Home / Math and Physics Files / Math / Curvilinear Systems / Tensor Doc and Support / tensor doc support 2_22_12 thru 3_8_12
confusion re arbitrary area xform
DOCX · 18.7 KB
Open DOCX file
A brief working note by Phil dated 2.20.12, with a comment added 2.28.12, supporting his tensor document on curvilinear systems. It explores building an arbitrary area patch as a linear combination of the N-piped areas dAn, then retracts those problems as irrelevant. It also recalls the rule dA'n = |J| R dAn for a vector density of weight -1 and asks how this squares with his Section 8 area results.
AI-written summary; may contain errors.
Extracted text (machine-read; may contain errors)
Confusion of the Day: arbitrary area transformation PhL 2.20.12
Comment Added 2.28.12. I was now OK with how dAn transformed where dAn was an N-piped area. But I then wondered how some arbitrary dA in x-space transformed? Well, I figured that out and added to my new Section 8 in progress. But before I did that, the two "problems" below arose because I was thinking that I had to construct the arbitrary area dA somehow as a linear combination of the dAn areas. But then I realized how to construct an arbitrary dA and it has nothing to do with such a linear combination described below, so the two Problems are incompetent, irrelevant and immaterial.
Problem: In 2D Cartesian space I have two edge vectors
dx1 = dx
dy1 = dy
How do I create a diff vector from these basic lengths which points at 45 degrees?
V = A dx1 + B dy1 = A dx + B dy
I could then select
A = k/dx B = k/dy
and I get
V = k ( + )
and I have solved the problem.
Problem: In 3D Cartesian space I have three area patches
dA1 = dx2dx3
dA2 = dx3dx1
dA3 = dx1dx2
How do I create an area patch from these basic patches which points in some given direction N?
[ this is the linear combination of area patches idea commented on above.]
Well, the solution is going to be
dA = k N
and we then get
Σici dAi = k N
c1dx2dx3 + c2dx3dx1 + c3dx1dx2 = k (N1 + N2 + N3 )
The solution is then
c1 = kN1/ (dx2dx3)
c2 = kN2/ (dx3dx1)
c3 = kN3/ (dx1dx2)
Warning: I have changed Appendix D so below |J| should really be J. The question posed remains a good one! Once you know that dA'n is a vector density of weight -1. the transformation rule is done! This might shorten Section 8 when I get back to it.
Problem: According to tensor doc page 102, we have
dA'n = |J|-(-1) R dAn = |J| R dAn = g'1/2RdAn
So if someone wants to know how an arbitrary patch of area transforms, the answer is this
dA'n = |J| R dAn
and in the other direction
dAn = |J|-1S dA'n
This result is trivially simple.
(1) Why then did I have to do all that work in Section 8 to determine how area transforms?
(2) How is the above consistent with my Section 8 area results?