Books on Group Theory
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Binder of Phil's notes from his Berkeley years. It opens with a short bibliography reviewing books on Lie groups, the Lorentz group and SU(3), including Wybourne, Naimark, Gelfand, Lichtenberg, Carruthers and Gourdin, with contents lists and opinions. It also has a June 1979 summary of major theorems in Tinkham's finite group text and handwritten pages that are largely unreadable in the extraction.
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Extracted text (machine-read; may contain errors)
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:= 1,Wybourne (1974):Classical GroupeforPhysicists.
This400page,well-printed, well-written bookisaverythorough |treatment ofLie Groups. There/is much discussion ofweights, Dyakin
diagrams, Cartan matrices. Thefe isaspecial section onthe 3-paraneter
groups which show upalot in physios. The text concludes with three
casestudies: theisotropic HO)thehydrogen ston,andshellstrusture, What isnot found inthis bookare: (1)details ofthe Poincare
andrestrioted Lorentzgroups.|(2)detailsofSU(3),
2,Lyubarskii (1960): Applications bsGroupTheory inPhysics.
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This 380 page Russian translation starts out with the finite groups
ad all the basic group theorems. However, itdoes have 50pages
specifically ontherepresentations oftheLorentz group andthe
spinor and tensor algebras. Also, disoussion ofinvariant wave
equations. Thebook isexceedingly dense inpriat, butgood enoughthat Weinberg references italone forthis Lorentz subject.
\ |3.Ruhl (1970): the Lorentz Group andHarmonic Analysis.
300pages andmuch more specialised than the above texts, this book
haslongsectionsontherepremnetations ofSL§2,C).Somehow,the 2 accentofthisbookseemstobqfunctions ofgroupspaces,Plancherelmeasures, and stuff like onewould find inaToller paper. Sort of
thegeneralized Fourier/Laplacd business. Infaet, theeapoftheboek
isachapter onRegge andToller poles.There isnothing inthis book about LieAlgebras orSU(3), although
dotted and undotted spiners do ‘getmentioned. Not aparticularly goodplacetostart. Fr{
4.Naimark (1964): Linear Representations ofthe Lorentz Group.
Atpanslation fromtheRussian bfWaimark's 1958text. 450pages,
good printing. Lote ofstuff on'spinor representations andintegral business. Concludes with discussion ofInvariat Equations.This book has too many proofs for myliking. Too specialized.
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5.Gelfand Minlos Shapiro (1963): Rebs oftheRotandLorgroups with Abpbioa.
Another 1958 Russian text transjation. Lots and lots oftalk about
spinors inboth the Rot and Lor| groups, and invariant equations.
Thisbookwasrecommended byMN:niko. Theauthors refer toNaimark'sbook asbeing more detailed. Iagree. Looks good.
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6.Lioktenberg (1970): Unitary SymdndElementary Particles.
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r2 230pages,wellorganized andprinted. Openswitheomments omLie Groups and algebras, Alot ea'the Young Tableaux methods for
deseribing multiplets. Dees theSU(3) Clebsch's, discusses 6-fold
way, then ghapter onSUg. Closgs with discussion ofquark models.Ilike.Wa | 7.Hammermesh (1962): Group Theory. |
Anice ehapter onLiegroups, Yutbeyond that itisallbasice. Thereisasmall piece about Lorents wayattheend. Donotbother with
thisbook, though itisanexcellent group theory text ingeneral.
8,Lipkin(1966): LieGroupsforpedestrian. 7
Notvery organized, buthashigher groups mentioned like SU4andSU6,
‘Tyere isapiece ontheYoung dtuff, andmention ofekarm, 160pages.Obviously nomentrion ofthearentgroup.
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18.L.O.Raifeartaigh :LecturesonLocalimGroupsandtheirRepresentations
Matscience Report 25,India. QA385 63!1964*Inst. ofMath. Studies, Madras-20, I.
-- —~ =Well written notes: ‘Goes into some oftheparameter ‘stuff that Bargmann uses~and
-+= thiswasveryhelpful. Healsodoesrootdiagrams etcwithespecial section onthe -
- construction ofinvariants._ Listofother“Matecinces givenonbackcover...
We"Topological Groupe”L.Pontajegin,(Moscow) Princeton UPress,1939
A385 P61939. \
This dlder book isconsidered oneofithestandard references. Contents:
7 a)abstract groups. ;
b)topological spaces’ .
-- ¢)topological groups |
d).representations ofcompact topological groups .e)abelaincases i . f)concept ofalie group
e g)structure ofcompact topological ghoups
- ~h)localiyisomorphic groups(andunjversal coveringgroups)~ 4)structure ofLieGroups. 4 ~
~~=20.Lyebl;-Group Theory andItsApplications, III--QA171162v.3PHYSThishas-anarticle by.Windternits! ontwovariable expansions andreduction
ofscattering amplitudes totheultimately dymanic. "Lorentz amplitudes:". Seems
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: Carruthers: "Introduction toUnitary Symmetry”:e ]‘reftQC7216291966Interscience Tracts.—§_LL
_Constents: - oo oS
1.su(2).
To DySUG).Cartan Weylstandard fora.VandFstarr. Weylgroupor~———
_ _ _ |. ofreflections. Regular rep=generator rep.
|_3sTheIRs. Discusses direct products, Casimirs, andrelevance toparticles.
4.Properties ofthe IRs. Clebsch*s. Tensor analysis.
5.SU(3) invariant vertices and amplitues. Ratios.
6.Breaking. Both kinds ofmass formulas. Magnetic moments.
7.Crossing symmetry. Isospin crossing matrices. SU(3) crossing matrices!
Appendixhasisoscalar factors. -————Added-nete-on-currentay ——- -— - — - 7 -
Thisbook4snumber 27inaseries ofmonographs inphysics. Soneofthe- ~|——~ctherones_ere-of-some.interest.One_on_optical models. — — ——
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book: Unitary Symmetry andElenentary Particles
D.B.LichtenbergAP(1970)QC721L486250pages db Contents:eee —~~~-—.(nupber of_pages_in_chapter)_—____1.Introduction tO" pee
~— ~~. .2.PropertiesofGroups 12 3.Symmetry, Reps, Multiplets OS
i.The Symmetric Group and Identical Particles 12V— 5.Lie‘groups-and-wlgebras-—— 8B6.Multiplets 23 :--—— JvYoung—Tableaux-and_Unitary-Symmetry———— —2/,-seer____________ __
8.Clebsh's B6V ey
——~-— -~9+TheEightfold way 2 -32 -10. The sU(6) 11
11. The Quark Model 3212,Variants ofquarkimédel ~~~-~~—‘10
1Introduction. Anpverview withsomeinteresting facts.4)saccbt,Schitz,Herglotzin1842,1697,1911 didinvariances of-class. lagr: b)Wigner showed that symtrans areeither unitary oranti. Only theunitery
_—..——.ones. have conservationJawa;thus,noTawforT,orTCP. 2.Groups. Alloldhat. Some facts that areinTinkham; mention ofSygroups.
3.Grab Bag. Vector space ofQM,anilinears, antiunitaries; group representations. 01iyeheSymmetric Group.ShortdealonYoungTables.Stecopy,seenotes.~~ 5.Tealgebras. Allthis stuff isdone inWybourne. Cartan Weyl standard form. Licht-“doesbetterby‘distinguishing rootvectors fromroote; otherwise saneold-things\9 D._%,taltizlete. Thegenerators, DandFsdandf,etc.Weighttheory.Lcallsthe _ estweight. "dominant weight." Highest_weight_p_qsumtheorem.SU(3)mitiplets andtensor operators. Uses mforweight. Again, allimown stuff, donotread this.__.7sYoungTableaux andSU(n).Verynicestuff. Seecopyandnotes.Class_and triality!
&.Clebsch’s. Nice, uses Youngs. Lots oftables, Wigner Eckart. See copy and notes.
9.8Fold Way. The basic multiplets ofparticles. U-spin section, theugQaxes.——2aaetclaixmissperfectUsinglet, justtothe-extent: thatUisgood——forstrongs. Does allthestandard U-spin predictions: mass splkts, Coleman
~ Glashow 1961 law, reaction-rate ratios, photopreduction-ratios,-photondecays. Photon issupposed tobe@Usinglet, hence ratios easy toget. Then GellMann~——-Okubos. Theinvariant_D andFcouplings writtenoutinfull,no_formaliam chosen. eWill copy page 178-9.
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book:UnitarsSymatries. 1 |Gourdin. Wiley, 1967 QC721G65 300pages
“= Contents: 1.The SU(3) group. 25
_2. Physical Interpretations 7
3.Particle Classification 12 ~ —
4.Strong Interactions 35———r Eiectromguetios———- —- 26.Weaks 26
7+ Nonleptonio—weake————_-—~—-- wg8.Thesite)group. 9 94.The80(6)_model .----——-- —— 10. Ide Algebra ofCurrents 20
11.Physical Conseq's ofSU(6) 9
~~—""""~ IeTiegroups andalgebras ToSe 713. Ide transformation groups 30
the Topologicats—- -- -3a -
15. Lie algebras ofthe semisimples 19—16.Representations ~— a -17. Tensor algebra ofthe linear group 12
appendix :isometries 000
TET havemoretimeto‘spend, this’would-bew-good place-to sportits— aaa
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/SummaryofMajorTheorems inTinckham i} June15,1979
i ®1,Rearrangement Theorem: group rearranged byleft orright miltiply byfixed element.
Jeads toHaar invariant measure for contihuous group.
2.ASubgroup anditscosets (either left orlright) partition agroup whose order ish.
Thus, since order ofcosets =order ofsubgroup’= g,youmust have h/g=integer .
3.IfAisfixed, andXrunsovergroup, theXAX> generates allelements oftheclass
containing A.Elements ofsame class are dalled conjugates. Identity inits own
private class. CBAsses always partition thegroup. ~ -
4.GreatOrthogonality Theorem: thematrices jfortheirreducible repsareorthogonal.
A 5.Dimensionality Theorem: sumof1,”=h,theorder, where1,=dimensionality ofrepresentation i.
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6.Character istrace ofmattix. Characters dftwodifferent repsareobthogonal. If
two group elements are inthe same class, jthey have the same character. Thus, the
rows ofacharacter table are orthogonal when weighted with class multiplicity.
7.Second-Orthogonality Theorem:theaittordhe columnsofcharactertableareorthogonal.8.Reduction: tofigureouthowarepreduced,realizethatthecharacterofthereducible
repmstbesumofcharacters inthedirectaThisishowyoudoit.
9.Celebrated Theorem: Theregular rep, 1g,=h,contains eachUIR4 1,tines.
@0.mumerofu'sisequaltothenumberot}classes.
{ 11. Abeliam groups: obviously each element ipinits own class, soh=number of
|UIR's,soeachUIR,hasdimension1,|
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Facts toRetain from Wybourne.
Chapter 3. definitions ofbasic coritinuous matrix groups +
(like GL(n,C) eto.)
matrix theorems.
Chapter 4. the parameter space
generators as gradient atidentity which isparameter origin.
the commutator oftwo group elements
structure constants and properties of
the infinitesimal operators
the general exponential form offinite group element.
Chapter 5. definition ofalie algebra
“-"~ basis’transforsiations oftheX'shomomorphisms, isomorphisms
automorphisms, inner and outer; the automorphic group
ideals, proper and improper (invariant subalgebras)
subalgebras
adjoint representations
complex extensions __
simple and semisimple algebras
the metric tensor orKilling form
the kth derived algebra ofanalgebra
asolveable lie algebra
directsumsandsemidirect suns =mthe Casimir operator ofasemisinple algebra
the corresponding group statements. .
theorem: asemisimple lie algebra can always be written asa
. direct sum ofideals, eath ideal forming asitiple glgebra.
example: Weinberg's decomposition ofthe Lorentz group into two
$U(2) algebras.
theorem: alie algebra is semisimple iff the metric tensor isinvertible.
One can always. check this directly from the structure constants.
theorem: any lie algebra can bewritten asthe semidirect. sum ofa
solveable lie algebra and asemisimple lie algebra.
example: Poincare group, Euclidean groups. Remember that in the def
ofsemidirect product, the first group (usually translations)
- —-— Will beanideal ofthe complete group. -- Z
Chapter 6. the Cartan Weyl basis, the Carten subalgebra
roots, their properties and theorens
Chapter 7. Dynkin diagrams and the Cartan matrix -
enumeration ofthe basic lie algebras.
Chapter 8. tle Chevalley basis
4
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=e Chapter9.represantations, redueibility of icontragradient reps,adjoint reps,realandcomplexreps. —j
theorem: asolveable group hae no finite dimensional irreducible
reps except one dimensional reps.
example: translations, abelian groups. There are nomatrices used
todescribe translations, eg.
theorem: the irreducible unitary reps ofaconnected, simple,
compact group are all of finite dimension,
. example? the rotation group orSU(n).
theorem: the irredueible unitary representations ofanoacompact
connected simple lie group are all of infinite dimension,
except for the trivial rep.
example: inSO(2,1) orSU(1'1), the matrices you can construct are
allnon-unitary. (eg, theboost matrices) _
Chapter 10 weights and how tolabel irred reps.
Chapter 11 Kronecker products
Chapter 12 more onlabelling reps with weights -
Chapter 13 the exceptional groups
_—*» Chapter 14 dimensions ofthe‘irredreps
Chapter 15 the Casimirs
representations ofSO(3) and SO(2,1) compared
- theorem: asemisimple lie group ofrank Lhas-L invariant
Casimirs, 411 may be constructed from one formula.
— -Noreover, the values ofthe Casimirs labe} completelyanyrep.lirred rep)
Chapter 16 global properties oflie groups
Chapter 17 the 3-parameter groups and realizations
Chapter 18 applications ofsu(1,1)
Chapter -19 generalized lie algebra Wigner Eckhart theorem
_finglly, the case studies. - oe.
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| Tayig,1977 YlenkinChapter 7 |
@ verywrrortunately Toverlooked thischaptel. Itcontains michinformation Tthought
was being originally presented inIBL-5527.| 50pages long, -I.have noXerox ofit.
1.Hypergeometric Furiction, 2
1, Definition
2. Relations .
3.Integrals involving
4.Jadobie (first kind only) polynomials exressed interms of.HGF. .
2TheGRoup SL(2,R). .
1,Remarks: accent here will beonldiagonal matrices
2,Parametrization. Theorem: youcshwriteg=d,pd,orsimilar, whered,are diagonal (unimédular) and piseither ay-boost ory-rotation form matrix. Close to
theEuleranglesbutnotquiteduetodetajisIhaveleftout. 3,Lie algebra stated
3.Irreducible Representations..| . 1.Description: converts the QU(2) shift rep toSL(@,R).Converts tousual
multiplie# rep inone real variable x.
2.Anotherrealization: Mellin'soff(x)and1)arecalledF,()andF(s). Groupactiononf(x)isthenconvetted toactiononFy(x).ThisgroupActionis thenwrittenasanintegral, therearealwaystwotermsbecause2x2sense.Kernels e ofintegrals arethefamous K,,(ya3\%ig).{ Youhave:
ario
R@ERO =Z .XOKO) =ZS.ayKaeafiteig) Fels
Thereps arelabelled by‘X=(Iu) soweare|doing Bargmann's C,series. Thekernelsarewrittén asintegral representations hére. a
4.Infinitesimal operators. Ie, generators are written inters ofvariable x
As Calculation of the Kernels.
1,Calculation oftheK'sforcasebfy-boobt (called h)ory-rotation (called u). Alsodoes for tribgulr matrices. For the ytrotation matrix hegets:
he (2880~
she ahs
Wath KeeQuer%h)=1POTEA22) che owct Qpimh) =ALPOMTPerrs leDeraPBNBonth“BE P28)|@s)a Bydoingac~a,c-b thingIcouldwritethigintermsofmyfunction 93)“(ewe). Bytheway,K,_=0. »
2.thé'caseoftriangularmatrices:|K'srecomputed e3.The general case. Multiply earildr results together.
44,Some hypergeometric integral trarjsforms. Nothing exciting here.
4
.Recurrence Formulas. Derives the usual recurrence formilas asinBateman by firstSatinengtheoperation ofdifferentialtion interms ofgeneratozs, then converting
thegeneratosrs totheMellinspace.TheK'sareusedhere. e
6.Integral reps, and composition formula.
1.Intro: from thegroup property, the kernels must compose with noconstants
atall, just Mellin-Barnes contour with adjacent "helicity" indices touching.
Rest: bychoosing simple K'sinside (ie, simple g's) youcanmake lots of
integral representations forthe outside Kfunction. Also, various special cases of
thecomposition formula (addition theorem) aredone. .
7.Triangular andHankel: adifferent representaiton ofsamegroup. Satherepresentations,
but new way todoit. Thé kennel now issome kind ofHanekel function. ‘Very short sec
nothing super.
Jena :
Comments: Nowhere inthis chapter dowefind any reference to Azimév's work. Nor
isanything said about "Legendre" .Nothing about "second kind Legendre". Whybother
4fyouareinterested intheHGFperse. Noneed toconvert toLegendre. Noonewould
know that these kernels areslose toassociated Legentre functions. Vilenkin simply
doesnotassociatéd theword"Legendre" withtheseocond kindfunctions:
Also, there isnocomment about tieD,,*fepresentations.
Ofcourse nothing ondiagonalization.
Thisworkwasreferenced by‘oneofthe-Abarbanel andSaunder's papers. Theyconverted
to e-functions.
Iwould criticize Vilenkin for omitting tomention Legendre, and also for
making theartifical separationg between QU(2) andSL(2,R). Thereal difference in
these twochapters isnotthegroup butrather thebasis. Thechapter 6isinthe
discrete basis andsoinvolved first kind loegendre functions; chapter 7haschosen
the continuous basis and involves the second-kind legendre functions.
1—
.
| a, diosdoask.cone BX \ -
@©@dakinonWade, eewvenins odNeue 8,NX,Ww
.&. &. .
akoh) PK|SEK OW=(ox|===eioecaySno
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aeitt ait 4itVy
= (te hhe\ 2 AERo =
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TakFRWeaKo=errdom. |SeaMame#we)= +=.
[u@ =os
Sows gate =N=-ief\= -3K a=ik,
ae ER =AK ' a= ak |.ariy= | -[Os=ide
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CS
AsIseeit,thieresultmustbetrueforallmel"andfor(mtn')oneitherlattice.
Afterall,weobtained thisresultfromVilenkins general representation, _ @
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Q A tentmo rage Rade)=GLBa=.Wises)Ge(ake.—Pele
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am*ive)() Sorekpon Ss rlvit. . J
:roarorpyl BAe {aUeCSEaa5\* —\ Wan & e
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— RbfaARweVane 7
- my AE ofWe =Fro(2)
"~ “But this cannot betrue because look atVilenkins symmitry rule top ofpage 124. This
shows clearly that his P's are not the same jasAzimovs. Therefore, -hemust have .
— faked usout byusing different Jacobis. Hig Pfunctions must bemore like my.d a6functions. Sothisthrowslotsoftingslff.
Comment:IsimplydonottrustVilenkin'seretions becauseherefusestostandardize things using hypergeonetric functions. Ihate thet, nowaytotellwhere youare.So
Ishdiildreallyonlyusehimforkdeas,notrresults.
|-
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Comment_onaCommonErrorinGroup/Theory:
|
>: 1Usually, thestandard grouprepforyulareads: 7-7-
a C3ES0
—_:One,atetheerronefous impression thetgo"willbethefiretgroupelenent
. _.. te"touch" x: le . re .
— Bo 2TOOT) HO=T|e ax. -.— :ToeSaige).-- These. equationsarewrong,InfactsBristhefirst,groupelementtotouch— ~%2.Theaboveequations aresimply almisunderstanding ofthenotation. The__|. bra-ket notation makesthisveryclepre __
,STAD =Cabal»ia.Bearnanning,TDSC)=$Gx).
©.SerSENT SO),ielTat(9)
SH dw = TOFD =GND BD=<xTd =LakRP=<aigixl
a<xLaad'x RQ=<jgax\ >.-oe _we ALT GAD AGTQgod. =Tego4 &). .
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i | RKmake Ghdock xJost=hax\P> =Ce@gax|>
=SxlTq|:
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t
e Gonment_on Normalizers_ chVilemewy,
1.SofarIhavebeenthinkinginsexksofhavingcompletefreedominchoosing™s"normalizer Aqfor arepfesentation. However, I’now think
certain choices are more natural than others. For example, look at
page 307 ofVilenkin where hedeal§ with SU(1,1) matrix elements.
There, equations (1)and (2)afe updengably true: these equations
give you the representations irred{cibles. Now, ifyou-choose basis
functions inthis space which are normalized and otthogonal, ie,
swe”- $m)=.fon€ee
- s+e well, this choiceisorthonormdl with.respect_to.the simplescalar product given in(4) page 304. whan you dothis, you get avery explicit
matrix element without any "normaljzer freedom". See (4).
2.Howthencanweunderstand the404ofchanging normalizers?
“TNS ime soneeene -fuls\= Ane
A da. 3 se vn= ow : \YorCaso =1.gou (Van nuded. Bubqo
e coudatinakoote/ 1en) |- “\ A Selher=ZTGuest ~*~Toagesr *2Qeioe OK,thenallyouhavetodoisretiefine thescalar product tonormalize
your basis sates. In-fact, now look -at-Viienkin~page-118 to-see that this
isexactly what hedoes for SU(2) jpatrix elements. 1 .
3.Thus, here iswhat ihave learned First, for SU(2), Vilenkin used the
standard normalizer thateverybody uses.Theonlyotherthingyouhaveto
“knowisthathechooses exp(+i0 U4)forbiscentrel groupelenent thus 7obtaining therotation matrixfunctions whichhecallsPJpn(z).
Second, for SU(1,1) inthp’continuous series Vilenkin chooses
theunitnormalizer A,=1.Then,hsshownonpage309,hechooses for
hiscentral element exp(-itK,) «|Theresulting matrix elements arethen; 1" called Bm(cht). thie _
4.KeepinmindthatAndrewsand1useJzastheircentralgenerator...
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andgenerates anewfunction byreplacing thsevariables withnewcomplex variablesobteinedsimplybymultiplying theoldvariatesbackwardsbya2x2matrixrepforg. Oddly enough, westart with a2-dimensional datrix representation ofgroup Gand from
thatweconstruct amoregeneralrepresentation asanoperator onafunction space.
Since ‘this fun¢tioni space has invariant subsfjaces under T(g) consisting ofhomogeneous
polynomials ofdegree 2L,weconclude that T(g) isahighly reducible representation.
Infact, we-are easily able todeduce the effect ofT(g) onafunction (2)
whichisrestricted totheHilbert subspace Hyofdegree 2Lpolynomials. Thisisshown
inequation (8).
Inthis sectdon 2.3, weshow that thdrepresentation Ty,does notitself have
invariant subspaces andistherefore irreducit le.Later,wewillshowhowequation (8)canbeused togetthematrix elements ofthdirreducible reps insome basis.
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AofHermann Chapter 3. “ ASUREDofHermannShaper35arTnteqets,ondPQ” [email protected]? thepurpose ofthischapter istolearn about therelationship
7 between the first and second kind functions} AsHis starting ‘point; Hreminds us
ofcertain ‘simple Tormulus whith rélute the|P, and-Q; functions. Heshall generalize
these Neuman formlae. ‘The trick for doing}so isoutlined: you want your e-functions
tobematrix elements. ofanoperator -D(g) insomeappropriate. space. _Forexample:
Ter Gt ee oo --
ExCay =<oelBG)KP . “ me)
When label jtakes special values (integers|.eg), the vectors shown are supposed to
space acertain space HJ.This isthe_usuallspace connected withDJ,ie,
- + -" s - -.t| Vay =ZoBROW _ (2)
Now suppose ithappens that these basis funttions are-not-really the usual things, and
that(j/k')isnotJustaKroenecker delta,|but rather, suppose thisquantity. is
|divergent, or-otherwise poorly defined. Ie} wearenotuseing @real scaler product
here,justabidinear form.Clearly, then,¥edonothaveanorthonormal basisin
ourspaceH'ofdimension2j+1.Thereforg,youcannotsimplysubstituteequation e@(2)into@1)andconclude thattheEfunctidns arethesameastheDfunctions. This
wouldbetheconclusion ifwedidhaveanolthonromal basis,sowehadbetternothavethat. . -
. Although youtannot put(2)into (1)asshown, youcandowhat, follows:
Ven enicg i Vent) AN AERCPQsGIOGd fAVE) DQ .. + . ~-=" \,=KDS)KDpw @) Pause before finishing. Thefirst step follows because D(g) issupposed tobe
agroup representation -byoperators in-our space. The second step involves some
kind of"adjoint" operator with respect tothis crazy scalr-like product. Nowfi ° from (2), taking the adjoint weget: wrongl Instead, thenext step isthis: youcaneasilyprovethattheadjointobjectisbasearepresentation, theonethatHcalls D'J(g). Itisthis representation-which issupposed todo(2)above. If-
it”does,thenyouceninsert(2)(withaprihieon"D)into(3)toget:
- ar ae ~omELDag"Cay)GeIB@VTED e«
.w
. \oe 4 odes _ >
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4 ~,
So,whatHisshowing us.is howthat“group-like property" might coineabout. we
repeatthatthereissomething rathertrickyaboutthescalarproductlikeform. e
2.General Remarks’ about Cauchy Kernels forComplex LieGroups.
Here weobtain amethod of‘sort of“extenting" afunction ohGtoanew
function onG,(minus G,however), where G,isthecomplexification ofG.The
newfunction P(g.) isgenerated byintegration oforoginal f(g) over G,weighted
by@special so-called "Cauchy'kernel". .
By,requiring that-this kernel havethespecial formG(g.+g)=.C(gg,),
thenewfunction F(g,) bears aspecial relation tof(g), namely: iff(g) maps
intoF(g,); then£(g,g) mapsintoF(g.g,)- Somehow, left~translation "shines
through" this"transformation". Righttranslation doesnot,however. (Here, 8
‘mstofGoiirse beifG).” 7
-~>Next; forreason-unknown, H-points ‘out-that-you can;“if-youTike;“alsoinsist
that the your Cauchy kernel-be "invariant undér AdK'* whereXis‘somesubgroup ofG.
‘Thenotation AdK*means the set’ofinner automorphisms ofGwhich aregenerated
bytheelements ofK.Ie,gmapsinto-kgk isanautomorphism. “invariance under
Ad'K"isafancywayofsaying thatC(g,)=0(kgk™). e
Ifthis condition isalso met, then not’ only will your cuachy transformation
beleft-translation "invariant" forallG,itwillalsoberight-translation’~ *
invariant TorXK.Ofcourse'thisimplies thatforK,tlemapés‘rilght~ andleft- .
translation invariant. The significance ofall this is: inthis case, iff(g)
isaspherical function, thensoisF(ge). Wehaveinmind,ofcourse, thatf(g)
islike-P;(z) andF(g¢)- 4slikeQ;(z¢).
For the reconrd, the phrase "spherical function" means two things
1)thefunction iseigenfunction.of differential casimir | .
2)thefunction isleft-and-right, translation invariant. Clearly, PyandQ;are
both spherical. oa
3.Hua's Constfuction ofCauchy Kernels. .
This isa-strange digression which israther vague. Apparently, Hua has
amethod_ which gives.you aformula for the Cauchy kernel for G=GL(n,R). H
claims, without explaining why,thatthisnicegenerel method simply doesnot e
apply tothe Lorentz group cases. Hua was 1963, bythe way.
‘ _ Oo
oa .
.Wignerd-functions ofthesecondkind.{ ; -Cee _ ~ - ry Iwillsimplystatethegistofthissectionwhichisveryclear.Suppose “""youactuallyHavesomeDandEfictions witcharérelatedasshownin(4.6)and -Au.7) (the-E and-D functions-are so-related!)./ Then, youcaninvent operators
- By(g)-andD,(g)inobviousway.Ttfollowsallinreverse,—that -theseoperators .arerelatedby.theCuchykerneltranaformpttion shawnin(4.3),andtheactualkernel Atself 4sgivenin(iy1). However, [email protected]
efunctions, ,Thepointisnotthatthere?somefancycompactformforthisCauchykernel.Thepoint,isthatthereexistssuchakernel,andtheDandE operatorsares@Telateds|esau.wt[fem Ls 5sGroup theoretic meaning-of the-integral tepresentations.
Hereab.last we.get.specific. Rirst!# quotesthestandard integer] reps_
fortheassociated PandQfunctions andnotes that. they look similar, Then -hesetsup.astandard(tome,bynow),realibation oftheSL(2,R)liealgebra |as6ifferential operators inareal“variablé whichhecellsTHETA, butwhich,is,@verymehLiketheqvariableofMuiunda,foiethatyoucantalkaboutthese °™
generators andheir eigerfunctions without! using anyscalar product. Next, ,
hesetsupwhathehopesaregoingtobs“tde-functions bychédsing @particuler
scalar products suggested bytheintegral répresentations He.sayst..Sag 2S50 Se. aw estVeeCRY=Sac_s™ expfth®)
. (x) -Cet SM by
Themost important thing tSedlide “at‘the atart ib’that these arenotthestates /m)
we‘are uBbd''to. |These aieactually ‘states Which diagtrialize oneoftHehyperbolic
gene¥ators.’ But, heistaking this generator! to..be anti-hermitian (formally, and
alsowrttohisscalarproduct). Thatiswhyhegetsm,whereIwouldgetip.Heneversayshismisreal,butIsuspectitsupposedtobereal.Therefore:Lali SSS GROOM) |=nadia bESage!-sAfterthis,Hcomesupwithaveryscsiforexpoentiating thedifferential
e gnérator. Thiswasaproblem Icouldneverseemtosolve. Iknewthatfirstorder-diffgensalwayscorresponded t6multiplierToe,‘butcouldneverdoitsoexplicitly!!!
- |
-- 80, having shown how tofind the multiplier rep, _Hproceeds toshow that
theintegralinquestiondoesinfactleadfousfunctionQ,™initsusualintegral =)rep.Sohuuray, hehasexplicitly written theQfunctions asmatrix elements of
certain operator insomespace. Backinsebtion 4wehaddone thisformally, but
weneverstatedanythingexplicitfortheoberators DandE,andnothingexplicitforthescalar product.” Here, things areméde explicit. .
Next,wechangevariablestowalorasHsays,uo.Herewrites thegenerators inthe-new variable -andnotésthatthese-are theones-having todo-
withthelinearfractional transformations itheu-plane.ForSL(2,R),these map the real line into the real line, and the circle into the unit circle. Thus,
either ofthese sets oftheu-plane isagogd cancidate forascalar product (because,
functions-on-the-real-line aremapped into functions-on-the-real-line, etc. We
have already used thereal axis togetthe rep. Itturns out, asonemight expect,thattheunitcirclegivestheintegralmeleethePfunctions,andHshowsit.Thissection isthenclosed outby#computing theexplicit "adjoint"rep
andshowingtheD=DEadditiontheorem.| -
e6,Thetechnique.ingeneralterms. _-| _
Iamnotquiteuptothis,butwillleyanyway.YouhaveagroupGand
asubgroup L,andsomehow thisgives aspacelG/L whose points aredencted simply
byp.Thismustbethattransitive spaceMpeVileniinmentions,thecosetspace. Recall thet allhomogeneous spaces must be Hpmomorphic toG/LYorsGifie subggroup Le
So,nowmake upsome functions onthis M-space, f(p). Then, make amultiplierrepresentationaSshownincoil(6.1). Then, take everything complex, so thhtMgoes tospace M,=Go/L,- Then
inthisspaceM,,takesomeothermanifold, tallStN,acertain lociofpoints PeUsethismanifoldtodefineascalarprodust|aeshowninp113.
IannotsureIamgetting thepoint! Itsoensthatyougenerate "second
kind" functions bysomehow changing thedomain ofyour scalar product. Thereason
Iamunclear isthat Idonotseeexactly hoyyoumake G/L=theunit circle. I
will golook atH's other book toseethis.| Ibet fiber bundles will get inthere.
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[see Chapter3\GroupRepresentations.
3:1-Linear vectorspaces. e 3:2. Linear dependence.
3:3. Notion ofbasis vectors inaspace.
3:4.Linear operators, equivalence oftwomatrices (similarity).
3x5. Representation ofagroup bymatrices. Multiplication formula.3-6.Character. i
Notion oftworepresentations being eghivalent bysimilarly. Character iseasilyseentobeinvariantundersimilarity, soatherquantity.CalledCHI.Notationis:
X%(R)=thecharacterinsome"|forgroupelementR Ky)Kyee++Ky =the classes.
Elements ofsame class have same character.
327,-Notion ofdirect sum representation .Blokk form.
3:8.Ideaofafunction beinginvariant under}somegroup(belongs toidentity rep).QM.2:9. Scalar products, unitary matrices.3210.AdjointandUnitaryoperators. | 3x11. Theorem: forfinite groups, youcanalkays arrange allrepresentations tobe
unitary.Ie,everyrepresentation iscoupetoaunitaryrep. e 3-12. Definition ofaHilbert Space.
3213. Reduciblitty.
Fully reducible means block form. This fisadirect sum. Youkeep looking for
invariant subspaces untiltherearenomore,thenyouhavefullyreducedtoirredubibles. |a;=multiplicityofsomerepLareduction. | 3o1k. Shitr Lemmas.
;
1.TwoUIR'sofdifferentdimensionscanhotbeintertwinedbyanymatrix. |2.Theonly matrix which intertwines aUIRwith itself istheidentity.
3:15. Orthogonality Relations.
Here based ontheShur lenmas isanexcellent derivation oftheGreat Orthogonality 4
Theorem: SnVIR' |
sumB%R),, "4ioON) aySq(9-103) |
From this, characger orthogonality isderived) .
uses: |fmHR)xR)"=dyy|>canalsowriteasclasssun.et
Theorem:numberofUIR'sequalsnumber/ofclasses Lx4 r)Theorem:sumofsquaredofdim'sofULR's=attheorder Zex”ae aeoem 4 po AYaan ae
|Ome,xwo. T=de | CCR)=(R))suaeevaileyen — J
4 | -2-| (chapter3,hamermesh)
13-16. Ifarepisasumofreps, thecharacters addintheobvious way. Thus:
® ©
WeBad@ ay=:cna)ro) a) =K®=ZwK@O a Ke MavKi
Yawdeorocker arog dsJam:
TCC Pe iA a mabg KOK 1pleatau,ar |
This tells youhowmany times aUIRoccurs injthereduction ofanarbitrary rep!!!Whilewerehere,letswritetheothermainformoutsnn — | (F), Ox:=SU . ZV@RW'= Sydybe. |
t 1
+ | wa! e|sagt g=&Bepro .
Nextcomes apotenti little theorem. Takesohearbitrary rep,getitscharacter Xe
Then compute the LHS ofthis equation:
a (o ha 1. \SZgins Ze G]igavse)
Thusy youhave computed thesumofthesquareS ofthemultiplicities ofreps, present
inyour original rep. Ifthat sumcomes out 1}your repwas anUIR! Ifthe sumwas
2,youknow your thing reduces into asumof{wodifferent UIR's, each occurs once, and
soon.This isacriterion forirreducibilit; Theidea isextended, Iskip fornow.
3217.GroupAlbegrausedtoprovemaincimoree,
Heregroupalbegraisdefined,fine.carpeted Theoremisproved:regularrepcontains eachUIRnytimes. Thisisthenused|to confirm thatg=sumofsuxn?of
the UIR's, anequality. Next, the group algebra isused toshow that:
Ss6)o)*J.OK=(BYTE Thisis“secondorthogonality” te e@ var ,=Gq)%S ‘thecolumnsareorthogonl.Thisalso ©sum ay convirms that thenumber ofUIR'saad equalsthenumberofclasses.“rae |
Bat. Progctna ALOK2a push Vad v®
Hamermesh, Chapter 5.
eComment: Ijust want totrack down afewnew fideas Iseesitting inthis chapter.
Sol. Gives the concept ofadirect product representation. This isvery similar toay
lectures onthis subject. Inparticular:
vier)@)=ofr)ofp) =thedirectproductmatrix
You pair the first index ineach pair, and the second indices.
Theorem: the character ofthe direct product kepissimply the product ofthe
two factor characters, Could not besimpler. Tosee this, just set jl-ikinthe
aboveformula andthensum. |
5-2.Thenotionofevenandoddreps.Wawedak.
Theorem: ifyoutakeD'xD",iethedirectpoduet oftworepresentations whichare
the same, you can doapreliminary reduction lofthe result thho two pieces, each
ofwhich may then befurther reducible. ~The jtwobasis functions are:
'S Sex -jis @foypryhe sym ant{isyms. oy osAy ' a
* = * RWyssleg SalOyDax|Ss.[Bel»)
yh aN ne(OwVas>AwWeMl=alWens\.
Iwill use Sand Asuperscripts instead ofH]s bracket notation. The idea istosymmetrize
and entisynmetrize onthe first~indéces. Your direct product space then breaks into
twoinvariantsubspaces.ThebasisraeWau AaS LookSee =ede LAST | dad=AMU)
2) A = - AaNey=Vabewy dain=EMAOYR~1) Itistrivial tocompute the charactér oftHe Sand Arepresentations, just from
their /definitions. You get:
s) may @*e= tw xe
A(py aL Wray nKR ®== NOCOY =CR.
-2- (chapter 5,hamermesh)
ot - 523, Definition: theadjoint representation gfD(R)is D(R) »called D(R)withbar.
e def:thecomplex conjugate repofD(R)|is obviously D(R).= *
fact: forunitary reps, Roxx D(R) =D'(R)} sononeed todistinguish them.
fact: thevarious theorems involving x(r)” Yes™“th shatbeing x(n!) =E(R),.
Thus,thecharacteroftheadjointrepappearnaturallyinvariousstatements.
SakeExistenceofhermitianinvariants.a525. Classification ofRepresentations. urThissectionisnewtomeandinterestin}. Ifyoupickaparticular IRofsome
group, itmust fall into oneofthree classes} (weareonly talking unitary reps here)
* (2)DequivalenttoD”butibemaderealsuchthatD-D™ (1)Dequivalent toD¥andsahbeoughttorealformDeD* /this type ofIRis galled a“real representation"
Inboth the above cases, the chpracter isreal for all group elements.
(3)DandDYarenotequivalent] (andherecharacter mustbecomplex).
eThere isatricky way totell which ofthese tatagories arep falls. You have this:
Va ry +t)AKER) =a". ePe tiay& o8)
Wigner calls: type(1)="integer" j
type (2)=half integer.
Example from self: Iwanted tosaythat the|spin-$ matrices involve complex numbers
which you can never get rid ofbyequivalencing, even thout the trace (characters)
are real. This isa“half—integral rep". On heother hand, the J=l matrices can be
made real. This isanintegral rep. On,ly préblem isthat g=infinity for rotation
group,butprobably thisclassification can$ecarried oversomehow.
Nextcomes abunch ofstrange theorems tboutthings like$(S)which isthe
number ofsquare roots ofgroup element S.I]will skip thése for now. There is
something here about ambivateht classes which Iskip.
5-6. Clebsch ~Gordon Series forproduct redubtion.
Here isthe basic stuff, the character Multiplication idea. Here isthe multiplicity:
e@ " »fowea K va Qe=(wey 2 ZX) ® (a =Gyr)5akorn«xxfever
-3-
: iTheorem: (Proved easily fromthepreceding equation). Consider pDixD y
e a)ifusv,theidentity repoccursexactlyonceinthereduction b)ifufv, the identity does not occur atall.
Example: InSU(3), the3and3reps arenot dquitalent, but3x3containts theidentity exactlyonce.I:thinkthisisanexarple.
5-7.TheClebschGordonCoefficients. ThisithesectionIhavebeenafterallthis
time. The Clebsch symbols are introduced and gfcourse you have toinclude amultiplicity
i \sotery 60 Fore ua
*Om) an6 Ss = a A seSOTCA [gs)
Iftherepresentations areunitgry, then the|Clebsch's areunitary andhave uricus
standard properties thatIrecall fromSU(2) analysig,, liketheDD=Dtheorem etc.
528. Simply Reducible Groups i
Herewerestrict interest intwoways:[tirst, assume thatallcharacters are
real which excludes groups with type-3 reprepentations. second, restrict togroups
ewithout multiplicity. SuchgroupsarethenfalledSR.Forsuchgroupswecanprove several interesting theorems. Bythe way,these restrictions apply tothe
rotation group, S3andS,.
Lemma: indirect products, integrality behaves reasonably. Eg, direct product of
two half-integral rpps gives only integral ps, etc.
Sublenma: ,D'xD"cancontainonlyintegral (type-1) reps.Thisnotionisofcoursefamiliarfromtherotationgroup. |Theorem: 4faUIRoccurs inD'xD", thenthatUIRmustbelong either toDxD)$or
DxD)® ,oneortother. Arepmust beeithe# "even" or"odd", Forreps which dont
. appear inssomeD'xD" nostatement maybe fade.
Example: Consider 1x1inrotation group. Yopget0+1+2. Thus 0,1,2 areeither even orodd.
sincetheyoccurinaD'xB". Since 1inthe]1x1isintegral, thesymmetric onesere
the"evens", so0and2areeven, and1is pdd.Consider $x}-0+1. Here, since #is
half-integral, thesymuetricwhichis1isfalled"odd".Consistent!.Thehalf-integral |repsdonotoccurinD'xD"andarethisneitherevenoroddinthissense. e5-9. The3-j symbols. Skip.
‘ t
Donn igh.
Hanmermesh_on Synmetric GroupS,aay.
1 @Jcomment: misisanexcertent reference. AllthosetrickyrulesjuststatedbyLicht.
arederived indetail here, though Ihave not}studied it. Chapter is100pages orso.
EL,Thissection discusses amethod ofconstfucting character tables forthe§,groups
by@sortofbullding-up method. Te,youuseinformation ontheS,,characters topt
theS,characters. Ihave not studied the section, butits gaol isclear. Here for
example aresomecharacter tables: |
'
\\ reas12, S, o @ Sa} OO}: ot @»
xe 1 1 An ee ec
xo ,oos\ Po a
KY2|ofmt! letsgetclearwhatthesetables aredoing. Gincegroupelenents insaneclassalways havesame character, you need only list the classes across the top. For the symmetric
groups classes are characterized bytheir cyqlic structure. Thus, inthe S,table aboveyouhave(1,1,1) referring totheidentity, reas(2,1) refers totranspositions
‘and(3)referstofullcyleismadebycombiningtwotranspostiéns. Allthesingle etranspostions are inthe same class, etc. Tha other number tells how many elements
are in the class shown.
2-2.ThissectionderivesFrobenius’gvvreformeforcharactersofS,.Bytheway, thephrase “simple character" refers tothe lcharacter ofanirreducible rep, whereas
compound character refers the character ofafreducible rep. Here wegetinto allkinds
ofpolynomials andthings. Looks ‘horrible.
‘ZB.Butherearethemeumonic results ofqlltheabovework. First,youcandeducethe
dimensionality ofeach UIRofS,simply bydounting the"standafd arranglements" of
thetableau. Inastandard arrangement, all‘the nnumbers must appear, numbers must
increase both across and down.
‘eke Agraphical method for getting the chdracgers.
Je. “Characters byrecursion formulas (baded onFreobertius formula)
e‘1-8HowtouseFrobenius formulafocomputecharacters.
AComment:Allof’tepreceding6sections, {33thickpages,aredevotedtoconstructionofcharacter tables forsymmetric groups!
oe
~te
Jel. Here isamethod for constructing not the characters but the actual detailed
represenation matrices. FollowspaperofYamanouchi 1937.Thesectionendswith t)alarge table which gives thematrices forallrepresentations of51,52, through S,.
Here istheS3table, forexample:
Ss on TV donne,
A eeayoy ey
eary (aay as) Fagrey ye 3&wy ela Tay bal [|
Details: thematricestare "alwayssymmetric soloneroffdiagonal notstated,youcanfill itinobviously. Also, matrices are only given for transpositions. You can get
the matrices for the rest ofthe group elements bymultiplying transposition matrices.
By’theway,thesearethesameasthematrices ofTinckhamforBrepofDj.Identify (12)=2A; (23)=B, (13) =Cetc. See page 8ofTinckham.
7-8.Thissection discusses "H{md's Method" ofconstructing wavefunctions 2(1,2...n)@
ofmaximal symmetry orantisymmetry. There isadirect connection between such functions
and the Young bisiness. Ihave not studied this and will not because Ithink later
section 8aremorerelevant.
29. Group Algebra Approach. This seems tobethe best way ofdoing things.
First, ifyou take any linear combination ofgroup operators, you have alinear
combination ofh=n!(for S,) operators. Thecoefficients mayberegarded ascomponents
ofanh-fold vector. Two such linear combinations may bemultiplied together inan
obvious way toget anew vector. Each linear combination isregarded asavector in
group albegra space. Pozzi had much tosay about this stuff. Given anirreducible
representation ofthe group, you can generate anirreducible representation ofthe
group algebra inobvious way.
The idea istodecompose the group algebra into adirect sum ofminimal ideals,
andthese guys inturn correspond totheUIR's ofthegroup. Itispossible to .
constreut projection operators called "idempotents" which take any element xofthe
group albegra and project out that portion which belongs toaparticular ideal minimale,Thesearecalled0,,€p...byHammermesh. Ifyoucanfindtheseprojectors, thenthee
problem offinding basis functions belonging toUIR's ismostly solved.
-3-
7-10. Young Operators. Here isthefundamenthl stuff: consider agiven Young Tableux,
ie,ayoung"pattern"or"diagram"whichisfjlledinwithnumbersinsomestandard r)arrengement, allnumbers appéaring once. The|obvious oneisallnumbers inincreasing
order, called normal tableau byMessiah. For this particular tableau, you can construct
anoperator Sand another one called A. Thest are best defined byMessiah page 1114
andarecalledPandQbyHanmermesh. TheP6rSoperator isaspecial symmetrizer:
itisasumofallthe permutations (group elements) which donotmix rows. The symmetrizer
issupposed tonotmixrows, theanti issupppsed tonotmixcolums.
Example1:8, |
B=eeCa)eQd+033) #Cray+(32)
Herethere isnothing toentisymnetrize. Note|howthe6elenents ofS,arelabelled
here. The lest two are made oftwo transposithons and thus have even "parity".
{
Example2:s, | :sEl Qee~@)-Y=GP+Gea(az)
And here there isnothing tosymnetrize.
Example 3:85
nen P=[ere\sonteaoAe(oayT] e+(05)] Kaa
Qele-@\\fe- GP]=©-GN-Gs)+(yes).
Inthefirst line Ihave added allpossible permutation operators which donotmixthetworows.Thereare12suchoperators.althesum,withparities,ofalloperatorswhich dont mixcolums. i
Theoyém: Ithink this isthemain ideay/in o¥der togenerfte the "basis fyfctions"
whjéhbelong toaYIRofS,,youfirstlistdffthestandard arrangement. Recall tha!
cg) Phereareexactly/as manyoftheseagthereavedimensigns oftheUIR.TMen,foreach
standard errangefent, construct P, zhenQ,andthen ofnstruct ¥=QP (this correspgnds
totheJobjecfs ofMessiah). This/operator Yjwill bya projector whi¢h willgiveyfo
the basis funétion corresponding Aoyour chosen tableau.
~h-
Now, here isthemain poop: Youknow that akiven UIRoccurs intheregular gep
(ie,thegroupalgebra)Ntimes,whereNisthedimensionality. TheseNoccurances e are, Ithink, correspondent tothe Npossible} standard arrangements you can make
inthe pattern ordiagram. Iamnow going tolshow how you find aset ofbasis functions.
foreach ofthese Nuirts. (wil...
First,eachEReoguugnes. getsitsomprojection operator called¥Y=QP,thej ofMessiah. Youtakeeachprojection operator andapply ittoallpossible groupalgebraelementsxuntilyouobteinastperyfF
Example: Consider Se Thetwo-dim repoccur$ twice .Foreach copy wecanconstruct
the projector: “
Peeste Yoar= Ann =[e-Gijeroo) a
Qee-08) =©-08) f0)~Gar) veHEYA,
! 5
aY=AnSa=VWercattens} =ee)4OS)-Gy=YH.
Letsworkfirst withthetopcopy. Takethe projector Yy,andapply itfromtheright (as
eMessiah shows) onto various elements ofthe joupalgebra:
é na GODY=GdTe~O9 409-(9)=GQ-(usf+e -@) 2Y/ SRTAL,
GO =GHYe~ CY+x)-GY}=(D-e +@yce)=-\
: CY =CTE ~Grs 69-2] =GY= GH)+Gu)—@) =YOY
. Iamconvinced that ifyougoonandapply ¥,|to allother group elements (thereby
spanning thegroup algebra), youwill never gdtanything other than alinear combination
ofXYandY's Thus, these maybetaken as“gpanners" ofthefirst copyofthetwo-dim
repof83+Infacttheycorrespond exactly t:Lickenbergs PSI1andPSI2.
Ifyou want anorthonormal basis, you jist doitinobvious way.
Insimilar manner, IcouldtakeXQandg¢nerate aYX,"suchthatTpandYt)"areoperators spanning the other uir's ‘ideal:".
.
Then finally togetfunctions which corfespong torepresentations, just apply
Yyand¥,' tof(x;,x21x3) andyouhaveit!
~5-
For example, wehave:
AGasy =XYFG)=$03)+Fas)4{Gry-@)
' 1F.2d) =YXFad=FUed)> 48) F3d-Asie)
Nowanypermutation acting ononeofthese fictions canonlylinear-conbine thembecause wehavealreadyshownthatY,isabignt-acting projector [thisproves
that(12)£,(123) =£11(123), eg]. But,¥,"F(12)Y.Thus GY," =G'¥,=in
themanifold. Inotherwords,¥,'isalsoapright-acting projector intothislitleUIR manifoad.
Conclusion: Both ofthe above linear combingtions "belong" tothe first copy ofthe
2-dim UIR occuring inthe regular rep decompdsition.
Normalization: Since Ifailed tonormalize |PandQabove, ¥,”=constant timesY,
s0not quite normalized right. Nobig deal.
Conclusion: Inowknowexactlyhowtoconstquctasetofbasisfunctionsforeach @ copy ofeach UIRappearing inaregular-rep decomposition ofS,. Foreach pattern
(ie, each UIR) draw thevarious standard aryangements. Each arrangement corresponds
toonecopy oftheUIR whose pattern theartangement isin.Then ,foreach arrangement
construct theprojector. Apply that projectof fromthe-right-only elements oftheperm
group until abasis hasbeen generated. Thenjapply thebais elements toanarbitrary
function togetthebasis functions. Ie,afimction f(123....n) .
Bythe wey, Ithink the basis functions fordifferent copies ofthe same UIR or
: different UIR's are automatically orthogonal} becausse the projectors really are
projectors inthis sense.
Hammermesh thenwrapsupthissection 7-10tyfinding thesymmetrizers andimplicitly
theprojectors forthevarious representaticns ofS,.Fine, nowlets continue to
thenextsection. |
{
.ot =6-i
1
411. Fork, and contruction ofdefinite symmetry wayefunctions.
Uptonowwehavebeenconsidering trygbneralstuff,functions £(1,2,3). Suppose ©nowthat this function £(1,2,3.....n) ispealiy aproduct ofndifferent, orthonormal
functions. INquantum mechanics, intheindepbndent particle approximation theenergy
ofsuchastateisthesumofthesinglestateenergies, andtherefore theenergyisinvariant underpermuations. Youcanthenonlypermutations togetlinearcombinations
which belongs totheUIR's ofgroup S,. |
Example: n=2, youcanhave u(1)v(2)+u(2)v(1), andtheobher one. Youstart here
withtwoindependent functions, andyouregrofp themsothattheyclassify intothe
vIR's.
Forne3there are6degenerate starting functions. Heclassffies theminto
theUIR's. Heonlygivestwofunctions forthe2-dimUI,©soheonlyhasatotelof6functions.IknowhowtomaketheotherreNext, hesays: suppose instead ofallthelittle functions being different, only
twodifferent functions were availble. Think Whathappens: yougoahead andconstruct
your projectors ¥=QP.When youapply this ¥{to anystarting function, youwill always
getzero ifyour tableau hadmore than tworows: reason bsthat youaretrying to
antisymmetrize .Ie,suppose youstartwith4tableau havingthreerows.Yousimply
cannotmakeanantisymmetric rank-3function ionlytwofunctions areavailble. eIngeneral, ifyouhave kdifferent states only (andnotthefull n),youcan
never have any functions belongs toUIR's witl more than krows!TherestofthissectionissomeFockwheIskipfornow.Ithinktheabovething iswhet isimportant here.
‘Tl2:Outerproducts. Ihavetodoasimpler exemple thenhegivestoseewhatisgoing
onhere. Consider this: youhave afunction whichissymmetric ,f(1,2) andisafunction
forparticles 1,2, Then imagine youhave another "system" consisting ofparticles 3and
4,also described byasymmetric function g(3,h). Thefunction f(1,2) belongs toadefinite
representation of85,andsodoes g(3,4)-
Nowsupposeyoumiltiply thesefunctions fogether:, Fy(1,2,3,4) =£(1,2)¢(3,4)- Ifyouonly apply (12)or(34)bype operations} this function always goesirito itself
end isinthat sense irreducible. But, what hbppens ifyouapply arbitrary group
permutations ofthegroup 8,22?Eg,(23)on|this func tiongives youanewfunction.
Sohereiswhatyoumight do:Apply elements ofS,tothisfunction togenerate
allpossiblenewfunctions.Iwilldotrisonthenextpage: @ :
1
\=
1
sot —Y-
ceRiaw= FO93@x) =Bae)
eODFla)=£0996,2)=Buy | e
(2)Fa(esy) =$3)gGs)=Fliesy) |
eR =ts = Flay)| ¢ 903) =fru),
'
Cafe =$y)x02) =Gury
Furtherapplications ofS,operators willnevdryieldanynewfunctions.
Sowenowhaveasetof6functions wietransform amongthenselves underS),
ie,wehavea6-dimensionalrepresentationaTheclaimisthatthisthingisinfact reducible, reducible into UIR's of|S).Forexample, ifyoutook thesum
ofthese 6functions, you would get afunction belonging to four boxes horizontale.
¥Mem-= mau+ +by.
Sothisisanexample ofan“outer produet" representation. .
Ingeneral,hereiswhatyoudotomakeénouterproductrep:takeasetof @venpartictes. assumethatyouhaveafunction £(1,2....n) descitbing thefirst r)setofnparticles andthisbelongs tooneof|the UIR's ofS_.Thisfunction has
lets sayN-1partners, because this rep ofS,|hes dimension N,This setofNfunctins
spans theUIR ofS,-
Similarly the second set ofparticles is{described byaset ofMfunctions which
span theMdimensional repofS,. Nowmultiply these twosets offunctions together
inellpossible ways:younowhaveasetofWNproduct functions. Next,applyell
elements ofthelarger group S,, toallofthese product functions. Inthis way
you will generate ahuges set offunctions which transform among themselves under
groupactionofelementsofS,,..Sincetestare(mn/n)waystochoosenparticlestobelongtothefirstset,Iwouldclaim=“)
Cut)a=Sumsusroarlly 2)oulposwg,Hanmermesh thendoesanexamplewhichearleeswithmyanalysisabove.Hethengivestherulesfordecomposing theoutereof+repintoirreducibles. Looksfamilartome. Many examples are given.
r)Thisisclear,butfdon'tyetknowthespotutnes (applicebility )ofanoutert)product. Notice that inthe outer product you pantke the "product" ofrepresentations
oftwodifferentgroups(possiblythesame)|youthenreducethisproductrelativetothelarger group S.... Very different from inner product.
woe
7-13. Inner products. Now wetake twoUIR's ofS, and reduce theresult according
toS.What does this mean? Take anNdimensional repofSyandtake itsNbasis
functions. AlsotakeanMdimensional repofSs,anditsNbaisfunctions. Multiply e ethese functions together inall possible ways. You now have NMfunctions. Now
application ofgroup elements of4S, tothis setoffunctions transforms them
amongthemselves. Eg, a
We#W=5qnaa: cv)£23) ga(ur,3)
1 x
=(Z fesya VSsb;9G) ), i
=Zar 2d\q (1s
Inthis example, the inner product rephasdimension 20 anditcanbesomehow reduced.
Sowhat arethe rules forreducing inner products? .
eSpecialCase:Supposeyouwanttocompute (y)x(n-1,1). Thisistosay, e@youwant (¥1:Yp110++) x(n-1,1). Recall that thenumbers inthis notation arejust
telling youabouv theYoung patterm: yy boxes infirst row, andso.on.These are
partitions ofn,ie,Yyt¥g++++ =nbecause there mustbenboseds ifyouaretalking
about arep ofS,.
Theanswer isthis: pull aboxoff(y)andstick itback oninallpossible
reasonable places. Eachrepyouthereby getiscontainted inthe,innre product. On .
topofthat, (y)itself iscontained intheinner product anumber oftimes equal
tothenumber ofdifferent values ofthevyless one.
Example: Sa
oy)
2)m*B =&+QDgecko) =ray
OF
aBeBe MBs = e Oy
A)ootDaackatWAsD=[2 deine
-8-
This last result follows since £(1,2) g(1,2){is obviously 12symmetric ifboth
functions areseperately. Thus,thetotallyspnmetric representation ofSislike e the singlet ofrotation group orany SU(n) grpup.
Notice that these results tell you: “the] product ofasymmetric function with
anantisymmetric function mistbeantisymmetric" andsoon. 7
1
Example 53}, Cane3 Bea-o0 Jdonee Racraiyfaster)mare(ns)
akomyamsgosby ne.aatycoped '
- CoatyCass.0)
. TE) EY =EIT [yuote
1 Cane31 Aer=8end[odeSonWe)feQi)=TH
ForanyS,group these three products arealfays obvious: total symmetry andtotal
antisymmetry. The difficult stuff iswhat hapbens’ with the other reps:
(Coan2)
°Ty FS=PRsGye) =
io) ay) Crer. |wot .-Saat = fey w= ay A+ (Pot) =mors
ay Gy
urvele -Cone3
Be P=Pe(@\b Ro.
prem {
Andthete youhaveit:Ifinally seewhére Feynman gotthose facts (eg,mixed times
mixed=S+A+Metc.
Hanmermesh gives someuseful general fordulas andhasatable forS,andS..
Te1k. Now comes_the Clbbsh problem: for example, wesee above how the inner produc
oftwo(2)1)repsofS3canbereducedinto42+(241)+(13).Whatwedonotyetknéwis'whichlinearcombination ofthe4functions yougetbymultiplying thetwo @starting repfunctions belongtowhichrepsinlthereduction. Ie,wedon'tyet.know
the Clebscho Gordon coefficients!
| |;
Aside onYananouthi Symbols. Recall that aUIRofS,ofdimension Nhasifso-called
standard arrangements. Wesort ofidentify each standerd arrangement with arowoftheNdimensional representation matrix. TheYamasymbolcanberegarded asalineare
way’todescribe the standard arrangement. Eabier towrite theYsymbol then todraw
the piture everytime. Example:
Weld aaaist (esa
ch
Howdid Idothis? Look forthe highest number, the 6,Itisinrow 1ofthe tebleau,
soputa1asfirst symbol in[ J.Where isthe 5?Row 2,sonext symbol isa2.And
50 on.
Fact: ifyou read the symbol inreverse, itisalways a“lattice permutation",
ie, there are always more 1's than 2's, more 2's than 3's and soon. Iguess this
can beshown tobetrue, given the rules for making the standard arrangement: increase
tothe right and down!
Now back tocomputing the Clebsch's. Hanmermesh gets very general and complicated
recursion relations andsoon,buthealsodoessomespecial cases. @
Case 1:When youcombine arepwith itself, theidentity (totally symmetric thing) occurs
once inthe result. TheGlebsh forthat combination isvery simple. Example:
an Oy @® al’
Px =m+ fP+F
L}—l 59i)GYany z = eck & LuarmaypoleingWes. Oxa4Giva
Bia\Wrp 7 oo“ 'sane Sobek[nerma FTO =PPG, 1@,Lad)Greaye \e
+[eqtrg’? a(Pet=pin mM=-luyy: ®~¢sfirg
Notice that the Y-symbol actually includes information about which rep you have: i8,
allbyitself ittelys youwhich UIRandwhich standard arrangement (row). Myresults
hereagreewiththefabletheygivelater. @
:
\ 1\e Ot) = w\RYLe, Yonds FZ wig
-~9-Let,me:repeat:thislast.example: |vr.
Wi+zitaytany toatindl a ae
an oe
ca: {PR+eel ‘This tells you exactly what Linear combination of"basis objects" goes with the totally
symmetric rep. Ithink itwould beuseful to deeexantly what this means. Each ofthese
M(mixed) representations has two basis functdons. Then here isthe claim:
a . Fars=xeSau3.(ye)+£desygerng
Qe)FAS)FOB)|ote|. Itcertainly isnot obvious tomethat the function socon structed is‘totally symmetric.
However, wecanshowthatdtreally workdesfollows: consider conbining an
earbitraryrepwithitself,andyouare="theidentityintheproduct.Youhave: OXX , 1 leq=e 2S, 5. DoD a pva\eyal 1SSC} apy &
we
= vy Crcanstan? Rios Fe AMoeRog
» — 2 ,=E¢Di(e\ [rs =Di®DY
=\ » ay ‘* &De@PDe @DADS
BEADCADLE)=Dale~3g1ne|LApeelTAyRysi>[-weaSUA+To. SonowTbelfeve it.Thisis«goodClebsh sgttoknowbecause youareoftencombining twolikeobjects toseewhatcombination is4tallysymmetric orwhatever.
Case 2: When you combine aUIR with the transposed UIR, among other things you get
thetotally antisymreponce,the(1")rep.HerearetheClebsh's forthiscase: \
tina) .,® oma erent : LO FAW Acey
Here the parity isjust the number oftranspositions away from the standard normal
arrangement. Here isasimple example:
.
a 1 aIeG)Te)eI .
bays lw) ti).
Here you are combining two‘one-dim reps, sonot much todo. Since only one possible
arrangement ineach, parity is+1+
Another example: e
: ue
: coke(ht(R=Dt)aOe Rx fP= +a eek.
=+ ‘ 4t a,PP+OPWe
x ' a kAtye ALbyten- Teyfa? Jequacate
« ®
-10-|
Case3:GeneralRule:whenyoucombineany|repwiththeTArepyougetthetranspose e ofthe original rep and nothing else! Inth4s case wealso know the clebshces.
Me. aBa=AbALOXAL, |
From PxG- Bangle*
‘ q*A*W _B-BE '
7p-cpy pom: Oe
: a @mw:A=> MY .3||.
Conclusion: forS31almost alltheClébshes drecovered bytheabove special cases,
seelabelling inred.ThecasemissedisalsoFiverinatablewhichIwillquotebelow.Note,bytheway,thattheClebshc's orebasedonadefinite convention for therepresentation matrices. Inotherwords,pereallyhavetocoordinate your representation tables with your Clebsch table:OnthenextpageIgiveacompleteS,cicbshtable:
(seenextpage)Bytheway,Ithinkthereis|symmetrypropertywhichsaysit
doesnot matter which order you putyour twoobjects.
End_ OfHammermesh Chapter 7onSymmetric
atte -\I-GompleteClebschTableforS,(seeselsfor2-dimrepmatrices)
a
m8 [mB] |
ee
feof: fe
a
ear |§P|ge|efe|sfi eeiee
SE |ee lee (ep|pe]
mr |-[xtiale |
Problem: Howcould one compute the Clebsch's from scratch for thig group?
@ +:Firstetesindouthowtomakeatotally bymmetric combination sincethisisthe
easiest todo.Weknowthereissomelinear cbnbination thatworks, callitV,t
= | Ng=ES RG Q) dheFeBGeBR
1
Rix=VeVR@) | Ifweinsertequation (1)intoequation (2)as.applygroupoperation RtotheMbasisfunctions weget this:
Ss 48 &SyVUMDBINKGE =|2Q HG; qe <8 sy eS ny
:
s 8=Ge2 mOE) ve:% .
s so jy ee.f= DED ;>* D=DB=H
i
t
= Ss =FIW=WS | Iexamined thisinsomedetail,butnowIseepfastwey:C,isamatrixwhichconmteswithallthematrices ofaUIR.Shurt tells us|thatC°ispooportional totheidentity.
Thus wemay conclude that:
, Ss8 s - Cy=KS Ks amahendd, Cy
Tofigure outtheconstant, wecanapply thecompletély general formula (5-111) which
OMtury \Cudye ZAes VEYNGEVYIMBS) =SpyBugSee
Forourapplication here uev= themixed rep, there arenomiltiplicitly labels needed
80we have ashorter version:
|
:Xs! ds \*
e ZL.CHIC y=Sale o
whereheresistherowindexfortherepyouf"combininginto".Forourpresent
caseweinsertourresultinthediagonal=pof(3)toget:dee cs u @Sisl-t se KrZlayy=1. s &SpatL et. GZyye Ze zie 2pKiag AkePe
This phase ischosen zero and wehave duplicated the results ofHam's table.
2.Comment: Notice that this family ofClebsth coefficients into the Srep does
notchange signunderinterchange ofiandSze, wehave:
(SIMA) =CS1Wj,Mi), \
According tolaterdiscussion inHanermesh, I]thinkthiepeansthattherepSis contained inthe symmetrized subspace ofthe product D! and its delta=+l. For
thegroupSyweknowthatallrepsaretype(1),realrepresentations, ie,theyare all integral representations inWigner sense.{Thus, rep $isan"even" rep.
3.NowletslookforClebshcs intotheArep!|
SitYonmonyYocdong|heansHea» (ey) ~ Sie @ah-2Viot ~2Octre
dw
=ACyDec(ODesCYRGetAyre
N ay wm
=>|DanQ@®Cre==VyDelODBR*) |(4)t
‘This appears as(5-114) Hamermesh. This istHetype ofrelation that allows you to
compute any Clebsch's. Along with the normal: zing consitions which I}1l record here:
Sot attated (5)ryCyC5=Serbanyen H 4Sem Om 2Syded &)¥ BMY Brey
-3-Nowrewriteinmatrixnotation,thenoltotheA-rep:
e a wt |YoLTZVaCes ZDYOCTDEM ‘Sy
nN yt law -\ >ZnO ILT=RATES]
WreA, OeDee Sedu |oe
A <\ Be(I= Dele Wow.
!
GeCa\(OsGre =(OwOry(ey& .(SGSS enanNeek)
Because ofthat delta, Inolonger have a"Shpr" bet, sohave tolook atvarious R's
eandseewhatweget.
GWC(t © o\ (ey© Qe-& aons(ANG EIGS) >Ske
Qua, atech=o.
Qua: Cady CaDee. Yer WSeeCaa|Ls Dacl
ar@=De. | Cay SDa
J4 |Ae) = see He,| GQ,Ly LL Heo DrCen)=B=Seay oh
kr°o1A atonAt e~ ee Le :-Go)¥
:.
AAA .arty (fie Ate Nomsea: in(crey=\5WAG) =oe
-a4
3.Nowletsgetthesephasesright.SupposefchoosetheS-repphasetobezero. @ ment amprobably not free toBoose this phabe also because wehave acondition:
Yetdont (aIe"TsBaBe)(9)
sAah | ar lESX|=o
Bey + 3G SsAo A1eMA/o re onl teC-kG) Ge "Gs gh-aSe 7G?)
soft BkOrSA apectuce JnergSe.AndesSS,
IthinkthateachfamilyofCcoefficients calhaveitsownarbitraryoverallphase
(the same forallmifthere isanmrow labe}). You can seebyinspection that
equation (4), the primal one, isinvariant under anoverall phase change ofthe
Cfamilies. The same applies to(5)and (6) dince the*appears there.
SincetheD'sareallreal,youknowyoujcanmaketheC'sallreal.Butthere @ isstill anarbitrary overall +1 for each Cfamily.
SoIwill choose toagree with Hamermesh:
Ot Aja AL Gh.+eGe) alCwye Qe
2CAsmimyy= =CA\Ay Kd
Therefore wefind that the A-rep isan"odd" xepresention.
4.Nowcomesthetoughie.Letbethemixedhep.Thenyouhave:i
: i
" ™ JDan(®) UWE) -QU) os
CuzCa=o * Yar ReQe). Quan
yal 1
\ ¢Ch=).\) Vyryo1s Z T = v ve (ei =GAYLE] Ga[>CeFNS)—Cae/
.oy =(2Ts"\ ah aN
Sothat was rather helpful. Now lets gotoR=13):
eAVW[Cl= WOC+GaceLC]
=-1)e')-8rd*) -“cy|BCe
SyfootsohCh)beet: |\
RACY Bar) 1& -\S\/G& 2chAER, 8)-cafes) &)
‘ a \ u5Reals eG LxIcaGe|=-2Bea
sYaleysce]=fcHeGch)=HER)
O43=220)ects-feek tLees =-2¢) 3Cy-Ca=+2Ch
3Gsdeo alee) [ead
axe +73Jen-s) meae-tt eed,
Br Crea. Oa
\ a 0 a o784= ond =y=(B=) (cCo)
Sowéhave reduced ittoasingle parameter, a
Nowapply equation 7inallways toseewiat gives:
algighye afalCtr taGeb,
kISPV=CAcata(CEGs}s (=teasone @idtheoy 2K(sayhijeo=-4 KC} oY
ros
6.| Soletsconvention thata=+1/SQRT2.Then|have:
vt 7 \ @Qu:k Que-i\ 2 :es -#Cus Ca= HE
This agrees exactly with the table.
TheMrepmust beeven because switching thelabels 12does notchange sign.
Te,
Ci(Ig) =FCth GRC) wmahar
Conclusion:
1)Thavederived llHanermesh's coefficientd forS,
2)Ineach family, anoverall phase canbeadded. Don't doit.
3)TheSandMrepsare"even" having delta =|+, whereas theArepis"odd", de~.
Thesignificance isthis: suppose youaredofng MxMinto M,S, orA.Ifyouswitch
your initial labels, thecoefficient will charge sign ifitisgoing into anoddrep.
Youcancheckthatthisruleworksforthewhdlesubtable. e@ 4)Ifyouswitch inthissense inanyofthe dthersubtables, yougetaplussign.
Thisisageneral symmetry rulederived byHinlaterchapter, something Icould
probably show but amtoo lazy now.
i
. EEE
an | Toe), 19i
Hamermesh, ‘Chapter 10:Irreducible Tensofs baallthat. .
e10-1.ThemostgenerallineargroupofsdunisofcourseGL(n),.Allgroups
ofinterest are subgroups ofGL(n), soanythifg you can say ingéneral about 6L(n) ‘is
very nice.
Thefirst thing youcandoisdefine a"Yector" with respect toGL(n), x,,having
ofcourse ncomponents. InSU(3), eg, a"vectér£ therefore has3-components. Ofcourse
there aretwoinequivalent 3-dim reps ofsu(B) sothere are really twokinds ofvectors,
but consider either kind.
Next, atensor ofrank rwith respect tolGL(n) ,orwith respect tosome n-dim
matrix group, isdefined. Just atransformatign law. One obvious way tomake’such a
tensorisFuggoeax?) 1d,youcancombiner different vectorsgustmultiplied together. Notice“that there afesubindices ontheindices. Thistensor
has ntimes rindependent components ifall yectors are different.
10-2. Decomposition ofspace ofrank-r tensor into invariant subspaces.
Gonsider somerank-4 tensor, seyGy145); »PikoneoftheYoungsymnetrizersforthe,group S,andapplyit-tothe ++subindices ofthistensor. Inthat
wayyouprnmuxc produce @tensor having adefinite symmetry wrtgroup S).
NwtakethisnewtensorandthinksboutHt.Bg,youmighthavethis: e@2a
tem A .1 # “This ‘tensor isassociated withaparticular rowofaparticuler representation.etofgroupS,.WhathappensifyoulapplyageneralGL(n)transformation
“Yothistensor?| * |
1
Fx=Diytig,BiniBiayhelis| .. i . RS
=AWApayy, ag,\VomiGo. . AyeeQuis Qingy Sivysyy
4,-TipsGoniiy
Youseethat the"rotated" tensor hasthesamd symmetry classification oftheorigianl
tensor. Any tensor canbeprojected into irreducible components which belong toUIR
rowsofUIR'sofS,whereristhetensorrank..Ofcoursethereasonthisistrue e isthat theGL(n) orwhatever group "transformations" commute with thepermutation
group action ofthe Sgroup.
This isimportant end isworth some time. Arank-r tensor can beacted upon by
group operators intwodifferent senses: elements ofS.cenpermite thesubindices,candelements ofsayGL(n)canactonthetensorintheusualsense.Thereasontheseé
actions commute isrether obvious, eg,
’
CHR=GOTRa=GdSawai Ryvo
=zAasAeRae==4GayePuy
‘ =zAeFie(OY)Fd=TeOdFra
Que, [Tad =O|comme
Now, isthere any connection between the rank rand the vector size n? Not
really, except this: inanyS,tableua there aregoing tobeacertain number of
rows. Thig number isofcourse some number less than orequal tor.For that tableau
with Rrows, there will exist notensors atall ifnislarger than R.Reason: infirstcolum.yopmstputRnumbers, butat,least.onenumbermustberepeated andthise
kills you under antisymmetrization: Remember that Y=QP sothe entisym isdone last.
Inparticular, ifnisgreater than ryou get notensors. Another, way tosay it:
ifyou are given avalue ofn,then the only tensors you can have correspond toYoung
diagrams with less than orequal tonrows.
Once more: suppose someone asks you: What irreducible tensors can you make
wrt group SU(3)? Answer: you canmake tensors ofanyrank ryou want. For given rank
r,the tensor isclassified byYoung diagram with rboxes but cannot have more than
three hmurmcknx rows inYoung pattern.
Bytheway, atthis point, “irreducible tensor" means atensor ofsome rank r
which belongs toaparticular UIRofS,. Sofarwehave said nothing about representations
ofthe group GL(n).
Next, Hshows how tomake TSorTAtensors out ofvectors. Itisvery easy to
make aTStensor ofrank-r. All you need isone vector x,then multiply rofthem
togehter and you are done. Tomake anTArank-r tensor, you need rdifferent vectors.
The TAtensor isthen just’ the Slater determinant. Ofcourse ifyou are making TAtensors,
youcannotmakeonewithrankrgreater thann,asdiscussed above.Ifrenthetensor eyou get 18maximal insome sense and isproportional tothe epsilon tensor.!!
-2-
10:3, UIR's ofGL(n) ,their dimensionality. te
WEknowthatwhentheGL(n)groupactsoharank-rtensor,thecomponents ofthis etensorgetmixedaround.In particular, suppose wehaveanirreducible rank-rtensor.
Weknow that after action byGL(n) operator, tensor keeps itssymmetry relative to
Sp
Letsgettothepoint. Suppose youhave4rénk-r tensor andyouhaveGL(n). This
tensor then hasrxn components which are mixed among themselves byGL(n). Thus,
‘thecomponents, ofthis tensor form amxrdimensional representation ofGL(n). But
such arepresentation ingeneral isreducible} -
Hereisthedeal:‘nowtakearank-rtengorwhichbelongstosomeUIRofS,.Because thistensor hascertain symmetry properties’ (dg,might betotally symmetric), notall
nxrelements are"independent" (ie,they ar§notlinearly independent; eg,perhaps
Fig=Fo13)+ Suppose there arereally onlyN|inddpdnenet elements. Thenclearly these
Nelements aregetting mixedamongthemselves joyGL(n). Thus,thisirreducible tensoris.givingyouarepresentation ofGL(n)ofsift NjOfcourseitisalsoin arepresentation ofSofsome other dimensidn.
Weneed anexample: Consider arank-3 tensor belonging to(3)rep(ie,theTS).UndertheactionofelementsofS3,thisaitransformsas2onedimensionalrepofS,__ regardlessofthevalueofn,But,itturnsontthatthenumberofindependent e@ elements ofthis tensor is(n+2/3) binomial poefficient. Ifn«2, this tensor
transforms asafour-dimensional rep ofGL(n).!
Recall that theelements ofS;here actohly on‘thesubindices; thatistosay,
elements ofS,actonthepositions ofindices. Whenyouarecounting thedimensionality
oftheS,representation, youarecounting Linbar combinations ofthethreeobjects(three positions, orthree subindices) which, thansSérm among themselves. Ontheother
hand,whenyouarecounting. theems theGL(n)UIR,youareinterestedinhowmany,Values anindexcantake. .
Sohere isthebigquestion: forGL(n) forsome fixed n,andforatensor of
fixed rank.r, andforaparticular Young diagram with rboxes, exactly howmany components
ofthistensor areindependent? Howdoyoucont theindependent components ofa
tensor ofrank rwhich isirreducible with respect toGL(n) according tosome Young
@iagram?? Answer: youcount the“standard ardangenents". When wecompute thedimensionalityofaUIRofS,whenalsoohoarrangéments,butinthatcase every integer from 1tormust appear oned. Inthis case, only numbers inthe
range 1toncanappear (nmaybesmaller orJarger than r),andmost importantly,
numberscanappearmorethanonte,aislongastheygivea"stendard arrangment" with enumbers’ thesameorincreasing across, increasihg down.
Thad,better doanexample ‘tounderstand theorigin ofthis counting rule, other
wise I'll forget itquickly.
Example: Consider arank-3 irreducible tensor belonging totheMrepof33.Lets
count the components ofthis tensorf
Tes|Fp--~|fip-fp-fip- fp-°
|Reab.Fe_-b|
So,ingeneral atensor ofthisformwould haven?=2?=8components. Butforthis
particular case you seethat 4elements vanish, and the other four arepairwise
related, soreally there are only two independent components.
Idon't really understand this counting stuff inmore gmplicated cases, but I
accept the result. Icould figure itout ifIwanted toinvest the time, but right now
Tdo not.
But Iknow the rule: just count the standard arrangements.
Ialso know ashortcut tothe rule which Icall the a/bmethod. This isafast
method ofcounting the standard arrangments. Here itis:
aa fei on zEE ges ts=>3 Saogee, 48 e
Ilearned this shortcut in,Lichtenberg.
So, byexamining irreducible tensors and counting their indpendent elements,
wearereally counting thedimensionality ofUIR's ofGL(n).
Outer Product Analysis. Now, observe that a"vector" isarank-1 tensor andit
belongs tothe[)representation ofgroupl S,,rather trivial.
Nowsuppose youwant tocombine twodifferent vectors (two systems) gomake a
rank-2 tensor. This isprecisly what that outer product deal did foryou!!! Recall
that youcombined anS,with an§,andclassified results into S,._. Soconsider:
Den-= m+A-\
XeYS KYA +HHS Y]ieee eeHOt ” Here wearecombining tworank-1 tensors togetsome rank-2
= tensors. BUT, eachirreducible tensor isassociated with eUIR.™~ ofGL(n), sothispicture alsodoesreduction ofproducts e
ofGL(n) UIR's, .(Ofcourse inthat sense itisaninner
product since each diagram refers toarep of6L(n).)
wee
-| Example 2:Hereissomething interesting. itrank-3 tensors canyoumakeby
ecombining asymmetric rank-2tensorwitha“peer?
Men= On+ a)
NowIwillbeveryexplicit withanexample: |g.,plusamomtnum, nelLorenta.
Yn,=CaP om
. Yama Syste=F LgphGa+SagtiSayP|
This istheonly completely symmetric tensor Youcanmake from these objects. Next:
XB=TAS AELA GILQuedas
2dpePy
= >SLapmPad—Qefa] :
Yeo SDHCOMON,Gayefs=[FOOD] (LyreBog+Joyefn)
*
a=3Lopypefa=vent .
“Tn=3Lapp PeeSikPatsayspa]
~2 Tp =FLaeens-amydpa- q
/
Te st *Spya—SymePr| ;
To Sp
Notice thatthe"other" combination ey -@Pu3isalinear combination ofthe
.twoMtensorsshown,itisnotlinearly{esosSo,wehaveconstructedallthe e tensors having anyS3symmetry that itispossible toconstruct fomthese objects!! And
theyaddupright.ObviouslythereisnoinTAcontributionhere.
10-k. About thesubgroups ofGL(n).
Thepoint here isthis: ifyourestreit yourself tocertain subgroups ofGL(n),theUIR'syoufound(andcounted) inthepreceding sections stillapply.Ie,ifyoue
have aVIRofGL(n) andyourestrict ittoGL(n)' (real only, GL(n,R) ifyoulike),
the rep isstill irreducible. That might not have been the case.
Here isapicture shoing the subgroups where irreduciblity ismaintained:
aArt
L
rT
. —s
Thus, theabove analysis gives thedimensionalities ofthereps ofSU(n), forexample.
Inpassing, Hhasafewcomments about Lie Algebras for some ofthese groups
GL(n) Lie algebra: 2{n) Kg=Bg vdbetsdemanle. (28padgoreAD
A D5,Kaw)=Baye SonKh LieAt-Xy=3; :
Qu) U(n)LieAlgebra: @Yay=%@Sabh.+ body
UJn) . . a .KO.Bide —CSeHLAhasteecon, ky Aoy y
ws)Xy=53,3
Fact: ifyou take any Young tableua which stands for arep ofone ofthese
groups, and ifyou add 2colum ofnboxes, the claims isthat you make nosignificant
change totherepresentiation: youcauses ittohave extra factor (deta)® carried
along ifyou add scolumns ofnboxes. Thus, essentially you ene free toalways cross
out"full colums". Thus, theUIR's ofGL(n) orone ofthe above subgroups are
really enumerated byYoung diagrams having less than nrows.
10-5+thecaseofO(n).Nowsomethinganteneydifferenthappens:here,whehyou
centract atensorontwoindices(takeits"tface"onthatpairofindieces) the eobject you get transforms asatensor ofrank|2 lower than the original tensor. In
theGL(n) case youcould still dothis contragtion, buttheobject yougetwould
nottransform asatensor: inO(n)youhavethatextra property oftheaj5which
makesthiswork:nefiely,ajaiyndye +*”| boa, :Sowhat,isthesignificance ofthistact? Supposeyoutake@tensorFy4, whichbelongs tosome synmetry of3.Youmiglt think that this tensor has
independent components and these are shuffled around inaninvariant subspacebytheO(n)operationsandthissubspaceisasrtnotso!Thereasonis
that this tensor, orthis invariant subapace, [actually isreducible further into
twopieces. ConsiderL:
Fouts=(Fens) +(daaHa+SaLaetiKi) mhTheclaimisthatanytensorcanbebrokenwatwopiecesassuggestedhere:thefirst
pieceiscompletely traceless (ie,contract ohanypairofindices andyougetzero).
The second piece. isthe remainder.
Youcanshowthateachofthesepiecestransforms onlyintoitselfunder0(n) etransformations, thé reason being that "contraption" operation, like the symmetries,
commutes with theO(n) transformastions. You cancompute H,L,K the three vectors
appearing inthe above just bytaking traces.
The usual simplest case ithis: “>
Ra=RatSav=F3RasfatGaBi =oRas [hae Ba cyBE
Hereyouseethegeneralidea:firstyouconhe‘thepiecewiththetrace,then
subtract tofind the traceless pensor.
Anytensorcanbedecompoesed inthisway}Intotraceless plus4,)tinesLover rank tensors.
10-6. Nowconsider thetraceless tensors. The|space oftraceless tensors isinvariant
underS_,permutations! SoifyouapplyaYoungsymmetrizertotracelesstensors, e@you generate irreducible tensors wrt O(n).
{
Theproblem now forO(n) istocount thedimensionality oftensors ofvarious
S,,symmetry which eretraceless, Obviously this extra tracelessness condition is
goingtolowerthenumberofindepéndent components. r)
Example:
View Fin,FayFae,Rae Bn6t(2)
Fa,Poety /4. O@).
Here the trace conditions easily give you the second pair ofelements interms of
the first, hence only 2independent elements.
Before welearn thegeneral rule forcounting inO(n), here isatheorem:
Theorem: ifyour Young diagram ofS,forarank rtensor hasmore then nboxes in
thesumofthefirst twocolums, then thecorresponding traceless tensor vanishes
identically, ie, has zero independent elements.
ome Fam =O ateZeBt 4x6h}.©),
Thus,‘yousimplycannotmakeatraceless rank-3tensorrelative to0(2)whichhas e
this symmetry!
NowHgoes ontogetcounting rules forspecial cases like 0(3) arid0(5). Basically
you just count how many conditions tracelessness implies, ther subtract those off the
count for GL(n).
Next Hshows howO(n)* isspecial case ofO(n)
10-7. Now recondider thedecomposition oftensor =traceless tnesor +extra piece.
Thetraceless tensor with S,repchoise forms anirreducible ¥pofO(n). Butthe
extra piece canbefurther reduced. Write second piece as(double traceless tneosr
+residuel’ lower piece having twodj,functions andsoon.
‘Thepoint ofdoing this issimply that youareshoiring howto"reduce" aGL(n)
representation into O(n) representations: Idont care nowabout this.
10-8,10-9. Symplectic groups. Skipped. .