high freq limits of fm,gm and hm REVIEWED
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Phil's notes dated 5.16.14, reviewed 10.8.14, deriving the large-ω limits of fm, gm and hm from the large-argument Bessel function asymptotics (NIST 10.7.8, 10.17.2). Results: fm and gm are independent of m, and hm is approximately zero, so Eθ is about zero. He applies them to the Appendix D electric fields and current densities Jz and Jr, and checks the magnitude and phase against his M-notation formula (2.3.5). Some equations are garbled in the extraction.
AI-written summary; may contain errors. This description is approximate.
Extracted text (machine-read; may contain errors)
High Freq Limits of fm, gm and hm PhL 5.16.14
This was early work on doing these large ω limits. They are now derived inside lines doc D.10 in a derivation that was first done below relating to the Bessel function of large argument. I also confirmed these limits with at least one mws files in this folder. Unlike the low ω results, I think my high ω results are accurate. (10.8.14)
1. Large ω limit of fm
Here is the fm case taken from lines doc
Fact: In the extreme skin effect regime,
fm(r) = -2j [ (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
fm(a) = -2j . (6.5.22)
Proof: From NIST 10.7.8 we find that for large x argument,
Jm(x) ≈ (2/πx)1/2 cos(x-mπ/2-π/4) . NIST 10.7.8
Then for x = βr = (j-1)(r/δ) from (6.5.9) and with δ << r ≤a we keep only the larger exponential term so that
Jm(x) ≈ (2/πx)1/2 cos(x-mπ/2-π/4) ≈ (2/πx)1/2 (1/2) e+r/δ ej[(r/δ)+mπ/2+π/4]
= (1/πβr)1/2 e+r/δ ej[(r/δ)+mπ/2+π/4] . (6.5.23)
From (6.5.14),
fm(r) ≡ [ - ] . (6.5.14)
We then examine the two terms
= = (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ-π/2]
= (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ+π/2] . (6.5.24)
Then
fm = [ - ] = (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ [e-jπ/2 - e+jπ/2]
= (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ [-j - j]
= -2j [ (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ] .
which then verifies (6.5.22). QED
2. Large ω limit of gm
Use this result from the previous section
Jm(x) ≈ (1/πβr)1/2 e+r/δ ej[(r/δ)+mπ/2+π/4]
Now, from (***),
gm ≡ [ + - ].
We then examine the three terms. We borrow this result from the previous section
= (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ+π/2] = j (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
so then the first term becomes
= j (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
The second term is
=
= (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ
and the third term is
= = (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ] ejπ
= - (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
Combining the three terms we get
gm ≡ [ + - ]
= j (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
+ (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ
- [- (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ
The last two terms are the same, so then
gm = { j + 2 } (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
But since we are doing x = βr >> 1 in this limit, this becomes just
gm = 2 (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
where we ignore that fact that m can get large in distant partial waves.
3. Large ω limit of hm
Same as previous section except
hm ≡ [- + + ].
so now the last two terms will cancel leaving just the first term (assuming we can ignore correction terms in the asymptotic expansion), so
hm = - { j } (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
4. Implication for the Appendix D electric fields:
Ez(r,m) = (1/4) ηm I Rdc (aβ) fm
Er(r,m) = (j/4) ηm I Rdc (aβd) gm
Eθ(r,m) = (1/4) ηm I Rdc (aβd) hm
fm = -2j [ (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
gm = 2 (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
hm = - { j } (a/r)1/2 e-(a-r)/δ ej[(r-a)/δ]
Comments:
(a) Notice that for x>> 1 we get hm ≈ 0 and then Eθ ≈ 0 which I like in general terms.
(b) Both fm and gm are independent of m.
(c) Recall from lines doc that
Jz(r,θ) = (-2j) [(a/r)1/2 e-(a-r)/δ ej[(r-a)/δ ](I/πa2)(βa/4) *
[ 1 + 2 Σm=1∞ (-1)m e-m|ξ|cos(mθ) ] .
(6.5.25)
and also
n1(ξ1,θ) = (q/2π)[ 1 + 2 !Syntax Error, I (-1)m e-m|ξ| cos(mθ) ] . Bipolar (A.13) (6.5.5)
allowing us to write
Jz(r,θ) = (-2j) [(a/r)1/2 e-(a-r)/δ ej[(r-a)/δ ] (I/πa2)(βa/4) (2π/q) n1(ξ1,θ)
We can make then a similar conclusion about Jr(r,θ) by replacing -2j by 2, so
Jr(r,θ) = 2 [(a/r)1/2 e-(a-r)/δ ej[(r-a)/δ ] (I/πa2)(βa/4) (2π/q) n1(ξ1,θ)
This shows that both Jz and Jr "track n(θ)" in the extreme skin effect regime.
(d) From this last equation we can state that
Er(r,θ) ≈ Er(a,θ) e(r-a)/δ ej(r-a)/δ (6.5.18)
and this then justifies the assumption I made in (6.5.18) !! So I can improve that section with these extra facts.
Maple Computations
Start with NIST 10.17.2, keeping a few leading terms in each inverse power expansion :
Jm(x) ≈ (2/πx)1/2 [ cos(w)*(1-a2(m)/x2) - sin(w)*(a1(m)/x) ]
where
w = x - mπ/2 -π/4
e-w = e-j(x-mπ/2-π/4) = e-j(z-π/4) ejmπ/2
But
x = βr = ej3π/4 (/δ) r
which has a large positive imaginary part for small δ, so w has a positive imaginary part. Then
cos(w) = [ ejw + e-jw]/2 ≈ (1/2) e-jw
sin(w) = [ ejw - e-jw]/2j ≈ -(1/2j) e-jw = (j/2)e-jw
Then our expansion above becomes
Jm(x) ≈ (1/2) (2/πx)1/2 [e-jw (1-a2/x2) - j e-jw (a1/x) ]
= (1/2πx)1/2 e-jw [ 1 -j a1(m) (1/x)- a2(m) (1/x2) + ... ]
= (1/2πx)1/2 e-jx ejπ/4ejmπ/2 [ 1 -j a1(m) (1/x)- a2(m) (1/x2) + ... ]
Now set
x = βr = (j-1)(r/δ)
so then
e-jx = e-j(j-1)(r/δ) = e(1+j)(r/δ)
Jm(x) ≈ (1/2πx)1/2 e(1+j)(r/δ) ejπ/4ejmπ/2 [ 1 -j a1(m) (1/x)- a2(m) (1/x2) + ... ]
Now look at
= = e(1+j)(r-a)/δ
and there are no more terms because m is the same top and bottom.
Next, look at
= e(1+j)(r-a)/δ ej2π/2
= - e(1+j)(r-a)/δ
When we add, we get
+ = e(1+j)(r-a)/δ *
[ 1 - ]
Now both x and xa are large so approx the ratio as
≈ 1 - ja1(m+1)(1/x) + ja1(m-1)(1/xa)
Then we have
+ = e(1+j)(r-a)/δ * [ ja1(m+1)(1/x) - ja1(m-1)(1/xa) ] (*)
Now look at the other term
Jm(x) ≈ (1/2πx)1/2 e(1+j)(r/δ) ejπ/4ejmπ/2 [ 1 -j a1(m) (1/x)- a2(m) (1/x2) + ... ]
= (2m/x) e(1+j)(r-a)/δ ejπ/2
and again we do our approximation on the ratio to get
= (2m/x) e(1+j)(r-a)/δ ejπ/2 [ 1 - ja1(m)(1/x) + ja1(m-1)(1/xa)]
= j (2m/x) e(1+j)(r-a)/δ [ 1 - ja1(m)(1/x) + ja1(m-1)(1/xa)]
Now look at hm :
hm ≡ [- + + ].
= - j (2m/x) e(1+j)(r-a)/δ [ 1 - ja1(m)(1/x) + ja1(m-1)(1/xa)]
+ e(1+j)(r-a)/δ * [ ja1(m+1)(1/x) - ja1(m-1)(1/xa) ]
= e(1+j)(r-a)/δ *
{ - j (2m/x) [ 1 - ja1(m)(1/x) + ja1(m-1)(1/xa)] + [ja1(m+1)(1/x) - ja1(m-1)(1/xa) ] }
first term last two terms
= e(1+j)(r-a)/δ *
{ - j (2m/x) + ja1(m+1)(1/x) - ja1(m-1)(1/xa) }
= e(1+j)(r-a)/δ { { j[ - 2m + a1(m+1)](1/x) - ja1(m-1)(1/xa) }
= e(1+j)(r-a)/δ j{ [ - 2m + a1(m+1)](1/x) - a1(m-1)(1/xa) }
This whole thing is then order 1/x so we get
hm ≈ 0
***********************
Compare my limit to the M notation:
Jm(x) = (1/2πx)1/2 e-jx ejπm/2 ejπ/4 [ 1 -j cm (1/x) - dm (1/x2) + ... ]
Pause. Compare this to
Jm(ej3π/4z) = Mm(z) ejθ(z) . (2.3.3)
so we have
x = ej3π/4z = (j-1)z/
e-jx = e-j(j-1)z/ = e(1+j)z/
My limit expressed in terms of z is then
Jm(x) ≈ (1/2π ej3π/4z)1/2 e(1+j)z/ ejπm/2 ejπ/4 [ 1 -j cm e-j3π/4 (1/z) - e-j3π/2dm (1/z2) + ... ]
|Jm(x)| ≈ (1/2π z)1/2 ez/ | 1 -j cm e-j3π/4 (1/z) - e-j3π/2dm (1/z2) + ... |
≈ (1/2π z)1/2 ez/ | 1 -j cm e-j3π/4 (1/z) |
and the leading factors agree with (2.3.5). Now,
| 1 -j cm e-j3π/4 (1/z) | = | 1 -j cm(-1-j) (1/z) | = | 1 +j cm(1+j) (1/z) |
= | 1 + cm(j-1) (1/z) |
So
| 1 + cm(j-1) (1/z) |2 = (1 + cm(j-1) (1/z)) (1 + cm(-j-1) (1/z))
= 1 + cm(-j-1) (1/z) + cm(j-1) (1/z))
= 1 - 2 cm (1/z)
=> | 1 -j cm e-j3π/4 (1/z) | ≈ 1 - cm (1/z) = 1 - a1(m) (1/z)
Now NIST says,
a1(m) : 2k-1 = 1 so numerator is (4m2- 1), denom = 8, so
a1(m) = (4m2- 1)/8
Then my limit becomes
|Jm(x)| ≈ (1/2π z)1/2 ez/ [ 1 - a1(m) (1/z) ]
= (1/2π z)1/2 ez/ [ 1 - (1/z) ]
= (1/2π z)1/2 ez/ [ 1 - (1/z) ]
This agrees with my (now corrected) (2.3.5)
How about the phase part?
Jm(x) ≈ (1/2π ej3π/4z)1/2 e(1+j)z/ ejπm/2 ejπ/4 [ 1 -j cm e-j3π/4 (1/z) - e-j3π/2dm (1/z2) + ... ]
≈ e-jπ3/8(1/2π z)1/2 e(1+j)z/ ejπm/2 ejπ/4 [ 1 -j cm e-j3π/4 (1/z) - e-j3π/2dm (1/z2) + ... ]
The leading factor has this phase (ignoring the [...] for the moment):
θ = -π3/8 + z/+mπ/2 + π/4 = -3π/8 + z/+mπ/2 + 2π/8 = -π/8 + z/+ mπ/2
This agrees with the leading terms of (2.3.5). Now for the bracket
[ 1 -j cm e-j3π/4 (1/z)] = 1 + cm(j-1) (1/z) // from a foot above
= (1 - cm (1/z) + j cm(1/z)
θ = tan-1 (y/x) ≈ y/x ≈ cm(1/z) / 1 ≈ cm(1/z) ≈ (4m2- 1)/8(1/z)
= (1/z)
and this agrees also with (2.3.5).
Fact: I have proven that my two limit formulas are the same and fixed some bugs!