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Lecture notes by Eef van Beveren (Univ. of Coimbra, dated 1988, version July 2007), kept in Phil's tensor support files. They begin with coordinate systems, Galilei and Poincaré transformations, and relativistic kinematics. They then cover covariant derivatives and Christoffel symbols, curves and surfaces in three dimensions, Gauss's Egregium theorem, curvature tensor, geodesics, and gravitation via curvature up to the Schwarzschild metric and planetary orbits.
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Some topics inGeometry andGravitation
EefvanBeveren
CentrodeFsicaTeorica
Departamen todeFsicadaFaculdade deCi^encias eTecnologia
Universidade deCoimbra(Portugal)
http://cft.s.uc.pt/eef
7deJulho de2007
Contents
IIntroduction 1
1Theaftermath ofaphysicsexam 1
2Movingreference system 4
3Transformations 7
4Galilei transformations 8
4.1Thekinetic energy ..................................9
5Pioncar etransformations 9
5.1Velocities neverexceed thevelocityoflight.....................11
5.2Small velocities ....................................11
5.3Energy andmomen tum................................12
5.4Totalinvariantmass .................................13
6Relativistic kinematics 14
6.1+ !K+K ..................................16
6.2Elastic Scattering inthecenter-of-mass system ...................17
6.3Elastic Scattering inthelabsystem .........................19
IIGeneralities 20
7Covariantandcontravariantcomponents 20
8Themetrical tensor 22
9Localbasis 23
10Themetric ofthelocalcoordinates 24
11Dieren tiation withrespecttothelocalbasis 24
12Christoel symbols(ane connection) 25
13Therelation betweentheane connection andthemetric 26
14Thederivativesofavector eld 27
15Covariantderivative 27
i
IIIThree dimensions 28
16Curvesinthree dimensions 28
17Thenatural localbasisofacurve 31
18Thederivativesofthenatural basis 33
18.1ProofoftheFrenet relations .............................33
18.2Darbouxvector ....................................34
19Atwo-dimensional surface inthree dimensions 35
20Thederivativesofthelocalbasis 37
21Curvesonthesurface 39
22Thecurvature ofthecurvesonthesurface 41
23Thecurvature ofthesurface 42
24Thelocalprinciple axes 44
25Egregium theorem ofGauss 46
26Thecurvature tensor 48
27Geodesics 50
IVExamples ofRiemann surfaces 51
28Thecylinder 51
29TheEllipsoid 53
30Geodesics onthesphere 57
31Thetorus 60
VThedescription ofgravitation bycurvature 63
32Rectilinear motion 63
33Parallel transp ort 65
34Parallel transp ortalong curvesatthesphere 66
35LocalEuclidean geometry 68
36Tidal forces 71
ii
37Theprinciple ofequivalence 73
38Minkowskian space-time 74
39Gravitational forces 76
40TheSchwarzschildmetric 77
41Planetary orbits 79
iii
Some topics inGeometry andGravitation
These notes arebornasaresult ofaseries ofdiscussions withmycolleague HumbertoPascoal
fromtheCentreofTheoretical PhysicsattheUniversityofCoimbra,Portugal, ontheprinciples
ofthedescription ofacurvedtwo-dimensional surface embedded inthreedimensions. Theideas
contained inthese notes arenotnew.Onthecontrary,thesimple andelegan tmetho dswhich
leadGauss tohisEgregium Theorem, leadustostudy inmoredetail asubjectwhichalmost two
centuries agohasbeenstudied byCarlFriedric hGauss (1777-1855), Janos Bolyai(1802-1860)
andNikolayIvanovichLobac hevski (1793-1856).
Thenotation whichIhaveusedinthisnotes, istheonewhichismost popular amongst
physicists, inorder nottodiscourage rstandsecond yearphysicsstuden ts.
Moreo ver,Idonotintendtoberigorous, neither complete.
Belowyoundtheliterature whichIconsulted.
Decem ber,1988.
EefvanBeveren
References
[1]A.Einstein, ZurElektrodynamik bewegterKorper,Annalen derPhysik,(1905).
[2]A.Duschek,Dierentialge ometrie ,Handbuc hderPhysik,Band III,edited byH.Thirring,
VerlagvonJulius Springer, Berlin, 1928, page153.
[3]Horst Tietz, Elementar eDierentialge ometrie ,Handbuc hderPhysik,Band II,edited byS.
Flugge, Springer-V erlag, Berlin, 1955, page146.
[4]H.S.M. Coxeter, F.R.S., Introduction toGeometry ,John Wiley andSons, Inc,NewYork,
1961.
[5]StevenWeinberg,Gravitation andCosmolo gy,JohnWiley andSons, Inc,NewYork,1972.
PartI
Introduction
Einstein's discoverythattheLorentztransformations followfromasimple principle, namely the
constancy ofthelightvelocityinallinertial reference frames, wasanimportantbreakthrough
forthedevelopmen tofafulltheory ofGravity.But,manyoldconcepts hadtobereplaced
aswell.Inthisnotes wewillpaysome attentiontoimportantcontributions fromdieren tial
geometry ,inparticular, tothenotion ofafreely movingparticle inacurvedmanifold.
Firstwepassthrough thedenition ofcoordinates andthedescription ofmovingobjectsby
acoordinate system. Then wepaysome attentiontoGalilei, LorentzandPoincar etransfor-
mations. InpartIIwecome tointroducethemain dish.
1Theaftermath ofaphysicsexam
Praia Perp^etuahasaverylongandperfectly straigh troadforbicycles alongside thebeach.
Onabeautiful sunnydayjustafewweeksbeforethebeginning ofthebeachseason, ayoung
man,named Alex, isseated attheveranda ofhisbeachapartmen tjustnexttotheroad. From
there hewatchesthemovementsonthebeachandenjoystheneverending sound ofthewaves
breaking intofoam atthesandofthebeach.Itisalovelyday,butonlyaveryfewpeople
arewalking inthesandortaking abathintheocean, probably sinceitisonlynineo'clockin
themorning. Heobserv esthatthismorning theice-cream vendor installed hiscarnexttothe
roadatonly43meters tohisright.Athisleftat39meters distance there isasmall restauran t
where youcaneatfreshsheverydayoftheyear.
Since Alexconsiders himself thecenteroftheUniverse,wherev erheisseated, healways
represen tstheorigin ofhiscoordinate system. Moreo ver,sinceheisnevertheless areasonably
welleducated person, hemeasures distances inmeters. Asfarasthebikeroadisconcerned we
willconsider onlyonedimension andindicate thecoordinate system ofAlexbyx(A).Forthe
ice-cream carwendthen
x(A)
ice-cream car=+43; (1)
whereas, fortheshrestauran tweobtain
x(A)
shrestauran t= 39: (2)
Theplusandminussigns havenothing todowithaclassication ofAlextowardseating ice
cream orsh,heactually lovesbothicecream andfreshsh,butindicate thatwehavechosen
1
thepositivesenseofthecoordinates inthedirection oftheice-cream car.Theoppositedirection
isthenautomatically inthenegativ esense. Onpurpose,wehavenotindicated unitsinformulas
(1)and(2),sincewehavestated theunitsystem ofAlexbefore.
Ayoung couple onabicycle passes by.They areBruno andClara whobothgreet Alex.
Bruno doesthepedaling, whereas seated onthebackthebike,hisarms around thewaistof
Clara whoisseated onthesaddle anddoesthesteering. They areheading towardstheice-
cream car.However,justsome meters afterpassing Alex, Bruno stops thebikeandsitswith
Clara inthesandnexttotheroad, Clara atBruno's lap.They aretalking aboutthephysics
exam ofyesterda yand,inparticular, discussing aproblem aboutrelativ emotion, while, inthe
mean time, hugging andkissing eachother. After somehalfanhourtheydecide tobuyanice
cream, butnotwithout measuring thedistance fromwhere theyareseated tillthecar.Bruno
measures distances inlargesteps, whichheknowsarejustequal toonemeter. So,hesetsout
towardsthecarandarrivesafter26steps. There, hepatien tlywaitsforClara.
Clara measures theworld,whichconsists outofeverything whichisclosetoher,inthewell-
shapedpalms ofherslimhands. Consequen tly,sheprefers tomeasure distances withthesizeof
herhands. Bruno enjoysobserving her,busyonherknees, slowlyapproac hinghim,byputting
onehand nexttotheother inthesandwhile thesunisshining onherback.Threeh undred
twentyveshecountswhen sheendsatBruno's feet.Welldone, Bruno agrees, Iknowthat
thepalms ofthose tender hands ofyoursmeasure precisely eightcentimeters. Hegiveshera
bigkissandorders theiricecreams. Onegirlish, withstrawberries, forhisClara, andonemore
serious, withchocolate, forhim.They walkbacktotheirbicycle while eating theiricecreams.
Inthecoordinate system ofBruno, whichweindicate byx(B),wendforthecoordinates of
theice-cream carandtherestauran trespectively
x(B)
ice-cream car=+26; (3)
and
x(B)
shrestauran t= 56: (4)
Furthermore, inthecoordinate system ofClara, whichweindicate byx(C),wendforthe
coordinates ofthesame respectively
x(C)
ice-cream car=+325; (5)
and
x(C)
shrestauran t= 700: (6)
Notice thattheorigins ofthecoordinate systems ofBruno andClara areattheposition where
theystoppedtheirbicycle.
While stillwalking, Bruno andClara seefarbehind therestauran thowblond beautyDiane
withherelegan tlegsispedaling herbicycle towardsthem. Clara isnotveryfondofmeetings
withBruno's former girlfriend. Inparticular not,when sheisdriving herbicycle dressed in
ascandalous minibikini. Butthen, Bruno putshisarmaround Clara's shoulders andgives
alongkisswithalittlebitofchocolate icecream inhercurly darkhairs fullofsand. Both
startcalculating howmuchtimewillelapse beforeDiane willpassbytheplace where theywere
seated.
Bruno starts hisstopwatchwhen Diane ispassing bytheshermen monumentat56meters
beyondtheshrestauran t.Hendsthatittakesherexactly 20seconds fromthere tothe
restauran t.So,heconcludes thatitwilltakeyetanother 20seconds beforeshewillreachthem.
2
Enough timetositdownwithClara, facing theocean, theirbacksturned towardstheroad.
Clara countstimewiththebeatsofherheart which,actually ,isbeating asbitfaster than
normal rightnow.Measuring exactly thesame distance asBruno hadselected, shecomes at
28beatsintotal. They sitdowninthesand, enjoyingtheiricecreams andpretending notto
notice whoispassing byonherbike.
Inthemean time,Alexalsohadcomeawareofwhowasapproac hinghimatherbicycle. Ever
sinceDiane hadbrokenupwithBruno, heassumed thathischances withherwerewritten inthe
stars. Therefor, healsomeasured herspeedathisstopwatchtocome tothesameconclusion as
Bruno, andprepared himself foragoodimpression onhis,asyetsecret, love.Inhiscoordinate
system hefound thatherposition coordinate attimet(A)isgivenby
x(A)
Diane
t(A)
= 95+2:8t(A): (7)
But,although hisformulacorrectly corresp ondstoDiane's motion, unfortunately forAlex,
Diane hardly responded tohis\howareyouDiane" when shepassed by.
Disapp ointed,heisstillwatchingher,when heassists howClara cannot resist togiveDiane a
provocativelookoverBruno's shoulder. Itisresponded byaslowandsensual helloofDiane. On
hearing herattractiv evoice,Bruno turns hishead, utters asoundless helloand,likehypnotised,
keepswatchingthemostpleasan tscene ofthesun-tanned bodyofthebeautyfulgirl,pedaling
onherbicycle, herblond hair
oating intheairlikethetailofacomet when itpasses closeto
thesun.However,Clara, disturb edbyBruno's confusion, reacts byputting what isleftofher
icecream onhisforehead. Thatgesture rapidly brings himbacktoreality.While joking about
herattackofjealousy ,heholds Clara rmly inhisarmsandkisses herdelicately .Both start
laughing andsoontheinciden tseems tobelong tothepast.
While refering tothemotion ofherbicycle, Bruno arms thatDiane's motion iswellde-
scribedbythefollowingformulainhiscoordinate system.
x(B)
Diane
t(B)
= 112+2:8t(B): (8)
Clara, stillnotcompletely secure ofherspellofcharm onBruno, isnotexactly eager toshare
herresult onthisparticular eventwithBruno. But,ontheother hand, shealsodoesnotwant
himtonotice herinsecurit y.So,shetellsBruno thatshefound
x(C)
Diane
t(C)
= 1400+25t(C): (9)
Bruno, stillabsentminded, saysthatheisnotcompletely surewhether thisagrees withhis
result (8).Itistobeadmired thatClara manages nottorespondthatheapparen tlyisnot
sureaboutseveralissues, but,instead, proposestovisitAlex. They decide togotoAlexand
checkwithhisndings.
Alex, gladtohavesome compan ytodistract himfromhisdisapp ointment,happily shares
thendings onthemotion ofhissecret love,withClara andBruno. Soonthethreestarttalking
aboutDiane, eachwithdieren tfeelings withregard tothefascinating girl.Bruno withsome
sadness aboutthewayhelosther,Alexregretting hisrecentfailure toattract herattention
andClara withsome latentboiling fury.
Based inequations (1)to(6),theyhadcome totheconclusion
x(B)=x(A) 17;x(C)=12:5x(B)and x(C)=12:5x(A) 212:5:(10)
Notice thatallrelations arelinear inthecoordinates, whereb ytherstjuststems fromthe
translation oftheorigin ofBruno andClara withrespecttotheorigin ofAlex, thesecond from
3
thedieren tunitsofBruno andClara, whereas thethirdrelation comes fromacombination of
thedierence inunits andthetranslation oforigins.
With respecttoinstan tsoftimetheyfound
t(B)=t(A);t(C)=1:4t(A)and t(C)=1:4t(B): (11)
Clara's heart beatwasabitfaster thanonepersecond. Hence, herunitoftimeisabitsmaller
thantheunitoftimeforBruno andAlex. Thelatter unitisthesecond.
2Movingreference system
Alex, Clara andBruno arestilltalking aboutDiane, when theysuddenly observ eherreturning
fromherbicycle trip.But,fromthelanguage ofherwell-shap edbody,Alexdeduces thatshe
isnotashappyaswhen shepassed byhisveranda earlier. Hedecides tocallher.
Thistimeheissuccesful, Diane stops herbicycle andaccepts hisinvitation tojointhem.
They greeteachother withhugsandkisses. Butjustafterthiswarmreception ceremon y,Clara
suddenly remem bersthatsheandBruno hadsomething urgenttoberesolved.Bruno stillhas
thenervetoaskwhat itwasagain thatisnowsuddenly sourgent.But,fortunately ,fromthe
expression atClara's faceheunderstands thatitisbetternottoinsist onhavinghisignorance
claried. Alexisdeligh tedwithClara's attitude andimpatien tlyawaitsthedeparture ofthe
couple. Asbyamiracle hehashisblond beautyDiane seated withhimathissofaonhis
veranda. Muchmore thanhehadbargained forearlier thismorning.
Without payingmuchattentiontoit,Alexhadnoticed thatDiane wasnotdriving herown
bicycle when shepassed byhisveranda forthersttime. Actually ,itisherfather's bicycle she
isusing. Thereason forthat,aswewillsee,isasubjectwhichshebynomeans isprepared to
confess toAlex.
Diane livesinasmall house neartheshermen monument.Inthemorning, when Diane
awakes,sheusually opensthewindo wofherbedroomcompletely andstaysthere forawhile
inhernightdress, leaning onherelbows,watchingthesea,thebeach,theseagulls andthe
people passing byattheroad. Thismorning, when shesawBruno andClara passing by,Diane
started toslipintoherdream world,thinking onhowmuchshehadenjoyedsuchtripswith
Bruno onhisbicycle. Inparticular, when he,liketodaywithClara, acted asthemotor ofthe
bicycle, whereas she,withhisarmsaround her,could justgotoanydirection whichcame to
hermind. Veryoften shehadsteered bothofthem toaquiet sunnyvalleyinthedunes, where
theyhadoncediscoveredaperfect siteforlovers,hidden bypleasan tvegetation ofredand
white
ourishing oleanders andyellowbroomwiththeirintense perfume. Shestarted feeling
likereturning toherbed.But,thenshesawaglimpse ofEricwhocomes regularly tothebeach
foraweekendorforafewdays,andwholivesinanapartmen tjusttwoblocksdowntheroad.
Eric,whoisprobably somewhere inhisearly twenties,hasastrong muscular bodyanda
pleasan tfacewithblond curlyhair.Heusestopractice jogging when heisatthebeach.When
Diana sawhimmovingtowardstheshermen monument,shecalculated fromhisspeedthatif
shecould manage, within veminutes,tobeonherbicycle infrontoftheshermen monument,
shecould justcatchupwithhimattheplace where thebikeroadturns awayfromthebeach,
towardstheinland, andwhere heprobably wouldrestalittlebeforereturning tohisapartmen t.
Thedistance tothatplace is2.1kilometers measured fromtheshermen monument.
Diane already started imagining Ericonthebackofherbikewithhismuscular armsaround
herbody.But,thensheremem beredthatherbike,unfortunately ,cannot carry persons inthe
back.Hence, shedecided totakeherfather's bikeinstead.
4
When shestarted outattheshermen monument,sheknew fromEric's speedthathewas
some 600meters far.Fromhervelocityshededuced thatinherreference frame, withher
father's bicycle attheorigin, thedistance toEricwasdecreasing at0.8meters persecond,
hence, thatEricwasapproac hingheratthatspeed.Itwouldthustake12.5minutesbeforeshe
wouldmeetEricrightattheplace whichshehadcalculated. Inhercoordinate system Diane
describ esEric's position by
x(D)
Eric
t(D)
=600 0:8t(D): (12)
AlexalsohadseenEricpassing bythismorning. Hehadmethimafewtimes inthe
discoth eque. So,theygreeted eachother. Alex, curious toknowatwhichplace Ericwould
turnaround toreturn home, measured hisspeedat2.0meters persecond. Inthecoordinates
ofAlex, Eric's position isgivenby
x(A)
Eric
t(A)
=505+2:0t(A); (13)
aslongashecontinuestomoveinthepositivesense withthesamevelocity.Thelatter formula
isexplained inmoredetail below.
Alexrestarted hisstopwatchwhen hesawDiane passing bytheshermen monument.Con-
sequen tly,hethereb ydenes forhimself anewbeginning oftimet(A)=0,atthesame time
that,coinciden tly,Diane started herstopwatch.Hence,
t(A)=t(D): (14)
ButAlex' choice ofanewinstan toftimet(A)=0,occurred 4minutesand12.5seconds after
Erichadpassed byhisveranda. InthatintervaloftimeEricmoved505meters. Consequen tly,
att(A)=0Ericisinposition
x(A)
Eric
t(A)=0
=505
inthecoordinates ofAlex. Thisexplains theconstan tinformula(13)and,moreo ver,agrees
withtheobserv ation ofDiane,
x(D)
Eric
t(D)=0
=600;
sinceDiane andAlexare95meters apart att(A)=t(D)=0.
Alex, whoisaverycurious person, asksDiane whysheisdriving herfather's bicycle. But
Diane, whohasofcourse nointentiontoshare herstory withAlex, tellshimthatherbikeis
brokenandhas
attires. Aleximmediatly oers himself torepair herbike.However,justwhen
Diane starts explaining thatherfather isalready taking careoftheissue, sheseesEricpassing
by,heading forhisapartmen t.Ericgreets Alexand,furthermore, givesabigsmile toDiane.
Alexnotices herblushing andfeelshisheart brokenforthesecond timethismorning.
But,heignores thisfeelings. Instead, hetellsDiane abouthisformula(13)onEric's dis-
placemen tinfunction oftime, whichhehaddetermined earlier thismorning when Ericwas
jogging towardstheother endoftheroad. Diane decides toalsoshare herformula(12)with
Alex. Forawhile theyarebothpuzzled aboutthedierences.
ButthenAlexnds thesolution. Hestarts explaining ittoDiane, bytelling herabout
hisformula(7)onhermotion, when shewascycling towardstheroadexit. Diane reacts
surprised andrstlooksawhile atAlexbefore sheaskshimwhichespionage service makes
himcalculating everybody'smovementsonthebicycle road. Now,Alexstarts blushing and
confesses thatinhercase,thecalculus hadbeendoneforhimtoknowhowmuchtimehehad
5
toprepare himself formaking agoodimpression onher.Healsotellsherthathehadbeen
verydisapp ointedwhen shehardly tooknotice ofhim.Diane's mouth stayshalfopenwhile she
continuesstaring atAlex, inspecting thenoble regular faceofthetallslimboy,outstanding in
physics, mathematics andchemistry .Then, suddenly shemovesslowlyasclosetohimasshe
canmanage andaskshimtoplease holdherverytight.
Atthispoint,itseems thatitmighttakeawhile beforeAlexwillexplain hissolution to
Diane, ifever.So,webetterdoitourselv es.
While Diane wasdriving herbicycle, herreference frame ofx(D)coordinates wasmoving
withher.Sheconsidered herself theorigin ofthatreference frame andwasmoreo vermoving
inthepositivesense. Informula(7)Alexhaddetermined herspeedat2.8(m/s) withrespect
tohiscoordinate system whichisthereference frame attachedtotheEarth.
Alexhasdetermined thespeedofEricat2.0(m/s) inthepositivesense informula(13).
Diane found informula(12)thatEricmovedinthenegativ esense, towardsher,withaspeedof
0.8(m/s). Hence, when wedenote speedbyvthenarelation forthevarious velocities involved,
isgivenby
v(D)
Eric=v(A)
Eric v(A)
Diane ; (15)
orinwords: Although running intheoppositedirection, Ericisapproac hingDiana sincetheir
distance isdecreasing withtime. Consequen tly,thevelocityofEricwithrespecttoDiane is
inthenegativ esense inDiane's coordinate system andequals thedierence ofthevelocityof
EricwithrespecttoAlex, whichisinthepositivesense, andthevelocityofDiane withrespect
toAlex, whichisalsointhepositivesense.
Now,howcantherelation (15)befullyrecoveredfromtherelations (13)and(12)?
Fromformula(7)weobtain inthereference frame ofAlextheposition oftheorigin ofthe
reference frame ofDiane (whichisherfather's bicycle) infunction oftheinstan toftimet(A)
measured atthewatchofAlex. Hence, wecandetermine theposition ofEric,x(A),atacertain
instan toftimet(A)inthecoordinate system ofAlex, starting fromhispostion inthecoordinate
system ofDiane andtheposition ofherorigin withrespecttotheorigin ofAlex:
x(A)
Eric
t(A)
=x(A)
Diane
t(A)
+x(D)
Eric
t(A)
: (16)
Here, wesubstitute equation (7),tond
x(A)
Eric
t(A)
= 95+2:8t(A)+x(D)
Eric
t(A)
: (17)
Next, when wesubstitute formula(12),alsousing therelation (14),thenwerecoverrelation
(13).
Now,fromformula(16)wemaydeduce
dx(A)
Eric
t(A)
dt(A)=dx(A)
Diane
t(A)
dt(A)+dx(D)
Eric
t(A)
dt(A): (18)
Inthesecond termontherighthand sideofformula(18),wemaysubstitute relation (14). We
obtain thenindeed relation (15)intheform
v(A)
Eric=v(A)
Diane+v(D)
Eric: (19)
Thelinear transformations (14)and(17)preserv etherelation (19),orequivalentlyrelation
(15). Transformations whichpreserv ethose relations arecalled Galilei transformations.
6
3Transformations
Fromtheprevious section wehaveundersto odthatitisveryimportanttodistinguish between
acoordinate system andthecoordinates ofamovingobject.Furthermore, weshould dene well
what wereally,reallywant(Spice girls,1994) when weconstruct coordinate transformations.
1.Coordinate system (reference frame)
Here, wedene acoordinate system asacontinuoussetofpointswhichrepresen tthe
positions ofpointlikeobjects. Weassume thatsuchpointsllupthewhole space. To
eachpointwemayassociateasetofrealnumbers,called vectors.Inonedimension each
pointischaracterized byonerealnumber,intwodimensions bytworealnumbers,etc.
Weassume furthermore thatneighbouring pointsarecharacterized byneighbouring sets
ofrealnumbers.Usually weerectasetofcoordinate axeswhichintersect allinonepoint,
theorigin ofthecoordinate system. Theorigin isrepresen tedbytheset(0,0,...,0).All
other pointsarerepresen tedbytheirprojections onthose axes. Inthatcasethewhole
space isdened oncetheunitvectors oneachaxisaredened.
2.Thecoordinates ofamovingobject
Amovingobjectisdescrib edbyasetofcoordinates whichvariesinfunction ofatime
parameter: (x1(t),x2(t),...,xn(t))inann-dimensional space. Theresulting space isa
one-dimensional subspace ofthefullcoordinate space. Inonedimension onedoesnot
notice wellthedierence betweenthespace andthesubspace whichdescrib esamoving
object.However,inhigher dimensions itisobvious, sincethespace describ edbyamoving
pointparticle isjustaline.
3.What wereally,really want
Wewanttostudy coordinate transformations whichdescrib ereference frames whicharein
relativ emotion withconstan tvelocity.Inparticular, wewanttostudy whatispreserv ed
under suchtransformations.
7
Inthefollowingwewillconsider twoone-dimensional reference systems AandBandindicate
thecoordinates andtimeparameters byrespectivelyx(A)andt(A)inreference frame Aandby
respectivelyx(B)andt(B)inreference frame B.
4Galilei transformations
Besides possible scaletransformations bychoosing dieren tunitsystems andwhichwewillnot
further discuss here,theGalilei transformations consist outof
1.translations
Wehavespacetranslations ,givenby
x(B)=x(A)+constan t; (20)
whichstemfromchoosing adieren torigin ofspace, andtimetranslations ,givenby
t(B)=t(A)+constan t; (21)
whichstemfromchoosing adieren tbeginning oftimecounting.
2.rotations
Inonedimension there arenorelevantrotations.
3.inversion
Wehavespaceinversion ,givenby
x(B)= x(A); (22)
whichstemfromchanging positiveandnegativ esense, andtimeinversion ,givenby
t(B)= t(A); (23)
whichstemfromcountingbackwardintime.
4.boosts
Under aboostweunderstand acoordinate transformation forrelativ elymovingreference
frames. SupposethatBismovinginthepositivesense withrespecttoAwithaconstan t
velocitygivenbyVandassume alsothatattimet(A)=0theorigins coincide and,
moreo ver,t(B)=t(A).Then thisboostisgivenbythecoordinate transformation
x(B)=x(A) Vt(A)=x(A) Vt(B): (24)
Alltheabovetransformations preserv edistanc eandrelativ emotion. Takeforexample the
boosttransformation (24)andtwopointlikeobjectsaandbinmotion. Lettheirmotion be
describ edby
x(A)
a
t(A)
and x(A)
b
t(A)
; (25)
8
inreference frame A.There arenorestrictions onthedependence oftheirargumen ttofthe
functions x(A)
a(t)andx(A)
b(t).Onemayconsider anymotion, like
x(A)
a
t(A)
=43+24cos
t(A)
and x(A)
b
t(A)
= 512+318t(A)5; (26)
orwhatev erother complicated motion.
Insystem B,whichishereconsidered tobeinmotion withrespecttosystem Awithconstan t
velocityV,using thetransformation (24)andt(B)=t(A),wendforthedescription ofthe
motion ofobjectsaandb
x(B)
a
t(B)
=x(A)
a
t(B)
Vt(B)and x(B)
b
t(B)
=x(A)
b
t(B)
Vt(B):(27)
Fortheirrelativ edistance inreference frame Bweobtain
x(B)
b
t(B)
x(B)
a
t(B)2=x(A)
b
t(B)
x(A)
a
t(B)2=x(A)
b
t(A)
x(A)
a
t(A)2:
(28)
Hence, therelativ edistance ofaandbisequal inbothreference frames AandBforalltimes.
Fortheirrelativ evelocityweobtain
dx(B)
b
t(B)
dt(B) dx(B)
a
t(B)
dt(B)=dx(A)
b
t(A)
dt(A) dx(A)
a
t(A)
dt(A): (29)
Hence, wendthatrelativ emotion isnotaected bytheGalilei transformations. Newtonian
physicsisthesame inreference frame Aasinreference frame B.
4.1Thekinetic energy
Thekinetic energy ofamovingpointparticle isrelated toitsmass, m,anditsvelocity,v,(or,
alternativ ely,itslinear momen tum), by
E(kinetic )=1
2mv2: (30)
Now,sincemassisinvariantunder Galilei transformations, andsince, moreo ver,velocities add
up(seeformula19),itisclear thatthekinetic energy ofaparticle isdieren tindieren t
inertial frames, under Galilei transformations.
5Pioncar etransformations
Instead ofleavingjxb xaj2invariant,asunder Galilei transformations, under Poincar etrans-
formations theeventdistanc e,forc=1givenby
(xb xa)2 (tb ta)2; (31)
isleftinvariant.
Therstquestion is,ofcourse, todene wellwhat thisquantityrepresen ts.Inorder to
answerthatquestion, westartbydening thenotion ofanevent.Aneventisthehappening
ofsomething atacertain place andatacertain time. Forexample, when Bruno stoppedthe
bicycle at9h02at17meters distance fromAlex, orwhen Ericpassed bytheveranda ofAlexat
9
9h36. These aretwoevents.Wecandetermine thequantity(31)forthose twoevents.Under
Poincar etransformations thisgivesthesame result forAlex, sitting inhissofaathisveranda,
asitgivesforDiane driving herfather's bicycle.
Forspace andtimetranslations andinversions itisobviousthatthequantity(31)isinvariant,
aswellasforspace rotations, because space rotations donottouchthetimeanddoleave
invariantdistances inspace. So,weonlyhavetoconsider Poincar etransformations forreference
frames whicharemovingwithrelativ econstan tvelocity=V=c,i.e.boosts.Thelatter
transformations arealsocalled Lorentztransformations.
Hence, thetaskistondatransformation formovingframes whichleavesthequantity(31)
invariant.ThishasbeendonebyAlbertEinstein (1905). Heobtained
x(B)=
x(A) t(A)
and t(B)=
t(A) x(A)
; (32)
where
=1
q
1 2: (33)
Itiseasytodemonstrate thatthecoordinate transformation (32)satises thecondition that
thequantity(31)isinvariant.Belowweexpress interms ofthecoordinates ofreference frame
A,theeventdistance (31)forthetwoeventsaandbasdetermined inreference frame B.We
makethereb yuseofexpressions (32)and(33).
n
x(B)
a x(B)
bo2 n
t(B)
a t(B)
bo2= (34)
=n
x(A)
a t(A)
a
x(A)
b t(A)
bo2 n
t(A)
a x(A)
a
t(A)
b x(A)
bo2
=
2n
x(A)
a x(A)
b
t(A)
a t(A)
bo2
2n
t(A)
a t(A)
b
x(A)
a x(A)
bo2
=
2
1 2
x(A)
a x(A)
b2+
2 1
t(A)
a t(A)
b2
=
x(A)
a x(A)
b2
t(A)
a t(A)
b2:
Once more using relation (32), wededuce belowarelation fortheaddition ofvelocities.
When reference frame Bmoveswithconstan tvelocity=V=cwithrespecttoreference frame
A,andanobjectmoveswithvelocitydx(A)=dt(A)inreference frame A,thenwendforits
velocityasmeasured withrespecttothecoordinates usedinreference frame Bthefollowing.
dx(B)
dt(B)=dx(B)
dt(A)
dt(B)
dt(A)=
dx(A)
dt(A) !
1 dx(A)
dt(A)!=dx(A)
dt(A)
1 dx(A)
dt(A): (35)
Inparticular foranobjectwhichtravelswiththespeedoflight(c=1)inframe A,wehavein
frame B
c(A)=dx(A)
light
dt(A)=1()c(B)=dx(B)
light
dt(B)=1
1 =1: (36)
10
Fromthisresult wemayconclude thatobjectswhichmovewiththespeedoflightwithrespect
tothecoordinates ofonereference frame, alsomovewiththespeedoflightasobserv edby
using thecoordinates ofareference frame whichisinmotion withaconstan tvelocitywith
respecttotherstreference system. Orinother words, lightmoveswiththesame velocity
withrespecttoobserv ersindieren tinertial systems.
5.1Velocities neverexceed thevelocityoflight
Ininertial frame Awestudy anobjectwithvelocityv(inunitsc)withrespecttothecoordinates
ofreference frame A.Weassume thatvissmaller thanthevelocityoflight,i.e.
jvj<1()1+v>0and 1 v>0: (37)
Letusfurthermore consider areference frame Bwhichmoveswithconstan tvelocity,also
smaller thanthevelocityoflight,withrespecttoreference frame A.Now,since bothvand
aresmaller thanthevelocityoflight,wehave,bytheuseofrelations (37),thefollowing
inequalities.
1 v>0
(1+v)(1 )<0() (1 v)<v
0<(1 v)(1+)()v <1 v:
Putting things together, wend
1<v
1 v=v(B)<+1: (38)
Thisproofsthatv(B),whichisthevelocityoftheobjectunder study,asmeasured inthe
coordinate system B,isalwayssmaller thanthevelocityoflightc=1,forthecasethat
velocities inAdonotexceed thevelocityoflight.
Velocities larger thanthevelocityoflight,while not(yet?)observ ed,donotseemtomake
partofourphysical world,hence, donothavetobeconsidered (yet?).Thisdoesnotmean that
itisforbidden tostudy theproperties oftachyons,but,justmeans thatwedonotyetneedto
study them.
5.2Small velocities
Here, wewillconcen trate onall-dayvelocities, likejogging Ericandbicycling Diane. With
respecttoAlexthevelocityofjogging Ericisgivenby(seeformula13)
dx(A)
Eric
dt(A)=2:0m/s
3:0108m/s=2
310 8: (39)
Furthermore, thereference frame ofDiane moveswithaconstan tvelocity(seeformula7)given
by
dx(A)
Diane
dt(A)=2:8m/s
3:0108m/s=2:8
310 8: (40)
11
Hence, bytheuseofformula(35),wendforthevelocityofEricinthereference frame of
Diane thefollowing.
2
310 8 2:8
310 8
1 2
32:8
310 16 0:8m/s
3108m/s
1+5:6
910 16
: (41)
Fromformula(41)weobtain theresult thatonlyinthe16-th decimal wemaynotice adierence
fromtheaddition rule(15). Inpractice itisimpossible toverifythisresult, sincealready the
errors inthemeasuremen tsofthevelocities ofEricandDiane areorders ofmagnitude larger.
Consequen tly,forall-dayvelocities wewillnotnotice anydierence betweenGalilei and
Poincar etransformations. Evenwiththevelocities ofsupersonic airplanes, whicharemore
thantwoorders ofmagnitude larger thanrunning ordriving abicycle, theeects areonly
insomewhere the11-th decimal. However,atcosmic scales orinparticle accellerators where
objectsreachvelocities close tothelightvelocity,thedierences betweenthetwotypesof
transformations areverywellobserv able. Millions ofexperimen tseverysingle dayconrm that
Einstein's basic assumption (1905) ontheconstancy ofthelightvelocitywasveryclever.
5.3Energy andmomen tum
Letusdene forapointparticle withvelocityv
"=1
p
1 v2and ~u=~v
p
1 v2; (42)
whichinonedimension reduces to
"=1
p
1 v2and u=v
p
1 v2: (43)
First, bytheuseofrelations (33)and(35),wedetermine
"(B)=1
q
1 v(B)2=
1 v(A)
q
1 v(A)2and u(B)=v(B)
q
1 v(B)2=
v(A)
q
1 v(A)2; (44)
whichcanbewritten intheform
(B)=
(A) u(A)
and u(B)=
u(A) (A)
: (45)
Oncomparison offormulas(45)withformulas(32),weobserv ethatthepair(;u)trans-
forms thesame wayasthepair(t;x).Consequen tly,thequantity
2 u2; (46)
isaninvariantunder Lorentztransformations.
Moreo ver,from
1
p
1 21
1 1
221+1
22; (47)
12
wendthattolowestorder
m"m+1
2mv2and mumv: (48)
Therstexpression informula(48)corresp ondstoaconstan t,m,whichrepresen tsthemass
ofaparticle, added tothekinetic energy oftheparticle. InNewtonian mechanics thezeroof
energy isanyhownotwelldened. Hence, m"represen tsforlowvelocities thekinetic energy
oftheparticle, sincetheconstan ttermisofnoimportance. Furthermore, thesecond termin
formula(48)represen tsthelinear momen tumoftheparticle forlowvelocities.
Those concepts canbegeneralized. Here, wedene forthetotalenergy,E,andthelinear
momentum ,pofaparticle whichhasamassmandwhichmoveswithvelocityvinacertain
reference frame
E=m
p
1 v2and p=mv
p
1 v2: (49)
Under Lorentztransformations Eandptransform thesame wayas"andu.Fromformula
(49)weobserv ethatwhen vapproac hesthelightvelocityc=1,thenEtends toinnit y.This
corresp ondsverywelltoexperimen talobserv ation inparticle accellerators.
When aparticle isatrest,itsenergy equals m.Thisisexactly themostfamous formulaof
physics: E=mc2.Therestmassmofaparticle isinvariantunder Lorentztransformations,
i.e.
E2 p2=m2: (50)
5.4Totalinvariantmass
Forasystem oftwoparticles aandbthetotalenergy isgivenby
E=Ea+Eb=q
m2a+p2a+q
m2
b+p2
b; (51)
andthetotallinear momen tum,obviously ,by
p=pa+pb: (52)
Itisnotdicult todemonstrate thatthetotalinvariant mass,ps,squared, dened by
s=fEa+Ebg2 fpa+pbg2; (53)
isinvariantunder Lorentztransformations.
13
6Relativistic kinematics
Most oftheconcepts whichwestudied intheforegoing, canstraigh tforwardly beextended to
three dimensions. Inthefollowing, westudy scattering processes inthree dimensions. For
scattering processes onecanavoidtocarry outexplicitly theLorentztransformations bythe
useoftheso-called Mandelstam variables. Thelatter areLorentzinvariant,hence thesame in
anyinertial frame.
Thetotalenergy ,Etotal,forasystem oftwonon-in teracting on-mass-shell particles ofmasses
m1andm2,whicharefreely movingwithlinear momen tarespectively~p1and~p2,isgivenby
thesumoftheindividual energies, E(~p1)andE(~p2)respectively,according to
Etotal=E(~p1)+E(~p2)=q
~p12+m12+q
~p22+m22: (54)
Inthecenter-of-mass frame, where ~p1= ~p2=~p,onehasthefollowingrelations:
s=(ECM,total)2=2~p2+m12+m22+2q
~p2+m12q
~p2+m22;
s 2~p2 m12 m222=4
~p2+m12
~p2+m22
;
4s~p2=s2 2s
m12+m22
+m14+m24 2m12m22;
and~p2=1
4snh
s (m1+m2)2ih
s (m1 m2)2io
: (55)
TheMandelstam variables, s,tandu,fortheprocess
1+2 !3+4 (56)
aredened by
s=(p1+p2)2;t=(p1 p3)2;u=(p1 p4)2; (57)
or,alternativ ely,byusing totalfour-momen tumconserv ation whichisgivenby
p1+p2=p3+p4; (58)
onealsohas
s=(p3+p4)2;t=(p2 p4)2;u=(p2 p3)2; (59)
Notice thatweuseherethemetric (+; ; ; ),whichforsgives
s=(p1+p2)2=(E(~p1)+E(~p2))2 (~p1+~p2)2: (60)
Inthethecenter-of-mass frame, where ~p1= ~p2,oneobtains, moreo ver
s=(E(~p1)+E(~p2))2=(ECM)2; (61)
whichequals thetotalinvariantmass, asalready anticipated informula(55).
Furthermore, from their denition oneobserv esthattheMandelstam variables (57)are
Lorentzinvariantandhence invariantswithrespecttoanyLorentztransformation.
14
Bytotalmomen tumconserv ation (58),onededuces
s+t+u=3p12+p22+p32+p42+2p1(p2 p3 p4)
=3p12+p22+p32+p42 2p12
=p12+p22+p32+p42
=m12+m22+m32+m42: (62)
Consequen tly,foron-mass-shell processes s,tanduarenotindependen t.
InFig.1wevisualize things forthecenter-of-mass frame.
CM1 2 ~p1 ~p2
m1 m2CM
43
~p4~p3
m4m3
#CM
Before collision After collision
Figure 1:Collision inthecenter-of-mass system. Before collision particle 1andparticle 2move
towardstheircenterofmass withequal andoppositethree-momen ta,~p1and~p2respectively.After
collision particle 3andparticle 4moveawayfromtheircenterofmasswithequal andoppositethree-
momen ta,~p3and~p4respectively.
Theangle betweenthedirection ofmotion oftheoutgoing particle 3andthedirection of
motion oftheincoming particle 1isdened astheangle#CMofthescattering processofformula
(56)inthecenter-of-mass system. Ithasthefollowingrelation withtheMandelstam variable
t.
t=(p1 p3)2(63)
=(p1)2+(p3)2 2p1p3
=(p1)2+(p3)2 2E(~p1)E(~p3)+2~p1~p3
=(m1)2+(m3)2 2q
(~p1)2+(m1)2q
(~p3)2+(m3)2+2j~p1jj~p3jcos(#CM):
15
6.1 + !K+K
Consider a+meson whichannihilates witha meson, resulting intwooutgoing Kaon
mesons, aK+meson andaK meson. The meson isatrestinthelaboratory ,whereas
the+meson hasatotalenergy of9.0GeV. TheKaon meson comes outwithanangle of60
withrespecttothedirection oftheincoming pion,inthecenter-of-mass system.
Giventhisinformation, wemaydetermine theother kinematical quantities. Forthemasses
oftheparticles wetake
m=0:14GeV ;mK=0:50GeV ;mK=0:89GeV :
Letusrstdetermine thetotalinvariantmassofthesystem.
ps=q
2m2+2E+m=1:60GeV :
With thatresult, alsousing formula(55),wemaydetermine ~p2inthecenter-of-mass frame.
(~p)2=1
4h
s 4m2
i
=0:62(GeV) :
Next, wecandetermine (~pK)2inthecenter-of-mass frame, asfollows
(~pK)2=1
4snh
s (mK+mK)2ih
s (mK mK)2io
=0:148(GeV) :
Thelinear momen tumofKisinthecenter-of-mass frame oppositeto~pK,ofcourse. Conse-
quently,wecancheckourcalculations bydetermining thetotalinvariantmasspsaftercollision.
Thisgives
ps=q
~pK2+m2
K+q
~pK2+m2
K=0:63(GeV) +0:97(GeV) =1:60(GeV) ;
whichisindeed what weobtained forthesituation beforecollision. Weobtain herethusthat
thetotalenergy beforeandaftercollision isthesame, hence, totalenergy isconserv ed.
Then wemaydetermine tandu
t=(m)2+(mK)2 2EEK+2j~pjj~pKjcos(#CM)= 0:437GeV2:
and
u=(m)2+(mK)2 2EEK+2j~pjj~pKjcos( #CM)= 1:04GeV2:
Wewilldenote thetotal momen tumofaparticle inthelaboratory byqanditslinear
momen tumby~q.The meson isatrest,hence ~q =0.Forthe+wehave
E(~q+)=q
(~q+)2+m2
+=9(GeV) ()~q+9(GeV) :
Moreo ver,since~q =0,wehaveforttherelation
t=(q qK)2=m2
+m2
K 2m q
~qK2+m2
K;
hence
~qK2= m2
+m2
K t
2m !2
m2
K=4:37GeV2:
16
Similarly
u=(q qK)2=m2
+m2
K 2m q
~qK2+m2
K;
hence
~qK2= m2
+m2
K u
2m !2
m2
K=4:66GeV2:
Also
E(~qK)=q
~qK2+m2
K=4:68(GeV) ;
and
E(~qK)=q
~qK2+m2
K=4:46(GeV) :
Finally ,wedetermine theangle intheframe ofthelaboratory ,ofthedirection oftheoutgoing
Kmeson withrespecttothedirection oftheincoming +meson.
cos(K;lab)=t m2
m2
K+2E(~q+)E(~qK)
2j~q+jj~qKj=0:9974 ;
corresp onding toanangle of4.1degrees.
Although hidden, bytheuseofMandelstam variables, theabovecalculus isbased inLorentz
transformations andtheconstancy ofthelightvelocity.Itis,furthermore based inthedeni-
tions(49)fortheenergy andlinear momen tumofamovingparticle. Theresults areveried
byexperimen t,theultimate judge onourguesses. Everysingle day,invarious particle ac-
cellerators, millions ofsuchscattering processes, involving two,ormanymore particles, are
performed. Uptilltoday,nothing hasbeenfound whichcon
icts withEinstein's assumptions.
6.2Elastic Scattering inthecenter-of-mass system
Inelastic scattering theoutgoing particles areidenticaltotheincoming particles, whichatthis
levelamoun tstom3=m1andm4=m2.When wedene thethree-momen tabeforeandafter
collision byrespectively~pand~p0,thenwehave
~p1= ~p2=~pand ~p3= ~p4=~p0; (64)
hence, byusing formula(55),
~p2=1
4snh
s (m1+m2)2ih
s (m1 m2)2io
and ~p02=1
4snh
s (m3+m4)2ih
s (m3 m4)2io
: (65)
Since, moreo ver,m3=m1andm4=m2forelastic scattering, wehaveforthecenter-of-mass
three-momen tainthatcase
~p2=~p02: (66)
Substitution oftheresult (66)inexpressions (61)and(63)givestheresults
s=q
(~p)2+(m1)2+q
(~p)2+(m2)22
=(~p)2+(m1)2+(~p)2+(m2)2+2q
(~p)2+(m1)2q
(~p)2+(m2)2
=2(~p)2+(m1)2+(m2)2+2q
(~p)2+(m1)2q
(~p)2+(m2)2; (67)
17
and
t=(m1)2+(m3)2 2q
~p2+(m1)2q
~p02+(m3)2+2j~pj~p0cos(#CM)
=2(m1)2 2
~p2+(m1)2
+2~p2cos(#CM)
=2~p2f 1+cos(#CM)g: (68)
Furthermore
u=(m1)2+(m4)2 2q
~p2+(m1)2q
~p02+(m4)2+2~p1~p4
=(m1)2+(m2)2 2q
(~p)2+(m1)2q
(~p)2+(m2)2 2~p2cos(#CM):(69)
Asisobvious fromthedenitions of#CMinFig.1and~pinformula(64),onehas
~p20and 1cos(#CM)+1; (70)
hence fortheMandelstam variables s(formula67)andt(formula68),wend
s(m1+m2)2and t0: (71)
18
6.3Elastic Scattering inthelabsystem
Inthelaboratory system particle 2isassumed tobeatrest. Thisisvisualized inFig.2.
Wedene thelaboratory four-momen tabyq1,q2,q3andq4,inorder todistinguish fromthe
center-of-mass four-momen ta.Westudy hereagain thecaseofelastic scattering, whichimplies
m3=m1andm4=m2.
1 2~q1
m1 m23
4~q3
~q4m3
m4#lab
Before collision After collision
Figure 2:Collision inthelaboratory system. Before collision particle 1moveswiththree-momen tum
~q1towardsparticle 2atrest(~q2=0)inthecenterofcoordinates. After collision particle 3andparticle
4moveawayfromthecenterofcoordinates withthree-momen ta~q3and~q4respectively.
Here, weobtain fortheMandelstam variables (57),which,asmentioned before, areinvariant
under Lorentztransformations, hence thesameforthelaboratory system andthecenter-of-mass
system,
s=(q1+q2)2=(m1)2+(m2)2+2E(~q1)E(~q2) 2~q1~q2
=(m1)2+(m2)2+2E(~q1)m2
t=(q1 q3)2=2(m1)2 2E(~q1)E(~q3)+2~q1~q3
=2(m1)2 2E(~q1)E(~q3)+2j~q1jj~q3jcos(#lab)
u=(q2 q3)2=(m1)2+(m2)2 2m2E(~q3): (72)
Alsousing formula(62),wendfort
t=2m1+2m2 s u=2m2(E(~q3) E(~q1)): (73)
Onedenes thekinetic energy oftheincoming particle by
T1=E(~q1) m1: (74)
Atthreshold, where ~q1=0,weobtain T1=0.
19
PartII
Generalities
7Covariantandcontravariantcomponents
Inavector space ofNdimensions wedene anarbitrary setofbasisvectors,
ei;i=1;:::;N; (75)
andtheirinnerpro ducts, givenby
eiej=gij;i;j=1;:::;N: (76)
Anarbitrary vectorvinthisN-dimensional vector space maybecharacterized byitscom-
ponents,vi,onthebasis(75),asfollows
v=viei; (77)
where, asusually ,repeated indices imply summation.
Using expression (76),weobtain fortheinnerpro ductoftwovectors theresult
vw=viwjeiej=gijviwj: (78)
Thevectorvofformula(77)mightequally wellbecharacterized byitsinnerpro ducts with
thebasisvectors (75). Forthispurposewedene
vi=vei: (79)
There exitsofcourse arelation betweenthetwoquantities viandvi,dened informulas
(77)and(79)respectively.Alsousing denition (76),weobtain forthatrelation thefollowing
result
vi=vei=vjejei=gijvj: (80)
Since wearefreetochooseanybasisintheN-dimensional vectorspace under consideration,
letusselect abasisfag,whichisrelated tothebasis(75)byanonsingular transformation A
givenby
aj=Ajieiandei=
A 1
ijaj: (81)
Thevectorvdened informula(77)hasnewcomponents,sayv0j,atthenewbasisfag.A
relation betweenthetwosetsofcomponentsis,bytheuseofthetransformations (81),readily
found, trough therelation
v0jaj=v=viei=vi
A 1
ijaj;
toyield
20
v0j=vi
A 1
ij: (82)
Wendthusthatthecomponentsofavectortransform withtheinverseofthetransformation
ofthebasiselemen ts,forwhichreason those componentsaresaidtobecontra-variant .
Thecomponentsofvwhicharedened informula(79)transform under thebasistransfor-
mation (81)asfollows
v0j=vaj=vAjiei=Ajivi: (83)
Aparan tly,thequantities(79)transform inthesamewayasthebasisvectors, forwhichreason
theyaresaidtobecovariant .
Theinversetransformation isforthecontravariantcomponentsgivenby
vi=v0jAji; (84)
as,bytheuseofthetransformation property(82)forcontravariantcomponentsandtheusual
rulesforthecomponentsofproducts oftransition matrices, caneasily beseenfrom
v0jAji=vk
A 1
kjAji=vk
A 1A
ki=vki
k=vi:
Anarbitrary pointPintheN-dimensional vectorspace under consideration canbecharac-
terized bythecomponentsfxgofitsposition vectorx(P),withrespecttothebasisfegwhich
isdened informula(75),butequally wellbythecomponentsfx0gwithrespecttothebasis
fagdened informula(81),according to
x(P)=xiei=x0jaj: (85)
Relations betweenbothsetsofcoordinates fxgandfx0gare,according toformulas(82)and
(84),givenby
x0j=xi
A 1
ijandxi=x0jAji: (86)
Suchrelations mightalsobeseenasthedenitions ofthebasistransformations (81).Moreo ver,
therelations (86)arelinear relations betweenthetwosetsofcoordinates andhence itfollows
@x0j
@xi=
A 1
ijand@xi
@x0j=Aji; (87)
suchthatwealsoobtain
x0j=xi@x0j
@xiandxi=x0j@xi
@x0j: (88)
21
8Themetrical tensor
Theobjectgwhichisdened informula(76),willbegiventhenamemetric altensor .Westudy
inthissection itstransformation rulesunder acoordinate transformation oftheform(88).
Fromrelations (76)and(81)oneobtains forthemetric g0atthefagbasis, thetransformation
rule
g0
k`=aka`=AkiA`jeiej=AkiA`jgij;
whichuponsubstitution ofrelation (87)takestheform
g0
k`=@xi
@x0k@xj
@x0`gij: (89)
Relation (89)isoneofthebasic relations indierential geometry .
Thecomponentsoftheinverseofthemetrical tensor aredenoted withupperindices, ac-
cording to
g 1gi
j=gikgkj=i
j: (90)
Those componentstransform under thecoordinate transformation (88)asfollows
g0k`=@x0k
@xi@x0`
@xjgij: (91)
Notice, thatbythedenition (76)boththemetric tensor anditsinversearesymmetric intheir
indices.
22
9Localbasis
Inthissection weconsider anorthonormal basisfeginanN-dimensional Euclidean space and
associated withitasetofcoordinates fxg.Theinner productofthebasis vectors (orthe
metric ofthespace) isthengivenby
eiej=ij; (92)
andanypointPinspace byitscomponents,according to
x(P)=xiei: (93)
Asanexample consider ordinary three-dimensional space.Forthethreebasisvectorswe
selectforourexample e1=^x,e2=^yande3=^z,whereasforthecoordinates wetakex,
yandz.
Now,inthisspace weselect adieren tsetofcoordinates fx0g,suchthateachpointinthe
vectorspace canuniquely bedescrib edbythose coordinates. Thismeans ingeneral thatthere
exists relations betweenthetwosetsofcoordinates fxgandfx0gwhicharesucien tlywell
behaved,suchthatwemaytakeasmanyderivativesasweneedinthefollowing.
Takeasanexample thesetofspheric alcoordinates r,#and'which arerelatedtothe
ordinary 3Dcoordinates, x,yandz,by
x=x(r;#;')=rsin(#)cos('),y=y(r;#;')=rsin(#)sin(')and
z=z(r;#;')=rcos(#).
Associated withthesetofcoordinates fx0gwechooseateachpointofourspace anewlocal
basisfu(x0(x))g,whichbasisservesformeasuremen tsinthedirect vicinit yofthepointunder
consideration, buthasnomeaning ataglobal level.Thetransformations whichrelate the
global basisfegandthelocalbasisfu(x0(x))g,aregivenby
uj(x0)=@xi
@x0jeiandei=@x0j
@xiuj(x0): (94)
Forthe3Dspheric alcoordinates, weobtain foralocalbasisthe^r,^#and^'unitvectors:
^r(r;#;')=f^xcos(')+^ysin(')gsin(#)+^zcos(#),
^#(r;#;')=r[f^xcos(')+^ysin(')gcos(#) ^zsin(#)]and
^'(r;#;')=r[ ^xsin(')+^ycos(')]sin(#).
23
10Themetric ofthelocalcoordinates
Themetric gofthenewcoordinates is,byanalogy offormula(76),determined bytheinner
products ofthelocalbasisvectors. Using formulas(92)and(94),onends
gk`(x0)=uk(x0)u`(x0)=@xi
@x0k@xj
@x0`ij; (95)
whereas, asinformula(91),fortheinversemetric follows
gk`(x0)=@x0k
@xi@x0`
@xjij: (96)
Forthe3Dspheric alcoordinates, wendforthemetric
g(r;#;')=0
BBBB@grrgr#gr'
g#rg##g#'
g'rg'#g''1
CCCCA=0
BBBB@^r^r^r^#^r^'
^#^r^#^#^#^'
^'^r^'^#^'^'1
CCCCA=0
BBBB@10 0
0r20
00r2sin2(#)1
CCCCA
(97)
11Dieren tiation withrespecttothelocalbasis
Fordieren tiation withrespecttothelocalcoordinates weintroduceanewnotation, inorder
tosimplify theformulastocome. Wewrite:
F(x0);i=@F(x0)
@x0i: (98)
Inthisnewnotation wemaycast,forexample, expression (95)forthelocalmetric, intheform
gk`(x0)=ijxi;kxj;`: (99)
Notice however,thatforthetransformation (96)thenotation remains asitwas.
Fordouble derivativeswehavetwoalternativ es,oneofwhichismore compact andwillbe
usedinthisnotes, i.e.
F(x0);ij=F(x0);i;j=@2F(x0)
@x0i@x0j: (100)
Since dieren tation doesnotdependontheorder, onehasmoreo verthat
F(x0);ij=F(x0);ji:
24
12Christoel symbols(ane connection)
Inthissection westudy howthelocalbasisvectors change ifwemoveinspace fromoneplace
totheother. Itmightbeclearthatthevariations ofthelocalbasisvectors insuchaprocess
arecompletely determined onceweknowthederivativesofthese vectors ineachpoint.So,
werestrict ourselv estoinnitesimal small variations inspace. Moreo ver,wemayassume that
thederivativeofoneofthelocalbasisvectors canbeexpressed asalinear combination ofthe
complete localbasis, since locallythelatter formacomplete basis. Thecoecien tsofsuch
expression arecalled ane connections ,symbol .Therelation is,bytheuseofthenotation
dened informula(98),givenby:
uj(x0);i= k
ij(x0)uk(x0): (101)
Inorder toexpress the 'sinterms ofderivatives,letus,alsousing formulas(94)and(100),
consider thefollowingexpression
uj(x0);i=
x`;je`
;i=x`;ije`=x`;ij@x0k
@x`uk(x0);
fromwhichwe,bycomparing withformula(101), deduce theidentity
k
ij(x0)=x`;ij@x0k
@x`: (102)
Notice thattheane connection issymmetric inthelowerindices, sincedieren tation is,i.e.
k
ij(x0)= k
ji(x0): (103)
Thenon-zer ocomponents oftheane connections forthe3Dspheric alcoordinates, are
thefollowing
r
##=x`;##@r
@x`= rsin(#)cos(')x
r rsin(#)sin(')y
r rcos(#)z
r= r;
r
''=x`;''@r
@x`= rsin(#)cos(')x
r rsin(#)sin(')y
r= rsin2(#);
#
''=x`;''@#
@x`= rsin(#)xcos(')+ysin(')
r2px2+y2z= cos(#)sin(#);
similarly
#
r#=1
r= #
#r; '
r'=1
r= '
'r; '
#'=cos(#)
sin(#)= '
'#(104)
25
13Therelation betweentheane connection andthe
metric
Forcompleteness, werepeatherethederivation oftherelation betweenthemetrical tensor (95)
andtheane connection (102).
First, wedetermine thederivativeofthecomponentsofthemetrical tensor withrespectto
thelocalcoordinates
gij(x0);k=
`mx`;ixm;j
;k=`mx`;ikxm;j+`mx`;ixm;jk:
Next, wenotice thatifwetakealinear combination oftheaboveexpression forthederivatives,
obtained bypermuting theindices (i;j;k),thenwecansingle outoneterm, according to
kij=1
2
gki;j+gkj;i gij;k
=`mx`;ijxm;k: (105)
Theabovequantities aretheChristoel symbols,whichcanberelated totheane connec-
tions(102), alsousing formula(96),by
gk` `ij=@x0k
@xp@x0`
@xqpqmnxm;ijxn;`
=@x0k
@xppqnqmnxm;ij= k
ij: (106)
Using themetric altensor which isgiven informula (97),weobtain forthenon-zer o
components oftheane connections forthe3Dspheric alcoordinates, thefollowing
r
##=grr r##= r; #
r#= #
#r=g## #r#=1
r;
r
''=grr r''= rsin2(#); '
r'= '
'r=g''