIlscImscIascInscIsscIkscIisc; (eds),Surface Waves in Geomechanics: Direct and Inverse Modellin g
for Soils and Rocks , Springer, 2005.
5.2 Linear elasticity, isotropic and anisotropic material s 103
We seek the solution of the system (5.160) in the form of a mono chromatic wave of
the frequency ω
u′
2=parenleftBig
A′eiks′x3+B′e−iks′x3parenrightBig
ei(kx1−ωt)≡
≡2(ReA′cosks′x3−ImA′sinks′x3)ei(kx1−ωt), (5.161)
u2=Beksx3ei(kx1−ωt).
This solution should satisfy the boundary conditions
1. Shear stress on the plane x3=His equal to zero, i.e.
∂u′
2
∂yvextendsinglevextendsinglevextendsinglevextendsingle
x3=H=0, (5.162)
2. shear stress and the displacement must be continuous on th e interfacex3=0
ρ′c′2
T∂u′
2
∂x3vextendsinglevextendsinglevextendsinglevextendsingle
x3=0=ρc2
T∂u2
∂x3vextendsinglevextendsinglevextendsinglevextendsingle
x3=0, ρ′c′2
T=µ′, ρc2
T=µ,
u′
2|x3=0=u2|x3=0. (5.163)
Substitution of (5.161) in (5.160) yields the compatibilit y conditions
s′2=c2
c′2
T−1, s2=1−c2
c2
T, c=ω
k. (5.164)
The boundary condition (5.162) leads to the following displ acement in the layer
u′
2=2ReA′cos(ks′(H−x3))
cos(ks′H)ei(kx1−ωt). (5.165)
Then the remaining two conditions (5.163) give rise to two eq uations for the constants
ReA′,B. As this system of equations is homogeneous the determinant must be zero and
we obtain the following Love dispersion relation
ω=c
Hs′bracketleftbigg
arctanparenleftbiggρc2
Ts
ρ′c′2
Ts′parenrightbigg
+nπbracketrightbigg
, n=1,2,3,..., (5.166)
wheres,s′must be real and smust be positive for the amplitude of the wave to decay
in the half-space. Consequently, according to (5.164),
c′
T≤c≤cT. (5.167)
Hence, the Love waves exist only in layers which are softer th an the foundation. Si-
multaneously, the dispersion relation has infinitely many s olutions, the so-called modes,
and the corresponding speeds of propagation depend on the fr equencyω. Love waves
are dispersive. This means that packages of waves of differen t frequency become broader
during the propagation — some of their monochromatic contri butions are slower than the
104 Elastic materials
others. For this reason, one introduces also an "average" sp eed of propagation which is
called the group velocity
cg=dω
dk=dω
dcphc2
ph
dω
dcphcph−ω, (5.168)
where the second part of the relation follows immediately fr om the definitions. Conse-
quently, we can find the group velocity immediately substitu ting the dispersion relation
(5.166). We show here only a simple numerical example for the following data (compare
examples in [1])
cT=5km
s, c′
T=3km
s,ρ′
ρ=0.875, H=10km. (5.169)
Results are plotted in Fig. 5.10.
Fig. 5.10: Phase and group velocity of the first mode of Love wa ve for the
data(5.169)
In contrast to the phase velocity the group velocity is not a m onotonous function of
the frequency. This property yields the existence of the so- called Airy phase which has
an important bearing in description of seismic waves13.
5.2.6 Principle of virtual work
Motivated by the principle of conservation of energy we pres ent now one of the most
important procedures in linear elasticity which forms both a method for mathematical
proofs of existence and uniqueness of solutions as well as a f oundation for numerous
approximate methods of solutions.
13for some details see: C.G.LIascIisc,K.WIiscIlscImscIascInscIsscIkscIisc; (eds),Surface Waves in Geomechanics: Direct and
Inverse Modelling for Soils and Rocks , Springer, 2005.
5.2 Linear elasticity, isotropic and anisotropic material s 105
Let us consider first the static problem. The body Btis loaded by external forces ρb
and tractionstngiven on the surface ∂Bσ
twith the prescribed displacement ubon the
remaining part of the boundary ∂Bu
t. This yields displacements u(x), stressesT(x)and
straine(x)in the bodyBt.
We impose on these displacements a virtual displacement δuwhich is small, continu-
ously differentiable and admissible. It means that it has to c omply to conditions limiting
the motion of the body. For instance, it must be zero on the bou ndary∂Bu
t.
The principle of virtual work says that the work done by virtu al displacements of
external loadings is equal to the work of internal forces, i. e.
integraldisplay
Btρb·δudV+integraldisplay
∂Bttn·δudS=integraldisplay
BtT·δedV, (5.170)
where
δe=1
2parenleftBig
(gradδu)+(gradδu)TparenrightBig
=1
2δparenleftBig
(gradu)+(gradu)TparenrightBig
. (5.171)
We shall see that this statement is related to the energy cons ervation (4.1).
In order to derive (5.170) we multiply the equilibrium condi tions byδuand integrate
over the bodyBt. We have
integraldisplay
Bt(divT+ρb)·δudV=0. (5.172)
This yields
integraldisplay
BtdivT·δudV=integraldisplay
Bt[div(Tδu)−T·gradδu]dV=
=integraldisplay
∂Bttn·δudS−integraldisplay
BtT·δedV, (5.173)
where we have used δu=0on∂Bu
t. This relation indicates (5.170).
Conversely the principle (5.170) yields local equilibrium conditions.
For isotropic elastic solids we can also write
T·δe=(λekkδij+2µeij)δeij=1
2λδ(eiiejj)+µδ(eijeij)=1
2δ(σijeij).(5.174)
Consequently
integraldisplay
Btρb·δudV+integraldisplay
∂Bttn·δudS=δE, E=integraldisplay
BtρεdV, ρε=1
2σijeij. (5.175)
Obviously, the quantity ρεis the potential energy of the linear elastic material. The
quantityEis called the work of deformations.
106 Elastic materials
As the body forces band tractionstnare given their variations are zero. Hence, we
can write
δΠe=0,Πe=E−integraldisplay
Btρb·udV−integraldisplay
∂Bttn·udS, (5.176)
whereΠeis the potential energy of the displacement field. The above c ondition shows
that this potential possesses an extremum in real motion. It is easy to see that it is
minimum. We have to compare the potentials Π′
eandΠefor displacements u+δuand
u. We have
ρε(eij+δeij)=ρε(eij)+ρ∂ε
∂eijδeij+1
2!∂2ε
∂eij∂eklδeijδekl+...,
⇒ρε(eij+δeij)−ρε(eij)=σijδeij+1
2∂σij
∂eklδeijδekl+... (5.177)
Therefore
Π′
e−Πe=integraldisplay
BtσijδeijdV−integraldisplay
Btρb·δudV−integraldisplay
∂Bttn·δudS+integraldisplay
Bt1
2∂σij
∂eklδeijδekldV=
=integraldisplay
Bt1
2∂σij
∂eklδeijδekldV=integraldisplay
Bt1
2(λδijδkl+2µδikδjl)δeijδekldV=
=integraldisplay
Bt1
2(λδeiiδejj+2µδeijδeij)dV= (5.178)
=integraldisplay
Bt1
2parenleftbiggparenleftbigg
λ+2
3µparenrightbigg
δeiiδejj+2µδeD
ijδeD
ijparenrightbigg
dV,
where
δeD
ij=δeij−1
3δekkδij, (5.179)
is the deviatoric part of δeij. The quantity (5.178) is positive if each contribution to
the sum is positive. This follows from the fact that δeiiandδeD
ijare independent and
arbitrary. Consequently, the potential Πepossesses the minimum in equilibrium if and
only if the material parameters satisfy the conditions
λ+2
3µ=K >0, µ>0. (5.180)
We have mentioned these limitations before. They indicate a s wellλ+2µ>0, i.e. (5.130)
and (5.133) which means that the minimum condition implies t he hyperbolicity of the
displacement equations.
We can easily extend the above principle on the full dynamic c ase. Then the principle
of virtual work (5.176) must be modified in the following way. We consider the motion
of the body between two instances of time, t1andt2. We consider the variation of real
displacement δuwhich satisfies the conditions
δu(x,t1)=δu(x,t2)=0. (5.181)
5.3 Thermoelasticity 107
Instead of (5.172) we have
t2integraldisplay
t1dtintegraldisplay
Btparenleftbigg
divT+ρb−ρ∂2u
∂t2parenrightbigg
·δudV=0. (5.182)
We have to transform the contribution of acceleration. If we introduce the kinetic energy
K=integraldisplay
Bt1
2ρ∂u
∂t·∂u
∂tdV, (5.183)
then
t2integraldisplay
t1δKdt=t2integraldisplay
t1dtintegraldisplay
Btρ∂
∂tparenleftbigg∂u
∂t·δuparenrightbigg
dV−t2integraldisplay
t1dtintegraldisplay
Btρ∂2u
∂t2·δudVdt. (5.184)
Due to conditions (5.181) the first integral on the right-han d side vanishes. Consequently,
δt2integraldisplay
t1(E−K)dt=t2integraldisplay
t1dtintegraldisplay
Btρb·udV+integraldisplay
∂Bttn·δudS, (5.185)
or
δt2integraldisplay
t1Ldt=0,L=K−Πe. (5.186)
This is the Hamilton principle. The functional Lis called Lagrangian of the system.
The Hamilton principle says that Lagrangian has an extremum in the interval of time
t1<t<t2, where in the endpoints of this interval the state of the body is known.
Hamilton’s principle has a very extensive physical literat ure as it is the main tool in the
derivation of model equations for numerous reversible proc esses of classical, relativistic
and quantum mechanics. The method based on the construction of Lagrangian and
various invariance principles yields equations of motion a nd conservation laws (see the
classical reference of Landau and Lifschitz [7]). Attempts to extend the method on
irreversible processes such as heat conduction or theory of dislocations in applications
to plasticity were not successful because the so-called Lag range-Euler equations which
follow as the equations of motion in this approach are invari ant with respect to time
reversal, i.e. they must be reversible.
5.3 Thermoelasticity
All processes in linear elastic materials which we have been discussing were assumed to be
isothermal. This is almost never the case and an influence of t emperature difference may
have a very substantial influence on the distribution of stre sses. We show the simplest
108 Elastic materials
possible extension of the linear elasticity on processes in which the temperature is variable
as well.
In the thermodynamic construction of a model we have to deal w ith at least two fields
in nonisothermal processes: displacement uand temperature T. For the displacement we
expect as before that it follows from the field equations cons tructed on the basis of the
momentum conservation law. On the other hand, the temperatu reTshould satisfy the
field equation which we assume to follow from the energy conse rvation law. Consequently,
we choose the equations (3.38) and (4.11) from which we const ruct the field equations.
In the linear problems they are as follows
ρ∂vk
∂t=∂σkl
∂xl+ρbk, (5.187)
ρ∂ε
∂t+∂qk
∂xk=σkl∂vk
∂xl,
where we have neglected the radiation and the mass density ρis constant.
For thermoelastic materials we assume that the stresses σkl, the internal energy εand
the heat flux qkare functions of the strain ekl, temperature Tand temperature gradient
∂T/∂xk. These constitutive functions should satisfy the second la w of thermodynamics
(4.20) which in the linear form is as follows
ρ∂η
∂t+divparenleftBigq
TparenrightBig
≥0, (5.188)
for all processes. The entropy density ηis also a function of the above listed constitutive
variables. We simplify the considerations by assuming thes e constitutive laws in the form
σkl=σkl(eij,T), ε=ε(eij,T), η=η(eij,T),
qk=−KT∂T
∂xk, (5.189)
whereKTis the thermal conductivity coefficient.The last relation is called Fourier’s law.
The detailed justification of these assumptions can be found in books on continuum
thermodynamics (e.g. [22]).
Now we exploit the inequality (5.188). The procedure is the s ame as for ideal gases
in Sec. 5.2. The momentum balance (5.187) does not impose any restrictions on the
inequality (5.188) due to the presence of acceleration. The elimination of the heat flux
from the inequality eliminates as well the constraint impos ed by the energy conservation.
We obtain
ρ∂ψ
∂t+ρη∂T
∂t+1
Tqk∂T
∂xk−σkl∂ekl
∂t≤0, (5.190)
ψ=ε−Tη=ψ(eij,T),
whereψis the Helmholtz free energy function. This inequality shou ld hold for all fields
of displacement and temperature. Due to the symmetry of the s tress tensor, we have
made the following replacement
σkl∂vk
∂xl=1
2σklparenleftbigg∂vk
∂xl+∂vl
∂xkparenrightbigg
=σkl∂ekl
∂t. (5.191)
5.3 Thermoelasticity 109
Now, the chain rule of differentiation and the linearity of th e inequality with respect to
the derivatives ∂T/∂t,∂e kl/∂tyield the following identities
σkl=ρ∂ψ
∂ekl, η=−∂ψ
∂T, ε=ψ−T∂ψ
∂T, (5.192)
and the residual inequality defining the dissipation
D=−qk∂T
∂xk=KTparenleftbigg∂T
∂xk∂T
∂xkparenrightbigg
≥0⇒K≥0. (5.193)
These relations immediately imply the following Gibbs equa tion of linear thermoelas-
ticity
dη=1
Tparenleftbigg
dε−1
ρσkldeklparenrightbigg
. (5.194)
Now, we are in the position to formulate the linear isotropic model. We assume that
the current temperature deviates only a little from the homo geneous initial temperature
T0, i.e. vextendsinglevextendsinglevextendsinglevextendsingleT−T0
T0vextendsinglevextendsinglevextendsinglevextendsingle≪1. (5.195)
Assuming in addition that the undeformed state ( ekl= 0) is stress-free we write the
Helmholtz free energy in the form of quadratic function with respect to the deviation
from the initial natural configuration
ρψ=−1
2ρcv
T0(T−T0)2−γ(T−T0)ekk+1
2cijkleijekl, (5.196)
cijkl=λδijδkl+µ(δikδjl+δilδjk).
The function must be quadratic due to relations (5.192) whic h imply that derivatives of ψ
must be linear. The coefficients in the above relation possess the following interpretation.
The internal energy follows in the form
ε=cv
2T0parenleftbigT2−T2
0parenrightbig+γ
ρT0ekk+1
2ρcijkleijekl. (5.197)
Consequently
∂ε
∂T=cvT
T0≈cv. (5.198)
Hence the coefficient cvis the specific heat by constant volume. Incidentally, the sp ecific
heats by constant volume and constant pressure, respective ly, are practically identical
for solids, in contrast to gases.
We proceed to the coefficient γ. For the stress tensor we obtain
σij=λekkδij+2µeij−γ(T−T0)δij. (5.199)
The first part is, obviously, identical with Hooke’s law for i sothermal processes. The
trace of this equation leads to
ekk=σkk
3K−γ
K(T−T0), K=λ+2
3µ. (5.200)
110 Elastic materials
Hence the coefficient γdescribes volume changes caused by the temperature differen ce.
It is called volumetric thermal expansion coefficient for sol ids. It is sometimes denoted by
αV. In experiments usually the linear thermal expansion coeffic ient for solids α=γ/3K
is measured. Some values of this coefficient are shown in the Ta ble below.
Table:Linearthermalexpansioncoefficient α=γ/3Kbracketleftbig10−6/◦Kbracketrightbig
aluminium 23.8 cast iron 11.8
asphalt 200 limescale 20
ice (0◦C) 0.502 marble 11
iron 12.1 polystyrene 60÷80
pyrex glass 3.2 porcelain 3÷4
crystal glass 0.45 sandstone 5
granite 3÷8firebrick 5
⋆In order to appreciate the order of magnitude of stresses cre ated by the temperature
difference we calculate the stress in a thin bar along x1-axis fixed on both ends and heated
uniformly from the temperature T0toT,T−T0=100◦. We choose steel as the material
for which
α= 11.8∗10−61/◦K,
λ= 11.78∗1010Pa, (5.201)
µ= 8.00∗1010Pa.
Then we have
e11= 0⇒σ22+σ33=2(λ+µ)ekk−2γ(T−T0)≈0,
i.e.ekk=γ
λ+µ(T−T0)=α3λ+2µ
λ+µ(T−T0). (5.202)
Hence, for our data,
σ11=λekk−γ(T−T0)=−αµ3λ+2µ
λ+µ(T−T0)=245 MPa. (5.203)
As the yield limit (the limit of elastic behavior) for constr uction steel is app. 250MPa
we see from the above example that relatively small temperat ure difference may create
already an irreparable damage in the material. It may, of cou rse, yield the buckling as
well. One should keep in mind that during a construction fire t he temperature difference
is app. 900◦and the temperature of magma is from 700◦C to 1300◦C, i.e. the rocks shortly
before melting reach the temperature app. 600◦C and this temperature difference yields
enormous thermal stresses. ⋆
By means of the above constitutive relations we can write the field equations. They
have the form
ρ∂2u
∂t2=(λ+µ)graddivu+µ∇2u−γgradT+ρb,
∂T
∂t=KT
ρcv∇2T−γT0
ρcv∂
∂tdivu. (5.204)
5.4 Poroelasticity 111
Clearly, due to the thermal expansion the equations are coup led. In many cases, one
can neglect the coupling in the equation for the temperature . Then the distribution of
temperature is determined as in the so-called rigid heat con ductors, i.e. in an undeformed
body and then this temperature field can be introduced to the d isplacement equations
as an external force.
5.4 Poroelasticity
Appearance of porous materials in nature is so common that we will not list even ex-
amples. Three of them are shown in Fig. 5.11. From the point of view of mechanics
the main issue in description of such materials is the coupli ng between the motion of the
solid skeleton and fluids in pores and channels. A proper cont inuum thermodynamics of
such systems requires a multicomponent modeling which is ca lled the theory of immis-
cible mixtures. We shall not enter this field of research in th ese notes and refer to many
monographs on the subject14.
Fig. 5.11: Examples of porous materials: sand, bronchus, to ilet paper
In this Subsection we show the modeling initiated by K. von Te rzaghi (1883-1963) who
proposed an extension of the classical linear elasticity by the diffusion equation for pore
pressure15. The couplings between the pore pressure and stresses in the solid skeleton
are similar to these in thermoelasticity. Consequently, th e model belongs to the class of
one-component models. Its motivation and modern developme nts within geomechanics
can be found in the book of H. F. Wang [20].
The main field is again the displacement u(x,t)but, in addition, we have to con-
sider volume changes of pore spaces. Macroscopically these changes are described by a
quantityεwhich is analogous to the volume changes of the skeleton give n bye=tre,
e=1
2parenleftBig
gradu+(gradu)TparenrightBig
. M. Biot has proposed in 194116a concept of the variation
14e.g.R.M.BIoscIwscIescInsc; Diffusion models implied by the theory of mixtures, in: C. Tru esdell,Rational
Thermodynamics, Second Edition , Springer, 237-263, N. Y., 1984,
J.BIescIascIrsc;Dynamics of Fluids in Porous Media , Dover, N.Y., 1972.,
as well as the monographs of Wilmanski [21], [22].
15K.IvscIoscInscTIescIrscIzscIascIgscIhscIisc; Erdbaumechanik auf bodenphysikalischer Grundlage , Deuticke, Wien, 1925,
K.IvscIoscInscTIescIrscIzscIascIgscIhscIisc; Theoretical Soil Mechanics , J. Wiley and Sons, New York, 1943.
16M.A.BIiscIoscItsc; General theory of three-dimensional consolidation, J. Appl. Physic ,12, 155-164, 1941.
112 Elastic materials
in water content, ζ, which is defined in terms of the volume changes by the relatio n
ζ=n0(e−ε), (5.205)
wheren0denotes the initial value of porosity. This is the fraction o f voids to the total
volume of the porous material, provided we choose a small dom ain for this definition.
These small domains are called Representative Elementary V olumes (REV). We shall
not discuss them in these notes. It can be shown that in a therm odynamical equilibrium
ζ=0which means that contributions of this variable to the model are irreversible. They
are related to the relative motion of solid and fluid componen ts, i.e. to the diffusion. We
can write
∂ζ
∂t=n0∂
∂t(divu−ε)=−n0divvseep,vseep=vF−∂u
∂t,∂ε
∂t=divvF,(5.206)
wherevFis the velocity of the fluid and vseepis the so-called seepage velocity.
For this reason, one cannot principally construct a variati onal formalism for such
models in spite of many publications in which it is though att empted.
Once we have the additional field ζwe can introduce a conjugate dynamic variable, p,
which is called pore pressure. The fundamental relations de fining the couplings between
the skeleton and the fluid can be written in principal coordin ates in the following form
e(1)=1
EparenleftBig
σ(1)−νparenleftBig
σ(2)+σ(3)parenrightBigparenrightBig
+p
3H,
e(2)=1
EparenleftBig
σ(2)−νparenleftBig
σ(1)+σ(3)parenrightBigparenrightBig
+p
3H, (5.207)
e(3)=1
EparenleftBig
σ(3)−νparenleftBig
σ(1)+σ(2)parenrightBigparenrightBig
+p
3H,
ζ=1
3HparenleftBig
σ(1)+σ(2)+σ(3)parenrightBig
+p
R,
where1/H,1/Rare the so-called Biot moduli: 1/His the so-called poroelastic expansion
coefficient, while 1/Ris the unconstrained specific storage coefficient. Their deta iled pre-
sentation can be found in the book of H. Wang [20]. It should be mentioned that M. Biot,
the founder of a systematic approach to the subject of porome chanics of saturated ma-
terials, was changing his notation many times and, for this r eason, some care is required
in reading his papers.
Certainly, the transformation of (5.207) to arbitrary coor dinates yields the extended
stress-strain relations. They have the form
σij=λekkδij+2µeij−αpδij, α=K
H, (5.208)
ζ=αekk+α
KuBp, B=αR
K,
whereαis called the Biot-Willis coefficient, Bis the Skempton coefficient,
Ku=K
1−αB, K=λ+2
3µ, (5.209)
5.4 Poroelasticity 113
andKuis called the undrained bulk modulus, i.e. the bulk modulus w hich corresponds to
ζ=0. Clearly, in addition to the Lamé constants λ,µ, the model contains two additional
material parameters, for instance, αandB, orαandKu.
In addition to the above described coupling properties betw een stresses, σijandp, and
strainseijandζ, we have to describe the flow of the fluid through the porous mat erials.
This is the subject of Darcy’s law. It relates the gradient of the pore pressure to the
relative velocity of the fluid and the skeleton, i.e. the seep age velocity,vseep=q/n0. It
can be written in the following form
q=−k
ηgradp, (5.210)
wherekis the so-called intrinsic permeability and ηdenotes the fluid viscosity. The ratio
k/ηis called the mobility. Some typical values of these paramet ers for water in pores
(i.e. forη=10−3Pa·s,ρ=1000 kg/m3,g=10m/s2) are shown in the Table.
Table:Permeabilityforafewrocktypes [20]
Rock typepermeability
kbracketleftbigm2bracketrightbigpermeability
[Darcy]hydraulic con-
ductivity[m/s]
sand
or sandstone10−121 10−5
sandstone
or limestone10−1510−310−8
granite or shale 10−1810−610−11
Once we have the constitutive relations (5.207) we can const ruct field equations using
the classical momentum conservation law and an additional e quation for the pore pres-
sure which follows from the definition of the variation in wat er content (5.205) and the
kinematic relation (5.206) combined with Darcy’s law (5.21 0)
ρ∂2u
∂t2= (λ+µ)graddivu+µ∇2u−αgradp+ρb, (5.211)
∂p
∂t=c∇2p−KuB∂
∂tdivu,
where
c=KuB
αk
η, (5.212)
is called the diffusivity.
Comparison of equations of linear thermoelasticity (5.204 ) and linear poroelasticity
(5.211) shows a full mathematical analogy of these models. T herefore many solution
available in thermoelasticity such as Green’s functions ca n be taken over to poroelasticity.
Let us mention that mechanics of poroelastic materials base d on the theory of mixtures
reveals many additional features related to porous structu res which cannot be described
114 Elastic materials
by the very simplistic model presented above. One of those fe atures is the existence of
an additional bulk wave, the so-called P2-wave, discovered theoretically already by J.
Frenkel (1944) and confirmed experimentally during the last two decades. This mode
of propagation cannot be described by equations (5.211) bec ause, like thermoelasticity
equations (5.204), the contribution of the pore pressure is described by the parabolic
equation (5.211) 2, corresponding to the heat conduction equation (5.204) 2which is par-
abolic as well.
Chapter 6
Viscoelastic materials
6.1 Viscoelastic fluids and solids
To the class of viscoelastic materials belong practically a ll elastic materials if they are
observed in sufficiently long times. The description of such m aterials contains a charac-
teristic relaxation time (or many, maybe even infinitely man y of them) and this may have
values from milliseconds to millions of years. In the latter case structural materials are
obviously considered to be elastic. Over the lengths of time required to build mountain
ranges, however, rocks appear to deform as very viscous fluid s via a process known as
slow creeping flow. Many materials such as polymers possess r elaxation times of some
hours to some years and then, of course, their viscous proper ties must be incorporated
in modelling as well. Models of viscoelastic materials deve loped from the combination of
elastic materials and viscous fluids.
Development of models of viscous fluids was initiated in time s of Isaac Newton. In
Book II of his Principia (1687) Newton formulated laws of res istance to the motion of
fluids.
The next essential step, definitions of various rheological materials including viscoelas-
tic materials was made first at the end of XIXth century. Maxwe ll, Boltzmann, Kelvin,
Voigt and many others introduced first simple and then more so phisticated models of
materials which were combinations of springs and dash-pots . We show some of them in
the next Subsection. At the end of 50th of XXth century the dev elopment of continu-
ous models began. This was initiated by works of A. E. Green, J . Ericksen and R. S.
Rivlin1and continued by B. D. Coleman, N. Gurtin, W. Noll, C. Truesde ll. Viscoelastic
1R. S. RIiscIvscIlscIiscInsc, J. L. EIrscIiscIcscIkscIsscIescInsc; Stress-deformation relations for isotropic materials, J. Rat. Mech.
Anal.,4, 323-425, 1955.
A.E.GIrscIescIescInsc,R.S.RIiscIvscIlscIiscInsc; The mechanics of non-linear materials with memory, I, Arch. Rat. Mech.
Anal.,1, 1-21, 1957.
A. E. GIrscIescIescInsc, R. S. RIiscIvscIlscIiscInsc; The mechanics of non-linear materials with memory, III, Arch. Rat.
Mech. Anal. ,1, 387-404, 1960.
A.E.GIrscIescIescInsc,R.S.RIiscIvscIlscIiscInsc,A.J.M.SIpscIescInscIcscIescIrsc; The mechanics of non-linear materials with memory,
II,Arch. Rat. Mech. Anal. ,1, 82-90, 1959.
B.D.CIoscIlscIescImscIascInsc,W.NIoscIlscIlsc ; Foundations of linear viscoelasticity, Rev. Mod. Phys. ,33, 239-249, 1961.
115
116 Viscoelastic materials
materials belong to the broader class of materials with memo ry developed in these works.
Mathematical Principles of Natural
Philosophy, London, 1687
Fig. 6.1: The beginning of Section V, Book II of Isaac Newtons ’s Mathemat-
ical Principles of Natural Philosophy (London, 1687), conta ining the model
of viscous fluids
6.1 Viscoelastic fluids and solids 117
In this Chapter, we present the main features of the viscoela sticity of solids. We
follow two classical books on the subject R. M. Christensen [ 3] and A. C. Pipkin [15].
In Fig. 6.2. we show schematically a distinction between vis coelastic solids and
viscoelastic (non-Newtonian) fluids. In the simple shear ex periment we apply to a rec-
tangle the shear deformation κ(t)=κ0H(t), whereH(t)is the Heaviside function. The
nonzero component of stretching (compare (2.65)) is then ∂κ/∂t=κ0δ(t). This means,
as shown in Part B) of the Fig. 6.2., that the shear stress in th e linear elastic material
remains constant and in the viscous fluid becomes infinite at t he initial instant of time
and then it is zero.
In the case of viscoelastic solid (see Part C) of Fig. 6.2.) th e stress would relax after
a long time to a finite value smaller than the initial value but different from zero (stress
relaxation). For a viscoelastic fluid the stress would begin with the same value as in the
case of viscoelastic solid but it would relax to zero as in the case of viscous fluid.
Fig. 6.2: Viscoelastic solids vs. fluids — stress relaxation in viscoelastic
solids and fluids
These observations will be justified on simple rheological m odels in the next Subsec-
tion and they will be incorporated in the construction of a st andard model of viscoelastic
solids.
The most important effect appearing in viscoelastic materia ls is creep. We explain this
notion on a simple example of a slab subjected to a one-step st ress history σ(t)=σ0H(t).
We show the behaviour schematically in Fig. 6.3. The respons e of an elastic solid would
beκ(t)=κ0H(t), i.e. constant shear for positive time t. In a viscous fluid, the shear
118 Viscoelastic materials
would increase at a constant rate, κ(t) =σt/η, whereηdenotes the viscosity. In a
viscoelastic material, the shear at first jumps so that the in stantaneous response is elastic.
The shear then continues to increase with a decreasing rate a nd it approaches a finite
limitκ(∞). This is the phenomenon of creep. Otherwise, if the shear inc reases linearly
in long times it is characteristic for a viscoelastic fluid.
Fig. 6.3: Behaviour of various materials under a one-step st ress history
(schematic) — creep in viscoelastic solids and fluids
The above mentioned creep effects yield the notion of memory i n the material behav-
iour. We quote here R. M. Christensen [3]: ’It is instructive to consider a situation which
represents a generalization of the response to a single sudd enly applied change of surface
traction. Suppose a material having instantaneous elastic ity and creep characteristics de-
scribed above is subjected to two nonsimultaneously applie d sudden changes in uniform
stress, superimposed upon each other. After the first applic ation of stress, but before
the second, the material responds in some time dependent man ner which depends upon
the magnitude of the first stress state. But now consider the s ituation that exists at an
arbitrary small interval of time after the sudden applicati on of the second stress state.
The material not only experiences the instantaneous respon se to the second change in
surface traction but also it experiences a continuing time d ependent response to the first
applied level of stress. An elastic material would respond o nly to the total stress level at
every instant of time. Thus, this more general type of materi al possesses a characteristic
which can be descriptively referred to as a memory effect. Tha t is, the material response
is not only determined by the current state of stress, but is a lso determined by all past
states of stress’.
Let us mention in passing that the theory of non-newtonian (v iscoelastic) fluids has
a very extensive literature which we do not quote in these not es.
6.2 Rheological models
We present here a few very simple models reflecting memory effe cts arising in viscoelas-
tic solids. Equations describing their behaviour follow as special cases of constitutive
6.2 Rheological models 119
relations for viscoelastic materials. R. M. Christensen in his book [3] presents first these
general constitutive relations and then simple rheologica l elements appear as illustration.
It seems to be more appealing to proceed the other way around.
Fig. 6.4.: Some rheological elements: spring and dashpot (u pper panel, on
top), Maxwell element (upper panel, on bottom), standard el ement (lower
panel).
The one-dimensional models are constructed by the combinat ion of springs and dash-
pot elements. The spring is an ideal elastic element obeying the linear force-extension
relation. The force and extension are analogs for stress and strain. This element fulfils
the relation
σ=G0κ. (6.1)
The dashpot is an ideal viscous element that extends at the ra te proportional to the
applied force
˙κ=dκ
dt=σ
η, (6.2)
whereηis the viscosity.
Various combinations of these two elements yield simple rhe ological models of vis-
coelastic materials. The simplest one is Maxwell’s model pr esented in Fig. 6.4. (upper
panel, on bottom). It is described by the conditions
σ=σel=σvis, κ=κel+κvis, (6.3)
σel=G0κel, σvis=η˙κvis,
120 Viscoelastic materials
with an obvious meaning of the notation. The elasticity cons tantG0,[Pa], is called in the
theory of viscoelasticity the relaxation modulus, and η,[Pa·s]is the viscosity. Relations
(6.3) yield the following constitutive equation for Maxwel l’s model
˙σ+1
τσ=G0˙κ, τ=η
G0. (6.4)
Obviously, it is an evolution equation for stresses σandτis the relaxation time. The
formal solution of this equation has the following form
σ=σ0e−t/τ−G0tintegraldisplay
0dκ
ds(t−s)e−s/τds, σ0=σ(t=0). (6.5)
For the constant stress σ=constthe equation (6.4) yields the constant rate of strain
This corresponds to the fluid-like behaviour in Fig. 6.3. The same conclusion follows in
the case of a constant strain ˙κ=0which yields the decay of stresses in time to zero. In
this case the solution of the equation (6.4) has the form σ=σ0e−t/τ.
Another model which can be simply constructed from the sprin g and dashpot is the
parallel connection. This is called the Kelvin model and it i s described by the conditions
σ=σel+σvis, κ=κel=κvis, (6.6)
σel=G0κel, σvis=η˙κvis.
This corresponds to the evolution equation for the strain κ
˙κ+1
τκ=σ
η. (6.7)
Hence, for the constant strain we obtain the elastic behavio ur. Otherwise, the formal
solution of the equation (6.7) has the form
κ=κ0e−t/τ+1
ηtintegraldisplay
0σ(t−s)e−s/τds. (6.8)
For the constant stresses σ0, this yields κ(t=0)=κ0andκ(t→∞)=σ0τ/η=σ0/G0.
This is the behaviour of the simplest viscoelastic solid (co mpare Fig. 6.3).
Another combination of springs and dashpots is the parallel combination of a spring of
elasticityG1and a Maxwell model with parameters G2,η. This is the so-called standard
rheological model. It is described by the relations
σ=σ1+σ2, κ=κ1=κM, (6.9)
σ1=G1κ1,˙σ2+η
G2σ2=G2˙κM.
These relations lead to the rate equation
˙σ+1
τ2σ=ητ1+τ2
τ1τ2parenleftbigg
˙κ+1
τ1+τ2κparenrightbigg
, τ1=η
G1, τ2=η
G2. (6.10)
6.2 Rheological models 121
This equation contains two relaxation times τ1,τ2.
In practical applications the above presented models are mu ch too simple. In order
to incorporate more relaxation times parallel arrangement s ofNMaxwell models are
constructed. This is called a generalized Maxwell model. Si milarly, by a series order
ofNKelvin models one can construct a generalized Kelvin model. The analysis of
properties of such models can be performed by the Laplace tra nsform. We shall not
present any further details concerning this subject and ref er rather to the book of D. R.
Bland2.
⋆It is instructive to investigate the form of the second law of thermodynamics for
rheological materials. In contrast to the full viscoelasti c models consequences of the
entropy inequality (4.20) can be easily found for those rheo logical cases. We consider
Maxwell’s model as an example. In the one dimensional linear case under considerations
the balance of internal energy (4.11) and the entropy inequa lity reduce to the following
form
ρ∂ε
∂t+∂q
∂x−σ∂κ
∂t=0, ρ∂η
∂t+∂
∂xparenleftBigq
TparenrightBig
≥0, (6.11)
whereqis thex-component of the heat flux and ηis the entropy density (not viscosity
in this exercise!). Combination of these two relations yiel ds
ρ∂ψ
∂t+ρη∂T
∂t+1
Tq∂T
∂x−σ∂κ
∂t≤0, ψ=ε−Tη. (6.12)
We have to write additional constitutive relations for the H elmholtz free energy ψand
the heat flux q. As we are interested in isothermal processes, the contribu tions∂T/∂t
and∂T/∂x vanish from the problem and we assume only that ψis of the following form
ψ=ψ(κ,σ). (6.13)
It is important to notice that both κandσare governed by differential equations and,
for this reason, should be treated as two independent fields. Now the inequality (6.12)
can be written in the form
ρparenleftbigg∂ψ
∂κ−σparenrightbigg∂κ
∂t+ρ∂ψ
∂σparenleftbigg
G0∂κ
∂t−σ
τparenrightbigg
≤0. (6.14)
where we have made use of (6.4). This inequality must hold for arbitrary derivatives
∂κ/∂t. Hence
∂ψ
∂κ+G0∂ψ
∂σ=σ
ρ,D=ρ
τ∂ψ
∂σσ≥0. (6.15)
The first relation can be considered to be the differential equ ation forψ. It is easy to
find its solution using the method of characteristics. It has the form
ψ=ψel(σ−G0κ)+σ2
2ρG0, (6.16)
2D.F.BIlscIascInscIdsc; The Theory of Linear Viscoelasticity , Pergamon Press, Oxford, 1960.
122 Viscoelastic materials
where independent variables are now ξ=σ−G0κandσ. The first part remains constant
along the straight lines on (σ,κ)-planes:ξ=σ−G0κ=const. This is an elastic part of
the solution. The second part of (6.15), the dissipation ine quality, yields τG0≥0, i.e.
the viscosity must be positive.
The above calculations are typical for systems with an evolu tion equation describing
additional fields in the model. In Maxwell’s model the stress σis such a field.
Let us mention in passing that the exploitation of the entrop y inequality (6.11) 2was
so easy because the constitutive relation for stresses has i n the Maxwell model the form
of differential equation. As we see further, general three-d imensional models may not
have this form. Usually they appear as functional dependenc ies. Then the evaluation
of thermodynamical restrictions requires special techniq ues, in particular the so-called
linear extensions of functionals (Fréchet derivatives). T his problem has been extensively
investigated in 60ties and it is sometimes called Coleman’s method from the name of its
founder. We shall not enter this subject in these notes. ♣
⋆Laplace transforms
We recall here the basic definitions of the Laplace transform needed in the theory
of viscoelasticity. It is well-known that many simple funct ions do not possess a Fourier
transform as the defining integrals fail to converge for infin ite limits. Therefore it is
convenient to consider not the transform of the function f(t)but rather of the function
f(t)exp(−rt). Then the transform
¯f(z)=∞integraldisplay
−∞f(t)exp(−zt)dt, z=r+iω, (6.17)
is called two-sided Laplace transform of f(t). Obviously the inverse follows by multipli-
cation of (6.17) by exp(rt)and integration
f(t)=1
2π∞integraldisplay
−∞¯f(r+iω)exp[(r+iω)t]dω. (6.18)
If we are only interested in values of f(t)fortpositive, it is sufficient to transform the
functionf(t)H(t)rather then f(t). In this manner we avoid problems with divergence
of the above integral for the lower limit of exp(−rt). Then the Laplace transform is the
cut off of the two-sided Laplace transform
¯f(z)=∞integraldisplay
0f(t)exp(−zt)dt. (6.19)
Its inverse has the form
f(t)H(t)=1
2π∞integraldisplay
−∞¯f(r+iω)exp[(r+iω)t]dω=1
2πir+i∞integraldisplay
r−i∞¯f(z)exp(zt)dz.(6.20)
6.3 Three-dimensional viscoelastic model 123
The first integral clears the meaning of the second integral. If the integral (6.19) converges
for some damping factor r=Rez, it also converges for all larger damping factors. Con-
sequently, the integral converges in some half-plane Rez > r0in the complex z−plane.
The liner=r0is called the abscissa of convergence. All values of rwhich lie to the right
ofr0are big enough for convergence. This is the very important pr operty because the
function¯f(z)has no singularity in the half-plane of convergence. Howeve r, it may have it
on the abscissa of convergence. As a consequence the integra ting¯f(z)around any closed
contour yields zero. It means that ¯f(z)is an analytic function of zin the half-plane of
convergence. This property is the basis for the calculation of inverse integrals (6.20).
Frequently used in application to viscoelasticity is the La place transform of the con-
volution integral. It is as follows3
∞integraldisplay
0
tintegraldisplay
0f(s)g(t−s)ds
bracehtipupleftbracehtipdownrightbracehtipdownleftbracehtipupright
convolution integral
exp(−zt)dt=¯f(z)¯g(z). (6.21)
Example : we consider the Maxwell model described by the evolution eq uation (6.4).
The Laplace transform of this equation yields
−σ0+z¯σ+1
τ¯σ=G0(−κ0+z¯κ). (6.22)
At the instant of the time t= 0we have the elastic reaction σ0=G0κ0.This is the
deformation of the spring in the Maxwell model before the das hpot had time to start
moving. This yields the solution of the problem in the transf ormationz−plane
¯σ=G0z
z+1/τ¯κ. (6.23)
Hence, the abscissa is crossing the point r0=−1/τ,ω=0. The half-plane to the right of
the vertical line r=r0contains no singular points of ¯σ. The inverse yields the solution
(6.5)♣
6.3 Three-dimensional viscoelastic model
Motivated by the above rheological considerations we const ruct now a constitutive model
for the three-dimensional viscoelastic continuum. We expe ct the stress tensor to depend
on the history of strain. We can formally postulate the follo wing relation
σij(t)=∞
Ψij
s=0(ekl(t−s),ekl(t)), (6.24)
3R.BIrscIascIcscIescIwscIescIlscIlsc; The Fourier Transform and Its Applications, 2nd Edition, McGraw—Hill, 1986 .
124 Viscoelastic materials
where∞
Ψij
s=0denotes a linear tensor valued functional mapping the strai n historyeij(t),
−∞ ≤t≤ ∞, into the stress history σij(t). In addition, the functional possesses
a parametric dependence upon the current value of strain eij(t)which describes the
instantaneous elastic response mentioned in the above pres ented properties of viscoelastic
materials. We do not include a dependence on the spatial vari ablexas the material
is assumed to be homogeneous. The above functional has an int egral representation
for continuous histories of strain. It follows from the Ries z representation Theorem4.
Namely, it has the form of the Stieltjes integral
σij=∞integraldisplay
0ekl(t−s)dGijkl(s), (6.25)
where each component of the fourth order tensor Gijklis of bounded variation. The
components of this tensor are called relaxation functions. The above convolution of the
constitutive law implies that it is invariant with respect t o arbitrary shifts in the time
scale. This invariance is related to the energy conservatio n but we shall not discuss it
any further in these notes.
Integral constitutive relations of this type are called the Boltzmann integrals (the
Boltzmann superposition principle).
The tensor Gijklpossesses obvious symmetries following from the symmetry o f the
stress and strain tensors
Gijkl(t)=Gjikl(t)=Gijlk(t). (6.26)
Assuming additionally the continuity of the first derivativ e of the tensor Gijkland
eij(t)=0fort<0we can write the relation (6.25) in the form
σij=Gijkl(0)ekl(t)+tintegraldisplay
0ekl(t−s)dGijkl(s)
dsds. (6.27)
This form exposes the instantaneous elastic reaction of the material. Bearing the conti-
nuity ofeij(t)in mind, we can integrate (6.27) by parts. It follows
σij=tintegraldisplay
0Gijkl(t−s)dekl(s)
dsds. (6.28)
Under the weaker assumption of a step discontinuity at t= 0one can generalize the
above relation5and obtain the following relation
σij(t)=Gijkl(t)ekl(0)+tintegraldisplay
0Gijkl(t−s)dekl(s)
dsds. (6.29)
4e.g.N.DIuscInscIfscIoscIrscIdsc,J.T.SIcscIhscIwscIascIrscItscIzsc; Linear Operators. Part I: General Theory , Interscience Publ.,
New York, 1958
5M.E.GIuscIrscItscIiscInsc,E.SItscIescIrscInscIbscIescIrscIgsc; On the linear theory of viscoelasticity, Arch. Rat. Mech. Anal. ,11,
291-356, 1962.
6.3 Three-dimensional viscoelastic model 125
In spite of the discontinuity at t=0the lower limit can be shifted from 0to−∞due to
the above mentioned shift invariance provided eij(t→−∞)→0. Integration by parts
yields then
σij(t)=tintegraldisplay
−∞Gijkl(t−s)dekl(s)
dsds. (6.30)
An alternative to the above constitutive relation is the inv erse
eij(t)=tintegraldisplay
−∞Jijkl(t−s)dσkl(s)
dsds, (6.31)
where
Jijkl(t)=Jjikl(t)=Jijlk(t), Jijkl(t)=0 for−∞<t<0. (6.32)
These functions are assumed to possess continuous first deri vatives and they are called
creep functions.
We limit all further considerations to isotropic materials . The most general isotropic
representation of the fourth order tensor contains two inde pendent parameters (compare
(5.21)). It is convenient to write it in the form
Gijkl(t)=1
3[G2(t)−G1(t)]δijδkl+1
2[G1(t)](δikδjl+δilδjk), (6.33)
whereG1(t)andG2(t)are independent relaxation functions. If we separate spher ical
and deviatoric parts of stress and strain tensors
σij=1
3σkkδij+σD
ij, σD
kk=0, (6.34)
eij=1
3ekkδij+eD
ij, eD
kk=0,
then the relation (6.30) splits in the following way
σD
ij(t) =tintegraldisplay
−∞G1(t−s)deD
ij(s)
dsds, (6.35)
σkk=tintegraldisplay
−∞G2(t−s)dekk(s)
dsds.
Similarly, the inverse relations obtain the form
eD
ij(t) =tintegraldisplay
−∞J1(t−s)dσD
ij(s)
dsds, (6.36)
ekk=tintegraldisplay
−∞J2(t−s)dσkk(s)
dsds.
126 Viscoelastic materials
whereJ1(t),J2(t)are two independent isotropic creep functions. Obviously, the func-
tionsG1,J1are appropriate for shear processes and G2,J2for dilatation processes.
The relaxation and creep functions are, of course, related t o each other. The easiest
way to find this relation is to perform the Laplace transforma tion on relations (6.35) and
(6.36)6. We obtain
¯σD
ij=z¯G1¯eD
ij,¯σkk=z¯G2¯ekk, (6.37)
¯eD
ij=z¯J1¯σD
ij,¯ekk=z¯J2¯σkk.
These relations imply
Jα=parenleftbig
z2Gαparenrightbig−1, α=1,2. (6.38)
The isotropic relations for elastic materials (5.21), (5.2 6) can be written in the form
σkk= 3Kekk, σD
ij=2µeD
ij, (6.39)
ekk=1
3Kσkk, eD
ij=1
2µσD
ij.
They would suggest that Jα(t) = [Gα(t)]−1. Relations (6.38) show that this is not
correct. However, it can be shown using properties of the Lap lace transform that limit
values indeed satisfy such relations
lim
t→0Jα(t)=lim
t→0[Gα(t)]−1,lim
t→∞Jα(t)= lim
t→∞[Gα(t)]−1. (6.40)
Incidentally, to be consistent with the linear elasticity o f isotropic materials relations
(6.39) suggest the following notation for relaxation and cr eep functions
µ(t)=G1(t)/2, K(t)=G2(t)/3. (6.41)
The above presented results suggest a useful short-hand not ation for Stieltjes convo-
lution integrals which has been introduced by Gurtin and Ste rnberg in the earlier quoted
paper. Namely, we write instead of (6.25) the following rela tion
σij=ekl∗dGijkl, (6.42)
i.e. we write for two arbitrary functions f,g
f∗dg=tintegraldisplay
−∞f(t−s)dg(s), g(t→−∞)=0, (6.43)
6It should be mentioned that, instead of the classical Laplac e transform (6.19) it may be more
convenient to use a modification which is called Laplace-Car son transform. It is defined by the relation
¯f(z)=z∞/integraldisplay
0f(t)exp(−zt)dt.
It is applied in the presentation of viscoelasticity by Lema itre and Chaboche [9]. We follow here rather
the older approach of Christensen [3] and Pipkin [15].
6.3 Three-dimensional viscoelastic model 127
wheref(t)is continuous for 0 ≤t≤∞. Iff(t) = 0 fort <0then one can show the
commutativity relation
f∗dg=g∗df. (6.44)
Consequently,
σij=Gijkl∗dekl,
which is the counterpart of (6.30).
The above notation leads to the following useful identities
f∗d(g∗dh) = (f∗dg)∗dh=f∗dg∗dh, (6.45)
f∗d(g+h) =f∗dg+f∗dh.
We shall not enhance the subject of a general theory of materi als with memory. This
can be found in classical monographs on the subject7.
We proceed to investigate an example which helps to clear the distinction between
the viscoelastic fluid and the viscoelastic solid. We consid er the case of the simple shear
defined by the relation (2.95). The amount of shear κ=κ0H(t)is assumed to be the
step function in time and it yields the stretching (2.65) in t he linear theory to be identical
with the time derivative of strain which is given by the rate o f shearing˙κ=κ0δ(t)
Dijei⊗ej=deij
dtei⊗ej=˙κ
2(e1⊗e2+e2⊗e1). (6.46)
Hence,
σD
12=κ0
2tintegraldisplay
0G1(t−s)δ(s)ds=κ0
2G1(t), G1(t)=0fort<0. (6.47)
It follows from the definition of a linear isotropic viscoela stic solid that the following
condition must hold
lim
t→∞G1(t)→nonzero constant ⇒solids. (6.48)
On the other hand, for viscoelastic (non-Newtonian) fluid
lim
t→∞G1(t)=0⇒fluids. (6.49)
The latter condition is necessary but not sufficient. In addit ion, the relaxation function
G1must fulfil a condition for the steady state flow. Then the visc oelastic fluid at large
values of time, where the steady state will be achieved, must behave like a viscous fluid
of the viscosity η. Hence, the relaxation time must have the property
η=1
2∞integraldisplay
0G1(s)ds(fluids). (6.50)
7C.TIrscIuscIescIsscIdscIescIlscIlsc,W.NIoscIlscIlsc; The Non-Linear Field Theories of Mechanics, Encyclopedia of Physics,
vol. III/3, S. Flügge (ed.), Springer, Berlin, 1965,
C. TIrscIuscIescIsscIdscIescIlscIlsc; A First Course in Rational Continuum Mechanics, The Johns Hopkins University
Press, Baltimore, 1972 (Chapter XIII).
128 Viscoelastic materials
6.4 Differential constitutive relations
We have seen on examples the simple rheological models that c onstitutive relations of
these models may have the form of evolution equations (rate- type constitutive relations).
This can be taken over to the description of a three-dimensio nal continuum. Let us
consider the following differential operator
p0σD
ij+p1dσD
ij
dt+p2d2σD
ij
dt2+...=q0eD
ij+q1deD
ij
dt+q2d2eD
ij
dt2+..., (6.51)
or, in the compact form,
P(D)σD
ij=Q(D)eD
ij, P(D)=Nsummationdisplay
k=0pkDk, Q(D)=Nsummationdisplay
k=0qkDk, Dk=dk
dtk.(6.52)
This type of operators appear, for instance, for generalize d Maxwell and Kelvin models
mentioned before. In order to see the significance of such mod els for viscoelasticity we
take the Laplace transform of (6.52)
¯P(z)¯σD
ij−1
zNsummationdisplay
k=1pkNsummationdisplay
r=1zrbracketleftBigg
dk−rσD
ij
dtk−r(t=0)bracketrightBigg
= (6.53)
=¯Q(z)¯eD
ij−1
zNsummationdisplay
k=1qkNsummationdisplay
r=1zrbracketleftBigg
dk−reD
ij
dtk−r(t=0)bracketrightBigg
,
where
¯P(z)=Nsummationdisplay
k=0pkzk,¯Q(z)=Nsummationdisplay
k=0qkzk. (6.54)
These relations follow easily by integration by parts. If we compare these relations with
(6.37) then they specify the relaxation function by the form ula
z¯G1=¯Q(z)/¯P(z), (6.55)
provided the initial conditions are constraint by the relat ions
Nsummationdisplay
r=kprbracketleftBigg
dk−rσD
ij
dtk−r(t=0)bracketrightBigg
=Nsummationdisplay
r=kqrbracketleftBigg
dk−reD
ij
dtk−r(t=0)bracketrightBigg
, k=1,2,...,N. (6.56)
Consequently the relaxation function G1is specified in terms of 2(N+1)parameters
p0,...,pN,q0,...,qNwhich are related to a sequence of relaxation times. Similar relations
can be introduced for the dilatational part of stress and str ain
L(D)σkk(t)=M(D)ekk(t), (6.57)
and these are again specified by a finite sequence of parameter s.
6.5 Steady state processes and elastic-viscoelastic corre spondence principle 129
The question if such models can be indeed physically plausib le is not simple. Some
models of this art, introduced for non-Newtonian fluids (the so-called Rivlin-Ericksen flu-
ids) show that there appear problems of stability8and convergence9for dynamic processes
and these models seem to work well for steady state flows. Ther e are claims that non-
Newtonian fluids require always the spectrum of infinitely ma ny relaxation times and,
consequently, such polynomial models as (6.52) are physica lly useless.
For viscoelastic solids a simple differential model is often based on the simplest dif-
ferential equation describing the evolution of stresses. T his is analogous to the Maxwell
model (6.4) constructed within the classical rheology. It i s based on the equation for
stresses
τdσD
ij
dt+σD
ij=2ηdeD
ij
dt, (6.58)
whereτis the relaxation time and ηis the viscosity. It is the so-called standard linear
viscoelastic solid [21]
6.5 Steadystateprocessesandelastic-viscoelasticcor-
respondence principle
Now we investigate a class of problems which appear in spectr al analysis of waves in
which we seek solutions in the form of monochromatic waves. I t is then important to
know the behaviour of the constitutive relation (6.35) if th e time dependence of the strain
is harmonic. We denote representatives of deviatoric and sp herical strains and stresses
by˜eand˜σ, respectively, and assume
˜e=˜e0eiωt, (6.59)
whereωis the frequency and ˜e0an amplitude. We write the typical contribution to
(6.35) in the following form
˜σ=tintegraldisplay
−∞Gα(t−s)d˜e
dsds, (6.60)
whereα=1or2in dependence of the choice of ˜σ. It is convenient to split the relaxation
modulus into two parts: G0
αandG1α, where the first part is equal to the limit of the
relaxation modulus for t→∞and, consequently, G1
α(t→∞)=0. Both parts are zero
for the time smaller than 0. Hence
˜σ=G0
α˜e0eiωt+iω˜e0tintegraldisplay
−∞G1α
(t−s)eiωsds. (6.61)
8D. JIoscIsscIescIpscIhsc; Instability of the rest state of fluids of arbitrary grade gre ater than one, Arch. Rat.
Mech. Anal., 75,251-256, 1981 .
9R.S.RIiscIvscIlscIiscInsc,K.WIiscIlscImscIascInscIsscIkscIisc; The passage from memory functionals to Rivlin-Ericksen con stitutive
equations, ZAMP, 38, 624-629, 1987
as well asK.WIiscIlscImscIascInscIsscIkscIisc [21]
130 Viscoelastic materials
Changing the variables η=t−swe obtain
˜σ=
G0
α+ω∞integraldisplay
0G1α(η)sinωηdη+iω∞integraldisplay
0G1α(η)cosωηdη
˜e0eiωt. (6.62)
Consequently, the stress ˜σis given by the complex modulus G∗
α
˜σ=G∗
α˜e0eiωt,
ReG∗
α=G0α+ω∞integraldisplay
0G1α(η)sinωηdη, (6.63)
ImG∗
α=ω∞integraldisplay
0G1α(η)cosωηdη.
The real part is called the storage modulus and the imaginary part the loss modulus.
The integration by parts yields the frequency limit behavio ur of the above moduli.
We have
ReG∗α(ω) =G0α+G1α(0)+∞integraldisplay
0dG1
α(η)
dηcosωηdη, (6.64)
ImG∗
α(ω) =−∞integraldisplay
0dG1
α(η)
dηsinωηdη.
Hence
ReG∗
α(ω=0)=G0α=Gα(t)|t→∞,ImG∗α(ω=0)=0. (6.65)
For the other limit, changing the variables ωη=τwe easily obtain
ReG∗α(ω→∞)=G0α+G1α(t=0)=Gα(t)|t→0,ImG∗α(ω→∞)=0.(6.66)
These relations show that for very high frequency the viscoe lastic solid behaves as an
elastic solid. The same concerns very low frequencies and th is differs solids from viscous
fluids.
The above considerations determine, obviously, the Fourie r transforms of the consti-
tutive relations. With the definitions for an arbitrary func tionf
¯f(ω)=∞integraldisplay
−∞f(t)e−iωtdt, f(t)=1
2π∞integraldisplay
−∞¯f(ω)eiωtdω, (6.67)
we have
¯σD
ij(ω) =G∗1(iω)¯eD
ij(ω), (6.68)
¯σkk=G∗2(iω)¯ekk(ω).
6.5 Steady state processes and elastic-viscoelastic corre spondence principle 131
The similarity of these relations to the elastic relations ( 6.39) is called the elastic-
viscoelastic correspondence principle . It has been first ob served by W. T. Read in
195010. With respect to the important practical aspects of this pri nciple we present it as
well for the Laplace transform.
Let us consider the full set of governing equations describi ng the boundary value
problem of a linear isotropic viscoelastic material. We hav e
eij=1
2parenleftbigg∂ui
∂xj+∂uj
∂xiparenrightbigg
, (6.69)
∂σij
∂xj+ρbi=0,forx∈Bt (6.70)
σD
ij(t)=2tintegraldisplay
−∞µ(t−s)∂eD
ij
∂sds, σkk=3tintegraldisplay
−∞K(t−s)∂ekk
∂sds, (6.71)
σij=1
3σkkδij+σD
ij, eij=1
3ekkδij+eD
ij, (6.72)
σij(t)nj=tn
iforx∈∂Bσ
t, ui(t)=uniforx∈∂Bu
t, (6.73)
ui(t)=eij(t)=σij(t)=0 for−∞<t<0, (6.74)
where we have used the notation (6.41) for the relaxation mod uli.
Laplace transform of these equations has the form
¯eij=1
2parenleftbigg∂¯ui
∂xj+∂¯uj
∂xiparenrightbigg
, (6.75)
∂¯σij
∂xj+ρ¯bi=0,forx∈Bt (6.76)
¯σD
ij(t)=2z¯µ(z)¯eD
ij¯σkk=3z¯K(z)¯ekk, (6.77)
¯σij=1
3¯σkkδij+¯σD
ij,¯eij=1
3¯ekkδij+¯eD
ij, (6.78)
¯σij(z)nj=¯tniforx∈∂Bσ
t,¯ui(z)=¯uniforx∈∂Bu
t, (6.79)
wherezis the transformation variable and bars denote Laplace tran sforms.
Obviously the set (6.75)-(6.79) has a form identical with eq uations of linear elasticity
except of complex moduli z¯K(z),z¯µ(z)which replace real moduli K,µof the elasticity
theory. This correspondence reveals the possibility of con verting numerous static solu-
tions of elasticity into quasi-static solutions of viscoel asticity. The main problem is now
the inversion of the Laplace transform.
One more general remark is appropriate for quasi-static pro blems of viscoelastic mate-
rials. Before we formulate it, let us collect the material fu nctions corresponding to the ma-
terial constants of elasticity. We have already the relatio ns (6.41), i.e. µ(t)=G1(t)/2,
10W. T. RIescIascIdsc; Stress analysis for compressible viscoelastic materials, J, Appl. Phys. , 21, 671-674,
1950.
132 Viscoelastic materials
K(t)=G2(t)/3and they yield in the transformed form (compare (5.29))
¯λ(z) =¯K(z)−2
3¯µ(z)=1
3parenleftbig¯G2(z)−¯G1(z)parenrightbig
,
¯E(z) = =3¯µ(z)¯K(z)
¯K(z)+1
3¯µ(z)=3¯G1(z)¯G2(z)
2¯G2(z)+¯G1(z), (6.80)
¯ν(z) =¯λ(z)
2parenleftbig¯λ(z)+¯µ(z)parenrightbig=¯G2(z)−¯G1(z)
2¯G2(z)+¯G1(z).
The question arises if we can apply the method of separation o f variables in a quasi-
static problems of linear viscoelasticity. It means that, f or instance, the displacement
should have the form
ui(x,t)=ˇui(x)u(t), (6.81)
whereu(t)is a common function for all components of the displacement. Hence, if we
neglect the acceleration (quasi-static problem!) and body forces, the field equations for
displacements have the form
∂2ˇui
∂xk∂xktintegraldisplay
−∞µ(t−s)du(s)
dsds+∂2ˇuk
∂xi∂xktintegraldisplay
−∞[λ(t−s)+µ(t−s)]du(s)
dsds=0.(6.82)
Obviously, the time contributions must be eliminated from t his equation and this yields
λ(t)+µ(t)=βµ(t), β=const. (6.83)
This yields immediately that Poisson’s ratio νmust be independent of time. Bearing the
last relation (6.80) in mind, we obtain the restriction
G2(t)
G1(t)=1+ν
1−2ν=const. (6.84)
In the similar manner we can prove that the ratio of creep func tions is a constant
J2(t)
J1(t)=1−2ν
1+ν=const. (6.85)
These two conditions are necessary for the applicability of the method of separation of
variables.
⋆We demonstrate the application of the correspondence princ iple on a simple ex-
ample. We consider the axial symmetric problem of the cylind er under the given radial
loading on both lateral surfaces. The outer surface is press urized by an elastic case11.
The Laplace transform of the radial displacement ¯ur(r,z)must fulfil the equation (see:
(5.44))
∂2¯ur
∂r2+1
r∂¯ur
∂r−¯u
r2=0, (6.86)
11R. M. CIhscIrscIiscIsscItscIescInscIsscIescInsc, R. N. SIcscIhscIrscIescIiscInscIescIrsc; Response to pressurization of a viscoelastic cylinder with
an eroding internal boundary, AIAA J. ,3, 1451, 1965.
6.5 Steady state processes and elastic-viscoelastic corre spondence principle 133
with the solution
¯ur=¯C(z)r+¯D(z)
r. (6.87)
In order to apply the boundary conditions, we have to write st ress-strain relations in
the transformed form. We have by the correspondence princip le
¯σrr= 2z¯µparenleftbigg∂¯ur
∂r+z¯ν
1−2z¯ν¯eparenrightbigg
,¯e=∂¯ur
∂r+¯ur
r,
¯σθθ= 2z¯µparenleftbigg¯ur
r+z¯ν
1−2z¯ν¯eparenrightbigg
, (6.88)
¯σzz=2z2¯ν¯µ
1−2z¯ν.
The boundary conditions for the pressurized cylinder have t he form
σrr(r=a,t) =−p(t), σrr(r=b,t)=−q(t), (6.89)
u(r=b,t) =q(t)bracketleftBigg
b2parenleftbig
1−ν2
cparenrightbig
EchbracketrightBigg
,
whereEc,νcare elastic properties of the case, his its thickness, bthe outer radius and
athe inner radius of the viscoelastic cylinder.
Easy calculations yield the following form of the transform ed stresses
¯σrr=C1−b2
r2C2,¯σθθ=C1+b2
r2C2,¯σzz=2z¯νC1, (6.90)
where
C1=−¯p(S−z¯µ)
(S−z¯µ)+(b2/a2)[S(1−2z¯ν)+z¯µ],
C2=¯p[S(1−2z¯ν)+z¯µ]
(S−z¯µ)+(b2/a2)[S(1−2z¯ν)+z¯µ], (6.91)
S=Ech
2b(1−ν2c).
Inverse transformations performed in the quoted work of Chr istensen and Schreiner
were made under the assumption that the modulus ¯µis a polynomial in zand the Poisson
numberνis constant (see above). The polynomial form of ¯µfollows from the following
considerations suggested by rheological models. It is assu med that the modulus µ(t)has
the form
µ(t)=G0+Nsummationdisplay
n=1Gne−t/τn, (6.92)
whereG0,Gn,τn,n= 1,...,N are constants. Obviously, τnhave the interpretation of
relaxation times. The values of these parameters are obtain ed by fitting to experimental
134 Viscoelastic materials
data (e.g. for harmonic torsional loading experiments of cy lindrical samples). Laplace
transform of (6.92) yields
z¯µ(z)=A(z)
Nproductdisplay
n=1(z+1/τn), (6.93)
whereA(z)is anNthgrade polynomial in zdetermined by coefficients Gn.
Now the inverse transformation can be made by the technique o f integration of the
function¯f(z) =P(z)/Q(z)whose denominator yields simple pole singularities (i.e.
zeros ofQ(z)) in the complex domain. We shall not quote rather complex fina l results.♣
Chapter 7
Plasticity
7.1 Introduction
Various plasticity models of mechanics are developed to des cribe a class of permanent
deformations. These deformations are generated during loa ding processes and remain
after the removal of the load. In this Chapter we present a few aspects of the classical
linear plasticity. This model is based on the assumption on t he additive separation of
elastic and plastic deformation increments. In nonlinear m odels it is the deformation
gradientFin which these permanent deformations are separated
F=FeFp, (7.1)
where the plastic deformation is described by Fpand the elastic part is Fe. Only the
product of these two objects is indeed the gradient of the fun ction of motion f. Neither
FenorFpcan be written in such a form — they are not integrable. In spit e of this
problem, material vectors transformed by Fpform a vector space for each material point
X∈B0and these spaces are sometimes called intermediate configur ations. We shall not
elaborate these issues of nonlinear models1. However, it should be mentioned that the
assumption (7.1) indicates the additive separation of incr ements of deformation in the
linear model. Namely, the time derivative of the deformatio n gradient has, obviously,
the form
˙F=˙FeFp+Fe˙Fp, (7.2)
which yields for small strains
˙e=˙ ee+˙ ep, (7.3)
where˙eeis the elastic strain rate and ˙ epis the plastic strain rate. In some older models it
is even assumed that this additive decomposition concerns s trains themselves: e=ee+ep
which is obviously much stronger than (7.3) and yields certa in general doubts.
1e.g. see:AIlscIbscIrscIescIcscIhscItsc BIescIrscItscIrscIascImsc; Elasticity and Plasticity of Large Deformations , Springer Berlin,
2008.
135
136 Plasticity
The aim of the elastoplastic models in the displacement form ulation is to find the
displacement vector uwhose gradient defines the strain e— as in the case of linear
elasticity, and the plastic strain epwhich becomes an additional field.
Fig. 7.1: States of material in the stress space Σ.A— the elastic state, B
— the plastic state.
The most fundamental characteristic feature of classical p lasticity is the distinction of
an elastic domain in the space of stresses Σ={T},T=σijei⊗ej. All paths of stresses
which lie in the elastic domain produce solely elastic defor mations, i.e. after inverting
the process of loading the material returns to its original s tate. This is schematically
shown in Fig. 7.1.
The elastic domain lies within the bounding yield surface al so called the yield limit or
the yield locus. Stress states which lie beyond this limit ar e attainable only by moving
the whole yield surface. Such processes are called hardenin g. In Fig. 7.1. we demonstrate
the so-called isotropic hardening. We return to this notion in the sequel. Increments of
plastic strains are described by stresses whose direction p oints in the outward direction
of the yield surface. This is related to the so-called Drucke r2stability postulate which
we present further.
The above described way of construction of plasticity is som etimes called stress space
formulation and it was motivated by properties of metals. Th ere is an alternative which
has grown up from soil mechanics3. Such materials as rocks, soils and concrete reveal
softening behaviour which violates Drucker’s postulate. I n order to avoid this problem,
the so-called strain space formulation4was developed in which, instead of Drucker’s
postulate one applies the Ilyushyn5postulate. The detailed discussion of these stability
problems can be found, for instance, in the book of Wu [24].
2D.C.DIrscIuscIcscIkscIescIrsc; A more fundamental approach to plastic stress-strain relat ions, in:Proc. 1st Nat.
Congress Appl. Mech., ASME, 487, 1951.
3This formulation has been initiated by the work: Z.MIrscIoacutescIzsc ; Non-associated flow laws in plasticity,
Journ. de Mecanique ,2, 21-42, 1963.
4J.CIascIsscIescIysc,P.M.NIascIgscIhscIdscIisc; On the nonequivalence of the stress space and strain space fo rmulations
of plasticity theory, J. Appl. Mech. ,50, 350, 1983.
5A.A.IIlscIyscIuscIsscIhscIiscInsc; On the postulate of plasticity, PMM, 25, 503, 1961.
7.1 Introduction 137
Fig. 7.2: Schematic plastic behaviour of various materials
In Fig. 7.2. we show schematically strain-stress curves for different types of materials.
The steepest curve in both pictures correspond to the so-cal led brittle materials which
practically do not reveal any plastic deformations prior to failure. Their deformations
under high loading are small and they absorb only a little ene rgy before breaking. It
should be underlined that many materials may behave this way in low temperatures
whereas their properties are very different in high temperat ures. This transition explains
mysterious catastrophes of Liberty ships in 40th of the XXth century.
The curves for ductile materials in Fig. 7.2. correspond to m aterials for which the
classical plasticity was developed. They possess relative large irreversible deformations
and by failure absorb a large amount of energy. Therefore the y are called tough.
138 Plasticity
Many damages and accidents of cargo
vessels were occurred, and especially
for Liberty Ships. The vast majority
of the sea accidents were related
to brittle fracture. By 1st of April 1946,
1441 cases of damage had been reported
for 970 cargo vessels, 1031 of which were
to Liberty Ships. Total numbers of 4720
damages were reported. Seven ships were
broken in two, e.g. "Schenectady".
7.2 Plasticity of ductile materials
We proceed to specify the yield surface in the stress space. A s mentioned above this stress
formulation was primarily motivated by plastic deformatio ns of metals. In such materials
the pressure phas practically no influence on plastic strains which means t hat the yield
surface should be described only by the stress deviator: σD
ij=σij+pδij, p=−1
3σkk.
The eigenvalues of the stress deviator follow from the eigen value problem
parenleftbig
σD
ij−sδijparenrightbig
nj=0, (7.4)
and the solutions must satisfy the condition
Is=s(1)+s(2)+s(3)=0. (7.5)
The eigenvalues s(α)and the eigenvalues σ(α)of the full stress tensor σijare, of course,
connected by the relation
σ(α)=s(α)−p, α=1,2,3. (7.6)
For the purpose of formulation of various hypotheses for the yield surface, it is con-
venient to calculate invariants of the stress deviator and t he maximum shear stresses.
As presented in Subsection 3.2.4 (compare the three-dimens ional Mohr circles), the ex-
tremum values of shear stress are given by the differences of t hree principal values of the
stress tensor (radii of Mohr’s circles)
τ(1)=σ(2)−σ(3)
2, τ(2)=σ(1)−σ(3)
2, τ(3)=σ(1)−σ(2)
2. (7.7)
Hence, we have as well
τ(1)=s(2)−s(3)
2, τ(2)=s(1)−s(3)
2, τ(3)=s(1)−s(2)
2. (7.8)
7.2 Plasticity of ductile materials 139
Further we use the sum of squares of these quantities. In term s of invariants of the stress
tensor and of the stress deviator it has the form
3summationdisplay
α=1parenleftBig
τ(α)parenrightBig2
=3
2bracketleftbigg1
3I2
σ−IIσbracketrightbigg
=−3
2IIs=1
2σ2
eq, σeq=radicalbigg
3
2σD
ijσD
ij,(7.9)
whereσeq=σ(1)in the uniaxial tension/compression for which σ(2)=σ(3)= 0. It
is clear that the second invariant of the deviatoric stresse s must be negative. These
relations follow from the definitions of the invariants
Iσ=σkk=−3p, IIσ=1
2parenleftbigI2
σ−σijσijparenrightbig, IIIσ=det(σij), (7.10)
Is= 0, IIs=−1
2σD
ijσD
ij=−J2=−σ2
eq
3, IIIs=J3=detparenleftbigσD
ijparenrightbig.
The quantity σeq=√3J2is called the equivalent (effective) stress.
Now, we are in the position to define the elastic domain in the s pace of stresses. It
is convenient to represent it by a domain in the three-dimens ional space of principal
stresses. In this space we choose the principal stresses σ(1),σ(2),σ(3)as coordinates. The
assumption that the pressure does not influence plastic stra ins means that yield surfaces
in this space must be cylindrical surfaces with generatrix p erpendicular to surfaces s(1)+
s(2)+s(3)=0, i.e.σ(1)+σ(2)+σ(3)+3p=0.The axis of those cylinders is, certainly,
the straight line σ(1)=σ(2)=σ(3). This line is called the hydrostatic axis. In general,
we can write the equation of the yield surface in the form
fparenleftbigJ2,J3,ep
ij,κ,Tparenrightbig=0, (7.11)
with the parametric dependence on the plastic strain ep
ij,temperature Tand the harden-
ing parameter κ. We return to these parameters later. Two examples of yield s urfaces,
discussed further in some details, are shown in Fig. 7.3.
It is also convenient to introduce a normal (perpendicular) vector to the yield surface
in the stress space given by its gradient in this space, i.e.
N=∂f
∂Tvextendsinglevextendsinglevextendsingle∂f
∂Tvextendsinglevextendsinglevextendsingle,i.e.Nij=∂f
∂σijradicalBig
∂f
∂σkl∂f
∂σkl. (7.12)
Then we can introduce local coordinates in which the yield fu nctionfidentifies the elastic
domain of the Σ-space assuming there negative values, i.e. for all elastic processesf <0.
We skip here the presentation of the history of the definition of yield surfaces which
goes back to Galileo Galilei. There are two fundamental form s of this surface which are
still commonly used in the linear plasticity of solids. The o lder one was proposed by H.
Tresca in 1864 and it is called Tresca-Guest surface. Its equ ation has the form
max
αvextendsinglevextendsinglevextendsingleτ(α)vextendsinglevextendsinglevextendsingle=σ0⇒σ(1)−σ(3)=2σ0>0, (7.13)
whereσ0is the material parameter and we have ordered the principal s tressesσ(1)≥
σ(2)≥σ(3). It means that the beginning of the plastic deformation appe ars in the point of
140 Plasticity
the maximum shear stress. In the space of principal stresses it is a prism of six sides and
infinite length (see: Fig. 7.3.). The parameter σ0may be dependent on all parameters
listed in the general relation (7.11).
Fig. 7.3: Yield surfaces in the space of principal stresses
The second yield surface was proposed in 1904 by M. T. Huber6and then rediscovered
in 1913 by R. von Mises and H. von Hencky. It says that the limit of elastic deformation
is reached when the energy of shape changes (distortion ener gy) reaches the limit value
ρεY. The distortion energy ρεDis defined as a part of the full energy of deformation ρε
reduced by the energy of volume changes ρεV(e.g. compare (5.175)). We have
ρε=1
2σijeij=1
2parenleftBigg
σijσkk
9Kδij+σijσD
ij
2µparenrightBigg
=
=1
2KparenleftBigσkk
3parenrightBig2
+1
4µparenleftbigσD
ijσD
ijparenrightbig⇒ρεV=p2
2K, ρεD=1
4µparenleftbigσD
ijσD
ijparenrightbig, (7.14)
i.e.ρεD=ρεY⇒ρεY=1
4µparenleftbig
σD
ijσD
ijparenrightbig
=σ2
eq
6µ.
Making use of the identity, following from (7.5),
3parenleftBig
s(1)s(2)+s(1)s(3)+s(2)s(3)parenrightBig
=−1
2bracketleftbiggparenleftBig
s(1)−s(2)parenrightBig2
+parenleftBig
s(1)−s(2)parenrightBig2
+parenleftBig
s(1)−s(2)parenrightBig2bracketrightbigg
,
(7.15)
6M. T. HIuscIbscIescIrsc; Przyczynek do podstaw wytrzymało ´sci,Czasop. Techn. , Lwów,22, 1904. Due to
the publication of this work in Polish it remained unknown un til the hypothesis was rediscovered by von
Mises and von Hencky.
7.2 Plasticity of ductile materials 141
we obtain
σD
ijσD
ij=1
3bracketleftbiggparenleftBig
s(1)−s(2)parenrightBig2
+parenleftBig
s(1)−s(2)parenrightBig2
+parenleftBig
s(1)−s(2)parenrightBig2bracketrightbigg
. (7.16)
Consequently, bearing (7.6) in mind, the yield limit is reac hed when the principal stresses
fulfil the condition
3σD
ijσD
ij=parenleftBig
σ(1)−σ(2)parenrightBig2
+parenleftBig
σ(2)−σ(3)parenrightBig2
+parenleftBig
σ(1)−σ(3)parenrightBig2
=2σ2Y, (7.17)
i.e.σeq=σY,
where
σY=radicalbig
6µρεY, (7.18)
is the yield limit ( σ(1)=σYin uniaxial tension, i.e. for σ(2)=σ(2)=0). It means that
for processes in which σeq<σYall states are elastic ( f <0) and otherwise the system
develops plastic deformations. Clearly, the relation (7.1 7) defines a circular cylinder in
the space of principal stresses. Its axis is again identical with the line σ(1)=σ(2)=σ(3),
it is extended to infinity and it has common generatrix with th e prism of Tresca as shown
in Fig. 7.3.
⋆In order to compare analytically both definitions of the yiel d surface we show that
the yield stress σYcalculated by means of the distortion energy of the Huber-Mi ses-
Hencky hypothesis (7.17) is not bigger than the material par ameter2σ0of the Tresca
hypothesis (7.13). Let us write (7.17) in the following form
σY=1√
2radicalBigparenleftbigσ(1)−σ(2)parenrightbig2+parenleftbigσ(2)−σ(3)parenrightbig2+parenleftbigσ(1)−σ(3)parenrightbig2=
=vextendsinglevextendsingleσ(1)−σ(3)vextendsinglevextendsingle
√
2radicalBiggparenleftbiggσ(1)−σ(2)
σ(1)−σ(3)parenrightbigg2
+parenleftbiggσ(2)−σ(3)
σ(1)−σ(3)parenrightbigg2
+1=
=vextendsinglevextendsingleσ(1)−σ(3)vextendsinglevextendsingle
√
2radicalBiggparenleftbigg1−µσ
2parenrightbigg2
+parenleftbigg1+µσ
2parenrightbigg2
+1=
=vextendsinglevextendsinglevextendsingleσ(1)−σ(3)vextendsinglevextendsinglevextendsingleradicalbigg
3+µ2σ
4, (7.19)
where
µσ=2σ(2)−parenleftbigσ(1)+σ(3)parenrightbig
σ(1)−σ(3), (7.20)
is the so-called Lode parameter which describes an influence of the middle principal
stressσ(2). Obviously−1≤µσ≤1which corresponds to σ(2)=σ(3)for the lower
bound, and σ(2)=σ(1)for the upper bound. It plays an important role in the theory o f
civil engineering structures. Hence
σY≤vextendsinglevextendsinglevextendsingleσ(1)−σ(3)vextendsinglevextendsinglevextendsingle=2σ
0.♣ (7.21)
142 Plasticity
⋆We demonstrate on a simple example an application of the noti on of the yield
stress. We consider a circular ring of a constant thickness w ith external and internal
radiiaandb, respectively, and an external loading by the pressures paandpbon these
circumferences. We check when the material of the ring reach es in all points the yield
stress according to the Huber-Mises-Hencky hypothesis. Th is is the so-called state of the
load-carrying capacity of this structure.
This is the axial symmetric problem of plane stresses. Conse quently, the principal
stresses in cylindrical coordinates are given by σ(1)=σrr,σ(2)=σθθ,σ(3)=0. These
components of stresses must fulfil the equilibrium conditio n (momentum balance (5.43))
dσrr
dr+σrr−σθθ
r=0, (7.22)
and, according to (7.17), at each place of the ring
(σrr−σθθ)2+(σrr)2+(σθθ)2=2σ2
Y. (7.23)
By means of (7.22) we eliminate the component σθθof stresses and obtain the following
equationparenleftbigg
rds
drparenrightbigg2
+sparenleftbigg
rds
drparenrightbigg
+s2−1=0, s=σrr
σY√
2. (7.24)
Solution of this quadratic equation with respect to the deri vativeds/dr yields
ds
dr=−s
2r±1
2rradicalbig
4−3s2. (7.25)
Consequently
ds
−s±√
4−3s2=dr
2r. (7.26)
As we have to require |s|<2/√
3we can change the variables
s=2√
3sinϕ, (7.27)
and this yields
−dϕ
tanϕ∓√
3=dr
2r. (7.28)
Hence, we obtain two solutions but only one of them is real and it has the form
r=Cradicaltpradicalvertexradicalvertexradicalvertexradicalvertexradicalvertexradicalvertexradicalbt1+3s2
4−3s2radicalBigg
s√
3
4−3s2+√
3expbracketleftBigg
−√
3
2arctans√
3√
4−3s2bracketrightBigg
, (7.29)
whereCis the constant of integration.
7.2 Plasticity of ductile materials 143
The construction of solution is shown in Fig. 7.4. in arbitra ry units. For the radius b
the value of the radial stress is given by σr=−pb. We adjust the curve described by the
relation (7.29) in such a way that it intersects the point (−pb,b)indicated by the circle
in Fig. 7.4. This yields the value of the constant Cin the solution. Then for the given
value of the radius awe find the value of the pressure pawhich yields the limit value for
the load of this structure, i.e. its load-carrying capacity .
Fig. 7.4: Construction of solution for the load-carrying ca pacity of the ring ♣
Yield surfaces impose conditions on elastic solutions unde r which the system possesses
only elastic strains. In some design problems this is alread y sufficient. However, many
engineering structures admit some plastic deformations — f or example, in the case of
concrete it is the rule — and then we have to find a way to describ e the evolution of
plastic strains ep.We proceed to develop such models.
First of all, we have to define not only the shape of the yield su rface in the stress space,
as we did above, but also its dependence on parameters listed in (7.11). We indicate here
a few important examples. It is convenient to write the yield function in the form
fparenleftbig
J2,J3,ep
ij,κ,Tparenrightbig
=F(J2,J3)−σYparenleftbig
ep
eq,κ,Tparenrightbig
=0, (7.30)
whereσYis the yield limit in the uniaxial tension/compression test for which
σ22=σ33=σ(2)=σ(3)=0⇒σeq=σ(1)=σ11, (7.31)
˙ep
11=−2˙ep
22=−2˙ep
33,˙ep
ij=0fori/negationslash=j⇒˙ep
eq= ˙ep
11.
whereσeqis given by (7.9), and it is assumed to be given in terms of argu ments listed
in (7.30).ep
eqis the equivalent plastic strain obtained from the integrat ion in time of the
effective rate of plastic deformation
˙ep
eq=radicalbigg
2
3˙ep
ij˙ep
ij. (7.32)
144 Plasticity
Obviously, for isotropic materials we expect ˙ep
ijto be deviatoric. This yields relations
(7.31).
Let us begin with the simplest case. In a particular case of id eal plasticity we consider
materials without hardening. Then the function (7.30) has t he form
f=radicalbigg
3
2σD
ijσD
ij−σY=0, (7.33)
with the constant yield limit σY. Of course, the stress tensor must be such that elastic
processes remain within the elastic domain which is charact erized byf <0. Plastic
deformations may develop for stresses which belong to the yi eld surface. Their changes
yielding plastic deformation must remain on this surface wh ich means that the increments
of stresses described by ˙σijmust be tangent to the yield surface. Hence, for such process es
˙f=∂f
∂σij˙σij=0, (7.34)
as the gradient ∂f/∂σijis perpendicular to the yield surface.
Now we make the fundamental constitutive assumption, speci fying the rate of plastic
strain˙ep
ijand require that this quantity follows from a potential G(σij)defined on the
stress space
˙ep
ij=˙λ∂G
∂σij, (7.35)
where˙λis a scalar function following from the so-called Prager con sistency condition.
We demonstrate it further.
Let us introduce the notion of the outward normal vector to th e surfacef=0(com-
pare (7.12)). Clearly
Nij=∂f
∂σijvextenddoublevextenddoublevextenddoublevextenddouble∂f
∂σklvextenddoublevextenddoublevextenddoublevextenddouble−1
,vextenddoublevextenddoublevextenddoublevextenddouble∂f
∂σklvextenddoublevextenddoublevextenddoublevextenddouble=radicalbigg
∂f
∂σkl∂f
∂σkl, (7.36)
is such a vector. For the yield surface (7.33) it becomes
Nij=σD
ijvextenddoublevextenddoubleσD
klvextenddoublevextenddouble,vextenddoublevextenddoubleσD
klvextenddoublevextenddouble=radicalBig
σD
klσD
kl=radicalbigg
2
3σY. (7.37)
Obviously, we have the following classification
˙ep
ij=braceleftBigg
0forf <0orf=0andNij˙σij<0.
˙λ∂G
∂σijforf=0andNij˙σij=0.(7.38)
The condition Nij˙σij<0means that the process yields the unloading — as Nijis or-
thogonal to the yield surface, ˙σijmust point in the direction of the elastic domain and,
consequently, the process must be elastic.
In a particular case when the potential Gand the yield function are identical we
obtain
7.2 Plasticity of ductile materials 145
˙ep
ij=˙λ∂f
∂σij. (7.39)
This is the so-called associated flow rule. In this case, the r ate of plastic deformation ˙ep
ij
is perpendicular to the yield surface, i.e. it is parallel to the normal vector Nij.
It is appropriate to make here the following remark concerni ng the geometry of the
yield surface. If this surface were not convex then in points in which it is concave tangent
changes of the stress tensor ˙σij, i.e.(∂f/∂σij)˙σij=0, would yield stresses in the interior
of the yield surface, i.e. in the range f <0. This would be related to the development
of pure elastic deformations in contrast to the assumption t hat tangent changes of stress
yield plastic deformations. Therefore, in the classical pl asticity nonconvex yield surfaces
are not admissible. This is the subject of the so-called Druc ker stability postulate. In
the local form for the associated flow rules (7.39) it can be wr itten as
˙ep
ij˙σij>0. (7.40)
It is also sometimes postulated in the global form
integraldisplayparenleftbig
σij−σ0
ijparenrightbig
dep
ij>0, (7.41)
which shows that the postulate imposes a restriction on the w ork of plastic deformations
between an arbitrary initial state of stress σ0
ijand an arbitrary finite state of stress σij.
For the Huber-Mises-Hencky yield function (7.33) we obtain the associated flow rule
˙ep
ij=˙λradicalbigg
3
2σD
ijvextenddoublevextenddoubleσD
klvextenddoublevextenddouble=˙λradicalbigg
3
2Nij. (7.42)
In the simple uniaxial tension/compression test we have the n
˙ep
eq= ˙ep
11=˙λ⇒˙ep
ijσij=˙λradicalbigg
3
2vextenddoublevextenddoubleσD
klvextenddoublevextenddouble=˙λσ11= ˙ep
eqσY. (7.43)
Hence for the rate of work (working) we obtain
˙W= ˙eijσij=parenleftbig˙ee
ij+ ˙ep
ijparenrightbigσij⇒
⇒˙Wp= ˙ep
ijσij=˙λradicalbigg
3
2vextenddoublevextenddoubleσD
klvextenddoublevextenddouble= ˙ep
eqσeq= ˙ep
eqσY. (7.44)
The last expression — ˙ep
eqσY— describes the plastic working in the one-dimensional test
which is an amount of energy dissipated by the system per unit time due to the plastic
deformation. Hence
˙λ≥0, (7.45)
and the equality holds only for elastic deformations. This s tatement follows easily from
the second law of thermodynamics.
146 Plasticity
In order to construct an equation for plastic strains we acco unt for the additive de-
composition (7.3). For f <0we have elastic processes and then this property indicates
(compare (5.26)) the following Prandl-Reuss equation for t he rate of deformation
˙eij=parenleftBigg
˙σD
ij
2µ+˙σkk
9KδijparenrightBigg
+˙λradicalbigg
3
2Nij= (7.46)
=parenleftBigg
˙σD
ij
2µ+˙σkk
9KδijparenrightBigg
+˙WpσD
ijvextenddoublevextenddoubleσD
klvextenddoublevextenddouble2. (7.47)
This follows from the property of isotropic elastic materia ls for which the eigenvectors
for the stress and for the strain are identical7. The spherical part is, obviously, purely
elastic while the deviatoric part can be written in the form
dσD
ij
dt+˙Wp4µ
3σ2
YσD
ij=2µdeD
ij
dt. (7.48)
This equation is very similar to the evolution equation for s tresses within the standard
linear model of viscoelasticity (6.58) divided by the relax ation timeτ. However, there is
a very essential difference between these two models. It is ea sy to check that the equation
of viscoelasticity (6.58) is not invariant with respect to a change of time scale t→αt,
whereαis an arbitrary constant. This indicates the rate dependenc e in the reaction of
the material. It is not the case for the equation of plasticit y (7.48). Differentiation with
respect to time appears in all terms of this equation and for t his reason the transformation
parameterαcancels out. This is the reason for denoting the consistency parameter by
˙λ=dep
eq/dt. It transforms: t→αt⇒˙λ→˙λ/α. Therefore, the classical plasticity is
rate independent. The response of the system is the same for v ery fast and very slow
time changes of the loading. In reality, metals do possess th is property when the rate of
deformation ˙ep
eqis approximately 10−6−10−41/s. For higher rates one has to incorporate
the rate dependence (compare the book of Lemaitre, Chaboche [9] for further details).
This yields viscoplastic models presented further in these notes.
In the more general case of isotropic hardening and for isoth ermal processes σYbe-
comes a function of ep
eqalone. For many materials it is also important to include the
temperature dependence. Then σYbecomes the function of these two quantities. The
model is similar to this which we have considered above but on e has to correct the defin-
ition of the consistency parameter ˙λ. Finally, a dependence on the hardening parameter
κmeans that we account for the accumulation of plastic deform ations in the material.
The most common definitions of this parameter are as follows
a) the parameter accounting for the accumulation of the plas tic energy
κ=tintegraldisplay
0σij(ξ)˙ep
ij(ξ)dξ, (7.49)
7In order to prove it, it is sufficient to compare the eigenvalue problems for deviatoric stress and
strain tensors.
7.2 Plasticity of ductile materials 147
b) Odqvist parameter accounting for the accumulation of the plastic deformation
(compare (7.30) and (7.32))
κ=tintegraldisplay
0radicalbigg
2
3˙ep
ij˙ep
ijdξ=tintegraldisplay
0dep
eq
dξdξ. (7.50)
Then the relation (7.11) yields the consistency condition
˙f=0⇒∂f
∂σij˙σij+∂f
∂ep
ij˙ep
ij+∂f
∂T˙T+∂f
∂κ˙κ=0. (7.51)
Simultaneously, ˙ep
ij/negationslash=0only in processes of loading which are defined by the relation
∂f
∂σij˙σij+∂f
∂T˙T >0. (7.52)
In the limit case∂f
∂σij˙σij+∂f
∂T˙T=0, (7.53)
we say that the process is neutral. Finally, for the process o f unloading,
∂f
∂σij˙σij+∂f
∂T˙T <0. (7.54)
Consequently, for the evolution of plastic deformation we h ave the following relations
˙ep
ij=
0for eitherf <0orf=0and∂f
∂σij˙σij+∂f
∂T˙T≤0
˙λ∂f
∂σijforf=0and∂f
∂σij˙σij+∂f
∂T˙T >0.(7.55)
In the case of the hardening parameter (7.49) the consistenc y condition (7.51) can be
written in the form
˙f=∂f
∂σkl˙σkl+∂f
∂T˙T+bracketleftBigg
∂f
∂ep
ij++∂f
∂κσijbracketrightBigg
˙ep
ij=0.
Hence, we obtain the following relation for the consistency parameter
˙λ=∂f
∂σkl˙σkl+∂f
∂T˙T
D, D=−∂f
∂ep
ij∂f
∂σij−∂f
∂κ∂f
∂σijσij. (7.56)
The quantity Dis called the hardening function. We have
˙λ>0⇒D>0. (7.57)
The flow rule can be now written in the form
˙ep
ij=1
D∂f
∂σijparenleftbigg∂f
∂σkl˙σkl+∂f
∂T˙Tparenrightbigg
. (7.58)
148 Plasticity
The right hand side is the homogeneous function of ˙σijand˙T. Consequently, this flow
rule possesses the same time invariance as the rule (7.39) fo r the model without hardening,
i.e. the model is rate independent.
Apart from the above presented isotropic hardening materia ls reveal changes of the
yield limit which can be attributed to the shift of the origin in the space of stresses. A
typical example is the growth of the yield stress in tensile l oading with the simultaneous
decay of the yield stress for compression. In the uniaxial ca se it means that the whole
stress-strain diagram will be shifted on a certain value of s tresses. This is the Bauschinger
effect.
Fig. 7.5: An example of Bauschinger effect in cyclic loading
The corresponding hardening is called kinematical or aniso tropic. It is described by
the so-called back-stress Z=Zijei⊗ejwhich specifies the shift of the origin in the stress
space. The yield function can be then written in the form
f(T,Z,κ)=F(T,Z)−σYparenleftbigep
eq,Tparenrightbig=radicalbigg
3
2¯σD
ij¯σD
ij−σY=0, (7.59)
where
¯σD
ij=σD
ij−Zij. (7.60)
One has to specify an equation for the back-stress. It is usua lly assumed to have the
form of the evolution equation, e.g.
˙Zij=˙β(σij−Zij), (7.61)
where˙βis a material parameter. We skip here the further details ref erring to numerous
monographs on the subject8.
8e.g. see the book [9] or
AIlscIbscIrscIescIcscIhscItscBIescIrscItscIrscIascImsc; Elasticity and Plasticity of Large Deformations , Springer Berlin, 2008.
MIiscIcscIhscIascIlslashscKIlscIescIiscIbscIescIrsc; Handbook of Computational Solid Mechanics , Springer, Heidelberg, 1998.
GIescIrscIascIrscIdscA.MIascIuscIgscIiscInsc; The Thermomechanics of Plasticity and Fracture, Cambridge University Press,
1992.
7.3 Plasticity of soils 149
7.3 Plasticity of soils
Theories of irrecoverable, permanent deformations of soil s is very different from the
plasticity of metals presented above. Metals produce plast ic deformations primarily
due to the redistribution and production of crystallograph ic defects called dislocations.
Plastic behaviour of soils is mainly connected with the redi stribution of grains and it is
strongly influenced by fluids filling the voids (pores) of such a granular material. Strain
due to the deformation of grains is often negligible in compa rison to the amount of shear
and dilatation caused by relative motions of grains. The beh aviour is entirely different
in the case of dry granular materials (frictional materials ) than a material saturated by,
for instance, water or oil where the cohesive forces play an i mportant role. A detailed
modern presentation of the problem of permanent deformatio ns of soils can be found in
the book of D. Muir Wood [23] (compare also a set of lectures vo n Verruijt [19]). Similar
issues for rocks are presented in the classical book of Jaege r, Cook and Zimmerman[6].
We limit the attention only to few issues of this subject.
Attempts to describe the plasticity of granular materials s tem from Coulomb, who
formulated a simple relation between the normal stress σnon the surface with a normal
vectornand the shear stress τnon this surface. It is a generalization of the law of
friction between two bodies and has the form
|τn|=c−σntanϕ, (7.62)
whereϕis the so-called friction angle (angle of repose) and cdenotes the cohesion
intercept. This relation is called Mohr-Coulomb law. For dr y granular materials the
cohesion does not appear, c= 0, and then the angle of repose ϕis the only material
parameter. It is, for instance, the slope of natural sand hil ls and pits (Fig. 7.6).
Fig. 7.6: Sand pit trap
of antlion in dry sand.
Slope almost equal to ϕ
The above relation leads immediately to the yield function i n terms of principal
stressesσ(1)>σ(2)>σ(3).. Namely
fparenleftBig
σ(1),σ(2),σ(3)parenrightBig
=parenleftBig
σ(1)−σ(3)parenrightBig
+parenleftBig
σ(1)+σ(3)parenrightBig
sinϕ−2ccosϕ=0. (7.63)
150 Plasticity
The derivation from properties of Mohr’s circle is shown in F ig. 7.7. Namely
|τn|=σ(1)−σ(3)
2cosϕ, σn=σ(1)+σ(3)
2−σ(1)−σ(3)
2sinϕ. (7.64)
Substitution in (7.62) yields (7.63).
Forϕ= 0andc=σ0the yield function (7.63) becomes the Tresca-Guest yield
condition (7.13).
Fig. 7.7: Construction of Mohr-Coulomb yield function
Cohesive forces are influencing not only the relation betwee n normal and shear stresses.
Due to the porosity of granular materials a fluid in pores yiel ds cohesive interactions as
well as it carries a part of external loading. This observati on was a main contribution of
von Terzaghi to the theory of consolidation of soils9. He has made an assumption that
the pore pressure pdoes not have an influence on the plastic deformation of soils . The
meaning of pis here the same as in Subsection 6.4. and it should not be conf used with
the trace of the bulk stress σij, i.e.p/negationslash=−1
3σkk. It means that the stress appearing in
yield functions must be reduced by subtracting the contribu tion of this pressure. If we
define the effective stress
σ′
ij=σij+pδij, (7.65)
then the Mohr-Coulomb yield function becomes
parenleftBig
σ′(1)−σ′(3)parenrightBig
+parenleftBig
σ′(1)+σ′(3)parenrightBig
sinϕ−2ccosϕ=0. (7.66)
σ′(α)=σ(α)+p, α=1,2,3.
This function is shown in the upper panel of Fig. 7.8.
Further we distinguish by primes all quantities based on the effective stress.
9K.IvscIoscInscTIescIrscIzscIascIgscIhscIisc; ErdbaumechanikaufbodenphysikalischerGrundlage, Franz Deuticke, Wien, 1925.
7.3 Plasticity of soils 151
Incidentally, a similar notion of effective stresses appear s in the theory of damage — it
is related to changes of reference surface due to the appeara nce of cracks. Such models
shall be not presented in these notes.
⋆Remark. There exists some confusion within the soil mechanics conce rning the
definition of positive stresses. Soils carry almost without exception only compressive
loads (compare Fig. 7.7. and 7.8.) and, for this reason, in co ntrast to the classical
continuum mechanics, a compressive stress is assumed to be p ositive. This is convenient
in a fixed system of coordinates related to experimental setu ps such as triaxial apparatus.
Then pressure pin the definition of effective stresses (7.65) would appear wi th the minus
sign. Usually it is denoted in soil mechanics by u. In some textbooks10both conventions
concerning the sign of stresses appear simultaneously. How ever, such a change of sign
in a general stress tensor yields the lack of proper invarian ce with respect to changes of
reference systems. It is also contradictory with the choice of the positive direction of
vectors normal to material surfaces on which many mathemati cal problems of balance
laws and the Cauchy Theorem rely. For these reasons, we work h ere with the same
convention as in the rest of this book — tensile stress is posi tive.
In addition, one should be careful in the case of relation of s uch one-component models
to models following from the theory of immiscible mixtures, for instance to Biot’s model.
Such models are based on partial quantities and then the pore pressurepis not the partial
pressurepFof a multicomponent model but rather p=pF/n, wherenis the porosity.♣
In soil mechanics, where the definitions of elastic domains d escribed in the previous
Subsection are not appropriate, it is convenient to introdu ce special systems of reference
in the space of effective principal stresses. One of them is di rectly related to the set of
invariants (7.10)
p′=1
3I′
1=−1
3I′
σ, q=radicalbig
3J′
2=σeq, r=33radicalbigg
J′
3
2. (7.67)
Another one is a cylindrical system. One of the axes is the pre ssureparenleftbig−1
3σ′
kkparenrightbig, i.e. it
is oriented along the line σ′(1)=σ′(2)=σ′(3). It is denoted by ξand scaledξ=I′
σ/√
3.
The other two coordinates are defined by the relations
ρ=radicalbig
2J′
2≡radicalbigg
2
3σ′
eq≡radicalBig
σ′D
ijσ′D
ij,cos(3θ)=parenleftbiggr
σ′eqparenrightbigg3
. (7.68)
These are the so-called Haigh—Westergaard coordinates. Th e(ξ,ρ)- planes are called
Renduli ˇc planes and the angle θis called the Lode angle. The transformation from these
coordinates back to principal stresses is given by the relat ion
σ′(1)
σ′(2)
σ′(3)=1
√
3
ξ
ξ
ξ
+radicalbigg
2
3ρ
cosθ
cosparenleftbigθ−2
3πparenrightbig
cosparenleftbigθ+2
3πparenrightbig
. (7.69)
Mohr-Coulomb yield function in the Haigh—Westergaard coor dinates has the following
formbracketleftBig√
3sinparenleftBig
θ+π
3parenrightBig
−sinϕcosparenleftBig
θ+π
3parenrightBigbracketrightBig
ρ−√
2ξsinϕ=√
6ccosϕ. (7.70)
10e.g. [23] orR.LIascInscIcscIescIlscIlscIoscItscItscIasc; Geotechnical Engineering, Balkema, Rotterdam, 1995.
152 Plasticity
Alternatively, in terms of the invariants (p′,q,r)we can write
bracketleftbigg1√
3cosϕsinparenleftBig
θ+π
3parenrightBig
−1
3tanϕcosparenleftBig
θ+π
3parenrightBigbracketrightbigg
q−p′tanϕ=c, (7.71)
θ=1
3arccosparenleftbiggr
qparenrightbigg3
.
As in the classical theory of plasticity, modifications of Mo hr-Coulomb condition were
introduced in order to eliminate corners in the yield surfac e. One of such modifications
was introduced by D. C. Drucker and W. Prager. This condition for the limit state of
soils has the following form
radicalbig
J′
2−√
3cosϕradicalbig
3+sin2ϕc−sinϕradicalBig
3parenleftbig
3+sin2ϕparenrightbigI′
σ=0, (7.72)
where the invariants J′
2andI′
σare defined by relations for effective stress analogous
to (7.10). This function is shown in the lower panel of Fig. 7. 8. The dependence on
the invariant I′
σfollows from the dependence of the yield in soils on volume ch anges,
i.e. it describes an influence of dilatancy on the appearance of the critical limit state.
Forϕ= 0andc=σY/√
3this condition becomes identical with Huber-Mises-Hencky
condition (7.17).
Due to its simplicity the Mohr-Coulomb yield surface is ofte n used to model the
plastic flow of geomaterials (and other cohesive-frictiona l materials). However, many
such materials show dilatational behavior under triaxial s tates of stress which the Mohr-
Coulomb model does not include. Also, since the yield surfac e has corners, it may
be inconvenient to use the original Mohr-Coulomb model to de termine the direction of
plastic flow. Therefore it is common to use a non-associated p lastic flow potential that
is smooth. For example, one is using the function
g=radicalBig
(αcYtanψ)2+G2(ϕ,θ)q2−p′tanϕ, (7.73)
whereαis a parameter, cYis the value of cwhen the plastic strain is zero (also called
the initial cohesion yield stress), ψis the angle made by the yield surface in the Renduli ˇc
plane at high values of p′(this angle is also called the dilation angle), and G(ϕ,θ)is an
appropriate function that is also smooth in the deviatoric s tress plane.
7.3 Plasticity of soils 153
Fig. 7.8: Yield surfaces (7.66)and(7.72)in the space of principal effective
stressesσ1=σ′(1),σ2=σ′(2), σ3=σ′(3).
We shall not expand this subject anymore. Due to the vast field of applications: soils,
powders, avalanches, debris flows and many others, the numbe r of models describing the
critical behaviour of such materials is also very large. Cap plasticity models, Cam-Clay
(CC) models, Modified-Cam-Clay (MCC) models, Mroz models, e tc. are based on similar
ideas as the models presented above. There exists also a clas s of hypoplasticity models
in which the notion of the yield surface does not appear at all and which seem to fit well
phenomena appearing in sands11.
11compare articles of E.BIascIuscIescIrsc : Analysis of Shear Banding with a Hypoplastic Constitutive Model
for a Dry and Cohesionless Granular Material, 335-350, and D. KIoscIlscIyscImscIbscIascIssc : The Importance of Sand
in Earth Sciences, both in: B.AIlscIbscIescIrscIssc (ed.);Continuous Media with Microstructure , Springer, Berlin,
2010.
154 Plasticity
7.4 Viscoplasticity
There are many ways of extension of the classical plasticity to include rate dependence.
Obviously, one of them would be to incorporate additionally some viscous properties
as we did in Chapter 7. This kind of the model is developed sinc e early works of P.
Perzyna12. The other way, less ambitous, is to incorporate a rate depen dence in the
definition of the yield function. In principle, the classica l yield function cannot exist in
such models but one gets results by direct extension of plast icity models presented in
this Chapter. For such models it is advocated in the books of L emaitre, Chaboche [9]
and Lemaitre, Desmorat [10].
We present here only a few hints to the model of the second kind . Namely, it is
assumed that the yield criterion satisfies the relation
f= 0,˙f=0— plasticity,
f=σV>0— viscoplasticity, (7.74)
withf <0satisfied in the elastic domain. σVis a viscous stress given by a viscosity law.
In both cases fcan be chosen according to the rules discussed in previous Su bsections.
For instance, in the case of Huber-Mises-Hencky model with i sotropic and kinematic
hardening we have
f= (T−Z)eq−κ−σY, (7.75)
(T−Z)eq=radicalbigg
3
2parenleftbigσD
ij−ZD
ijparenrightbigparenleftbigσD
ij−ZD
ijparenrightbig,
whereκdescribes the isotropic hardening related to the size growt h of the yield surface.
It may be, for instance, assumed to have the exponential form
κ=κ∞bracketleftbig1−expparenleftbig−bep
eqparenrightbigbracketrightbig, (7.76)
whereκ∞,bare material parameters depending on temperature. Sometim es a power law
κ=Kpparenleftbigep
eqparenrightbig1/Mis sufficient.
Kinematic hardening described by the back-stresses Zijrequires an evolution equa-
tion. It may have the form (7.61) or it may be the so-called Arm strong-Frederick law13
d
dtparenleftbiggZij
Cparenrightbigg
=2
3˙ep
ij−γ
CZij˙ep
eq, (7.77)
for which the identification of parameters is easier [10].
The viscous stress σVis also given by various empirical relations. Two of them hav e
the form
1) Norton power law
σV=KNparenleftbig˙ep
eqparenrightbig1/N, (7.78)
12e.g.P.PIescIrscIzscIyscInscIasc; The constitutive equations for the rate sensitive plastic m aterials,Quart. Appl.
Math.,20, 321-332, 1963.
13P.J.AIrscImscIsscItscIrscIoscInscIgsc,C.O.FIrscIescIdscIescIrscIiscIcscIksc; A mathematical representation of the multiaxial Bausching er
effect, CEGB Report, RD/B/N731, Berkeley Nuclear Laborator ies, 1966.
7.4 Viscoplasticity 155
2) exponential law leading to the saturation at large plasti c rates
σV=K∞bracketleftbigg
1−expparenleftbigg
−˙ep
eq
nparenrightbiggbracketrightbigg
, (7.79)
whereKN,K∞,Nandnare material parameters.
In Fig. 7.9 we show a comparison of results for various viscou s models14.
Fig. 7.9: Relaxation test for the identification of viscosit y parameters —
Inconel alloy at θ=6270C.
For the alloy investigated by Lemaitre and Dufailly the foll owing parameters are
appropriate
E=160 GPa,KN=75GPa/s1/N, N=2.4, K∞=104GPa,n=1.4×10−2s−1.
Rate-dependent viscoplastic models must be used in cases of high deformation rates.
For metals, the rates up to app. 10−31/s do not influence substantially results in the
plastic range of deformations. For higher rates the yield li mit may grow even three times
by the rate1001/s15.
14J.LIescImscIascIiscItscIrscIesc,J.DIuscIfscIascIiscIlscIlscIysc; Damage measurements, Engn. Fracture Mech., 28, 1987
15P.PIescIrscIzscIyscInscIasc; Thermodynamics of Inelastic Materials (in Polish), PWN, Warsaw, 1978.
156 Plasticity
Chapter 8
Dislocations
8.1 Introduction
One of the difficult questions of materials science some 100 ye ars ago was the elucidation
of the mechanism of plastic deformation of crystalline bodi es. Plasticity of ductile mate-
rials described in Subsection 8.2 is purely macroscopic and the range of its applicability
can be explained only by means of microscopic properties of m aterials. In 30th of the
XXth century it was shown by A. H. Cottrell, E. Orowan, M. Pola nyi, J. W. Taylor,
that dislocations, line defects in crystalline bodies, are the source of plastic deformation.
Since this discovery a new branch of plasticity has been deve loped — crystal plasticity. It
began with works of Schmid, Boas, Taylor and yielded importa nt results in the field of
evolution of plastic anisotropy, textures, cold rolling an d forge techniques of metals.
In this Chapter, we present some properties of discrete disl ocations as well as a contin-
uum model of these defects. The theory of discrete dislocati ons found an application in
modeling of rupture appearing by earthquakes. This applica tion shall be briefly presented
at the end of this Chapter.
We begin with the formal definition of the dislocation. There are two possibilities.
One of them was proposed by C. Somigliana (1914) and it is base d on the notion of the
dislocation line. Another one was introduced by V. Volterra (1907) and it is using a
notion of a singular surface on which the displacement vecto ruis discontinuous. Both
definitions yield similar models but they are not equivalent1. In Fig. 8.1. and 8.2. we
show a few schematic pictures of the dislocation in a crystal . In the left panel of Fig.
8.1. we show the result of a removal of half-planes of atoms fr om an infinite ideal cubic
crystal. In result the upper half-space and the lower half-s pace possess a misfit. In
order to correct it, in the vicinity of the horizontal cut the lattice constants (distance
between lines indicated in the Figure) must be different. Thi s yields the existence of
infinite straight lines perpendicular to the page in which on e of the atomic half-planes
terminates and in their neighborhood the lattice is distort ed. This line defect is called the
1see: introduction to the subject by T. Mura [13]. A detailed d iscussion of the problem can be found
inZ. MIoscIsscIsscIascIkscIoscIwscIsscIkscIasc; Self-equilibrated stresses and dislocations (in Polish), in:Technical Mechanics.
Vol. IV: Elasticity , M. Sokolowski (ed.), PWN, Warsaw, 1978,
157
158 Dislocations
edge dislocation. Obviously, if we try to complete a closed c urve around such a line we
have to make different number of lattice steps in one directio n than we make backwards.
This is seen even better in the cartoon of the screw dislocati on in the right panel of this
Figure.
The above described construction is demonstrated again in t he Föll cartoons of Fig.
8.2. The right panel shows the combination of the edge and scr ew dislocations in which
the vectorbdescribing the misfit is neither perpendicular to the disloc ation line (edge
dislocation) nor parallel to this line (screw dislocation) . It forms rather an angle of sixty
degrees with this line. Obviously, depending on the combina tion, this angle may be
arbitrary.
Dislocation lines carry both an accumulated energy and self -equilibrated stresses in
the reference state of the body. They try to minimize this ene rgy by minimizing the
length. This means that in the infinite ideal crystal they for m straight lines. However,
in real finite crystals this is not possible. Consequently, t hey must either terminate on
the boundaries or, which is mostly the case in reality, they m ust form closed circuits.
This is also the reason for their motion. Under loading — shea ring in the plane of misfit,
this lines change the curvature and, in attempt to minimize t he length, they are shifted
along this plane.
Fig. 8.1: Schematic picture of a two-dimensional misfit alon g the horizontal
line yielding edge dislocation line every 20 steps (left pan el) and a schematic
picture of the screw dislocation (right panel)
8.2 Continuum with dislocations 159
Fig. 8.2: Three characteristic types of dislocations: edge (left panel), screw
(middle panel) and "sixty degree" (right panel)2
We proceed to the mathematical description of the dislocati on.
8.2 Continuum with dislocations
The closed curve Dis said to be the dislocation line (dislocation loop) in a con tinuum if
a line integral along any sufficiently small closed circuit Bcircumventing once the curve
Dpossesses the property contintegraldisplay
Bdu=b, (8.1)
for an arbitrary loading of the continuum. Obviously, uis the displacement vector and
b/negationslash=0is called the Burgers vector of the dislocation line D. According to Stokes Theorem
(1.59), for differentiable displacement field u(x,t)we can write the integral in the form
contintegraldisplay
B∂ui
∂xjdxj=integraldisplay
SBǫkij∂2ui
∂xi∂xjnkdS=0, (8.2)
whereSBis a surface spanned on the curve B. Hence, the definition (8.1) is nontrivial
only for displacement fields which are discontinuous on the s urfaceSB. This relates the
Somigliana definition of the dislocation to the surface defin ition introduced by Volterra.
For energetic reasons bis usually the shortest translation vector of the lattice; e .g.
|b|=a/2<110>for the fcc lattice. The assumption that the Burgers contour B
is sufficiently small means that it encloses only one dislocat ion lineDand that it is
intersecting only once a surface span by the line D. This is schematically shown in Fig.
8.3.. The sign of the Burgers vector bis defined by the right screw rule shown also in
the Fig. 8.3..
2afterHIescIlscImscIuscItscFIodieresisscIlscIlsc ;Defectsincrystals , http://www.tf.uni-kiel.de/matwis/amat/def_en/index .html
160 Dislocations
Fig. 8.3: Dislocation loop D,
Burgers contour B
and the sign convention
One of the surfaces related to the dislocation line is the cyl inder for which the curve
Dis the directrix and whose generatrix are straight lines in t he direction of the Burg-
ers vectorb. This is the so-called gliding surface along which dislocat ions move most
frequently because the resistance of the crystal to such a mo tion is in this surface the
smallest (the conservative motion). Another possibility w hich requires much more energy
is the so-called climbing of dislocations (the nonconserva tive motion). The latter requires
some atomic diffusion processes. For details we refer to nume rous books on the subject3.
We proceed to describe the geometry of the dislocation line. It is described by the
position vector
x=ζ(l,t), (8.3)
wherelis a parameter along the line. Then the tangent vector and the velocity of
dislocation are defined by the relations
dζk=∂ζk
∂ldl⇒tk(x,t)=contintegraldisplay
Dδ(x−ζ(l,t))dζk, (8.4)
˙ζk=∂ζk
∂t,
where the vector field t(x,t)is given in the whole continuum but it is different from zero
only on dislocation lines.
In order to describe the continuous fields in the presence of d islocation we introduce
the tensor of distortion βwhich smears out the Burgers condition (8.1). This tensor
3e.g.:
J.WIescIescIrscItscImscIascInsc,J.R.WIescIescIrscItscImscIascInsc; Elementary Dislocation Theory, Macmillan, New York, 1967,
D.HIuscIlscIlsc;Introduction to Dislocations, Pergamon, 1975,
J.D.EIsscIhscIescIlscIbscIysc; Continuum Theory of Lattice Defects, Solid State Physics , vol.3, 79, Academic Press,
N.Y., 1956,
A.M.KIoscIsscIescIvscIiscIcscIhsc; Crystal Lattice: Photons, Solitons, Dislocations , John Wiley, 1999.
8.2 Continuum with dislocations 161
coincides with the gradient of displacement in simply conne cted domainsPwhich do not
contain dislocation loops: P∩D=∅. Hence we define
duj=βijdxi,withβij(x,t)=∂uj
∂xiforx∈P. (8.5)
Then the condition (8.1) has the form
bj=contintegraldisplay
Bβijdxi=integraldisplay
SBǫkli∂βij
∂xlnkdS, (8.6)
where the second relation follows from the Stokes Theorem fo r an arbitrary surface SB
spanned on the curve B.
This relation allows to smear out the field of distortion. Nam ely, for the dislocation
loopDintersecting a surface SBin the pointx, as shown in Fig. 8.4:
Fig. 8.4: Orientations of Burgers
surfaceSBand dislocation loop D
we use the following identity
integraldisplay
SB
contintegraldisplay
Dδ(x−ζ)dζkn
kdS=
1
−1
0for the same orientation of nanddζ,
for the opposite orientation of nanddζ,
forDnot intersecting SB.
(8.7)
Then (8.6) can be written in the form
bjintegraldisplay
SB
contintegraldisplay
Dδ(x−ζ)dζkn
kdS=integraldisplay
SBǫkli∂βij
∂xlnkdS. (8.8)
This relation must hold for an arbitrary surface SBspanned on the Burgers contour B.
Consequently,
ǫkli∂βij
∂xl=bjtk, (8.9)
162 Dislocations
where we have used the definition (8.4) of the vector ttangent to the dislocation loop
D. This is the differential form of the Burgers relation (8.1). As the vectortis different
from zero only on dislocation lines the above relation state s that the distortion βhas
a vector potential beyond the dislocation line ( rotβ=0), i.e.β=graduas we have
already mentioned before.
The tensor
α=b⊗ti.e.αij=bitj, (8.10)
is called the tensor of dislocation density. Obviously, it s atisfies the relation
ǫilk∂βkj
∂xl−αij=0. (8.11)
The above considerations allow to write the full set of equat ions which determine the
distortionβand other fields of a linear elastic continuum caused by a give n dislocation
line. In the static case the problem is quite simple. We use th e equilibrium condition
∂σij
∂xj=0, (8.12)
which follows from (3.38) and the Hooke law (5.21)
σij=cijklβkl, cijkl=λδijδkl+µ(δikδjl+δilδjk). (8.13)
We have to incorporate the relation (8.11) which describes t he loading by the dislocation.
To do so we differentiate the equilibrium condition and subse quently we substitute (8.13)
cijkl∂2βkl
∂xj∂xp=0.
Now we multiply (8.11) by ǫiql, and use the identity
ǫkplǫkqi∂βij
∂xq=(δpqδil−δqiδqj)∂βij
∂xq=∂βlj
∂xp−∂βpj
∂xl=ǫkplαkj, (8.14)
which follows from the contracted epsilon identity (1.41). Finally, we have
cijkl∂2βpl
∂xi∂xk=cijklǫqpk∂αql
∂xi. (8.15)
Together with the condition
ekl=1
2(βkl+βlk), (8.16)
the equation (8.15) fully describes the problem. Once we find βijwe can find stresses
from Hooke’s law (8.13). As this field of stresses follows onl y from the presence of the
dislocation without any external load we say that it is self- equilibrated.
Solutions of this equilibrium problem are very important be cause they determine the
stress concentration in the vicinity of the line defect. The y can be found by means of the
8.2 Continuum with dislocations 163
Green function of the linear elasticity. We quote here only t he result of W. G. Burgers
for the displacement uin the case of a dislocation loop Dwith the constant Burgers
vectorb. It has the form
uk=−1
4πbkcontintegraldisplay
Dǫijlrjkl
r(r−riki)dζi+1
4πǫkijbicontintegraldisplay
Ddζj
r+1
4πλ+µ
λ+2µǫijlbj∂
∂xkcontintegraldisplay
Drl
rdζi,
rk=xk−ζk(l), r=√rkrk, (8.17)
wherekis the unit vector perpendicular to the plane of the loop D.
Only in exceptional cases one can perform analytically the i ntegration in the above
relation. It can be done for the straight line dislocations. In such a case, one obtains, for
instance, the following components of stresses
1) screw dislocation given by l= (0,0,1)wherelpoints in the direction of the
dislocation line D, andb=(0,0,b)
σx=σy=σz=τxy=0, (8.18)
τxz=µb
2πy
x2+y2, τyz=−µb
2πx
x2+y2,
2) edge dislocation given by l=(0,0,1),b=(b,0,0)
τxz=τyz=0,
σx=b
2π2µ(λ+µ)
λ+2µyparenleftbig
3x2+y2parenrightbig
(x2+y2)2,
σy=−b
2π2µ(λ+µ)
λ+2µyparenleftbig
x2−y2parenrightbig
(x2+y2)2, (8.19)
σxz=b
2π2µλ
λ+2µy
x2+y2,
σxy=−b
2π2µ(λ+µ)
λ+2µxparenleftbig
x2−y2parenrightbig
(x2+y2)2.
Solutions for dislocations in some anisotropic media can be found in the explicit form
as well.
We do not present details of the dynamic theory of dislocatio ns4. The Burgers con-
dition holds true also in this general case but one has to cope with the problem of elimi-
nation of the acceleration term in the equation of motion. On e can derive an additional
equation for the evolution of the distortion β
∂βkl
∂t−∂vl
∂xk=Jkl, (8.20)
4some aspects of this theory can be found in the earlier quoted work of Z. Mossakowska as well as:
H.ZIoscIrscIsscIkscIisc; Theory of discrete defects, Arch. Mech. Stos., 18, 3, 1966.
164 Dislocations
whereJklis the dislocation flux given by the relation
Jkl=blǫkijcontintegraldisplay
D(t)˙ζiδ(x−ζ(l,t))dζj. (8.21)
Some universal solutions are known also in this case but we sh all not quote them in these
notes.
8.3 On plasticity of metals
As we have mentioned at the beginning of this Chapter, the veh ement research of the
continua with dislocations was connected with the discover y that plastic deformations of
metals are related to the redistribution and production of d islocations. In low tempera-
tures, i.e. temperatures below app. 70% of the temperature o f melting point, dislocations
are moving on characteristic crystallographic planes on wh ich they require the least en-
ergy for the motion. During this motion they get stacked on bo undaries of grains of
polycrystals and on other obstacles. One of them may be a poin t in which more than
one dislocation appear simultaneously and their Burgers ve ctors annihilate each other,
i.e.summationtext
αb(α)= 0, whereαnumbers the dislocations in this point. Such knots play an
important role in the production of dislocations. Namely, t he shear stress which acts in
the slip plane of motion of a dislocation is bending a line of d islocation pinned to two
such obstacles. The loop is trying to minimize the energy whi ch leads to overhanging
shown in Fig. 8.5. When the two sides (green in Figure) meet th ey annihilate because
their Burgers vectors are identical but of the opposite sign . The loop becomes free to
move and the rest of the virginal line of dislocation begins t he process anew. This is the
so-called Frank-Read source of dislocations.
Fig. 8.5: Frank-Read source of dislocation
8.4 Dislocations in geophysics 165
This and similar mechanisms yield the production of disloca tions which is an irre-
versible process related to the increment of plastic strain s. During plastic deformations
the number density of dislocations may grow from some 1010to10201/cm2.
Fig. 8.6: Electron microscope
picture of Frank-Read source.
Black traces are dislocations
on the surface of the sample
Modeling of such processes is based on certain microscopic o bservations transferred to
the level of continuum. The fundamental role plays here the s o-called Orovan equation
which relates the rate of shearing to the Burgers vector, spe ed of dislocations and dislo-
cation density. Together with the evolution equation for th is density in which intensities
of sources are incorporated one obtains a semistructural pl asticity model, the so-called
crystal plasticity which successfully solved many problem s of mechanics of metals5.
In high temperatures the process becomes more complicated b ecause the defects
pinned to the grain boundaries begin to move as well. In this r ange the theory of
dislocations as presented above cannot be applied anymore.
8.4 Dislocations in geophysics
The origin of various models of dislocations goes back to the defective structure of crys-
talline bodies such as metals. However, we have seen that the se models describe line
defects in continua independently of a particular crystall ine lattice. Only some indica-
tions concerning the Burgers vector bear on crystallograph y. Therefore one can apply
such models in all cases in which a description of a discontin uous displacement field is
needed. This is indeed the case in modeling of earthquakes. M ost likely it was A. E.
H. Love in 1945 who proposed to apply the Volterra dislocatio n model6in description
of earthquakes. The problem of seismic sources was discusse d by Vvedenskaya (1956),
Steketee (1958) and others7. The modern presentation of the subject can be found in
the book of Aki and Richards [1].
5for the introduction to crystal plasticity see the book of K. Wilmanski [22]. Many details can be
found in the monograph R.W.K.HIoscInscIescIyscIcscIoscImscIbscIesc; The Plastic Deformation of Metals , E. Arnold, 1968,
andU.F.KIoscIcscIkscIssc,A.AIrscIgscIoscInsc,M.AIsscIhscIbscIysc; Thermodynamics and Kinetics of Slip, vol.19, Chalmers, B.,
Christian, J. W. and Massalski, T. W. (eds.), Pergamon Press , Oxford, 1975.
6V.VIoscIlscItscIescIrscIrscIasc, Sur l’équilibre des corps élastiques multiplement connexe s, Ann. Sci. l’École Normale
Supérieure, Paris, 24, 401-517, 1907.
7A.V.VIvscIescIdscIescInscIsscIkscIascIyscIasc; Determination of displacement fields for earthquakes by mea ns of the disloca-
tion theory (in Russian), Izv. Akad. Nauk SSSR, Geofiz., 3, 277-284, 1956,
166 Dislocations
The mechanism of earthquake rupture may be more complicated than this which can
be described by the Volterra dislocation. It is related to cr ack formation and it is coupled
to complicated tectonic processes which we do not discuss in this book. Reader interested
in these problems is referred to an article of J. Rice [16]. We leave out the discussion of
the structure of forces acting in the fault — according to Aki , Richard [1] the so-called
double couple theory seems to be prevailing, and limit the at tention to modeling a slip
in the fault and its action on the vicinity.
A fault surface SDwith the boundary ∂SB=Dlies in a linear isotropic medium and
it is assumed to be perpendicular to the x3-axis. A slip is presumed to take place in
the direction of a unit vector l=l1e1+l2e2. Then the displacement vector possesses a
discontinuity
∆u=u+−u−=b=|∆u|l, (8.22)
wherebis the Burgers vector for the dislocation line D. Hence, Volterra dislocation
allows to take over all results the theory of dislocations in the description of such a
fault defect. Strictly speaking, the definition of Volterra dislocation requires as well that
derivatives of uonSDare continuous which means, of course, also the continuity o f
the stress. The field of displacement created by the dislocat ion yields a system of self-
equilibrated stresses and, for this reason, an accompanyin g distortion may be considered
as a field of initial deformations e0
ijgiven by the relation
e0
ij=−bjintegraldisplay
SDδ(x−ξ)nidS. (8.23)
This relation yields immediately the notion of moment tenso r densitymijgiven by the
Hooke’s law for the initial deformation
mij=cijkle0
kl, (8.24)
and, consequently, a definition of forces appearing in the eq uation for the real displace-
mentu
X0
k=−∂mkl
∂xl, ρ∂2ui
∂t2=cijkl∂2uk
∂xl∂xj+X0
i. (8.25)
Obviously, the tensor of material parameters for isotropic materialscijklhas the form
(5.21). Now, the dynamic Green function (5.64) yields solut ions for the displacement. For
instance, for the source which is the Heaviside function bH(t)we obtain the displacement
in the far field approximation in the following form
uL
i=M0
4πρc3
Lr(nkll+nllk)xixkxl
r3δparenleftbigg
t−r
cLparenrightbigg
, nkek=e3,l=l1e1+l2e2,
uS
i=M0
4πρc3
Tr(nkll+nllk)parenleftBig
δik−xixk
r2parenrightBigxl
rδparenleftbigg
t−r
cTparenrightbigg
, (8.26)
J .A. SItscIescIkscIescItscIescIesc; Some geophysical applications of the theory of dislocation s,Can. J. Phys. ,36,
1168-1198, 1958.
Some details can be found in the book of A. Udias: PrinciplesofSeismology , Cambridge Univ. Press.,
1999.
8.4 Dislocations in geophysics 167
whereM0=ηb(areaSD)is the seismic moment, ηdenotes the rigidity modulus. These
are two arrivals, longitudinal and transversal, in a point w ith the distance rfrom the
source.
The model indicated above specifies various notions of the ea rthquake such as seismic
moment, its decomposition into various forces acting on the plane of the defect including
the mentioned above double couples. However, in many respec ts it seems to be too
simplified. For instance, it does not contain any criteria fo r the rupture. We shall not
elaborate this subject any further.
168 Dislocations
Chapter 9
Appendix: Green functions for
isotropic elastic materials
9.1 Purpose
Green’s functions known also as fundamental solutions serv e the purpose of construction
of analytical solutions of linear differential equations. T hey also form the basis for at least
two important procedures of approximation. The first one yie lds the so-called boundary
element methods. The second one evaluates average macrosco pic properties of materials
with microstructure.
The Green function allows to solve the linear equation
Lu+f=0, (9.1)
whereLis the linear operator, uan unknown vector function and fa given function.
For the purpose of this Appendix we assume the operator Lto be of the second order
and the domain to be infinite. For finite domains one can obtain solutions by a simple
transformation which we present further.
The formal solution of the equation (9.1) in the static case c an be, for instance, written
in the form of the following convolution integral1
u=G∗f=integraldisplay
G(x−x1)f(x1)dV1, (9.2)
whereGis the Green tensor for the static problem.
In the following two Sections we present the construction of Green’s functions for
static and dynamic problems of linear elasticity. We follow here the presentation of T.
D. Shermergor [17].
1e.g.R.IdscIescWIiscItsc; Continuum theory of stationary dislocations, Solid State Physics, 10,249, 1960.
169
170 Appendix: Green functions for isotropic elastic materi als
9.2 Statics of isotropic elastic materials
In this Subsection we present the construction of Green’s fu nction for the linear elasticity
in the static case. The operator Lhas in this case the following form
L=Likei⊗ek, Lik=∂
∂xjcijkl∂
∂xl, (9.3)
wherecijklis the tensor of elasticity. For heterogeneous materials it may be dependent
on the pointx. We consider only homogeneous materials for which it consis ts of material
constants. For isotropic materials it has the following exp licit form
cijkl=λδikδjl+2µδijδkl, (9.4)
whereλ,µare Lamé constants.
Substitution of (9.2) in (9.1) yields
L(x)integraldisplay
G(x−x1)f(x1)dV1=−f(x). (9.5)
Consequently, the Green function must satisfy the equation
L(x)G(x−x1)=−1δ(x−x1),1=δijei⊗ej, (9.6)
andδ(x−x1)is the Dirac function.
Obviously, in the linear elasticity the vector udenotes the displacement. Then the
components of the Green function Gij(x−x1)define the components of displacement
ui(x)at the pointxof the infinite medium caused by the unit force acting at the po intx1
in the direction ej. If the medium is finite the Green function specifies the displ acement
uby the relation2
um(x)=integraldisplay
VGim(x−x1)fi(x1)dV1+ (9.7)
+integraldisplay
∂Vbracketleftbigg
ui(x1)cijkl∂Gkm
∂xl(x−x1)+Gim(x−x1)σij(x1)bracketrightbigg
njdA1,
where∂Vis the surface of the domain Vandniare components of the normal vector of
this surface.
The form of the Green tensor Gijfollows from the equation (9.6). It is usually found
by means of the Fourier integral transform. We have
¯G(k)=integraldisplay
G(x)e−ik·xdVx,G(x)=1
8π3integraldisplay
¯G(k)eik·xdVk. (9.8)
Application of the Fourier transform to the equation (9.6) f orx1=0(this assumption
is immaterial as for the infinite domain we can always shift th e origin of the coordinates
to the pointx1), i.e. to the equation
cijkl∂2Gkn
∂xj∂xl(x)=−δinδ(x)
2R.IdscIescWIiscItsc; Continuum theory of stationary dislocations, Solid State Physics, 10,249, 1960.
9.2 Statics of isotropic elastic materials 171
yields
¯ζik¯Gkn(k)=δin,¯ζ
ik=cijklkjkl. (9.9)
This is the set of algebraic relations which can be solved by i nverting the matrix ¯ζ
ik. In
the case of isotropic materials given by (9.4) it is immediat e. It can be done as well for
materials with the hexagonal symmetry3. In general some approximate methods such as
the method of perturbation must be applied4,5.
For isotropic materials we have
¯
ζik=µk2δik+(λ+µ)kikk, k2=kiki. (9.10)
Consequently
¯Gik=¯ζ−1
ik=1
µparenleftbigg1
k2δik−κkikk
k2parenrightbigg
, κ=λ+µ
λ+2µ. (9.11)
It remains to invert the Fourier transform. Before we do so le t us quote an identity
which follows from considerations of electrostatics. In su ch a case the Maxwell equations
describing the electromagnetic field reduce to the followin g two equations
divE=4πρ,rotE=0, (9.12)
whereEthe electric field and ρis the electric charge density. The second relation implies
the existence of the potential ϕsuch that
E=−gradϕ. (9.13)
The choice of signs is the matter of tradition. Consequently , the equation determining
the potential ϕhas the form of the Poisson equation
∇2ϕ=−4πρ,∇2=∂2
∂xk∂xk, (9.14)
3see:E. M. LIiscIfscIsscIhscIiscItscIzsc, L. N. RIoscIsscIescInscIzscIwscIescIiscIgsc; O postrojenii tensora Grina dla osnownogo urawnienia
teorii uprugosti w sluczaje nieograniczenoj uprugo-aniso tropnoj sredy (in Russian), JETF, 17, 9, 783,
1947,
E.KIrscIodieresisscInscIescIrsc; , Das Fundamentalintegral der anisotropen elastischen Diff erentialgleichungen, Z. Phys. ,
151, 4, 504, 1958,
L. LIescIiscIcscIescIksc; The Green function of the theory of elasticity in an anisotro pic hexagonal medium,
Czechosl. J. Phys. ,B19, 6, 799, 1969.
4e.g.T.MIuscIrscIasc;Micromechanics of Defects in Solids , 2nd ed., Martinus-Nijhoff, Dordrecht, 1987.
5e.g. the quotation of the Abstract of the paper of L.J.GIrscIascIysc,D.GIhscIoscIsscIhsc,T.KIascIpscIlscIascInsc; Evaluation of
the anisotropic Green’s function in three dimensional elas ticity, Computational Mechanics ,17, 4, 1996:
A perturbation expansion technique for approximating the t hree dimensional anisotropic elastic
Green’s function is presented. The method employs the usual series for the matrix (I—A)−1to ob-
tain an expansion in which the zeroth order term is an isotrop ic fundamental solution. The higher order
contributions are expressed as contour integrals of matrix products, and can be directly evaluated with
a symbolic manipulation program. A convergence condition i s established for cubic crystals, and it is
shown that convergence is enhanced by employing Voigt avera ged isotropic constants to define the expan-
sion point. Example calculations demonstrate that, for mod erately anisotropic materials, employing the
first few terms in the series provides an accurate solution an d a fast computational algorithm. However,
for strongly anisotropic solids, this approach will most li kely not be competitive with the Wilson-Cruse
interpolation algorithm.
172 Appendix: Green functions for isotropic elastic materi als
where the last relation for the Laplace operator holds for Ca rtesian coordinates. An
easy argument based on the balance equation of charge6yields for the charge density
ρ=eδ(x)the following solution of (9.14)
E=ex
r3⇒ϕ=e
r, r2=x·x, (9.15)
whereeis the electric charge. Obviously, it is the Coulomb law. Now the substitution of
ϕin (9.12) yields a representation of the Dirac δ-function by a function regular beyond
the pointx=0. We have
δ(x)=−1
4π∇2parenleftbigg1
rparenrightbigg
. (9.16)
We use this identity in the derivation of the Green function.
In addition to the above identity we have
∇2r=∂2r
∂xk∂xk=∂
∂xkparenleftBigxk
rparenrightBig
=2
r. (9.17)
Hence, bearing (9.16) in mind,
−8πδ(x)=∂4r
∂xk∂xk∂xl∂xl. (9.18)
We apply to this relation the Fourier transform. It follows
integraldisplay∂4r
∂xk∂xk∂xl∂xle−ik·xdVx= (9.19)
=integraldisplay∂
∂xkparenleftbigg∂3r
∂xk∂xl∂xle−ik·xparenrightbigg
dVx+ikkintegraldisplay∂3r
∂xk∂xl∂xle−ik·xdVx=...
...=k4integraldisplay
re−ik·xdVx,
where we have used the Gauss divergence theorem and accounte d for the fact that surface
integrals must vanish for the infinite domain. Application o f the inverse transform yields
r=−1
π2integraldisplayeik·x
k4dVk. (9.20)
Differentiation of this relation leads to the following iden tities
∂2r
∂xk∂xl=1
π2integraldisplaykkkl
k4eik·xdVk,∇2r=1
π2integraldisplayeik·x
k2dVk. (9.21)
Now we are in the position to find the Fourier inverse of the rel ation (9.11). Bearing
(9.8) in mind we obtain immediately
Gik(x)=1
8πµparenleftbigg
δik∇2r−κ∂2r
∂xi∂xkparenrightbigg
= (9.22)
=2−κ
8πµparenleftbiggδik
r+κ
2−κxixk
rparenrightbigg
, κ=λ+µ
λ+2µ≡1
2(1−ν).
6e.g.L.D.LIascInscIdscIascIusc,E.M.LIiscIfscIsscIhscIiscItscIzsc; Course of Theoretical Physic , vol. 2:The Classical Theory of
Fields , 4th ed., Oxford, Butterworth-Heinemann, 1980.
9.3 Dynamic Green function for isotropic elastic materials 173
This is the Green function for static equations of the linear isotropic elasticity.
9.3 Dynamic Green function for isotropic elastic ma-
terials
In the dynamic case we have to include the inertial force in th e momentum balance
equation. Hence for the linear elasticity the relation (9.3 ) for the operator Lmust be
replaced by the following one
L=Likei⊗ek, Lik=−δikρ∂2
∂t2+∂
∂xjcijkl∂
∂xl, (9.23)
whereρis the constant mass density.
For isotropic materials defined by (9.4), we have
Lik=−−δikρ∂2
∂t2+(λ+µ)∂2
∂xi∂xk+µ∂2
∂xl∂xlδik. (9.24)
Green’s tensor for the above operator will be sought again by the Fourier transfor-
mation. In the dynamic case we have to perform also the transf ormation with respect
to time. To this aim we could use Laplace transform or, as we do below, we have to cut
the Fourier transform to the range of nonnegative time. This reflects the principle of
causality (determinism) of classical mechanics. Conseque ntly, the Green function has to
satisfy the following equations
LilGlj(x,t) =δijδ(x)δ(t)fort≥0, (9.25)
Gij= 0 fort<0.
Obviously, the Green function Gijdetermines the displacement ui(x,t)in the instant
of timetand at the point xcaused by the unit force acting in the ej-direction in
the instant of time t= 0at the pointx=0. Causality physically means that the
displacement cannot be caused by incoming waves which shoul d not exist yet before the
force was applied at the point x=0.
As before, the displacement ui(x,t)for an arbitrary given external force fj(x,t)is
then specified by the convolution integral
ui=Gil∗fj. (9.26)
Obviously the time integration in (9.25) yields immediatel y that the static Green
functionGij(x), calculated in the previous Section should satisfy the rela tion
Gij(x)=∞integraldisplay
−∞Gij(x,t)dt. (9.27)
174 Appendix: Green functions for isotropic elastic materi als
As already mentioned we find the Green function for the infinit e medium by the
double Fourier transform
¯G(k,ω) =integraldisplay integraldisplay
G(x,t)ei(k·x−ωt)dVxdt, (9.28)
G(x,t) =1
16π4integraldisplay integraldisplay
¯G(k,ω)e−i(k·x−ωt)dVkdω.
We callkthe wave vector and the scalar ωthe frequency. Then after the Fourier trans-
form the operator Lij(x,t)for isotropic materials has the following form
¯Lij(k,ω)=ρω2δij−(λ+µ)kikj−µk2δij, (9.29)
and the equation (9.25) becomes purely algebraic
¯Lik¯Gkj=−δij. (9.30)
We have to invert the matrix (9.29). Hence, after easy calcul ations the Fourier trans-
form of the dynamic Green function is as follows
¯Gij=1
µk2−ρω2bracketleftbigg
δij−(λ+µ)kikj
(λ+2µ)k2−ρω2bracketrightbigg
. (9.31)
Obviously, the static transform of the Green function (9.11 ) follows from (9.31) by
the substitution ω=0.
It is convenient to write the above relation by means of the sp eeds of propagation of
longitudinal and transversal waves in a linear elastic mate rial
c2
L=λ+2µ
ρ, c2
T=µ
ρ. (9.32)
We obtain
ρ¯Gij=1
c2
Lk2−ω2bracketleftBigg
δij−parenleftbig
c2
L−c2Tparenrightbig
kikj
c2
Lk2−ω2bracketrightBigg
. (9.33)
The inverse of the above relation is given by the double integ ration prescribed by
(9.28)2. We perform first the integration with respect to the wave vec tork. We have
Gij(x,ω)=1
8π3integraldisplay
¯Gij(k,ω)e−ik·xdVk. (9.34)
Hence
Gij(x,ω)=I0δij−∂I
∂xi∂xj, (9.35)
where
I0=1
8π3integraldisplaye−ik·x
c2
Tk2−ω2dVk=1
4πrc2
Texpparenleftbigg
−iωr
cTparenrightbigg
,
I=−c2
L−c2T
8π3integraldisplaye−ik·x
(c2
Lk2−ω2)(c2Tk2−ω2)dVk (9.36)
=1
4πrω2bracketleftbigg
expparenleftbigg
−iωr
cLparenrightbigg
−expparenleftbigg
−iωr
cTparenrightbiggbracketrightbigg
.
9.3 Dynamic Green function for isotropic elastic materials 175
Calculations of integrals I0andIare made using the method of residua for complex func-
tions. In order to use this method we assume formally that bot h speeds of propagation
are complex. This would indeed be the case for viscoelastic m aterials. We demonstrate
the calculations on the example of the integral I0. Then
c2
T(ω)=Rec2T(ω)+iImc2T(ω)=[1+iβ(ω)]Rec2T(ω). (9.37)
This extension yields the following form of the integral I0
I0=1
8π3integraldisplaye−ik·x
c2
T(ω)k2−ω2dVk=
=1
8π3integraldisplay∞
0integraldisplayπ
0eikrcosθ2πsinθk2
c2
T(ω)k2−ω2dkdθ= (9.38)
=1
4π2irintegraldisplay∞
0kparenleftbigeikr−e−ikrparenrightbig
c2
T(ω)k2−ω2dk=1
4π2irintegraldisplay∞
−∞keikr
c2
T(ω)k2−ω2dk.
This integral can be evaluated by the method of residua. Obvi ously, it possesses two
poles
k=±ω
{[1+iβ(ω)]Rec2
T(ω)}0.5=±ωexpbracketleftbig−i
2arctanβ(ω)bracketrightbig
braceleftbiggradicalBig
1+β2(ω)Rec2
T(ω)bracerightbigg0.5. (9.39)
The pole with the minus sign lies in the second quadrant of the complex plane while the
other pole lies in the fourth quadrant. Hence, we choose as th e path of integration the
real axis and the semicircle of the infinite radius in the uppe r part of the complex plane.
We obtain
I0=1
4πrc2
Texpbracketleftbigg
−irω
cT(ω)bracketrightbigg
. (9.40)
The transition cT(ω)→cTgives the desired result. In a similar manner one can calcula te
the integral I. We have to use obvious identities when differentiating in (9 .35)
∂r
∂xi=ni,∂2r
∂xi∂xj=1
r(δij−ninj), nini=1. (9.41)
It follows
Gij(x,ω)=1
r[h(ωr)δij+g(ωr)ninj], (9.42)
where
h(ωr) =1
4πr2ρω2braceleftbiggbracketleftbiggparenleftbigg
1+irω
cLparenrightbigg
e−iωr/cL−parenleftbigg
1+irω
cTparenrightbigg
e−iωr/cTbracketrightbigg
+r2ω2
c2
Te−iωr/cTbracerightbigg
,
g(ωr) =−1
4πr2ρω2braceleftbiggbracketleftbigg
3parenleftbigg
1+irω
cLparenrightbigg
−−r2ω2
c2
Lbracketrightbigg
e−iωr/cL− (9.43)
−bracketleftbigg
3parenleftbigg
1+irω
cTparenrightbigg
−r2ω2
c2
Tbracketrightbigg
e−iωr/cTbracerightbigg
176 Appendix: Green functions for isotropic elastic materi als
This is, obviously, the Green function for monochromatic wa ves of the given frequency
ω. The time dependence of solution is then given by the factor exp(iωt).
It remains to perform the second inverse transformation. We use here the following
relations
1
2πintegraldisplay∞
−∞eiωtdω=δ(t),
1
2πintegraldisplay∞
−∞1
iωeiωtdω=H(t)=braceleftbigg1fort>0,
0fort<0,
−1
2πintegraldisplay∞
−∞1
ω2eiωtdω= Ψ(t)=braceleftbiggtfort>0,
0fort<0,(9.44)
∂Ψ
∂t=H(t),∂H
∂t=δ(t).
Bearing these relation in mind as well as
∂2
∂xi∂xjparenleftbigg1
rparenrightbigg
=3ninj−δij
r3, (9.45)
−1
2πintegraldisplay∞
−∞1
ω2parenleftbigg
1+irω
cLparenrightbigg
eiω(t−r/cL)dω= Ψparenleftbigg
t−r
cLparenrightbigg
+r
cLHparenleftbigg
t−r
cLparenrightbigg
,
and similarly for cT, we finally obtain the dynamic Green function
4πρGij(x,t)=δparenleftbigg
t−r
cTparenrightbiggparenleftbiggδij
c2
Tr−xixj
c2
Tr3parenrightbigg
+
+δparenleftbigg
t−r
cLparenrightbiggxixj
c2
Lr3+ (9.46)
+∂2
∂xi∂xjparenleftbigg1
rparenrightbigg
tparenleftbigg
Hparenleftbigg
t−r
cLparenrightbigg
−Hparenleftbigg
t−r
cTparenrightbiggparenrightbigg
.
The first contribution describes the transversal part of the impulse which arrives with the
speedcT, the second contribution is the longitudinal part of the imp ulse which arrives
with the speed cLand the third contribution is the evolution of the impulse be tween the
arrival of the longitudinal and transversal parts.
Easy integration in the relation (9.27) yields the static Gr een function given by the
relation (9.22).
Bibliography
[1]K. AIkscIisc, P. G. RIiscIcscIhscIascIrscIdscIssc; Quantitative Seismology , University Science Books,
Sausalito, 2002.
[2]RIoscImscIescIsscIhsc C. BIascItscIrscIasc; Elements of Continuum Mechanics , AIAA Education Series,
Reston, 2006.
[3]R.M.CIhscIrscIiscIsscItscIescInscIsscIescInsc; Theory of Viscoelasticity. An Introduction , Academic Press,
N. Y., 1971.
[4]M.E.GIuscIrscItscIiscInsc; TheLinearTheoryofElasticity , in: C. Truesdell (ed.), Encyclopedia
of Physics, vol. VIa/2 (Mechanics of Solids), Springer, Ber lin, 1972.
[5]K. HIuscItscItscIescIrsc, K. JIodieresisscIhscInscIksc; Continuum Methods of Physical Modeling. Continuum
Mechanics,DimensionalAnalysis,Turbulence , Springer, Berlin, 2004.
[6]J. C. JIascIescIgscIescIrsc, N. G. W. CIoscIoscIksc, R. W. ZIiscImscImscIescIrscImscIascInsc ;Fundamentals of Rock
Mechanics, Blackwell, 2007.
[7]L. D. LIascInscIdscIascIusc, E. M. LIiscIfscIsscIhscIiscItscIzsc; Mechanics, Third Edition, Butterworth-
Heinenann, Oxford, 1976.
[8]L.D.LIascInscIdscIascIusc,E.M.LIiscIfscIsscIhscIiscItscIzsc; TheoryofElasticity , 3rd ed., Oxford, Butterworth-
Heinemann, 1986.
[9]J.LIescImscIascIiscItscIrscIesc,J.-L.CIhscIascIbscIoscIcscIhscIesc; MechanicsofSolidMaterials , Cambridge Univer-
sity Press, 1990.
[10]J. LIescImscIascIiscItscIrscIesc, R. DIescIsscImscIoscIrscIascItsc ;Engineering Damage Mechanics, Springer, Berlin,
2005.
[11]I-SIhscIiscIhscLIiscIusc; ContinuumMechanics , Springer, Berlin, 2002.
[12]Y.A.MIescIlscInscIiscIkscIoscIvsc; InfluenceFunctionApproach: SelectedTopicsofStructural Me-
chanics, WIT Press, 2008.
[13]T.MIuscIrscIasc; The continuum theory of dislocations, Adv.Mater.Res., 3, 1, 1968.
[14]R.W.OIgscIdscIescInsc; Non-LinearElasticDeformations , Dover, Mineola, N. Y., 1984.
177
178 BIBLIOGRAPHY
[15]A.C.PIiscIpscIkscIiscInsc; LecturesonViscoelasticTheory , Springer, New York, 1972.
[16]J. R. RIiscIcscIesc; The Mechanics of Earthquake Rupture, in: Physics of the Earth’s
Interior , A. M. Dziewonski, E. Boschi (eds.), North Holland, 1980.
[17]T. D. SIhscIescIrscImscIescIrscIgscIoscIrsc; Teoria uprugosti mikroneodnorodnych sred, (in Russian),
"Nauka", Moscow, 1977.
[18]S.TIiscImscIoscIsscIhscIescInscIkscIosc,J.N.GIoscIoscIdscIiscIescIrsc; TheoryofElasticity , McGraw-Hill, N. Y., 1951.
[19]A.VIescIrscIrscIuscIiscIjscItsc; SoilMechanics, Delft University of Technology, 2006.
[20]H. F. WIascInscIgsc; Theory of Linear Poroelasticity with Applications to Geome chanics
andHydrogeology , Princeton University Press, 2000.
[21]K.WIiscIlscImscIascInscIsscIkscIisc; ThermomechanicsofContinua , Springer, Berlin, 1998.
[22]K. WIiscIlscImscIascInscIsscIkscIisc; Continuum Thermodynamics. Part I: Foundations, World Scien-
tific, 2008.
[23]D. MIuscIiscIrsc WIoscIoscIdsc; Soil Behaviour and Critical State Soil Mechanics, Cambridge
University Press, 1990.
[24]HIascInsc-CIhscIiscInscWIusc; ContinuumMechanicsandPlasticity , Chapman&Hall/CRC, 2005.
Index
acoustic waves, 81
Airy function, 91
Airy phase, 104
Almansi-Hamel measure, 31
amplitude of wave, 97
angle of repose, 149
anisotropic hardening, seekinematical hard-
ening
anisotropic material, 73
Armstrong-Frederick law, 154
associated flow rule, 145
back-stress, 148
balance of internal energy, 62
Bauschinger effect, 148
Beltrami-Michell stress equations, 89
Bernoulli Theorems, 50
biharmonic function, 90
Biot moduli, 112
Biot-Willis coefficient, 112
body force, 48
Boltzmann integral, 124
Boltzmann superposition principle, 124
boundary conditions, 80
Boussinesq problem, 86
Boussinesq representation, 84
Boussinesq-Somigliana-Galerkin solution, 85
brittle materials, 137
bulk modulus, seecompressibility modulus
bulk waves, 99
Burgers vector, 159
Cauchy equation, 50
Cauchy relation, 50
Cauchy stress tensor, 49
Cerrutti problem, 88Christoffel symbols, 78
Clausius-Duhem inequality, 65
cohesion, 149
cohesion yield stress, 152
Coleman’s method, 122
compatibility condition, 41
compatibility equation, 41
compliance, 74
components of tensor, 13
compressibility modulus, 74
compressible Mooney-Rivlin material, 71
concentration of stresses, 94
consistency parameter, 146
consolidation of soils, 150
continuity of tractions, 51
continuity relation, 45
contracted epsilon identity, 15
contravariant base vector, 77
convolution integral, 123
coordinates of vector, 11
covariant base vector, 77
covariant derivative, 78
creep, 117
creep functions, 125
current configuration, 21
curvilinear coordinates, 77
cylindrical coordinates, 78
d’Alambert solution, 82
damping, 97
damping factor, 123
Darcy’s law, 113
dashpot, 119
deformation gradient, 24
relative, 33
determinant, 15
179
180 INDEX
diffusion, 112
diffusion equation, 111
diffusivity, 113
Dirac function, 83, 170
direction of propagation, 97
discontinuity of mass density, 47
dislocation density, 162
dislocation flux, 164
dislocation line, 159
dislocation loop, seedislocation line
dispersion relation, 98
displacement approach, 72
displacement vector, 30
dissipation, 109
distortion, 160
distortion energy, 140
Drucker stability postulate, 145
Drucker’s postulate, 136
Drucker-Prager yield surface, 152
dry granular materials, seefrictional mate-
rials
ductile materials, 137
dynamic compatibility conditions, 51
dynamic Green function, 174, 176
earthquake rupture, 166
edge dislocation, 158, 163
effective stress, 150
effective stress , seeequivalent stress
eigenvalue, 16
eigenvalue problem, 15
eigenvector, 16
Einstein convention, 11
elastic domain, 136
elastic material, 69
elastic-viscoelastic correspondence principle,
131
elasticities,seeresponse coefficient
elasticity modulus, seeYoung modulus
energy conservation, 61
entropy flux, 65
entropy function, 65
entropy production, 65
equivalent plastic strain, 143
equivalent stress, 139Euler-Piola-Jacobi identities, 35
Eulerian coordinates, 23
evolution equations, 128
exterior product, seevector product
far field approximation, 83
first law of thermodynamics, 63
Flamant problem, 92
Fourier integral transform, 122, 170
Fourier relation of heat conduction, 66
Fourier’s law, seeFourier relation of heat
conduction
Frank-Read source of dislocations, 164
frequency of wave, 97
friction angle, seeangle of respose
frictional materials, 149
function of motion, 23
Galerkin function, 90
Gauss Theorem, 18
generalized Kelvin model, 121
generalized Maxwell model, 121
Gibbs equation for ideal fluids, 68
Gibbs equation of linear thermoelasticity,
109
Green function, 82, 169
Green tensor for static problem, 169
Green-St. Venant measure, 31
group velocity, 104
Gurtin Theorem, 38
Hadamard Theorem, 47, 95
Haigh—Westergaard coordinates, 151
Hamilton principle, 107
hardening function, 147
hardening parameter, 146
harmonic function, 84
heat conductivity, 66
heat flux vector, 62
Heaviside function, 83
Helmholtz decomposition, 17
Helmholtz free energy, 66, 67, 74, 108
Hooke law, 73
Huber-Mises-Hencky surface, 140
hyperbolicity, 81
INDEX 181
hypoplasticity models, 153
ideal fluid, 66
Ilyushyn postulate, 136
immiscible mixture, 111
incompressible material, 76
influence function, 82
integrability conditions, 35
internal energy density, 62
intrinsic permeability, 113
irrotational flow, seepotential flow
isotropic compliance matrix, 74
isotropy of the material, 70
Kelvin model, 120
kinematical hardening, 148
kinetic energy, 62
Kirchhoff modulus, seeshear modulus
Kirchhoff Theorem, 38
knot, 164
Kronecker delta, 10
Lagrange-Euler equations, 107
Lagrangian, 107
Lagrangian coordinates, 23
Lamé constants, 73
Lamé equations, seeNavier-Cauchy equa-
tions
Laplace operator, 79
Laplace operator , 80
Laplace transform, 122
latent heat, 64
left Cauchy-Green deformation tensor, 29
left stretch tensor, 29
Leibniz Theorem, 18
Levi-Civita symbol, seepermutation sym-
bol
Lie derivative, 35
linear isotropic elastic material, 73
linear thermal expansion coefficient, 110
load-carrying capacity, 142
local rotation, 26
Lode angle, 151
Lode parameter, 141
longitudinal wave, 82, 96loss modulus, 130
Love dispersion relation, 103
Love waves, 102
mass conservation, 44
mass density, 44
material body, 21
material domain, 44
material time derivative, 45
material vector, 24
maximum shear stresses, 59
Maxwell construction, 66
Maxwell’s model, 119
membrane with cavity, 92
memory effect, 118
metric tensor, 77
mobility, 113
modes, 103
Mohr’s circle, 58
Mohr-Coulomb law, 149
moment of momentum, 51
moment tensor density, 166
momentum, 48
momentum conservation law, 49
monochromatic wave, 97
Navier-Cauchy equations, 77
near field approximation, 83
non-associated plastic flow potential, 152
non-Newtonian fluid, seeviscoelastic fluid
normal stresses, 49
Norton power law, 154
Odqvist parameter, 147
Orovan equation, 165
orthogonal tensor, 14
orthotropic material, 73
Papkovich-Neuber potentials, 84, 91
permutation symbol, 15
phase, 97
phase equilibrium line, 66
phase shift, 97
phase speed, 97
physical components, 77, 78
Piola-Kirchhof stress tensor, 48
182 INDEX
plane strains, 57, 90
plane stresses, 57, 91
plane wave, 97
plastic strain, 136
plastic working, 145
Poisson number, 75
polar decomposition, 26
pore pressure, 111, 112, 150
pore spaces, 111
poroelastic expansion coefficient, 112
porosity, 112
porous material, 113
potential energy, 106
potential flows, 50
Prager consistency condition, 144
Prandl-Reuss equation, 146
pressure, 50
pressure function, 50
principal direction of stress tensor, 53
principal invariants, 16, 53
principal stretch, 31
principal values of stress tensor, 53
principle of virtual work, 105
pure strain, 39
radiation, 62
rate-type constitutive relations, 128
Rayleigh waves, 100
reference configuration, 22
relaxation functions, 124
relaxation time, 115
Rendulic planes, 151
Representative Elementary Volumes, 112
residual inequality, 67
response coefficient, 71
rheological elements, 119
right Cauchy-Green deformation tensor, 29
right stretch tensor, 26
rigid body rotation, 36
rigid displacement, 37
rigid heat conductor, 111
Rivlin-Ericksen fluids, 129
rotation vector, 39
rule of transformation, 11, 14scalar potential, 18
scalar product, 10
screw dislocation, 158, 163
second law of thermodynamics, 65
seepage velocity, 112
seismic waves, 104
self-equilibrated stresses, 158, 162
separation of variables, 132
shear modulus, 74
shear stresses, 49
shear wave,seetransversal wave
simple extension, 39
simple shear, 40
simple shearing, 25
singular surface, 46
Skempton coefficient, 112
small deformation, 31
solid skeleton, 111
Somigliana dislocation, 157
Sommerfeld condition, 99
specific enthalpy, 64
specific entropy, 65
specific heat, 109
spectral representation, 17, 98
spherical coordinates, 79
spin, 34
spring, 119
square-cube law, 6
standard linear viscoelastic solid, 129
standard rheological model, 120
Stokes Theorem, 18
storage modulus, 130
strain field, 36, 40
strain space formulation, 136
stress approach, 72
stress relaxation, 117
stress space formulation, 136
stress vector, seetraction
stretching, 34
supply of energy, 62
surface waves, 99
technical frequency, 98
tensor of the second rank, 13
tensor product, 13
INDEX 183
thermal conductivity, 108
thermodynamical potential, 67
thermoelastic materials, 108
traction, 48, 50
trajectory of motion, 32
transversal wave, 82, 96
transversely isotropic material, 73
Trefftz potential, 85
Tresca-Guest surface, 139
unconstrained specific storage coefficient, 112
undrained bulk modulus, 113
uniform dilatation, 39
uniform extension, 24
variation in water content, 112
vector potential, 18
vector product, 15
vector space, 9
dimension, 10
velocity, 32
velocity gradient, 34
virtual displacement, 105
viscoelastic fluid, 117
viscoelasticity of solids, 117
Voigt notation, 72
Volterra dislocation, 157
volumetric thermal expansion coefficient, 110
wave length, 98
wave number, 97
waves of weak discontinuity, seeacoustic
waves
working of body forces, 62
yield function, 139
yield limit,seeyield surface
yield locus,seeyield surface
yield surface, 136, 139
Young modulus, 75